Answer:
d
Explanation:
a mutation is the variation of a norm, a mutation can alter any organism in any way
Question 13
A hot air balloon has a pressure of 0.715 atm while the temperature outside is 30
degreeſ C. What will the pressure be if the temperature drops to 10 degrees C while
volume remains constant? Do not write units in the answer. Make sure to convert
temperature values to Kelvin.
Answer:
0.668 atm
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 0.715 atm
Initial temperature (T₁) = 30 °C
Final temperature (T₂) = 10 °C
Volume = constant
Final pressure (P₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 30 °C
Initial temperature (T₁) = 30 °C + 273
Initial temperature (T₁) = 303 K
Final temperature (T₂) = 10 °C
Final temperature (T₂) = 10 °C + 273
Final temperature (T₂) = 283 K
Finally, we shall determine the final. This can be obtained as follow:
Initial pressure (P₁) = 0.715 atm
Initial temperature (T₁) = 303 K
Final temperature (T₂) = 283 K
Final pressure (P₂) =?
P₁ / T₁ = P₂ / T₂
0.715 / 303 = P₂ / 283
Cross multiply
303 × P₂ = 0.715 × 283
303 × P₂ = 202.345
Divide both side by 303
P₂ = 202.345 / 303
P₂ = 0.668 atm
Thus, the final pressure of the hot air balloon is 0.668 atm
By which method the following mixture can be separated?(i)mixture of colours (ii) Minerals oil.
the answer ie the second option
Minerals oil
How is motion involved in your lives?
Answer:
By walking and stuff, duh.
Explanation:
We walk, motion.
We drive, motion.
We eat, motion.
We talk, motion.
What is the mass of 2.90 ×1022 formula units of NaOH (Molar mass = 40.0 g/mol)?
[tex]\text{mass of NaOH = 2.90 × 10²² NaOH formula units} × \frac{\text{1 mol NaOH}}{\text{6.022 × 10²³ NaOH formula units}} × \frac{\text{40.0 g NaOH}}{\text{1 mol NaOH}}[/tex]
[tex]\boxed{\text{mass of NaOH = 1.926 g}}[/tex]
Answer:
[tex]\boxed {\boxed {\sf 1.93 \ g \ NaOH}}[/tex]
Explanation:
1. Convert Formula Units to Moles
To do this, we use Avogadro's Number: 6.02*10²³. It is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, it is formula units of sodium hydroxide.
[tex]\frac {6.02*10^{23} \ formula \ units \ NaOH}{1 \ mol \ NaOH}[/tex]
Multiply by the given number of formula units.
[tex]2.90*10^{22} \ formula \ units \ NaOH*\frac {6.02*10^{23} \ formula \ units \ NaOH}{1 \ mol \ NaOH}[/tex]
Flip the ratio so the formula units will cancel.
[tex]2.90*10^{22} \ formula \ units \ NaOH*\frac {1 \ mol \ NaOH}{6.02*10^{23} \ formula \ units \ NaOH}[/tex]
[tex]2.90*10^{22}*\frac {1 \ mol \ NaOH}{6.02*10^{23}}[/tex]
[tex]\frac {2.90*10^{22} \ mol \ NaOH}{6.02*10^{23}}=0.04817275748 \ mol \ NaOH[/tex]
2. Convert Moles to Grams
For this, we use the molar mass. It is the grams per mole of a substance. We are given this value for sodium hydroxide: 40.0 g/mol
[tex]\frac {40.0 \ g\ NaOH}{1 \ mol \ NaOH}[/tex]
Multiply by the moles we calculated.
[tex]0.04817275748 \ mol \ NaOH*\frac {40.0 \ g\ NaOH}{1 \ mol \ NaOH}[/tex]
The moles cancel.
[tex]0.04817275748 *\frac {40.0 \ g\ NaOH}{1 }[/tex]
[tex]0.04817275748 *{40.0 \ g\ NaOH=1.926910299 \ g\ NaOH[/tex]
3. Round
The original measurement of formula units has 3 significant figures, so our answer must have the same. For the number we calculated that is the hundredth place.
[tex]1.92\underline6 910299 \ g \ NaOH[/tex]
The 6 in the thousandth place tells us to round the 2 to a 3.
[tex]1.93 \ g \ NaOH[/tex]
There are approximately 1.93 grams of sodium hydroxide.
PLEASEEEE HELLPPP I CANT FAILL PLSS
what kinda of water movement helps the fishing industry
Answer:
Upwelling is the natural process which brings cold, nutrient-rich water to the surface. A huge upwelling regularly occurs off the coast of Peru, which enjoys a large fishing industry as a result. Upwelling is a process in which currents bring deep, cold water to the surface of the ocean.
Explanation:
good luck
How do you know a chemical reaction has occurred?
Answer:
To tell if a chemical reaction has occurred look at its color change, temperature change, Precipitate formation, gas production, and light emission.
PLZZZ HELP CHEMISTRY QUESTION DOWN BELOW IMAGE SHOWWN BELOW
If a drum skin vibrates with a frequency of 100 Hz, how many times does it move up and down each second?
( Chemistry )
How many grams are in 32.2 L of CO2?
Answer:
63.25 grams of CO₂
Explanation:
To convert from liters to grams, we first need to convert from liters to moles. To do this, we divide the liters by 22.4, the amount of liters of a gas per mole.
32.2 / 22.4
= 1.4375 moles of CO₂
Now we want to convert from moles to grams. To do this, we multiply the moles by the molar mass of CO₂. The total molar mass can be found on the periodic table by adding up the molar mass of carbon (12) and two oxygen (32).
12 + 32 = 44
Now we want to multiply the moles by the molar mass.
1.4375 • 44
= 63.25 grams of CO₂
This is your answer.
Hope this helps!
An unknown solid is entirely soluble in water. On addition of dilute HCl, a precipitate forms. After the precipitate is filtered off, the pH is adjusted to about 1 and H2S is bubbled in; a precipitate again forms. After filtering off this precipitate, the pH is adjusted to 8 and H2S is again added; no precipitate forms. No precipitate forms upon addition of (NH4)2HPO4. The remaining solution shows a yellow color in a flame test.
Based on these observations, which of the following compounds might be present, which are definitely present, and which are definitely absent.
CdS, Pb(NO3)2, HgO, ZnSO4, Cd(NO3)2, and Na2SO4
Answer:
Pb(NO3)2
Cd(NO3)2
Na2SO4
Explanation:
In the first part, addition of HCl leads to the formation of PbCl2 which is poorly soluble in water. This is the first precipitate that is filtered off.
When the pH is adjusted to 1 and H2S is bubbled in, CdS is formed. This is the second precipitate that is filtered off.
After this precipitate has been filtered off and the pH is adjusted to 8, addition of H2S and (NH4)2HPO4 does not lead to the formation of any other precipitate.
The yellow flame colour indicates the presence of Na^+ which must come from the presence of Na2SO4.
Write the IUPAC names of the given carboxylic acids. A molecule has the condensed formula C H 3 C H 2 C H (O C H 3) C H 2 C O O H. IUPAC name: A six membered hydrocarbon ring with three double bonds. The group C O O H is attached to ring carbon one, and a chlorine atom is attached to ring carbon four. IUPAC name:
Answer:
The correct answer is -
3-methoxypentanoic acid, and
4-chlorobenzoic acid
Explanation:
1. condensed formula of the molecule is -
CH3CH2CH(OCH3)CH2COOH and the number of the carbons would be count from the end of carboxylic acid. So, the counting as given in the image, it shows there are 5 carbon so it is Penta and has methyl group on fourth carbon so 4-methyl, therefore, its IUPAC name will be - 4-methyl pentanoic acid
2. similarly for the molecule with COOH group attached with ring carbon and chlorine is represented as in the image and it shows a benzene ring and COOH group is present at C1 and chlorine is in C4 so the name would be 4-chlorobenzoic acid.
The International Union of Pure and Applied Chemistry (commonly abbreviated to IUPAC) recommends a systematic approach for the nomenclature of organic compounds, which is referred to as the IUPAC nomenclature of organic compounds. Here the IUPAC names are 4-methyl pentanoic acid and 4-chlorobenzoic acid.
In essence, the condensed structural formula is a system for writing organic compounds in a single line of text.
1. CH₃CH₂CH(OCH₃)CH₂COOH and the number of the carbons would be counted from the end of carboxylic acid. So, the counting as given in the image shows there are 5 carbon so it is Penta and has methyl group on the fourth carbon so 4-methyl, therefore, its IUPAC name will be - 4-methyl pentanoic acid
2. Similarly the molecule with COOH group attached with ring carbon and chlorine is represented as in the image and it shows a benzene ring and COOH group is present at C-1 and chlorine is in C-4 so the name would be 4-chlorobenzoic acid.
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For each of the following precipitation reactions, complete and balance the equation, indicating clearly which product is the precipitate.
a) Ba(NO3)2(aq) + (NH4)2SO4(aq) ->
b)CoCl3(aq) + NaOH(aq) ->
c)FeCl3(aq) + (NH4)2SS(aq) ->
Answer: a) [tex]Ba(NO_3)_2(aq)+(NH_4)_2SO_4(aq)\rightarrow BaSO_4(s)+2NH_4NO_3(aq)[/tex]
b) [tex]CoCl_3(aq)+3NaOH(aq)\rightarrow Co(OH)_3(s)+3NaCl(aq)[/tex]
c) [tex]2FeCl_3(aq)+3(NH_4)_2S(aq)\rightarrow Fe_2S_3(s)+6NH_4Cl(aq)[/tex]
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
A double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.
The balanced chemical equations are:
a) [tex]Ba(NO_3)_2(aq)+(NH_4)_2SO_4(aq)\rightarrow BaSO_4(s)+2NH_4NO_3(aq)[/tex]
b) [tex]CoCl_3(aq)+3NaOH(aq)\rightarrow Co(OH)_3(s)+3NaCl(aq)[/tex]
c) [tex]2FeCl_3(aq)+3(NH_4)_2S(aq)\rightarrow Fe_2S_3(s)+6NH_4Cl(aq)[/tex]
HELPPPPP ASAP PLEASEEE
Answer:
c
Explanation:
Involuntary muscles, like skeletal muscles, help move the bones
Answer:
the second and last one is correct
since bones protect our internal organs like heart, pancreas,etc and give the body its shape
Explanation:
second point it is true that in our body there are more than 600 muscles and the bones are about 206 I think
Write the Ground state electron configuration of Ca using the noble-gas shorthand notation
Answer:
[Ar] 4s2
Explanation:
The noble gas that comes before Ca is Ar, so that's what you'll use for the noble-gas shorthand part of it. Ca has two additional electrons in the 4s orbital, hence the 4s2.
The ground state electronic configuration of calcium using noble gas short hand notation is [Ar]4s².
What is noble gas short hand notation ?Noble gas short hand notation comprises of the symbol of the last noble gas which is prior to the concerned atom which is followed by the configuration of the electrons which remains.
This notation helps in shortening of electronic configuration which is otherwise huge for elements with high atomic numbers.This is possible cause it uses the preceding noble gas configuration which accounts for that many electrons and the remaining electrons are filled in the next higher sub shell.
For calcium, preceding noble gas is argon which accounts for 18 electrons and for remaining two electrons they are placed in 4s sub shell thus making the total count of electrons to 20.
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A bolt of lightning is an example of static discharge.
TRUE
FALSE
Answer:
True
Explanation:
3,01 x 10^23molecules H.O
Answer:
Therefore Mass of 6.022 x10^23 molecules= 32 g.
Explanation:
how many grams are in8.2'10^22 molecules of N2i6
Explanation:
Hope the picture with the working out helps :)
For the following equilibrium reaction, what will happen if heat is removed (the temperature goes down)?
CO(g) + 2H2(g) ⇌ CH3OH(g) + heat
Answer:
The reaction will proceed to the right and produce more products.
Explanation:
The reaction produces heat, so it is exothermic. If you remove heat, the reaction counters that by producing more products and replacing the heat that was lost.
Is liquid ammonia a household acid?
Yes it is an cleaning product
Answer:
yes
Explanation:
it cleans in the house
when the energy is released what happens to the energy of the system
Answer:
Whether a chemical reaction absorbs or releases energy, there is no overall change in the amount of energy during the reaction. That's because energy cannot be created or destroyed. This is the law of conservation of energy.
What are the organisms that swim in the upper region of the open ocean?
Answer:
Epipelagic (sunlight)
Explanation:
Examples of organisms living in this zone are plankton, floating seaweed, jellyfish, tuna, many sharks, and dolphins.
A sample of N 2 gas has a volume of 30.0 ml at 25 degrees * C and 730 mmHg. What would be the volume of the gas at 50 ^ 0 * C and 1 atm pressure? a. 31.2 ml b. 26.6 mL c. 33.9 ml d. 57.6 ml
Answer:
your answer is D. 57.6
Explanation:
730+30.0+25+2=
A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:
Fe2O3(s) + 3 H2(g) →2Fe(s) + 3 H2O(9)
Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation
of H2O(g) is kJ/mol.
Answer:
-252.5 kJ/mol = ΔH H2O(g)
Explanation:
ΔH Fe2O3 = -825.5kJ/mol
ΔH H2 = 0kJ/mol
ΔH Fe = 0kJ/mol
Based on Hess's law, ΔH of a reaction is the sum of ΔH of products - ΔH of reactants. For the reaction:
Fe2O3(s) + 3 H2(g) →2Fe(s) + 3 H2O(g)
ΔHr = 67.9kJ/mol = 3*ΔH H2O + 2*ΔHFe - (ΔH Fe2O3 + 3*Δ H2)
67.9kJ/mol = 3*ΔH H2O + 2*0kJ/mol - (ΔH -825.5kJ/mol + 3*Δ H2)
67.9 = 3*ΔH H2O(g) + 825.5kJ/mol
-757.6kJ/mol = 3*ΔH H2O(g)
-252.5 kJ/mol = ΔH H2O(g)Can somebody please help me!!!!
Answer:
Friston to energy
Explanation:
Friction to Energy as its a energy stooping the object form moving
Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
4HCl(g) + O2(g)—>2H2O(g) + 2Cl2(g)
Answer:
ΔH°r = -114.40 kJ
Explanation:
Let's consider the following balanced equation.
4 HCl(g) + O₂(g) ⇒ 2 H₂O(g) + 2 Cl₂(g)
We can calculate the standard enthalpy change of the reaction (ΔH°r) using the following expression.
ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)
where
ΔH°f: standard heat of formation n: moles p: products r: reactantsΔH°r = 2 mol × ΔH°f(H₂O(g)) + 2 mol × ΔH°f(Cl₂(g)) - 4 mol × ΔH°f(HCl(g)) - 1 mol × ΔH°f(O₂(g))
ΔH°r = 2 mol × (-241.82 kJ/mol) + 2 mol × 0 kJ/mol - 4 mol × (-92.31 kJ/mol) - 1 mol × 0 kJ/mol
ΔH°r = -114.40 kJ
state the conditions under which copper reacts with sulphuric (vi) acid and give an equation for the reaction
Answer:
When the metal reacts with hot, concentrated sulphuric acid, the products of the reaction are copper (II) sulphate, sulphur dioxide and water. Cu + 2H2SO4 = CuSO4 + SO2 + 2H2O. This is a typical redox reaction in which the acid is reduced to SO2, but no hydrogen is produced here
Add an oxide ion to Fe2O3
Answer:
Iron Oxide (Fe2O3) also known as rust is also an ionic bond, it has metallic compound Iron (Fe) which contains positively charged cations and it has nonmetallic compound Oxygen (O) which contains negatively charged anions.
Explanation:
i hope it help
A 10.0-mL sample of sulfuric acid, H2SO4, from a battery of an old car is diluted to 100.0 mL, and a 10.00-mL aliquot (portion) of the diluted acid is then titrated with 0.2500 M NaOH solution. If the concentration of H2SO4 in the original battery was 3.25 M, how many milliliters (mL) of the NaOH solution is required to titrate the sulfuric acid present in the 10.0-mL portion of dilute acid solution
Answer:
26.0 mL
Explanation:
The reaction that takes place is:
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂OFirst we calculate the molar concentration of the diluted sulfuric acid solution, using the C₁V₁=C₂V₂ formula:
3.25 M * 10.0 mL = C₂ * 100 mLC₂ = 0.325 MNow we calculate how many H₂SO₄ moles would there be in 10.00 mL of this diluted solution, using the definition of molarity:
0.325 M * 10.00 mL = 3.25 mmol H₂SO₄Then we convert 3.25 mmoles of H₂SO₄ into mmoles of NaOH, using the stoichiometric coefficients of the balanced reaction:
3.25 mmol H₂SO₄ * [tex]\frac{2mmolNaOH}{1mmolH_2SO_4}[/tex] = 6.5 mmol NaOHFinally we calculate the required volume of the NaOH solution, using the definition of molarity:
6.5 mmol NaOH / 0.2500 M = 26.0 mLA 15.0 mL solution of Sr(OH)2 is neutralized with 29.8 mL of 0.350 M
HCI. What is the concentration of the original Sr(OH)2 solution?
Answer:
[Sr(OH)₂] = 0.699 M in Sr(OH)₂ sol'n (1 sig. fig)
Explanation:
Concentrated-1 Sr(OH)₂ = M₁ = unknown Concentration-2 HCl = M₂ = 0.350M
Volume of Concentrate = V₁ = 15ml Volume of Diluted = V₂ = 29.8ml
Using the Dilution Equation
Molarity x Volume of Concnt'd Soln = Molarity x Volume of Diluted Soln
From definition of molarity (M) = moles solute / volume of solution in Liters
=> moles solute = Molarity x Volume in liters*
*Note: if volume units are the same on both sides of the dilution equation then one may retain the volume in ml.
M₁ x V₁ = M₂ x V₂
=> 15ml · [Sr(OH)₂] = 30ml X 0.350M HCl soln
=> [Sr(OH)₂] = 29.8ml X 0.350M / 15ml = 0.695333... (calculator answer)
=> [Sr(OH)₂] = 0.7 M in Sr(OH)₂ sol'n (1 sig. fig)
__________________________________
work check:
M₁ x V₁ = M₂ x V₂
0.6953M x 15ml = 0.35M x 29.8ml
10.43 moles = 10.43 moles QED