Sandeep used 8 litres of fuel to travel 76 miles.

He wants to know how many miles he will be able to travel with 22 litres of fuel.

He assumes that the distance travelled and the amount of fuel used are directly proportional.

How many miles can he drive with 22 litres of fuel?

Answer:

height is 7 inches

Step-by-step explanation:

a=1/2bh

28=1/2(8)h

28=4h

/4

7=h

check your work

8x7= 56

56/2=28

Step-by-step explanation:

[tex]2 {x}^{2} + 11x + 5 \\ {x}^{2} + 5.5x + 12.5 \\ = -2.75-2.222i \\ \: \: \: - 2.75 + 2.22i \\ \alpha = - 2.75 - 2.22i \\ \beta = - 2.75 + 2.22i[/tex]

[tex] { \alpha }^{4} + { \beta }^{4} = -284.2912344[/tex]

[tex]\frac{1}{ \beta } + \frac{1}{ \alpha } + 2 \alpha \beta = 24.9818[/tex]

Answer:

Andre     Noah     Weeks

 20           10             1

 25         17.50         2

 30           25            3

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

f(-3)=-2(-3)+4=6+4=10

Answer:

alex

Step-by-step explanation:

Answer:

3(x+7)

Step-by-step explanation:

Answer:

5 is the hight

Step-by-step explanation:

Answer:

sorry but all i got from this is the first one should be -3

Step-by-step explanation:

sorry that i couldn't answer all :)

Answer:

Value of boat = $23,400

Loss of value by boat per year = 8%

To find: -  Monthly percent decrease in value of boat.  

Solution: - Decrease of value per year = 8% of $23,400 = $1,872. Monthly decrease in value = $1,872/12 = $156. Monthly percentage decrease = ($156/$23,400) * 100 = 0.6667 or 0.67 (rounded to nearest hundredth)

Step-by-step explanation:

Answer:

Step-by-step explanation:

d+821=5323

d=4502

So the distance she climbed in the first four days was 4502 feet.

Answer:

x = 8

y = 8√3

Step-by-step explanation:

sin(30) = 1/2

cos(30) = √3/2

They are rule!!!

Answer:

hannah is 47 and Anthony is 45

Step-by-step explanation:

Sum= 92= a+(a+1)

sum= 45+(46+1)

sum= 45+47

sum= 92

Answer:

your answer will be A

Step-by-step explanation:

^_^

Answer:

Step-by-step explanation:

x=57

y=57

z=66

Answer: 6 units

Step-by-step explanation:

Since this is just a reflection, the length of A'C' shouldn't be different from the length of AC.

Answer:

189/230

Step-by-step explanation:

Convert these to fractions first, because then it would be easier to calculate.

3 39/50 divided by 4 3/5

Turn the fractions into improper fractions:

189/50 divided by 23/5 = 189/50 times the reciprocal of 23/5

So we have:

189/50 x 5/23 = 945/1150 = 189/230

Answer:

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4 .

Answer:

B) 10

Step-by-step explanation:

Exterior angle property: Exterior angle equals the sum of opposite interior angles.

12x + 10 = -10 + 7x +  70 {Subtract 10 from both sides}

12x        = -10 + 7x + 70 - 10        

       12x = -10 + 70 - 10 + 7x  {Combine like terms}

      12x  = 50 + 7x          {Subtract 7x from both sides}

12x - 7x = 50

       5x = 50 {Divide both sides by 5}

         x = 50/5

x = 10

Answer:

.5

Step-by-step explanation:

slope = rise/run= 1.5/ 3= 0.5

hope that helps if it does please mark as brainliest.

Answer:

1. The sides are: 38.5, 39.5, 40.5 and 41.5

2. Presently, Inzo is 15 years old and Miz is 10 years old

3. [tex]Distance = 3682km[/tex]

4. Possible pairs are: (12, 14), (16, 18) and (20, 24)

5. [tex]L < 38m[/tex]

Step-by-step explanation:

The question has lots of missing details. See the comment section for complete question

Solving (a):

Given

Shape: Quadrilateral

Sides: Consecutive

[tex]Perimeter = 160[/tex]

Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.

So, the perimeter is:

[tex]Perimeter = x + x + 1 + x + 2 + x + 3[/tex]

This gives:

[tex]160 = x + x + 1 + x + 2 + x + 3[/tex]

Collect Like Terms

[tex]160 -1-2-3= x+x+x+x[/tex]

[tex]154= 4x[/tex]

Divide both sides by 4

[tex]38.5 = x[/tex]

[tex]x =38.5[/tex]

So, the sides are: 38.5, 39.5, 40.5 and 41.5

Solving (b):

Given

Presently: [tex]Inzo = 10 + Miz[/tex]

Five years ago: [tex]Miz - 5= \frac{1}{3} * (Inzo-5)[/tex] --- (Missing from the question)

Required: Determine their present ages

Substitute [tex]10 + Miz[/tex] for Inzo in the second equation

[tex]Miz - 5 = \frac{1}{3} * (10 + Miz - 5)[/tex]

[tex]Miz - 5 = \frac{1}{3} * (Miz + 5)[/tex]

Multiply both sides by 3

[tex]3Miz - 15 = Miz + 5[/tex]

Collect Like Terms

[tex]3Miz -Miz = 15 + 5[/tex]

[tex]2Miz= 20[/tex]

Divide both sides by 2

[tex]Miz = 10[/tex]

Substitute 10 for Miz in [tex]Inzo = 10 + Miz[/tex]

[tex]Inzo = 10 + 5[/tex]

[tex]Inzo = 15[/tex]

So presently, Inzo is 15 years old and Miz is 10 years old

Solving (3):

Given

Express Train:

[tex]Speed = 100kph[/tex]

[tex]Time = t[/tex]

Local Train:

[tex]Speed = 45kph[/tex]

[tex]Time = t + 45[/tex]

Required: Determine the distance between A and B

Distance is calculated as:

[tex]Distance = Speed * Time[/tex]

For the express train:

[tex]Distance = 100 * t[/tex]

For the local train

[tex]Distance = 45 * (45 + t)[/tex]

Distance between both stations are equal; So,

[tex]100 * t = 45 * (45 + t)[/tex]

[tex]100 t = 2025 + 45t[/tex]

Collect Like Terms

[tex]100 t -45t= 2025[/tex]

[tex]55t= 2025[/tex]

Divide by 55

[tex]t = 36.82[/tex]

Substitute 36.82 for t in [tex]Distance = 100 * t[/tex]

[tex]Distance = 100 * 36.82[/tex]

[tex]Distance = 3682km[/tex]

Solving (4):

Let the even numbers be: n and n + 2.

Sum greater than 24: [tex]n + n + 2 > 24[/tex]

Sum less than 60: [tex]n + n + 2 < 60[/tex]

So, we have:

[tex]n + n + 2 > 24[/tex]

[tex]2n + 2 > 24[/tex]

Collect Like Terms

[tex]2n > 24-2[/tex]

[tex]2n > 22[/tex]

[tex]n > 11[/tex]

[tex]n + n + 2 < 60[/tex]

[tex]2n + 2< 60[/tex]

Collect Like Terms

[tex]2n < 60-2[/tex]

[tex]2n < 58[/tex]

Divide by 2

[tex]n<29[/tex]

So, we have:

[tex]n > 11[/tex] and [tex]n < 29[/tex]

So, possible pairs are: (12, 14), (16, 18) and (20, 24)

Solving (5):

Given

[tex]Perimeter < 152m[/tex]

Required: Find the possible lengths

Let the length be L.

Perimeter is calculated as:

[tex]Perimeter =4 * L[/tex]

[tex]Perimeter =4 L[/tex]

So, we have:

[tex]4L < 152m[/tex]

Divide through by 4

[tex]L < 38m[/tex]

Hence, length is less than 38m (e.g. 37m)

The correct answer is b) Sometimes.

Given that a statement,

"The sum of two numbers is __________ greater than either number."

We need to fill the blank from the options provided.

The sum of two numbers can be greater than either number depending on the specific values of the numbers.

Let's consider some examples:

Example 1: If we have two positive numbers, such as 3 and 4, their sum (3 + 4 = 7) is greater than either number individually.

Example 2: If we have one positive number and one negative number, such as 5 and -8, their sum (5 + (-8) = -3) is greater than -8 but less than 5.

Example 3: However, if we have two negative numbers, such as -2 and -4, their sum (-2 + (-4) = -6) is not greater than either number individually.

Therefore, since the statement holds true in some cases but not in others, the correct answer is sometimes (b).

Learn more about Sum click;

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Answer:

it's 35

Step-by-step explanation:

3+5 = 8

35 is odd

and 3-5 = 2

Answer: 5.9j-6

Step-by-step explanation:

Answer:

annual: $18000

weekly: $346.15