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A certain shade of blue paint is made by mixing 1/2 of a quart of blue paint with 1/8 of a quart of white paint.

How much white paint would you need to mix with 2 2/3 quarts of blue paint to make the same shade of paint?

Explain the error.

Calculate the correct solution.

Answer:

7/10

Step-by-step explanation:

We can use the slope formula to find the slope

m = ( y2-y1)/(x2-x1)  where ( x1,y1) and (x2,y2) are two points on the line

m = ( 24-17)/(25-15)

   = 7/10

  = 7/10

Answer:

The answer is 3.2

Step-by-step explanation:

Answer:

x = 60

Step-by-step explanation:

Let x = ?

120 + 95 +85 +x =360

x +300 =360

x = 360-300

x = 60

Answer:

[tex]30^{\circ}[/tex].

Step-by-step explanation:

Let [tex]\theta[/tex] denote the unknown angle of elevation. Let [tex]h[/tex] denote the height of the tower.

Refer to the diagram attached. In this diagram, [tex]{\sf A}[/tex] denotes the top of the tower while [tex]{\sf B}[/tex] denote the base of the tower; [tex]{\sf BC}[/tex] and [tex]{\sf BD}[/tex] denote the shadows of the tower when the angle of elevation of the sun is [tex]60^{\circ}[/tex] and [tex]\theta[/tex], respectively. The length of segment [tex]{\sf AB}[/tex] is [tex]h[/tex]; [tex]\angle {\sf ACB} = 60^{\circ}[/tex], [tex]\angle {\sf ADB} = \theta[/tex], and [tex]{\sf BD} = 3\, {\sf BC}[/tex]..

Note that in right triangle [tex]\triangle {\sf ABC}[/tex], segment [tex]{\sf AB}[/tex] (the tower) is opposite to [tex]\angle {\sf ACB}[/tex]. At the same time, segment [tex]{\sf BC}[/tex] (shadow of the tower when the angle of elevation of the sun is [tex]60^{\circ}[/tex]) is adjacent to [tex]\angle {\sf ACB}[/tex].

Thus, the ratio between the length of these two segments could be described with the tangent of [tex]m\angle {\sf ACB} = 60^{\circ}[/tex]:

[tex]\begin{aligned}\tan(\angle {\sf ACB}) &= \frac{\text{opposite}}{\text{adjacent}} = \frac{{\sf AB}}{{\sf BC}}\end{aligned}[/tex].

[tex]\begin{aligned}\frac{{\sf AB}}{{\sf BC}} = \tan(60^{\circ}) = \sqrt{3}\end{aligned}[/tex].

The length of segment [tex]{\sf AB}[/tex] is [tex]h[/tex]. Rearrange this equation to find the length of segment [tex]{\sf BC}[/tex]:

[tex]\begin{aligned} {\sf BC} &= \frac{{\sf AB}}{\tan(\angle ACB)} \\ &= \frac{h}{\tan(60^{\circ})}\\ &= \frac{h}{\sqrt{3}} \\ &\end{aligned}[/tex].

Therefore:

[tex]\begin{aligned}{\sf BD} &= 3\, {\sf BC} \\ &= \frac{3\, h}{\sqrt{3}} \\ &= (\sqrt{3})\, h\end{aligned}[/tex].

Similarly, in right triangle [tex]{\sf ABD}[/tex], segment [tex]{\sf AB}[/tex] (the tower) is opposite to [tex]\angle {\sf ADB}[/tex]. Segment [tex]{\sf BD}[/tex] (shadow of the tower, with [tex]\theta[/tex] as the angle of elevation of the sun) is adjacent to [tex]\angle {\sf ADB}[/tex].

[tex]\begin{aligned}\tan(\angle {\sf ADB}) &= \frac{\text{opposite}}{\text{adjacent}} = \frac{{\sf AD}}{{\sf BD}}\end{aligned}[/tex].

[tex]\begin{aligned}\frac{{\sf AB}}{{\sf BD}} = \tan(\theta) \end{aligned}[/tex].

Since [tex]{\sf AB} = h[/tex] while [tex]{\sf BD} = (\sqrt{3})\, h[/tex]:

[tex]\begin{aligned}\tan(\theta) &= \frac{{\sf AB}}{{\sf BD}} \\ &= \frac{h}{(\sqrt{3})\, h} \\ &= \frac{1}{\sqrt{3}}\end{aligned}[/tex].

Therefore:

[tex]\begin{aligned}\theta &= \arctan\left(\frac{1}{\sqrt{3}}\right) \\ &= 30^{\circ}\end{aligned}[/tex].

In other words, the angle of elevation of the sun at the time of the longer shadow would be [tex]30^{\circ}[/tex].

Answer:

2.3

Step-by-step explanation:

4²+b²=4.6²

16+b²=21.16

-16 -16

b²= 5.16

b=√5.16

b= 2.3

Answer:

2.27 in   ~2.3 in to the nearest tenth

Step-by-step explanation:

It is a right triangle ....so yo can use pythagorean theorem

4^2 + b^2 = 4.6^2

b = 2.27

Answer:

The answer is 240 degrees

Step-by-step explanation:

A full circle is 360 degrees.

We know one angle is 120 degrees.

360-120=240 degrees

Answer:

[tex]\textsf{Volume}=\sf \dfrac{175}{3} \pi \:yd^3[/tex]

Step-by-step explanation:

[tex]\textsf{Volume of a cone}=\sf \dfrac{1}{3} \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substituting the given value into the formula:

[tex]\begin{aligned}\implies\textsf{Volume} &=\sf \dfrac{1}{3} \pi (5^2)(7)\\\\&=\sf \dfrac{1}{3} \pi (25)(7)\\ \\&=\sf \dfrac{1}{3} \pi (175)\\ \\&=\sf \dfrac{175}{3} \pi \:yd^3\\\\\end{aligned}[/tex]

Answer:

The volume of cone

radius (r) = 5 yd

height (h) = 7 yd

The volume of cone

[tex] = \frac{1}{3} \pi {r}^{2} h[/tex]

Substituting the value of 'r' and 'h' in the formula.

[tex] = \frac{1}{3} \times \frac{22}{7} \times {5}^{2} \times 7 \\ = \frac{1}{3} \times 22 \times 5 \times 5 \\ = \frac{550}{3} {yd}^{3} [/tex]

[tex] \text {The volume of cone is} \frac{550}{3} {yd}^{3} [/tex].

[tex] \mathcal {BE \: \: BRAINLY} [/tex]

Answer:

Step-by-step explanation:

it's a right triangle

AREA = 1/2 × l × w

so

1/2 * 4 * 3 =

2 * 3 =

6

Answer:

6 m^2

Step-by-step explanation:

This is a triangle and in triangles to find the area we use the following formula:

1/2*b*h (b: base, h: height)

The base of this triangle is 4m and the height is 3m

1/2*4*3 = 6

The area is presented with square units so the answer for this question is 6 m^2

This transformation of the polygon ABCD to A'B'C'D' is a by a factor of 2

The coordinates are given as:

Calculate the distance AB and A'B' using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}[/tex]

This gives

[tex]AB = \sqrt{(3-1)^2 + (0-0)^2} = 2[/tex]

[tex]A'B' = \sqrt{(6-2)^2 + (0-0)^2} = 4[/tex]

Divide A'B' by AB to determine the scale factor (k)

k = 4/2

k = 2

Hence, this transformation is a by a factor of 2

Read more about transformation at:

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Step-by-step explanation:

Simplify the expression by using the Distributive Property.

For this expression, we'll be distributing. In simpler terms, multiplying 3 into the values inside the parentheses.

Think of the expression as;

[tex]3(3a-6)=(3 \times3a)+(3 \times -6)[/tex]

Multiply;

[tex]3 \times 3a=9a[/tex] (Multiply the whole number.)

[tex]3 \times -6=-18[/tex]

Your simplified expression is [tex]9a-18.[/tex]

The histogram of a probability distribution is right-skewed and each bar has the same width and the same height.

It is defined as the numerical data representation in the graph with the help of a bar without space. The histogram gives an idea about the data's approximate distribution.

We have:

The player receives one ticket from the game for every 10 points scored. So,

Number of tickets received T = (1/10)X

From the table attached, we can plot a graph or probability histogram using the number of tickets on the horizontal axis and the probability on the vertical axis.

Right-skewed is the probability distribution. Each bar has the same width and the same height, which symbolizes the likelihood. The highest likelihood is 0.32, which is represented by the right-hand highest bar. The rightmost bar represents the lowest value of 0.07.

Thus, the histogram of a probability distribution is right-skewed and each bar has the same width and the same height.

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Answer:

So the answer is (15.8)

Answer:

3602 people in 15 years

Step-by-step explanation:

2000 ( 1 + .04)^n         .04 is 4%    n = years

2000 ( 1.04)^15 = 3602 people

Answer:

put the x by the number 4

Step-by-step explanation:

Answer:

x=

1

3

y+

17

3

Step-by-step explanation:

This is all i can get so far, if can improve opon this let me know

Answer: G

Step-by-step explanation:

1 pound equals =16 ounces

12.5 * 16=200

so 200 ounces.

Answer:

Step-by-step explanation:

5+1+3+8+2=19

3/19 = 16%

[tex](\sin^2 \theta + \cos^2 \theta)(\sin \theta + \cos \theta)\\\\=1 \cdot(\sin \theta + \cos \theta)\\\\=\sin \theta + \cos \theta[/tex]

Answer:

D: cos^3(O)

Step-by-step explanation:

Answer:

35%

Step-by-step explanation:

35+25+40=100

Since the total is 100 we know that any number out of 100 will be that percentage.

Answer:

36

Step-by-step explanation:

[tex] \frac{40}{32} = \frac{45}{?} \\ \frac{32 \times 45}{40 } = 36[/tex]

If quadrilateral H is a scaled copy of quadrilateral G then the value of i is 36.

A quadrilateral is a closed shape and a type of polygon that has four sides, four vertices and four angles.

Given that Quadrilateral H is a scaled copy of quadrilateral G.

Two quadrilaterals are similar if their corresponding angles are equal and also their corresponding sides must be proportional.

The sides are proportional.

40/32 = 45/i

We have to find the value of i

Apply cross multiplication

40i=45(32)

40i = 1440

Divide both sides by 40

i = 1440/40

i = 36

Hence, if quadrilateral H is a scaled copy of quadrilateral G then the value of i is 36.

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Answer:

answer down below

Step-by-step explanation:

Answer:

Step-by-step explanation:

Draw the 2 lines of the equations on graph paper.

The coordinates of the point where they cross is the solution

The answer is (5/2, 4/3)

Answer:

C. (5/2, 4/3)

Step-by-step explanation:

The system of equations that are given are:

To solve, let's use the substitution method.

See Below:

So solving by substitution:

// Solve equation [2] for the variable  x

// Plug this in for variable  x  in equation [1]

// Solve equation [1] for the variable  y

// By now we know this much :

// Use the  y  value to solve for  x

Therefore, the solution is:

[tex]{x,y} =\frac{101}{42} ,\frac{19}{14}[/tex]

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[tex]cos^{-1}[cos(\omega)]\implies \omega \\\\[-0.35em] ~\dotfill\\\\ cos\left( -\frac{\pi }{6} \right)\implies \stackrel{symmetry~identity}{cos\left( \frac{\pi }{6} \right)} \\\\\\ cos^{-1}\left[ cos\left( -\frac{\pi }{6} \right) \right]\implies cos^{-1}\left[ cos\left( \frac{\pi }{6} \right) \right]\implies \cfrac{\pi }{6}[/tex]

why did we use the positive version of π/6?

well, the inverse cosine function has a range of [0 , π], and -π/6 is on the IV Quadrant, out of the range for it, however it has a twin due to symmetry on the I Quadrant, that is π/6, thus the reason.

The angle in the interval (0, pi) whose cosine value is √3 / 2 is π/6 radians.

Cosine of an angle is defined as the ratio of the adjacent side to the hypotenuse of a right angled triangle.

We have to find the angle in the interval (0, π) such that the cosine of the angle is √3 / 2.

We know that, ratio of sides of 30-60-90 triangle is 1 : √3 : 2.

Hypotenuse = 2x

Adjacent side to 30° = √3 x

Cos (30°) = Adjacent side / Hypotenuse

               = √3 x / 2x

               = √3 / 2

30 degrees is equivalent to 30 × (π/180) = π/6 in radians

Hence π/6 is the angle in the interval (0, π) whose cosine value is √3 / 2.

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The true statement about the two functions is:

"Both f(x) and g(x) increase on the interval of (–4 , ∞)."

Here we have the functions:

f(x) = log₂(4x)

g(x) = 4x - 3

That can be seen in the graph at the end. In the graph the green one is the logarithmic function.

As you can see there, both of these have similar ranges that go from (-∞, ∞) and both are increasing functions.

Then the correct statement is:

Both f(x) and g(x) increase on the interval of (–4 , ∞).

Where f(x) is actually increasing on all it's domain which is  (-∞, ∞), so the statement is true.

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Answer:

Both f(x) and g(x) have a common domain on the interval (0, ∞).

Step-by-step explanation:

The person explained it perfectly in this link shown below

https://brainly.com/question/28219401?referrer=searchResults

pls give me brainist for finding the answer

Also, the answer to the question

"What type of function is f(x) = 2x^3 – 4x^2 + 5?"

A) Exponential

B) Logarithmic

C) Polynomial

D) Radical

The answer is C) Polynomial

Explanation:

The exponential equation would look like this: f(x) = 2^x

with x for the exponent

The logarithmic equation would look like this: f(x) = log2 + 4

with log in the equation

The radical equation would look like this: f(x) = x^2 + 4x -1

                                                                              3x^2 -9x +2

With divide by something