Q. Three horses A, B, and C are in a race, A is twice as likely to win
as B and B is twice as likely to win as C. What are their
respective probabilities of winning?

Answers

Answer 1
the probability of horse C winning = x
the probability of horse B winning = 2x
the probability of horse A winning = 4x
Total probability of winning is 1
So P(A) + P(B) + P(C) = 1
—> x + 2x + 4x = 1 —> x = 1/7

The probability of winning of horses A, B, and C are 4/7, 2/7, and 1/7

Related Questions

An engineer wants to obtain a random sample of the output from a process manufacturing digital cameras. The process operates 16 hours per day, five days per week. She selects five cameras on Monday, Tuesday and Wednesday at random between 3pm and 4pm each day. This is an example of

Answers

Answer:

Non-Random Sample

Step-by-step explanation:

A sample in which each element has an equal chance of being selected is known as a random sample. Otherwise, a sample is said to be a non - random sample.

An engineer selects five cameras on Monday, Tuesday, and Wednesday at random between 3 pm and 4 pm each day. So, the cameras that are not in the process of production between 3 pm and 4 pm have no chances of being selected.

So, each camera does not have an equal chance of being selected.

This is an example of a non - random sample.

A bag has 8 red tiles and 2 green tiles. In a charity carnival game, you pay $5 to randomly pull a tile from the bag. The payout for pulling a red tile is $1 and the payout for pulling a green tile is $10. Which of the followig are true or false.

a. The expected payoff per game for the charity is $2.20.
b. In 20 games, the charity can expect to make $44.
c. In 30 games, the charity can expect to make $120.
d. In 5 games, the player can expect to lose $11.

Answers

Answer:

B:True

Step-by-step explanation:

B is true as a bag of 8 red tiles and 2 green tiles you pay 5 per tile meaning in twenty games you pay $100(50 per bag) and the total amount you win back is $56(28 per bag) so the equation would be $100 - $56= $44 profit to the charity

Hence only statement 1 is correct,∴The expected payoff per game for the charity is $2.20.

What is payoff?

Money provided to someone as a bribe, reward, or when they leave a position. As a result, a mathematical function representing the award awarded to a single player at the game's conclusion has been developed.

How to Solve?

Given a bag of tiles containing 8 red tiles, 2 green tiles.

Probability of drawing a red tile =1/8

Probability of drawing a green tile =1/2

If red tile is pulled payout is $1 else $10

Payout=

payout for 1 game= $1*8/10+$10*2/10-$5=2.20

payout in 20 games =$1*10*8/10+$10*10*2/10-$5*20=-72

payout for 30 games=$1*15*8/10+$10*15*2/10-$5*30=0

payout in 5 games=$1*5*8/10+10*5*2/10-$5*5=$25

Hence only statement 1 is correct, ∴The expected payoff per game for the charity is $2.20.

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Please answer this correctly

Answers

Answer:

V =113.04 cm^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

V = 3.14 (3)^2 4

V = 3.14 *9*4

V =113.04 cm^3

Answer:

Step-by-step explanation:

3*3.14

9.42*9.42

88.7364*4

354.9456 rounded to

355

If the p-value for a hypothesis test is 0.027 and the chosen level of significance is a=0.05, then the correct conclusion is to

Answers

Answer:

[tex] p_v = 0.027[/tex]

And for this case we have a significance level [tex] \alpha=0.05[/tex] and then:

[tex] p_v <\alpha[/tex]

So then we have enough evidence to reject the null hypothesis. And we can conclude in favor the alternative hypothesis.

Step-by-step explanation:

For this case we have the following hypothesis:

[tex]Null hypothesis: p =p_o[/tex]

[tex]Alternative hypothesis: p \neq p_o[/tex]

And for this case we got the following hypothesis:

[tex] p_v = 0.027[/tex]

And for this case we have a significance level [tex] \alpha=0.05[/tex] and then:

[tex] p_v <\alpha[/tex]

So then we have enough evidence to reject the null hypothesis. And we can conclude in favor the alternative hypothesis.

Fill in missing information to make the equality true:
(... +2a)2 = … +12ab2+4a2.

Answers

Answer:

I suppose it should be

6b² and (6b²)²

or

6b² and 36[tex]b^{4}[/tex]

Step-by-step explanation:

(a+b)² = a² + 2ab + b²

therefore

(6b²+2a)² = (6b²)² + 12ab² + 4a²

The missing information to make the equality true are 3b² and (3b²)². This can be obtained by using the algebraic identity (x+y)² =x² + 2xy + y².

Find the missing information:

Let the missing information be p and

Then the given equation will be: (p+2a)² =p² + 12ab² + 4a²

The algebraic identities is (x+y)² =x² +2xy+y²

Comparing the given equation with the algebra formula we get

y=2a

2xy =12ab² ⇒2x(2a) = 12 ab² ⇒ x = 3b²

Therefore the given equation will be

(3b²+2a)² = (3b²)²+12ab²+4a²

Hence the missing information to make the equality true are 3b² and (3b²)².

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Solve for x.
x + 3 = Sqrt 4x+17

Answers

Answer:

Step-by-step explanation

How many fluid ounces are there in 3 pints and 4 fluid ounces?

Answers

Answer:

52 US fluid ounces

Step-by-step explanation:

6 fluid ounces

How many fluid ounces in a pint? There are 16 fluid ounces in a pint.

Answer: 52 fluid ounces

A hose can fill a swimming pool in 12 hours. Another hose needs 6 more hours to fill the pool than the two hoses combined. How long would it take the second hose to fill the pool?

Answers

Answer:

I believe it is 12, but I'm not sure.

Step-by-step explanation:

If there is 2 of the first hose, then it can fill the pool twice as fast, so thats 6 hours. (12 divided by 2 = 6).

If the second hose takes 6 hours more than that, then that would be 12 hours.(6+6=12)

In the chi-square test of association, as the difference between the observed and expected proportions increases... a. the chi-square test statistic increases b. the chi-square critical value increases c. the likelihood of rejecting the null hypothesis increases d. the likelihood of rejecting the null hypothesis decreases e. the chi-square critical value decreases f. the chi-square test statistic decreases

Answers

Answer:

Opton A

Step-by-step explanation:

In the chi-square test of association, as the difference between the observed and expected proportions increases, the chi-square test statistic also increases. This is because if the claim made in the null hypothesis is true: the claim that frequency of the observed is equal to that of the expected (Oi = Ei) then, the observed and the expected values are close to each other and the difference Oi − Ei  is small for each category and the chisquare test statistic is small.

But when the observed data does not fit to what is expected  as of the null hypothesis, the difference between the observed and  expected values, Oi − Ei  is large producing a large chi square statistic.

Which is the vertex of x^2 + 10x = - 17?

Answers

Answer:

(-5, -8)

Step-by-step explanation:

Parabolas always have a lowest point (or a highest point, if the parabola is upside-down). This point, where the parabola changes direction, is called the "vertex". If the quadratic is written in the form y = a(x – h)2 + k, then the vertex is the point (h, k).

x^2 + 10x = - 17

x^2+10x+17=0

x^2+2*5x+25 - 8=0

(x+5)^2-8=0

h=-5, k= -8

vertex is (-5, -8)

The city of Raleigh has 9,200 registered voters. There are two candidates for city council in an upcoming election: Brown and Feliz. The day before the election, a telephone poll of 200 randomly selected registered voters was conducted. 65 said they'd vote for Brown, 121 said they'd vote for Feliz, and 14 were undecided.

A. what is the population of this survey?B. What is the size of populationC. What is the size of the sampleD. Give the sample statistic for the proportion of voters surveyed who said they'd vote for Brown.E. Based on the sample, we might expect how many of th 9500 voters to vote for Brown

Answers

Answer:

A) The population of this survey is the registered voters in the city of Raleigh.

B) 9500

C) 200

D) 0.325

E) 3088

Step-by-step explanation:

A) The population of this survey is the registered voters in the city of Raleigh.

B) Population size can be defined as the total number of individuals in a population. Here the total number of individuals are the registered voters in the city. Therefore the size of the population is 9500.

c) Sample size is defined as the number of individual samples in a statistical test. Here the sample size is the 200 randomly selected registered voters. It is denoted as "n".

d) The sample statistic for the proportion of voters surveyed who said they'd vote for Brown would be:

p' = voters for brown / sample size

[tex] p' = \frac{65}{200} = 0.325 [/tex]

The sample statistic for the proportion of voters surveyed who said they'd vote for Brown is 0.325

E) The expected number of voters for Brown based on the sample:

0.325 * 9500 = 3087.5

Approximately 3088

The expected number of voters for Brown based on the sample might be 3088 voters.

Which of the following is the result of the operation below?

Answers

Answer:

The result of the operation is:

[tex]\left[\begin{array}{ccc|c}1&2&3&6\\0&-1&-2&-8\\0&2&1&5\end{array}\right][/tex]

Step-by-step explanation:

The matrix provided is:

[tex]\left[\begin{array}{ccc|c}1&2&3&6\\1&1&1&-2\\0&2&1&5\end{array}\right][/tex]

The operation to be performed is:

[tex]-R_{1}+R_{2}[/tex] → [tex]R_{2}[/tex]

The operation implies that, we need to replace the values in row 2 by the result of the expression ([tex]-R_{1}+R_{2}[/tex]).

Complete the operation as follows:

[tex]\left[\begin{array}{ccc|c}1&2&3&6\\1&1&1&-2\\0&2&1&5\end{array}\right]\rightarrow \ \left[\begin{array}{ccc|c}1&2&3&6\\(-1+1)&(-2+1)&(-3+1)&(-6-2)\\0&2&1&5\end{array}\right][/tex]

                            [tex]\rightarrow\ \left[\begin{array}{ccc|c}1&2&3&6\\0&-1&-2&-8\\0&2&1&5\end{array}\right][/tex]

Thus, the result of the operation is:

[tex]\left[\begin{array}{ccc|c}1&2&3&6\\0&-1&-2&-8\\0&2&1&5\end{array}\right][/tex]

Answer:

A

Step-by-step explanation:

edge 2021

Find the probability of the indicated event if ​P(E)equals0.25 and ​P(F)equals0.40. Find​ P(E or​ F) if​ P(E and ​F)equals0.05.

Answers

Answer:

[tex] P(E) =0.25, P(F) = 0.40, P(E \cap F) =0.05[/tex]

[tex] P(E \cup F)= P(E) +P(F) -P(E \cap F)[/tex]

And replacing we got:

[tex] P(E \cup F)=0.25 +0.40 -0.05 = 0.6[/tex]

Step-by-step explanation:

For this case we have the following probabilities given:

[tex] P(E) =0.25, P(F) = 0.40, P(E \cap F) =0.05[/tex]

And we want to find this probability:

[tex] P(E \cup F)[/tex]

And we can use the total probability rule given by:

[tex] P(E \cup F)= P(E) +P(F) -P(E \cap F)[/tex]

And replacing we got:

[tex] P(E \cup F)=0.25 +0.40 -0.05 = 0.6[/tex]

A tent is an example of a____a0____a1.

Answers

Answer:

triangular prism

Step-by-step explanation:

A triangular prism has 3 rectangular sides and 2 triangles as the base

The answer is : Triangular, Prism

Have a great day!

God bless you!

Consider the line 9x – 7y=-8.
What is the slope of a line perpendicular to this line?
What is the slope of a line parallel to this line?
Slope of a perpendicular line:
Х
?
Slope of a parallel line:

Answers

Answer:

Step-by-step explanation:

Before you can answer you have to solve the equation for y.

Y = 9/7 x+8/7

Parallel lines have the same slope so would also be 9/7

Perpendicular lines have opposite reciprocal slope so would be -7/9

Answer:

y=-9/7x-8/7

Step-by-step explanation:

9x – 7y=-8

-9x           -9x

-7y=-9x-8

then divide all sides by -7

y=-9/7x-8/7

Jose constructed Triangle DCE, where m∠D = 103° and m∠C = 22°. Remy constructed triangle PQT, where m∠Q = 22°, and m∠T = 55°. Are the two triangles similar to one another? *



Yes, because two pairs of corresponding angles in the triangles are congruent.



No, because none of the corresponding pairs of angles in the triangles are congruent.



No, because 103 + 22 ≠ 22 + 55.



There is not enough information to determine if the two triangles are similar to one another.

Answers

Answer:

The missing angle in Jose's triangle is 180 - 103 - 22 = 55° and since both triangles have two congruent pairs of corresponding angles the answer is yes.

Answer:

Yes

Step-by-step explanation:

They are similar by angle-angle similarly theorem

In two triangles, if two pairs of corresponding angles are congruent, then the triangles are similar . (Note that if two pairs of corresponding angles are congruent, then it can be shown that all three pairs of corresponding angles are congruent, by the Angle Sum Theorem.)

Two cyclists, 55 miles apart, start riding toward each other at the same time. One cycles 5 miles per hour faster than the other, and they meet after 5 hours of riding.

a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r to represent the speed of the slower cyclist.

b. What are the speeds of the two cyclists?

Answers

Answer:

r = 6 mph and f = 11 mph

Step-by-step explanation:

Representations:  

1) speed of faster cyclist:  f = r + 5

2) speed of slower cyclist:  r

Distances covered:

(r + 5)(5 hr) + r(5) = 55 mi (total distance covered)

Then 5r + 25 + 5r = 55, or, after reducing this equation:

r + 5 + r = 11, or

2r = 6

Then r = 6 mph and f = 11 mph

An insurance company charges $800 annually for car insurance. The policy specifies that the company will pay $1000 for a minor accident and $5000 for a major accident. If the probability of a motorist having a minor accident during the year is 0.2 and of having a major accident is 0.05 (and these events are mutually exclusive), what is the insurance company's expected profit on the policy

Answers

Answer: the expected profit will be $755 annually.

Explanation: Expected Profit (EP) = Charges (income for the insurance company) - probability of minor accidents X amount payable for a minor accident - probability of mayor accidents X amount payable for a major accident.

800- 1000 (0.2) -5000 (0.05)= 800-20-25= 755

Please help me thanks

Answers

Answer:

-75 and 75

Step-by-step explanation:

The two numbers chosen or plotted by them are:

-75 and 75

Step-by-step explanation:

It is given that Bernita and Derek each plot a number on a number line with the properties:

1. The two numbers they have plotted are unique or different.

2. Also there absolute value is same.

3. The sum of the absolute values of the numbers is 150.

We know that Absolute value of a positive number is a number itself and absolute value of a negative number is it's inverse.

So the two numbers that satisfy the above three properties are:

-75 and 75.

On her way to work, a commuter encounters four traffic signals. Assume that the distance between each of the four is sufficiently great that her probability of getting a green light at any intersection is independent of what happened at any previous intersection. The first two lights are green for forty seconds of each minute; the last two, for thirty seconds of each minute.What is the probability that the commuter has to stop at least three times?

Answers

Answer:

7 in 36 or 0.1944

Step-by-step explanation:

The probability of having to stop at least three times is the probability of getting 3 or 4 red lights.

For the first two lights, the probability of getting them red is 20 in 60 (1/3).

For the last two lights, the probability of getting them red is 30 in 60 (1/2).

The probability of all of them being red is:

[tex]P(R=4) = \frac{1}{3}*\frac{1}{3}*\frac{1}{2}*\frac{1}{2}\\P(R=4) =\frac{1}{36}=\frac{1}{36}[/tex]

The probability of three of them being red (3 red + 1 green) is:

[tex]P(R=3) = {(1-\frac{1}{3})*\frac{1}{3}*\frac{1}{2}}*\frac{1}{2}+(1-\frac{1}{3})*\frac{1}{3}*\frac{1}{2}*\frac{1}{2}+\frac{1}{3}*\frac{1}{3}*(1-\frac{1}{2})*\frac{1}{2}+\frac{1}{3}*\frac{1}{3}*(1-\frac{1}{2})*\frac{1}{2}\\P(R=3) =2*(\frac{2}{3}*\frac{1}{3}*\frac{1}{2}*\frac{1}{2})+2*(\frac{1}{3}*\frac{1}{3}*\frac{1}{2}*\frac{1}{2})\\ P(R=3) =\frac{4}{36}+\frac{2}{36}\\ P(R=3) =\frac{6}{36}[/tex]

Therefore, the probability of at least three red lights is:

[tex]P=\frac{1}{36}+\frac{6}{36}=\frac{7}{36}\\ P=0.1944[/tex]

The probability is 7 in 36 or 0.1944.

The probability that the commuter has to stop at least three times is at least 5.55%.

Since on her way to work, a commuter encounters four traffic signals, assuming that the distance between each of the four is sufficiently great that her probability of getting a green light at any intersection is independent of what happened at any previous intersection, and the first two lights are green for forty seconds of each minute; the last two, for thirty seconds of each minute, to determine what is the probability that the commuter has to stop at least three times the following calculation must be performed:

4/6 = 2/3 = 0.66666  0.5 x 0.5 x 0.333 = 0.083333 0.5 x 0.333 x 0.333 = 0.055555

Therefore, the probability that the commuter has to stop at least three times is at least 5.55%.

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A classroom contains 13 students. A student committee of 3 (president, vice-president, and treasurer) must be selected. Harry Potter will serve only as president and only if either of his friends Ron Weasley or Hermione Granger serve as vice president; otherwise he leaves the group. The others (including Ron and Hermione) have no such restrictions. What is the probability that Ron or Hermione become the president of this group

Answers

Answer:

16.39%

Step-by-step explanation:

We have a total number of forms, which are as follows:

-Harry Potter will serve as President AND Ron will serve as Vice President AND anyone will serve as Treasurer:

p1 = 1P11 = 11! / (11-1)! = 11

-Harry Potter will serve as President AND Hermione will serve as Vice President AND anyone who serves as Treasurer is:

p2 = 1P11 = 11! / (11-1)! = 11

- Harry Potter will not serve as President means that no one except Harry Potter (12 remaining students) serve in three locations:

p3 = 12P3 = 12! / (12-3)! = 1320

in total it would be:

11 + 11 + 1320 = 1342

Now the favorable cases are:

- Hermione becomes the president of this group, which means that anyone except Hermione and Harry Potter (11 remaining students) serve in the remaining two places:

p1 = 11P2 = 11! / (11-2)! = 110

- Ron becoming the president of this group means that anyone except Ron and Harry Potter (remaining 8 students) serve in the remaining two places:

p2 = 11P2 = 11! / (11-2)! = 110

adding it would be: 110 + 110 = 220

now then the final probability is the favorable cases among the totals:

220/1342 = 0.1639

Which means that the probability is 16.39%

Answer:

33% probability

1/3

Step-by-step explanation:

100% Hermione though.

Simplify: StartRoot 64 r Superscript 8 Baseline EndRoot

Answers

Answer:

  8r^4

Step-by-step explanation:

  [tex]\sqrt{64r^8} =\sqrt{(8r^4)^2}=\boxed{8r^4}[/tex]

Answer:

8r^4

Step-by-step explanation:

list 5 rational numbers between -4/7 and 1/2

Answers

Answer:

0, 1/10, 2/10, 3/10, 4/10, or

Step-by-step explanation:

-4/7 is about -0.57 in decimal form,

1/2 is 0.5

So we need to find 5 rational numbers between -0.58 and 0.5

A rational number is a number which can be expressed as a fraction.

0 can be expressed as 0/10

0.1 can be expressed as 1/10

0.2 can be expressed as 2/10

0.3 can be expressed as 3/10

0.4 can be expressed as 4/10

So just use those.

Factor completely x3 + 9x2 + 27x+ 27

Answers

Answer:

(x + 3)^3

Step-by-step explanation:

I don't exactly know how to break this down into small steps. I can tell you that it is something like (x + a)^3

It turns out that a = 3 because all the signs in the given equation are +

Answer

(x + a) = (x + 3)^3

What decimal part of one dollar is three quarters?

Answers

Answer:

0.75

Step-by-step explanation:

One dollar/four quarters-1.00

three quarters-0.75

two quarters-0.50

one quarter-0.25

Hope this helps

The distribution of grades in an introductory finance class is normally distributed, with an expected grade of 68. If the standard deviation of grades is 15, in what range would you expect 68.26 percent of the grades to fall? (Round answers to 2 decimal places, e.g. 15.25. Hint: Think in terms of what the expected highest and lowest scores would be for 68.26% of the students taking the exam.)

Answers

Answer:

The range that you would expect 68.26 percent of the grades to fall is between 53 and 83.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 68, \sigma = 15[/tex]

Middle 68.26% of the grades:

From the

50 - (68.26/2) = 15.87th percentile

To the

50 + (68.26/2) = 84.13rd percentile.

15.87th percentile:

X when Z has a pvalue of 0.1587. So X when Z = -1.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1 = \frac{X - 68}{15}[/tex]

[tex]X - 68 = -1*15[/tex]

[tex]X = 53[/tex]

84.13rd percentile:

X when Z has a pvalue of 0.8413. So X when Z = 1.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1 = \frac{X - 68}{15}[/tex]

[tex]X - 68 = 1*15[/tex]

[tex]X = 83[/tex]

The range that you would expect 68.26 percent of the grades to fall is between 53 and 83.

What is the best interpretation of V(4)=64

Answers

I assume the normal function is V(x)=y

So if we plug it in, we know that at x=4, the y value of the function is 64.

The wattle thickness (in millimeters) of 15 randomly selected chickens was measured before and after treatment with phytohemagglutinin (PHA). Does treatment with PHA increase wattle thickness

Answers

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

The wattle thickness (in milimeters) of 15 randomly selected chickens was measured before and after treatment with PHA. Does treatment wih PHA increase wattle thickness?

Chicken Number // Pretreatment // Posttreatment

1 // 1.05 // 3.48

2 // 1.01 // 5.02

3 // 0.78 // 5.37

4 // 0.98 // 5.45

5 // 0.81 // 5.37

6 // 0.95 // 3.92

7 // 1.00 // 6.54

8 // 0.83 // 3.42

9 // 0.78 // 3.72

10 // 1.05 // 3.25

11 // 1.04 // 3.66

12 // 1.03 // 3.12

13 // 0.95 // 4.22

14 // 1.46 // 2.53

15 // 0.78 // 4.39

Solution:

Corresponding wattle thickness before and after treatment form matched pairs.

The data for the test are the differences between the wattle thickness at pretreatment and posttreatment.

μd = wattle thickness at pretreatment minus wattle thickness at posttreatment

Pretreatment. Posttreatment diff

1.05 3.48 -2.43

1.01 5.02 -4.01

0.78 5.37 -4.59

0.98 5.45 -4.47

0.81 5.37 -4.56

0.95 3.92 -2.97

1 6.54 -5.54

0.83 3.42 -2.59

0.78 3.72 -2.94

1.05 3.25 -2.2

1.04 3.66 -2.62

1.03 3.12 -2.09

0.95 4.22 -3.27

1.46 2.53 -1.07

0.78 4.39 -3.61

Sample mean, xd

= (-2.43 - 4.01 - 4.59 - 4.47 - 4.56 - 2.97 - 5.54 - 2.59 - 2.94 - 2.2 - 2.62 - 2.09 - 3.27 - 1.07 - 3.61)/15 = - 3.264

xd = - 3.264

Standard deviation = √(summation(x - mean)²/n

n = 15

Summation(x - mean)² = (- 2.43 + 3.264)^2 + (-4.01 - 3.264)^2 + (-4.59 - 3.264)^2+ (-4.47 - 3.264)^2 + (-4.56 - 3.264)^2 + (-2.97 - 3.264)^2 + (-5.54 - 3.264)^2 + (-2.59 - 3.264)^2 + (-2.94 - 3.264)^2 + (-2.2 - 3.264)^2 + (-2.62 - 3.264)^2 + (-2.09 - 3.264)^2 + (-3.27 - 3.264)^2 + (-1.07 - 3.264)^2 + (-3.61 - 3.264)^2 = 627.32444

Standard deviation = √(627.32444/15

sd = 6.47

For the null hypothesis

H0: μd ≥ 0

For the alternative hypothesis

H1: μd < 0

1) The distribution is a students t. Therefore, degree of freedom, df = n - 1 = 15 - 1 = 14

The formula for determining the test statistic is

t = (xd - μd)/(sd/√n)

t = (- 3.264 - 0)/(6.47/√15)

t = - 1.95

We would determine the probability value by using the t test calculator.

p = 0.036

Assume alpha = 0.05

Since alpha, 0.05 > than the p value, 0.036, then we would reject the null hypothesis. Therefore, we can conclude that at a significance level of 5%, treatment with PHA increase wattle thickness

Please answer this correctly

Answers

Answer:

0

Step-by-step explanation:

Since the original: 6 is not either the largest or the smallest, it wouldn't affect the range

The only numbers that can affect the range when replaced are the greatest and the least values: 5 and 9

In 1970, the average length of a major league baseball game was 150 minutes compared to 180 minutes in 2018. Calculate the absolute and relative change in major league baseball game times from 1970 to 2018. Round your answer for relative change to the nearest whole percent.

Answers

Answer:

30 min20%

Step-by-step explanation:

The absolute change in game length is ...

  (180 min) -(150 min) = 30 min . . . . change in game length

__

The relative change is expressed as a fraction of the original game length:

  (30 min)/(150 min) × 100% = 20% . . . . relative change in game length

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