Select all acute angles:

Answer:

k=-2

Step-by-step explanation:

Using substitution to find what you're missing, (in this case k) is when you plug each letter into the other equation:

-4k+3=3k+17

So now solve for k:

subtract 3 from both sides...

-4k=3k+14

subtract 3k from both sides to combine with -4k...

-7k=14

divide -7 from both sides...

k=-2

The solving of the fractions simply shows that the value of 1 2/3 + 3 1/2 is 5 1/6.

The first fraction give is:

= 1 2/3 + 3 1/2

= 1 4/6 + 3 3/6

= 4 7/6

= 4 + 1 1/6

= 5 1/6

Also 3/4 - 5/7 will be:

= 3/4 - 5/7

= 21/28 - 20/28

= 1/8

It should be noted that when solving fractions, it's important to have a common denominator.

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Answer: p = 9h

Step-by-step explanation:

     If she makes 9 dollars of every hour of work, this will be a linear equation. We will write it as the following:

      p = 9h

Answer:

9h/p

Step-by-step explanation:

9 x # of hours = total pay

$9 is the dollars for each hour, so you multiply that by how many hours Maria works. You will get the total pay.

Step-by-step explanation:

angle ADC = angle ABC / 2

= 135/2 = 67.5°

AC = 2r * sin (62.5)

AC = 1.84r

r is the radius of circle

Answer: a= - [tex]\frac{b}{x}[/tex]- [tex]\frac{c}{x2}[/tex]

Step-by-step explanation:

1. Move all terms not containing [tex]\alpha[/tex] to the right side of the equation.

[tex]\alpha[/tex][tex]x^{2}[/tex]=-bx-c

2. Divide each term in [tex]\alpha x^{2}[/tex]=-bx-c by [tex]x^{2}[/tex] and simplify.

a= - [tex]\frac{b}{x}[/tex] - [tex]\frac{c}{x^{2} }[/tex]

Using the Central Limit Theorem, it is found that none of the samples satisfy the normal condition.

It states that the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex], as long as at least one of these following conditions is respected.

In this problem, the underlying distributions are skewed, and both sample sizes are less than 30, hence none of the samples satisfy the normal condition.

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Answer:

N/A

Step-by-step explanation:

Answer:

Nth term = 19 - 4(n-1)

Step-by-step explanation:

First term be A

Nth term = A - 4(n-1)

3rd term = 11 = A - 4*2 = A - 8

A = 19

Nth term = 19 - 4(n-1)

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]x + y =3\implies y=-x+3\implies y=\stackrel{\stackrel{m}{\downarrow }}{-1}x+3 \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{-1\implies \cfrac{-1}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{-1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{-1}\implies 1}}[/tex]

Answer:

i think so 4.32 L

Answer:

126 mi²

Step-by-step explanation:

Surface Area of a Rectangular Prism :

Answer:

x = -22.5

Step-by-step explanation:

Assuming 4x + 90 = 0

4x + 90 = 0

4x = -90

-90/4 = -22.5

radius of small cone= 4 cm

radius of large cone= 6 cm

height of small cone= 4 cm

height of large cone= 20 cm

[tex]v = \frac{1}{3} \pi {r}^{2} h[/tex]

[tex]v = \frac{1}{ 3} \times \pi \times {6}^{2} \times 20[/tex]

[tex]v = 753.98 \: {cm}^{3} [/tex]

[tex]v = \frac{1}{ 3 } \pi {r}^{2} h[/tex]

[tex]v = \frac{1}{3} \times \pi \times {4}^{2} \times 4[/tex]

[tex]v = 67.02 \: {cm}^{3} [/tex]

[tex]v = 753.98 - 67.02[/tex]

[tex]v = 686.96 \: {cm}^{3} [/tex]

volume of smaller cone:

[tex] = 67.02 {cm}^{3} [/tex]

volume of larger cone:

[tex] = 753.98 {cm}^{3} [/tex]

frustum:

[tex] = 686.96 {cm}^{3} [/tex]

The equation first, third, fifth and seventh are equivalent to the fifth, second, fourth and eighth equation.

Equivalent expressions are the expression whose result is equal to the original expression, but the way of representation is different.

Equivalent expression can be found out by simplifying the given equation.

First equation given as,

[tex]\left(-14+\dfrac{3}{2}b\right)-\left(1+\dfrac{8}{2}b\right)[/tex]

Simplify it further,

[tex]\left(-14+\dfrac{3}{2}b\right)-\left(1+\dfrac{8}{2}b\right)\\-14+\dfrac{3}{2}b-(1+4b)\\-14+\dfrac{3}{2}b-1-4b\\-15-\dfrac{5}{2}b[/tex]

Third equation in the problem given as,

[tex]\left(5+2b\right)+\left(2b+\dfrac{3}{2}\right)\\5+2b+2b+\dfrac{3}{2}\\4b+\dfrac{13}{2}[/tex]

Simplify it further,

[tex]\left(-14+\dfrac{3}{2}b\right)-\left(1+\dfrac{8}{2}b\right)\\-14+\dfrac{3}{2}b-(1+4b)\\-14+\dfrac{3}{2}b-1-4b\\-15-\dfrac{5}{2}b[/tex]

Similarly, the fifth and seventh equation are simplified and equivalent to the fourth and eight respectively.

Thus, the equation first, third, fifth and seventh are equivalent to the fifth, second, fourth and eighth equation.

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[tex]\large\displaystyle\text{$\begin{gathered}\sf 1. \ \sqrt{5x+4} -1=2x \end{gathered}$}[/tex]

The root of the equation is solved first. Afterwards, both members of the equality are squared, the powers are developed and it is solved.

     [tex]\large\displaystyle\text{$\begin{gathered}\sf \sqrt{5x+4}=2x+1 \Longrightarrow 5x+4=(2x+1)^2 \end{gathered}$}[/tex]

           [tex]\large\displaystyle\text{$\begin{gathered}\sf 0=4x^2 +4x+1-5x-4 =4x^2-x-3 \\ &= 4\left(x^2-\dfrac{1}{4}-\dfrac{3}{4} \right)\\ &=4\left(x-1\right)\left( x+\dfrac{3}{4}\right) \end{gathered}$}[/tex]

                                           [tex]\large\displaystyle\text{$\begin{gathered}\sf x_1=1 \qquad x_2=-\dfrac{3}{4} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf 2. \ 3\sqrt{x-1}+11=2x \end{gathered}$}[/tex]

The root of the equation is cleared. Then, both sides of the equality are squared, the powers are developed and it is solved by the general formula.

               [tex]\large\displaystyle\text{$\begin{gathered}\sf 3\sqrt{x-1}=2x-11 \Longrightarrow 9(x-1)=(2x-11)^2 \end{gathered}$}[/tex]

            [tex]\large\displaystyle\text{$\begin{gathered}\sf 0=4x^2 -44x+121 -9x+9 =4x^2-53x+130 \end{gathered}$}[/tex]

   [tex]\large\displaystyle\text{$\begin{gathered}\sf x_{1,2}=\dfrac{53\pm \sqrt{(-53)^2-4(4)(130)}}{2(4)}=\dfrac{53\pm \sqrt{2809-2080}}{8}\\ &=\dfrac{53\pm \sqrt{729}}{8} = \dfrac{53\pm 27}{8}; \end{gathered}$}[/tex]

                               [tex]\large\displaystyle\text{$\begin{gathered}\sf \begin{matrix} \ \ \ \ \ \ x_{1}=\dfrac{53+ 27}{8} \qquad &\ \ \ \ \ x_2=\dfrac{53 - 27}{8}\\ x_1=\dfrac{80}{8} \qquad &\ \ x_2=\dfrac{26}{8}\ \ \ \\ x_1=10 \qquad &x_2=\dfrac{13}{4} \end{matrix} \end{gathered}$}[/tex]

Answer:

OBtuse <

Step-by-step explanation:

Answer:

$ 141 690 .

Step-by-step explanation:

It is already rounded  to the nearest 10 dollars

Hey there!

10(0j + 4j + 40)

DISTRIBUTE 10 WITHIN the PARENTHESES

= 10(0j) + 10(4j) + 10(40)

= 0j + 40j + 400

COMBINE the LIKE TERMS

= (0j + 40j) + (400)

= 0j + 40j + 400

= 40j + 400

Therefore, the answer should be:

40j + 400

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

[tex]\boxed{40j + 400}[/tex]

Step-by-step explanation:

Given expression:

[tex]10(0j + 4j + 40)[/tex]

Since the expression inside the parentheses can be simplified, it is suggested to simplify the expression, inside the parentheses, first.

[tex]\implies10[j(0 + 4) + 40][/tex]

[tex]\implies 10[4j + 40][/tex]

Now, simplify the distributive property.

The distributive property can be simplified by multiplying the term outside the parentheses with all the terms inside the parentheses.

[tex]\implies 10[4j + 40][/tex]

[tex]\implies [4j \times 10] + [40 \times 10][/tex]

[tex]\implies \boxed{40j + 400}[/tex]

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[tex]5^2(5^3 \cdot 5^2)\\\\=5^{2+3+2}\\\\=5^7\\\\=78125[/tex]

Answer:

5^7 or 78125

Step-by-step explanation:

5^2 (5^3 x 5^2)

This is the 5^2 is the same thing as 5x5 while 5^3 is the same as saying 5x5x5, when we evaluate these equations we get a new formula:

= 25 ( 125 x 25)

now we simplify.

= 25 (3125)

= 78125

Answer:

2:35 pm

If an hour is 60 minutes, what we know is that 30 minutes is half. However, we must subtract 55 from 30 (In time)

To make this easier, subtract 55 by actual 30, and split 55 into 2 parts, the result of subtraction, and the other value, 30

[tex]55-30=25[/tex]

Now, subtract.

[tex]3:30 - 30 = 3:00[/tex]

[tex]3:00-25=35[/tex]

If this is the case, the lesson must have started at 2:35 pm

Answer:

3 1/2

Step-by-step explanation:

the letter j is HALFway between four and three so it is 3 1/2

Answer:

5.5 Hours

or

5 Hours 30 Minutes

Step-by-step explanation:

[tex]\cos32^{\circ} \\\\=\sin(90-32)^\circ~~~~~~~~~~~~~~;[\cos \theta = \sin(90- \theta)]\\\\=\sin 58^{\circ}[/tex]

The factorization of the given polynomial is:

p(x) = (x - 2/3)*(x - 1) = (1/3)*(3x - 2)*(x - 1)

We have:

[tex]p(x) = 3x^2 - 5x + 2[/tex]

First, we need to find the two roots for the equation, then we use Bhaskara's formula to get:

[tex]x = \frac{5 \pm \sqrt{5^2 - 4*3*2} }{2*3} \\\\x = \frac{5 \pm 1}{6}[/tex]

So the two solutions are:

x = (5 + 1)/6 = 1

x = (5 - 1)/6 = 4/6 = 2/3

Then the polynomial can be written as:

p(x) = (x - 2/3)*(x - 1)

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Answer: (3x -2) and (x-1)

Step-by-step explanation:

Just took the test

Answer:

Its was 2002 since that is the first heightest bar pass 3000

The two-way table is an illustration of probability, and the value of P(Adult|Second run) is 0.600

The probability to calculate is given as: P(Adult|Second run)

This means:

The probability that an Adult is selected given that the adult runs the second run

The formula to solve this is:

P(Adult|Second run) = n(Adult and Second run)/n(Second run)

From the table, we have:

n(Adult and Second run) = 219

n(Second run) = 365

So, we have:

P(Adult|Second run) = 219/365

Evaluate

P(Adult|Second run) = 0.600

Hence, the value of P(Adult|Second run) is 0.600

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Answer:

The value of P rounded to the nearest thousandth would be 0.6

Hope this helped!

Answer:60-30 I guess

Step-by-step explanation:n60-30=30

Answer:

you can find the given attachment

Answer: y-2 > 1/4(x-4)

Step-by-step explanation:

use slope formula y2-y1/x2-x1 so 2-0/4-(-4) = 1/4

slope int form is y-y1 = m(x-x1)

plug in one point

y-2 = 1/4(x-4)

insert (0,0)

you find y-2 > 1/4(x-4)

Answer:

Sum equation: x + y = 29

Difference equation: x - y = 13

Answer:

A. 17

B. 16

Step-by-step explanation:

F(5)

5 > 2 so you plug the 5 into 3x+2

F(-2)

-5 < -2 < 2 so you plug the -2 into (x-2)^2