Pls solve with working out. Ok thanks

The ratio of the sides of the given similar triangles is: C. 4/12 = 5/15 = 1/3.

The corresponding sides of similar triangles have ratios that are equal to each other.

The corresponding sides and their ratios are:

4/12 = 1/3

5/15 = 1/3

Therefore, the ratio of their sides in its lowest term is:

C. 4/12 = 5/15 = 1/3

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The equation of the sine function will be y = -3 sin [2(x + π)] + 2. Then the correct option is A.

It is a function that repeats itself in a particular time interval.

The equation is given as

y = A sin (ωx + Ф) + C

Where A is the amplitude, ω is the frequency, Ф is the phase difference, and C is the constant.

From the graph, we have

A = -3

ω = 2

Ф = 2π

C = 2

Then we have the equation will be

y = -3 sin [2(x + π)] + 2

Then the correct option is A.

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Answer:

The equation of the line is y ≥ 1/3(x)-1

Step-by-step explanation:

Given

The line intersects y-axis at (0,-1). Therefore, the y-intercept is -1

The line passes through the points (0,-1)  and (3,0)

The slope can be obtained as follows,

m = 0-(-1)

        3-0

    = 1/3

The linear equation with slope and intercept  is given as follows.

y = mx + c

Substitute 1/3 for m, 3 for x and 0 for y  in equation  to obtain the value of

c .

0 = 1/3 *3 + c

c= -1

To check whether the equation includes origin substitute 0 for x and 0 for y in equation

Therefore, y≥ mx+c

                      = 1/3*x-1

Hence, Linear inequality represented is y ≥ 1/3(x) -1

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Answer:

40 square units

Step-by-step explanation:

The question gives that both the large shape and the small missing shape are rectangles.  The formula for the area of a rectangle is [tex]A=bh[/tex] where "A" is the "Area", "b" is the "base" (bottom edge), and "h" is the height (side edge).

For rectangles, opposite sides (example: top & bottom) have the same length, so the top of the missing rectangle must also be 3.

To find the area of the figure, we must find the difference (subtraction) between the large rectangle (without a hole out of it) and the rectangular hole.

[tex]A_{\text{figure}}=A_{\text{large rectangle without hole}}-A_{\text{hole}}\\A_{\text{figure}}=(7)(7)-(3)(3)\\A_{\text{figure}}=49-9\\A_{\text{figure}}=40[/tex]

So, the area of the figure is 40 square units.

Answer:

40

Step-by-step explanation:

We can make a big square by making a line at the top open edge (as shown in the image attached below). We will first solve for [tex]A_{2}[/tex] and then [tex]A_{1}[/tex], and then finally solving for out answer by subtracting [tex]A_{1}[/tex] from [tex]A_{2}[/tex] .

[tex]A_{2}[/tex] is a square with side lengths of 7, so the area is 7 * 7 = 49.

[tex]A_{1}[/tex] is a smaller square with side lengths of 3, so the area is 3 * 3 = 9.

[tex]A_{2} - A_{1} = 49 - 9 = 40[/tex]

∴ Our final answer is 40

Answer:

3,-2

Step-by-step explanation:

set y =0 and solve

(-x-2)(x-3)=0

the values 3, -2 solve the equation and are your x-intercepts

Step-by-step explanation:

Most standard rain gauges have a wide funnel leading into the cylinder and are calibrated so that one-tenth of an inch of rain measures one inch when it collects inside.

Answer:

5^20

Step-by-step explanation:

since you have brackets around (5^5) you can multiply the exponents. if you think about it what you're essentially doing is

(5 * 5 * 5 * 5 * 5) * (5 * 5 * 5 * 5 * 5) * (5 * 5 * 5 * 5 * 5) *

(5 * 5 * 5 * 5 * 5)

which is why you can multiply the exponents to simplify

Answer:

y = 4

Step-by-step explanation:

1) Simplify [tex]3^5[/tex] to 243.

[tex]{9}^{y}=\frac{243\times {9}^{6}}{{27}^{3}}[/tex]

2) Simplify [tex]{9}^{6}[/tex] to 531441.

[tex]{9}^{y}=\frac{243\times 531441}{{27}^{3}}[/tex]

3)  Simplify  [tex]243\times 531441[/tex] to  129140163.

[tex]{9}^{y}=\frac{129140163}{{27}^{3}}[/tex]

4) Simplify  [tex]{27}^{3}[/tex]  to  19683.

[tex]{9}^{y}=\frac{129140163}{19683}[/tex]

5) Simplify  [tex]\frac{129140163}{19683}[/tex] to 6561.

[tex]{9}^{y}=6561[/tex]

6) Convert both sides to the same base.

[tex]9^y=9^4[/tex]

7)  Cancel the base of 9 on both sides.

[tex]y=4[/tex]

Cheers,

ROR

Answer:

y = 4

Step-by-step explanation:

Decompose  in base 3

[tex]9^{y} =\frac{3^{5} (3^{2})^{6} }{(3^{3})^{3} } =\frac{3^{5}3^{12} }{3^{9} } =\frac{3^{17} }{3^{9} } =3^{17-9} =3^{8}[/tex]

if

[tex]3^{8} =(3^{2} )^{4} =9^{4}[/tex]

then

[tex]9^{y} =9^{4}[/tex]

[tex]y=4[/tex]

Hope this helps

X and 73 are same-side interior angles, which are supplementary (they add up to 180).

x + 73 = 180

x = 107

X and (6y - 79) are vertical angles, which are congruent (have the same measure/value.

x = 6y - 79

107 = 6y - 79

6y = 186

y = 31

Hope this helps!

Answer:

quadrant 4

Step-by-step explanation:

(2,-5) would be in the 4th quadrant

Answer:

3 is the smallest prime factor.

Step-by-step explanation:

ionk how to explain it but trust me its right.

When a given function is written with factors in the form of ( x - r ), then r is a zero of the function.

We're given:

Therefore, the zeros of the function are 7 and -6.

-6, 7

The zeroes of the function will be equal to ( 7, -6 ).

It is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

Given function:-

As we can see that the quadratic equation in the factorized form is ( x - 7 ) ( x+ 6 ) so we will equate each factor to zero.

( x- 7 )  = 0

x = 7

( x+ 6 ) = 0

x = -6

Therefore zeroes of the function will be equal to ( 7, -6 ).

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The simplification of the given algebra we see is; 9 + 3((a√a + a - a + √a)/(a - 1)) - ³/₂₀((√5 - 5)(a - 5√a)) - (a² - 4a√a - 5a)/((√a + 1)*√5 + 5))

We are given the algebra expression;

A = [3 + ((a + √a)/(√a + 1))][3 - ((a - 5√a)/(√5 + 5))]

When we multiply out, we will get;

9 + 3((a + √a)/(√a + 1)) - 3((a - 5√a)/(√5 + 5)) - [((a + √a)/(√a + 1)) * ((a - 5√a)/(√5 + 5))]

⇒ 9 + 3((a√a + a - a + √a)/(a - 1)) - ³/₂₀((√5 - 5)(a - 5√a)) - (a² - 4a√a - 5a)/((√a + 1)*√5 + 5))

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Answer: [tex]-1, \frac{4}{3}[/tex]

Step-by-step explanation:

[tex]3x^{2}-5x+6=10-4x\\\\3x^{2}-x-4=0\\ \\ (x+1)(3x-4)=0 \\ \\ x=\boxed{-1, \frac{4}{3}}[/tex]

Answer:

x = -1
x = 4/3

Step-by-step explanation:

Hello!

First, let's convert the equation into Standard Form: [tex]ax^2 + bx + c = 0[/tex]

We can solve this by factoring the quadratic. We have to find two numbers that multiply to [tex]ac[/tex] but add up to [tex]b[/tex].

The two numbers would be -4 and 3. We can expand -x to -4x + 3x, and then factor by grouping.

Use the Zero Product Property. Set each factor to zero and solve for x.

The solutions to the quadratic are -1 and 4/3.

The expression is 17.

An expression is a sentence with a minimum of two numbers or variables and at least one math operation.

Given:

10+(6-3) 22-4-1

Using the BODMAS rule,

First solve the bracket term

10+ 3 * 22 -4-1

Now, perform multiplication

10+66-4-1

Now, subtraction

10+66-5

=10+61

And lastly addition

=71.

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Answer:

17

Step-by-step explanation:

the answer is 17 :)

Answer:

eather a 5:7 or c 3:4

Step-by-step explanation:

i rlly do hope this helps and good luck

The numeric values of the given expressions are given as follows:

1) 2.

2) -3.

We find the numeric value of an expression replacing all instances of x by the number.

The expression 1 is:

3 + x + (-7) = 3 + x - 7 = x - 4.

When x = 6, the value is:

x - 4 = 6 - 4 = 2.

The expression 2 is:

x + (-5) + 5 = x - 5 + 5 = x.

Hence, when x = -3, the value is:

x = -3.

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B will be at the place of E after all three rotations. So the correct option is B.

Moving in a circular plane with respect to the fixed point is called as the rotation of the object.

If rotation maps to The three rotations for B will be

The given B after one rotation will shift in place of C

After the second rotation will shift in place of D

After the third rotation will shift in place of E

B will be at the place of E after all three rotations. So the correct option is B.

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Answer:

y

Step-by-step explanation:

the value of y may be y or on the alphabetic order 25th

Answer:

6 square units

Step-by-step explanation:

base = 4 units

height = 3 units

 [tex]\sf \boxed{\bf Area \ of \ triangle = \dfrac{1}{2}*base*height}[/tex]

                                  [tex]\sf =\dfrac{1}{2}*4*3\\\\ = 2*3\\\\ = 6 \ square units[/tex]

[tex]\Large❏ \: \large\begin{gathered} {\underline{\boxed{ \rm {\blue{Area \: of \: triangle \: = \: \frac{1}{2} \: \times \: Base \: × \: Height }}}}}\end{gathered}[/tex]

[tex]\rm \large \red{\: Area \: of \: triangle }\large\purple\implies \tt \large \: \frac{1}{2} \: \times \: Base \: × \: Height [/tex]

[tex]\rm \large \red{\: Area \: of \: triangle }\large\purple\implies \tt \large \: \frac{1}{2} \: \times \: 4 \: × \: 3 [/tex]

[tex]\rm \large \red{\: Area \: of \: triangle }\large\purple\implies \tt \large \: \frac{1}{ \cancel2} \: \times \: \cancel{4} \: ^{\green2} \: × \: 3 [/tex]

[tex]\rm \large \red{\: Area \: of \: triangle }\large\purple\implies \tt \large \: 2 \: \times \: 3[/tex]

[tex]\rm \large \red{\: Area \: of \: triangle }\large\purple\implies \tt \large \: 6[/tex]

Hence , the area of triangle is 6 units.

The equation which best represents the scenario is, x²/2=271

Area is the quantity that expresses the extent of a region on the plane or on a curved surface. The area of a plane region or plane area refers to the area of a shape or planar lamina, while surface area refers to the area of an open surface or the boundary of a three-dimensional object.

Perimeter is a length of the boundary surrounding the area

Area of rectangle=length x Breadth

Perimeter=2(length+breadth)

length=x

breadth=x/2

Area=271ft²

Area=length x breadth

So, using the given value we can write

271=x²/2

⇒x=√542

      =23.28ft

Therefore, the equation which best represents the scenario is, x²/2=271

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Answer:

g

Step-by-step explanation:

for this function, we put in the value of "g" (because it is the cause of the function--it is the independent variable [it changes; and it doesn't rely on something else to change] )

so, because the part independently changing is the gas used, that is our input of this graph.

(you can imagine this to be a graph, which typically has the independent variable that we are directly changing--x--along the x-axis, which is where we would place g.)

hope this helps!!

Answer:

$ 603.77

Step-by-step explanation:

Find unit rate of  dollars per hour :   359/22

   now multiply by hours :    359/22  * 37 = 603.77

Answer:

$603.77

Step-by-step explanation:

if they work 22 hours a week

and once a week they make $359

therefore divide to get the hourly rate

359/22 = 16.3181818182

they make 16.3181818182 per hour

then we have to multiply the hourly by the hours worked

16.3181818182 * 37 = 603.772727273

since this is in dollars ($) we round to the second decimal place (hundredths)

meaning we cut off the numbers after it

603.77║2727273

then, determine if the thousandths place is equal to or greater than five or less than five

since it is a 2 then the 7 stays the same

if it were a 5 or greater we would round up, making the 7 in the hundredth place turn into an 8.

therefore your answer is $603.77

hope this helps:)

Answer:

1/3

Step-by-step explanation:

the answer is 1/3 because the probability of landing on a 7 is 1/3 and the probability of landing on any number less than 9 is 2/3. Then, you multiply the probabilities: 1/3 * 2/3 = 2/9 = 1/3

$2.50

Step-by-step explanation:

10 dimes are 100 aka 1 dollar, and 30 nickels make 250

Answer:

Step-by-step explanation:

Use trigonometry to solve for unknowns.

#1

#2

#3

Answer:

x=4

Step-by-step explanation:

2x-8-x+4-6=0

or,2x-x-8+4=0

or,x-4=0

or,x=0+4

•°•x=4

ans

Answer:

x = 2 or 7

Step-by-step explanation:

(x-4)² - (x-4) - 6 = 0

x²-8x+16-x+4 -6 = 0

           x²-9x+14 = 0

           (x-2)(x-7) = 0

∴x = 2 or 7

Step-by-step explanation:

here is your answer. where are you from

The cost price is Rs22600, the marked price is Rs31640 and the Profit percentage is 19%.

The percentage is defined as a given amount in every hundred. It is a fraction with 100 as the denominator percentage is represented by the one symbol %.

For example, if you say 678, we must also know the whole number, but if you say 80%, it becomes evident. The percentage is the same as the amount of that value but ranges from 1 to 100.

Let's say

Cost of article = c

Given,

Marked 40% above the cost price and sold with 15% discount including 10% VAT at Rs. 26,894

1.4c - 0.15×(1.4c) = 26894

c = Rs 22600

So,

Marked price = 1.40c = Rs 31640

Profit percentage = ( 26894 - 22600)22600 = 19%.

Hence cost price is Rs22600, the marked price is Rs31640 and the Profit percentage is 19%.

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Answer:

225 cm²

Step-by-step explanation:

dilatation factor = 3 , then

area factor = 3² = 9

the area of the dilated polygon is then 9 times the area of the original so

area of dilated polygon = 9 × 25 = 225 cm²

Answer:

Mixed Number: 11 1/5

Improper Fraction: 56/5

Step-by-step explanation:

Given:

It takes 3/7 tonnes of sand to make a tonne of concrete.

Mason has 4 4/5 tonnes of sand.

To Find:

How much concrete, in tonnes, can he make?

Give your answer as a fraction in its simplest form.

Solve:

By the given , takes 3/7 tonnes of sand = tonne of concrete.

Thus, we divide the total of tonnes of sand Mason have by how many it takes to make a tonne of concrete.

Hence, we have;

[tex]4\frac{4}{5}\div \frac{3}{7}[/tex]

Convert to improper fraction;

[tex]=\frac{24}{5}\div \frac{3}{7}[/tex]

Using the fraction rule;

[tex]\frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}[/tex]

[tex]=\frac{24}{5}\times \frac{7}{3}[/tex]

Cross-cancel common factor - 3

[tex]=\frac{8}{5}\times \frac{7}{1}[/tex]

Multiply fraction:

[tex]=\frac{56}{5}[/tex]

Convert improper to mixed number:

[tex]=11\frac{1}{5}[/tex]

Hence, the answer is [tex]\mathrm{11\frac{1}{5}\;or\;\frac{56}{5} }[/tex]

RevyBreeze

Answer:

[tex]\rm Improper \ fraction : \sf \sf \dfrac{56}{5} \ of \ concrete[/tex]

[tex]\rm Mixed \ fraction: \sf 11\dfrac{1}{5} \ of \ concrete[/tex]

Explanation:

[tex]\sf concrete = total \ tones \ of \ sand \ \div \ unit \ rate \ of \ sands \ required \ to \ make \ concrete[/tex]

Here given:

Concrete:

[tex]\sf \rightarrow 4\dfrac{4}{5} \div \dfrac{3}{7}[/tex]

[tex]\rightarrow \sf \dfrac{24}{5}\div \dfrac{3}{7}[/tex]

[tex]\rightarrow \sf \dfrac{24}{5}\times \dfrac{7}{3}[/tex]

[tex]\rightarrow \sf \dfrac{56}{5}[/tex]

[tex]\rightarrow \sf 11\dfrac{1}{5}[/tex]