rewrite the equation y-8=2 into slope form

The correct answer is A.

Step - by - step answer:

Mario will travel a distance equal to 1 circumference of the wheel for each complete revolution of the wheel.

Circumference of Mario's wheel, C = πD, where D is the diameter of the circle.

Hence, C = 26π inches

Speed = Distance / Time

Distance for 200 revolutions in ft = 26π x 200 x 1/12

Time in sec = 60

So, speed =  (26π x 200)/(12 x 60)

= 65π/9

=22.69 is the average speed.

P.s: Answer is copied from https://www.myactguide.com/math/mario-was-riding-a-bicycle-with-wheels-26-inches-in-diameter

Answer:

2 5/7 5/7 -1/7, -5/7, 1 2/7, -2 2/7, -1 5/7

(a) X ≈ N (0.10 , 0.02²)

(b) The probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.

(c) The 60th percentile is 11%.

A. X ~ N( , )  

B. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11%.

C. Find the 60th percentile for this distribution.

According to the question,

The random variable X is defined as the THC content for a bag of marijuana that is sold on the street.

(a)The random variable X is Normally distributed with mean, μ = 0.10 and standard deviation, σ = 0.02.

Therefore, X ≈ N (0.10 , 0.02²)

(b) The value of P (X > 0.11) as follows:

P (X > o.11_ = P(X -μ/a > [tex]\frac{0.11-0.10}{0.02} \\[/tex])

= P(Z > 0.50)

= 1 -P (Z <0.50)

= 1- 0.69146

= 0.30854 ≈ 0.31

Hence,

the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 11% is 31%.

(c)Let x represent the 60th percentile value.

Then, P (X < x) = 0.60.

⇒ P (Z < z) = 0.60

The value of z is,

z = 0.26.

Now put the value of x as follows:

z = x - μσ

0.26 = x - 0.100.02

x = 0.10+ ( 0.26 x 0.02)

x = 0.1052

x ≈ 0.11

Therefore,

The 60th percentile is 11%

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There is a 75% chance that it will rain here or on Mars is false because there is a 25% chance that it will rain here and not on Mars.  

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We have:

There is a 50% chance of rain here and a 25% chance of rain on Mars. Therefore, there is a 75% chance that it will rain here or on Mars.

The probability that it will rain here:

P(rain here) = 50%

P(rain on mars) 50%

P(not rain here) = 100 - 50 = 50%

P(not rain on mars) = 100 - 50 = 50%

P(rain here and not on mars) = 0.5×0.5 = 0.25 or 25%

Thus, there is a 75% chance that it will rain here or on Mars is false because there is a 25% chance that it will rain here and not on Mars.  

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Answer:

3.5 km

Step-by-step explanation:

Answer:

it is 2 spaces away. a positive number from zero would be +2 and a negative number would be -2

Step-by-step explanation:

Answer:

X = 14

Let the unknown no. be X

mean= sum of all no. / no. of terms

17 = 15 + 17 + 20 + 22 + X+ X / 6

17 * 6 = 74 + 2X

102 - 74 = 2X

28 = 2X

28/2 = X

14= X

Answer:

(-5, -6)

Step-by-step explanation:

The smaller integer is x.

The larger integer is x + 1.

x + 1 = 7 + 2x

-x = 6

x = -6

x + 1 = -6 + 1 = -5

Answer: (-5, -6)

The quotient [tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex] is [tex]x^3 + 2x - 3[/tex]

The quotient can be represented as:

[tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex]

Start by expanding the dividend

[tex]x^5 + 2x^3 - 5x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex]

Rewrite as:

[tex]x^5 + 2x^3 - 3x^2 - 5x^3 - 10x + 15 \div x^2 - 5[/tex]

Factorize the dividend

[tex]x^2(x^3 + 2x - 3) - 5(x^3 + 2x - 3) \div x^2 - 5[/tex]

Factor out x^3 + 2x - 3

[tex](x^2- 5)(x^3 + 2x - 3) \div x^2 - 5[/tex]

Cancel out the common factor

[tex]x^3 + 2x - 3[/tex]

Hence, the quotient [tex]x^5 - 3x^3 - 3x^2 - 10x + 15 \div x^2 - 5[/tex] is [tex]x^3 + 2x - 3[/tex]

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Answer: x3 + 2x – 3

Step-by-step explanation:

The solution will be x= -10

Simplifying the given expression

[tex]1.8(1.1x - 1.3) - 1.88 = - 24.02[/tex]

Step1: Convert decimal to fraction

[tex]1.8( \frac{11x}{10} - 1.3) - 1.88 = - 24.02[/tex]

[tex]1.8( \frac{11x}{10} - \frac{13}{10} ) - 1.88 = - 24.02[/tex]

[tex]\frac{18}{10} ( \frac{11x}{10} - \frac{13}{10} ) - 1.88 = - 24.02[/tex]

Step2: Make denominator common

[tex]\frac{18}{10} ( \frac{11x - 13}{10}) - 1.88 = - 24.02[/tex]

Step3: Simplifying the fraction

[tex]\frac{9}{5} ( \frac{11x - 13}{10}) - 1.88 = - 24.02[/tex]

Step4: Make denominator common

[tex] \frac{9(11x - 13)}{5 \times 10} - \frac{1.88 \times 50}{50} = - 24.02[/tex]

[tex] \frac{9(11x - 13)}{50} - \frac{94}{50} = - 24.02[/tex]

[tex] \frac{9(11x - 13 - 94)}{50} = - 24.02[/tex]

[tex] \frac{99x - 117 - 94}{50} = - 24.02[/tex]

Step5: Simplifying

[tex] \frac{99x - 211}{50} = - 24.02[/tex]

[tex] 99x - 211 = - 24.02 \times 50[/tex]

[tex] 99x - 211 = - 1201[/tex]

[tex] 99x = - 1201 + 211[/tex]

[tex] 99x = - 990[/tex]

[tex] x = \frac{ - 990}{99} [/tex]

[tex]x = - 10[/tex]

Hence, the solution x=-10

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The answer to the question on Parallelograms being rectangles is that; No; the diagonals may not be congruent

1) We cannot conclude that the parallelogram is a rectangle but we can say that all rectangles are parallelograms.

2) The explanation for number 1 above is that the parallelogram's diagonals may not be equal or congruent but in rectangles diagonals are always equal and bisect each other.

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The amount in the new checking account is 600 dollars

The operation (5 α 3) + (7 α 5) is 46.

She had 1000 dollars in her checking account. she had a loan of 800 dollars to pay.

After paying her loan form her checking account the balance of the loan reduce to half.

Therefore, she paid 800 / 2 = 400 dollars for her loan

Hence,

Her new checking account = 1000 - 400 = 600 dollars

a α b = ab - a + b

Therefore,

(5 α 3) + (7 α 5)

(5 α 3) = 5(3) - 5 + 3 = 13

(7 α 5) = 7(5) - 7 + 5 = 33

Therefore,

(5 α 3) + (7 α 5) = 13 + 33 = 46

Note: I can't use the at symbol because it is a swear word.

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Answer:

55

Step-by-step explanation:

1+1 = 2

1+2 = 3

2+3 = 5

3+5 = 8

5+8 = 13

8+13 = 21

13+21 = 34

21 +34 = 55

PLEASE GIVE BRAINLIEST

Answer:

105.6397

ROUNDED ANSWER:

105

The quadratic equation in standard form is:

[tex]y = 2x^2 - 8x + 6[/tex]

Here we have the quadratic equation:

[tex]y = 2*(x - 2)^2 - 2[/tex]

Here we need to expand the right side, remember:

[tex](a + b)^2 = a^2 + 2ab + b^2[/tex]

Using that, we get:

[tex]y = 2*(x - 2)^2 - 2 = 2*(x^2 - 4x + 4) - 2\\\\y = 2x^2 - 8x + 8 - 2\\\\y = 2x^2 - 8x + 6[/tex]

This is the quadratic equation in standard form.

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Let x be multiple-choice questions
Let y be short-answer questions

x + y = 28

3x + 5y = 100

The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

Parameters

[tex]$x^{2}=4 p y$[/tex]

[tex]$y=h$[/tex]

[tex]\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\[/tex]

Generally, the equation for the Area is mathematically given as

[tex]& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\[/tex]

[tex]&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

In conclusion,  the equation for the Area is

[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

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Answer:

y = (3/2)x - (1/2)

Step-by-step explanation:

The general structure of a line in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept. You have been given the value of "m" (3/2). To find the value of "b", you should plug "m" into the equation in addition to the "x" and "y" values from the given point (1,1)

(1,1) ----> x = 1, y = 1

m = 3/2

y = mx + b                                <----- Slope-intercept form

y = (3/2)x + b                            <----- Plug (3/2) into "m"

1 = (3/2)(1) + b                           <----- Plug values into "x" and "y" from point

1 = (3/2) + b                              <----- Multiply (3/2) and 1

(2/2) = (3/2) + b                        <----- Change 1 into common denominator

(-1/2) = b                                  <----- Subtract (3/2) from both sides

Because you now have values for both variables, you can construct your final equation.

y = (3/2)x - (1/2)

The result after rationalizing is [tex]\frac{9\sqrt{x+3} }{x+3}[/tex].

Rationalization can be considered as the process used to eliminate a radical or an imaginary number from the denominator of an algebraic fraction.

Here, given fraction

 [tex]\frac{9}{\sqrt{x+3} }[/tex]

Multiply and divide by [tex]\sqrt{x+3}[/tex], we get

[tex]\frac{9}{\sqrt{x+3} } \frac{\sqrt{x+3} }{\sqrt{x+3} }[/tex]  =  [tex]\frac{9\sqrt{x+3} }{x+3}[/tex]

Thus, the result after rationalizing is [tex]\frac{9\sqrt{x+3} }{x+3}[/tex].

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Answer:

The very last one is a function

Step-by-step explanation:

The last one is a function because there are no y values that repeat. For example, If the points on one graph are like this; (1, 3) (2, 3); then it cannot be a function, the y values cannot repeat if it is a function.

To make things easier, just try to imagine vertical drawing lines through each point in every graph, if this imaginary vertical line passes more than one point in any graph, then that graph is not a function.

I hope this helps!! :D

Answer:

The last graph represents a function.

Explanation:

A function cannot be one-to-many, i.e., one value of x cannot produce multiple values of y.

In the first graph, when x = 1, y = 3 and y= -2, so it is not a function.

In the second graph, when x = 2, y = 2 and y = -2, so it's not a function.

In the third graph, when x = -3, y = 2 and y = -2, so it's not a function.

∴ In all the graphs except the last, single values of x give multiple values of y on the graph, so they are not functions.

Answer:

4 inches

Step-by-step explanation:

In a regular pentagon, all sides are equal in length

A cylinder is a three-dimensional structure formed by two parallel circular bases connected by a curving surface. The volume of the cylinder is 1330.4644 cm³.

A cylinder is a three-dimensional structure formed by two parallel circular bases connected by a curving surface. The circular bases' centers overlap each other to form a right cylinder.

Given the height of the cylinder is 14 cm, while the diameter of the cylinder is 11 cm. Therefore, the volume of the cylinder can be written as,

The volume of the cylinder = (π/4)×(D²) × H

                                               = (π/4)×(11)² × 14

                                               = 1330.5 cm³

Hence, the volume of the cylinder is 1330.5cm³.

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Answer: f(-3)=g(-3)

Step-by-step explanation:

The graphs intersect at x = -3.

The correct option is f(-3) = g(-3).

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Given that two lines are intersecting at point (-3, -4)

Therefore the system of equations of these two have a solution at (-3, -4)

So, if taking the lines as function,

We have f(x) and g(x),

so both of them are intersecting at (-3, -4) so the range when the domain is -3 will be equal.

Hence the correct option is f(-3) = g(-3).

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Answer:

740

Step-by-step explanation:

$415-$230=$185

$185×0.25=740 max miles

The solution for the first inequality is a ≥ 2 or a ∈ [2, ∞), and for the second inequality the solutions are b < -5 or b ∈ (-∞, -5)

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have two inequalities:

a.) -12a +7 ≤31

b.) -9 > 3b +6

a)  -12a +7 ≤ 31

-12a ≤ 31 - 7

-12a ≤ 24

-a ≤ 2

a ≥ 2  (sign changed because multiplied by a negative number)

a ∈ [2, ∞)

b.) -9 > 3b +6

-15 > 3b

-5 > b

or

b < -5

b ∈ (-∞, -5)

Thus, the solution for the first inequality is a ≥ 2 or a ∈ [2, ∞), and for the second inequality the solutions are b < -5 or b ∈ (-∞, -5)

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The x intercept of the linear equation is -4 and y intercept is 8.

The intercept of the linear equation is calculated as follows;

x - y/2 = -4

make y the subject of the formula;

y/2 = x + 4

y = 2x + 8

y = 0 + 8

y = 8

0 = 2x + 8

2x = -8

x = -4

Thus, the x intercept of the linear equation is -4 and y intercept is 8.

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Answer:

The x intercept of the linear equation is -4 and y intercept is 8

Step-by-step explanation:

The difference in the given functions is 2x^3 + 6x^2 -8x + 1

Given the following function a shown

f(x)= 2x^3 + 6x^2 -5x - 3

g(x)= 3x-4

Take the difference

(f-g)(x) = f(x) - g(x)

Substitute

(f-g)(x)  = 2x^3 + 6x^2 -5x - 3 - (3x - 4)

Expand

(f-g)(x)  = 2x^3 + 6x^2 -5x - 3 - 3x + 4

(f-g)(x) = 2x^3 + 6x^2 -8x + 1

Hence the difference in the given functions is 2x^3 + 6x^2 -8x + 1

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Answer:

y = -5

Step-by-step explanation:

Isolate y:

-3x + 9y = -57

9y = -57 + 3x

y = (-57/9) + (3/9)x

Substitute for x:

y = (-57/9) + (3/9)(4)

y = (-57/9) + (12/9)

y = (-45/9)

y = -5

Answer:

[tex]\mathsf {y = -5}[/tex]

Step-by-step explanation:

[tex]\textsf {Given :}\\\textsf {-3x + 9y = -57}[/tex]

[tex]\textsf {Divide throughout by 3 :}[/tex]

[tex]\mathsf {\frac{1}{3} \times (-3x + 9y) = \frac{1}{3} \times -57}[/tex]

[tex]\mathsf {-x + 3y = -19}[/tex]

[tex]\textsf {Substitute x = 4 :}[/tex]

[tex]\mathsf {-(4) + 3y = -19}[/tex]

[tex]\mathsf {3y = -15}[/tex]

[tex]\textsf {Divide by 3 on both sides :}[/tex]

[tex]\mathsf {\frac{3y}{3} = \frac{-15}{3} }[/tex]

[tex]\mathsf {y = -5}[/tex]

The y-coordinate of the other endpoint is 10 units.

The given coordinates are H (-5, 2) and G (–9, –6).

We need to find the y-coordinate of the other endpoint.

The mid-point formula is  [tex](x, y)=(\frac{x_{1}+x_{2} }{2} , \frac{y_{1}+y_{2} }{2})[/tex]

Now, [tex](-5, 2)=(\frac{x_{1} +(-9)}{2} , \frac{y_{1} +(-6)}{2})[/tex]

⇒[tex]2=\frac{y_{1}-6 }{2}[/tex]

⇒[tex]4=y_{1}-6[/tex]

⇒[tex]y_{1}=10[/tex]

Therefore, the y-coordinate of the other endpoint is 10 units.

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The answer to this question is (A) left.