Problem 9-8 (modified). The height of adult males in a particular city is normally distributed, with mean 69.5 in. and standard deviation 2.65 in. When a random sample is taken of size 20, find (1) the standard error of Xbar

Answers

Answer 1

Complete Question

Problem 9-8 (modified). The height of adult males in a particular city is normally distributed, with mean 69.5 in. and standard deviation 2.65 in.

When a random sample is taken of size  20, find (1) the standard error of Xbar

(2) the probability that Xbar falls within .5 in. of the true mean

Probability=

Answer:

1

[tex]\sigma_{\= x} = 0.5926[/tex]

2

[tex]P( 69 < \= X < 70) = 0.60134[/tex]

Step-by-step explanation:

From the question we are told that

  The true  mean is  [tex]\mu = 69.5 \ in[/tex]

  The standard deviation is  [tex]\sigma = 2.65 \ in[/tex]

    The sample size is n =  20

Generally the standard error of Xbar[tex](\= x)[/tex] is mathematically represented as

     [tex]\sigma_{\= x} = \frac{\sigma }{\sqrt{n} }[/tex]

=>  [tex]\sigma_{\= x} = \frac{ 2.65 }{\sqrt{ 20 } }[/tex]

=>  [tex]\sigma_{\= x} = 0.5926[/tex]

Generally for  [tex]\= x[/tex] to fall within 0.5 of the true mean the [tex]\= x[/tex] must be within

     [tex]a = \mu + 0.5[/tex]

=>   [tex]a = 69.5 + 0.5[/tex]

=>   [tex]a = 70[/tex]

or  [tex]b = \mu -0.5[/tex]

=>    [tex]b = 69.5 -0.5[/tex]

=>    [tex]b = 69[/tex]

Generally the probability that  [tex]\= x[/tex] fall with 0.5  of the true mean is mathematically represented as

     [tex]P( 69 < \= X < 70) = P(\frac{69 - 69.5 }{ 0.5926} < \frac{\= X - \mu }{ \sigma_{\= x} } <\frac{70- 69.5 }{ 0.5926})[/tex]

=>  [tex]P( 69 < \= X < 70) = P(-0.844 < Z < 0.844)[/tex]

=>  [tex]P( 69 < \= X < 70) = P( Z < 0.844) - P( < -0.844)[/tex]

From the z table the probability of  (  Z    < 0.844)  and   (  Z    < -0.844)  is  

     [tex]P( Z < 0.844) = 0.80067[/tex]

and

    [tex]P( Z < - 0.844) = 0.19933[/tex]

So

   [tex]P( 69 < \= X < 70) = 0.80067 - 0.19933[/tex]

=>  [tex]P( 69 < \= X < 70) = 0.60134[/tex]

Answer 2

The standard error of the given data comes to be 0.593.

It is given that

mean [tex]\mu[/tex] = 69.5 inch

Standard deviation [tex]\sigma[/tex] = 2.65 inch

Sample size n =20

What is the standard error?

The standard error is a statistical term that measures the accuracy with which a sample distribution represents a population by using standard deviation.

The standard error is given by:

[tex]SE =\frac{\sigma}{\sqrt{n} }[/tex]

[tex]SE =\frac{2.65}{\sqrt{20} }[/tex]

[tex]SE=0.593[/tex]

Hence, the standard error of the given data comes to be 0.593.

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Related Questions

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The answer would be 9023/1000 as a mixed number.

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Answers

Answer:

5/8

Step-by-step explanation:

Simplify the following:

(2 + 1/2)/4

Put 2 + 1/2 over the common denominator 2. 2 + 1/2 = (2×2)/2 + 1/2:

((2×2)/2 + 1/2)/4

2×2 = 4:

(4/2 + 1/2)/4

4/2 + 1/2 = (4 + 1)/2:

((4 + 1)/2)/4

4 + 1 = 5:

(5/2)/4

5/2×1/4 = 5/(2×4):

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Fourteen more than three times a number is sixty-seven.

Answers

Answer:

67 = 3n + 14

Step-by-step explanation:

So we know its going to equal 67, and 3 times a number is the same as 3n more than is to show addition. That means you are adding 14 to 3n.

That's why it would be,

14 + 3n = 67

Hope that helps and have a great day!

Answer:

8[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

67 ÷ 3 - 14

22[tex]\frac{1}{3}[/tex] - 14

8[tex]\frac{1}{3}[/tex]

Hope this helps!

Have a nice day!

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Suppose the weather at Chebyshev Citadel is either sunny or cloudy. A sunny day is followed by a sunny day with probability 0.7, and a cloudy day is followed by a sunny day with probability 0.5. If it is sunny today, what is the probability that it will be sunny 3 days later

Answers

Answer:

0.628

Step-by-step explanation:

From the information given:

Let S represent sunny days and C represent cloudy days;

S is expressed in the matrix to be in the first row and first column

C is expressed in the matrix to be in the second row and second column

Then, the transition for the probability matrix can be computed as follows:

[tex]P = \right. \left[\begin{array}{cc}0.7&0.3\\0.5&0.5\\\end{array}\right][/tex]

[tex]P^2 = \right. \left[\begin{array}{cc}0.7&0.3\\0.5&0.5\\\end{array}\right] \right. \left[\begin{array}{cc}0.7&0.3\\0.5&0.5\\\end{array}\right][/tex]

[tex]P^2 = \right. \left[\begin{array}{cc}0.49+0.15&0.21+0.15\\0.35+0.25&0.15+0.25\\\end{array}\right] \right.[/tex]

[tex]P^2 = \right. \left[\begin{array}{cc}0.64&0.36\\0.60&0.40\\\end{array}\right] \right.[/tex]

[tex]P^3 = \right. \left[\begin{array}{cc}0.64&0.36\\0.60&0.40\\\end{array}\right] \right. \right. \left[\begin{array}{cc}0.7&0.3\\0.5&0.5\\\end{array}\right][/tex]

[tex]P^3 = \right. \left[\begin{array}{cc}0.628&0.372\\0.62&0.38\\\end{array}\right] \right.[/tex]

So, if it is sunny, the probability that it is going to be sunny 3 days later = 0.628

Using the transition of the events, it is found that there is a 0.628 = 62.8% probability that it will be sunny 3 days later.

The transition of events, considering that it is sunny today and we want it to be sunny 3 days later, is given by:

S - S - S - S

S - C - S - S

S - S - C - S

S - C - C - S

Considering the probabilities stated in the exercise(S - S: 0.7, S - C: 0.3, C - S: 0.5, C - C: 0.5), for the last three days, the probability is:

[tex]p = 0.7^3 + 0.3(0.5)(0.7) + 0.7(0.3)(0.5) + 0.3(0.5)(0.5) = 0.628[/tex]

0.628 = 62.8% probability that it will be sunny 3 days later.

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10
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Step-by-step explanation:

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Answer:

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Answers

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An office will increase salary to its top 8% employees on the basis of a performance score the office created for each employee. The performance score is approximately normal with mean 82.5 and standard deviation 9.25. How high must an employee score in order to qualify for increase in the salary?

Answers

Answer:

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Step-by-step explanation:

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Answers

Complete Question:

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Answer:

22%

Step-by-step explanation:

Given

[tex]x = 88[/tex]

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Required

Determine the sample proportion, p

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Substitute values for x and n

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Answers

Step-by-step explanation:

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Answer:

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Answer:

Step-by-step explanation:

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Answers

Answer:

y=7x+2

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Step-by-step explanation:

y=mx+b

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A car is moving at an acceleration of 20 m/s^2 and hits a wall with a force of 400 N. What is the mass of the car?

Answers

i dont know the answer but i know in the end ill get free points.

Answer:

Acceleration = change in velocity/change in time, a = (vf - vi)/t [Units: m/s/s or m/s2] .. Example: A car collides with an insect. If the car exerts a force of 10N on the insect what ... a level sidewalk at a constant speed of 1m/s if the frictional force is 400N? ... d) When the stick is hit slowly string 2 breaks because of the inertia of mass M.

Study the area model.
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Answers

answr is A
explanation:

A triangle has side lengths measuring 20 cm, 5 cm, and n cm. Which describes the possible values of n?
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x
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Answers

Answer: D  15 < n < 25

In triangleJKL, If angle J is seven less than angle L and angle k is 21 less than twice angle l, find the measure
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Answers

Answer:

J=35  K=63  L=42

Step-by-step explanation:

Convert 54 2/7 to a fraction in lowest term and please work the problem out for me so I can understand how you got the answer thank you

Answers

Answer: 19/35

1) Put it over 100.

(54 2/7)/100

2)Simplify

(54 2/7)/100 = 19/35

[tex]54(\frac{2}{7})[/tex]% can be converted into a fraction of [tex]\frac{19}{140}[/tex].

What is a fraction?

"A fraction represents a part of a whole or, more generally, any number of equal parts."

The given percentage of the number is

[tex]= 54(\frac{2}{7})[/tex]%

[tex]= \frac{380}{(7)(100)}[/tex]

[tex]= \frac{19}{7(20)}[/tex]

[tex]= \frac{19}{140}[/tex]

Therefore, the required fraction is [tex]\frac{19}{140}[/tex]

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