Solve and graph 4<-1/3n

Answer:

Composite area is 400+157=557

or 400 + 50pi

Step-by-step explanation:

First find the area of the square

A=s*s A= 20*20

Area of the square portion is 400

then find the area of the semicircle- we know the diameter of the circle is 20, so the radius is 10.

[tex]A=\frac{1}{2} \pi r^{2}[/tex]

so

[tex]A=\frac{1}{2} \pi 10^{2} \\A=\frac{1}{2}\pi 100\\A=50\pi \\A= 157[/tex]

Composite area is 400+157=557

or 400 + 50pi

Answer:

3x - 4 = 20

3x = 20 + 4

3x = 24

x = 24/3

x = 8

Answer:

[tex]3x - 4 = 20 \\3x = 20 + 4 \\ 3x = 24 \\ 3x \div 3 = x \\ 24 \ \div 3 = 8 \\ x = 8 [/tex]

Answer:

[tex]x = \frac{48}{\sqrt{3}}[/tex]

[tex]y = \frac{24}{\sqrt{3} }[/tex]

[tex]z = 24[/tex]

Step-by-step explanation:

___________________________________________________________

FACTS TO KNOW BEFORE SOLVING :-

For a triangle with one of it's acute angle α (alpha) , the value of :-

___________________________________________________________

In the question , first of all lets find the value of z. So,

[tex]\cos 45 = \frac{z}{24\sqrt{2}}[/tex]

[tex]=> \frac{1}{\sqrt{2}} = \frac{z}{24\sqrt{2}}[/tex]

[tex]=> z = \frac{24\sqrt{2}}{\sqrt{2}} = 24[/tex]

Length of the altitude perpendicular to side (z + y) = [tex]\sqrt{(24\sqrt{2})^2 - 24^2} = 24[/tex]

Now , lets find the value x. So,

[tex]\sin 60 = \frac{24}{x}[/tex]

[tex]=> \frac{\sqrt{3}}{2} = \frac{24}{x}[/tex]

[tex]=> x = \frac{48}{\sqrt{3}}[/tex]

Also ,

[tex]\cos 60 = \frac{y}{x}[/tex]

[tex]=> \frac{1}{2} =\frac{y}{\frac{48}{\sqrt{3}}}[/tex]

[tex]=> y = \frac{48}{2\sqrt{3}} = \frac{24}{\sqrt{3}}[/tex]

Answer:

!

Step-by-step explanation:

here it is!!!!!!!!!!!!!!!

Answer:

i got 21/1

Step-by-step explanation:

Answer: x = 16

Step-by-step explanation:

Answer:

85

Step-by-step explanation:

He has 170 correct answers, so 170 * 0.5 = 85 points  #0.5 points per 1 question

Answer:

Step-by-step explanation:

Repost with picture and I can help you

sorry I cant answer your question if all you write " is help me pls"

Answer: The survey will likely overestimate mean annual salary because those with higher salanes may be more likely to respond to the survey.

Step-by-step explanation:

We should note that this is voluntary response because despite the fact that the email was sent to the students, a graduate can decide to be part of the sample or not.

In this case, those that have higher salaries will be more likely to respond to their emails than those that have lower salaries. Therefore, the survey will likely overestimate mean annual salary.

Answer:

4

Step-by-step explanation:

x² = 8x - 16

x² - 8x + 16 = 0

(x - 4)² = 0

x = 4

Answer:

0.03, 0.06, 0.2, 0.76, 1

Step-by-step explanation:

Answer:

523.6 m³

Step-by-step explanation:

The polyhedron is an oblique cone

Volume of oblique cone = ⅓πr²h

r = x = 5 m

h = y = 20 m

Volume = ⅓*π*5²*20

Volume = ⅓*π*25*20

Volume = 523.598777 ≈ 523.6 m³ (nearest tenth)

9514 1404 393

Answer:

  1a. E = 5×1.59^t

  1b. 32 GWh

  1c. 1986

Step-by-step explanation:

1a. An exponential model looks like

  f(t) = a·b^t

where 'a' is the value when t=0, and 'b' is the growth factor in the time period associated with t.

Here, 'a' is 5 (GWh), and 'b' is 1+59% = 1.59. Then the desired model is ...

  E = 5·1.59^t . . . . . where t is years after 1980, and E is in GWh.

__

1b. For t=4, we have ...

  E = 5·1.59^4 ≈ 31.96 ≈ 32

About 32 GWh was generated in 1984.

__

1c. The value of t for a given value of E is ...

  E/5 = 1.59^t . . . . divide by 5

  log(E/5) = t·log(1.59) . . . . take logarithms

  t = log(E/5)/log(1.59) . . . . divide by the coefficient of t

For E = 80, the years after 1980 are ...

  t = log(80/5)/log(1.59) ≈ 5.98

About 80 GWh were generated in 1986.

Answer:

50 dollars per month

Step-by-step explanation:

Money saved over time period x / Time period x = $250/5 months=$50/1 month

Answer:

c.{-2,2}

Step-by-step explanation:

6

x

2

−

24

=

0

Use the quadratic formula to find the solutions.

−

b

±

√

b

2

−

4

(

a

c

)

2

a

Substitute the values

a

=

6

,

b

=

0

, and

c

=

−

24

into the quadratic formula and solve for

x

.

0

±

√

0

2

−

4

⋅

(

6

⋅

−

24

)

2

⋅

6

Simplify.

x

=

±

2

The final answer is the combination of both solutions.

x

=

2

,

−

2

Answer: (a)-48 days

Step-by-step explanation:

Given

Joan is watching 275 episodes of Cheers and already watched 83

She can watch 4 episodes per day

Remaining episode 275-83=192

No of days required to finish Cheers

[tex]\Rightarrow n=\dfrac{192}{4}=48\ \text{days}[/tex]

Answer:

B

Step-by-step explanation:

I chose the answer B because there is no there should be no exponents to make the answer linear

Answer:

B because Linear equation doesnt have an exponent

Answer:

17x + 56 = 0

Step-by-step explanation:

add 2x and 15x

Answer:

sorry I can't answer

Step-by-step explanation:

pls thanks me

Answer:

169.28

Step-by-step explanation:

18.4x9.2=169.28

Answer:

The dolphin will be above the surface of the water for 2 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

The height of the dolphin after t seconds is given by:

[tex]h(t) = -16t^2 + 96t - 128[/tex]

According to Micha's model, how long will the dolphin be above the surface of the water?

It stays above the surface of the water between the first and the second root. Initially, it is below water, when the first time for which [tex]h(t) = 0[/tex] it crosses the surface upwards, and then the second time for which [tex]h(t) = 0[/tex] it crosses the surface downwards.

We have to find these roots. So

[tex]h(t) = -16t^2 + 96t - 128[/tex]

[tex]-16t^2 + 96t - 128 = 0[/tex]

Multiplying by -16

[tex]t^2 - 6t + 8 = 0[/tex]

[tex]\Delta = (-6)^{2} - 4*1*8 = 36 - 32 = 4[/tex]

[tex]t_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4[/tex]

[tex]t_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2[/tex]

4 - 2 = 2

The dolphin will be above the surface of the water for 2 seconds.

Answer:

2x^3  +7x^2+3x-2

Step-by-step explanation:

3x^3 +7x^2 -x

- ( x^3 -4x +2)

------------------------

The first step is to line up the variables by degree

 3x^3 +7x^2 -x

- ( x^3           -4x +2)

----------------------------

Then distribute the minus sign

 3x^3 +7x^2 -x

-  x^3           +4x -2

----------------------------

2x^3  +7x^2+3x-2

Answer: use  the app photomath. its free.  you take a picture and it will show you all the steps in depth

Step-by-step explanation:

Answer:

5) 10³: So you do 10* 10*10= 1,000

so 10³= 1,000

All you are doing is takeing the number and multiplying itself to the power.

6) (-7)⁴= so you are taking the -7 in parenthesis and making it positive, then you are taking the positive 7 and doing  7⁴. Once you do that you get positive 2401.

8) 3+6* (-5) to the second (i dont have the symbol) so you are going to do PEMDAS: Parenthesis, Expression, Multipulcation, Divison, Addition and Subtraction. so it would be 5+6*25to the second. So you do multipulcation first, so do 6*25=150. Then do addition and do 150+3=153

Step-by-step explanation:

5) 10³= 1,000

6)(-7)⁴= 7⁴= 2401

8)3+6* (-5) to the second= 3+6* (5) to the second= 3+6* 25= 6*25= 150+3= 153

Answer to 8 is= 153

I hoped this helped you :D

Answer:

hmmm

Step-by-step explanation:

not sure man

Answer:

(b)

Step-by-step explanation:

Given

A roll of a six sided die

Required

Which of the options is true

A) P(Even) = 1/4 and P(Odd) = 3/4

In a die, we have:

[tex]S = \{1,2,3,4,5,6\}[/tex] -- sample space

[tex]E = \{2,4,6\}[/tex] --- Even

[tex]O = \{1,3,5\}[/tex] -- Odd

The probability of even is the number of even sides over total.

i.e.

[tex]P(Even) = 3/6[/tex]

[tex]P(Odd) = 3/6[/tex]

Hence, (a) is incorrect

(b) A) P(Even) = 1/2 and P(Odd) = 3/2

In (a), we have:

[tex]P(Even) = 3/6[/tex]

[tex]P(Odd) = 3/6[/tex]

Simplify each

[tex]P(Even) = 1/2[/tex]

[tex]P(Odd) = 1/2[/tex]

Hence (b) is true

Since (b) is true, (c) and (d) are false