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multiply

Answer:

K = 43

Step-by-step explanation:

We'll begin by determining the gradient of the equation 5y + 4x = 8. This can be obtained as follow:

5y + 4x = 8

Rearrange

5y = 8 – 4x

5y = –4x + 8

Comparing 5y = –4x + 8 with y = mx + c, the gradient m is –4

Next, we shall determine the gradient of the line perpendicular to the line with equation 5y = 8 – 4x.

This can be obtained as follow:

For perpendicular lines, their gradient is given by:

m1 × m2 = – 1

With the above formula, we can obtain the gradient of the line as follow:

m1 × m2 = – 1

m1 = –4

–4 × m2 = – 1

Divide both side by –4

m2 = –1/–4

m2 = 1/4

Finally, we shall determine the value of k as follow:

Coordinate => (k, 4) and (3, –6)

x1 coordinate = k

y1 coordinate = 4

x2 coordinate = 3

y2 coordinate = –6

Gradient (m) = 1/4

m = (y2 – y1) / (x2 – x1)

1/4 = (–6 – 4) / (3 – K)

1/4 = –10 /(3 – K)

Cross multiply

3 – K = 4 × –10

3 – K = –40

Collect like terms

– K = – 40 –3

–k = –43

Divide both side by – 1

K = –43/–1

k = 43

Answer:

meters must be converted into millimeters.

Step-by-step explanation:

the Answear is B,D,A,C

Answer:

eEEE

Step-by-step explanation:

Answer:

answer d 2/6

which is 1/3 =0.333333333

Answer:

2/6

Step-by-step explanation:

Answer:

The correlation coefficient  is r = 0.52

Step-by-step explanation:

From the question we are told that

            The correlation coefficient  is r = 0.52

 Generally correlation has no unit and is not affected by unit (i.e it show the ratio between two quantities )

Hence a change of the unit of measurement of  length from cm to mm will not affect the correlation coefficient r hence the value will still remain  r = 0.52

Answer:

Step-by-step explanation:

Answer:

623

Step-by-step explanation:

2486/4 is the middle number = 621.5

Four numbers so the nearest whole numbers are the middle two

620, 621, 622, 623

=623

Answer:

Average Rate = 55mph

Step-by-step explanation:

Now it’s time to tackle the original question. Going from point A to point B, the cheetah traveled at an average rate of 70 mph. Returning to point A, the cheetah traveled at an average rate of 40 mph.

Can we say that this cheetah’s average rate was 55 mph?

a.The average rate for the trip is equal to the total distance traveled divided by the total time traveled.

Average Rate = 70+ 40/2= 110/2 = 55mph

Yes the average rate of the cheetah is 55 mph

The following equations represent the distance traveled on each leg of the trip.

First leg of trip: td=r1 t1= 70*t

Second leg of trip: td=r2 t2= 40*t

Write an equation for the average rate for the trip. Remember, the cheetah runs from point A to point B and back to point A.

Total distance = r1 t1+ r2 t2

Average rate = Total distance / total time

                        =  r1 t1+ r2 t2/ t1+ t2

                        =70t+ 40t/ 2t

                         =110t/2t

                          = 55mph

Answer:

the answer is 55 mph

Step-by-step explanation:

Average rate = Total distance / total time

                       =  r1 t1+ r2 t2/ t1+ t2

                       =70t+ 40t/ 2t

                        =110t/2t

Step-by-step explanation:

A.

Cost of 4 lots for $48,000= 48000*4

=$192,000

Sales made from all 7 lots = 33000*7

= $213,000

Profit =213,000-192,000

Profit =$39,000

Percent profit =(39000/192000) *100

=0.20*100

=20%

B.

Total interest formula=

Principal Loan Amount x Interest Rate x Time

Interest =30000x0.12x5

Interest = $18,000

Monthly payments for 5 years

= 18000/12*5

=18000/60

=$300

Answer:

0.303 or 30.3%

Step-by-step explanation:

We are given;

Variance; Var = 49

Sample size; n = 145

Standard error from mean; SEM = 0.6

Now, standard deviation is given by the formula;

SD = √Var

SD = √49

SD = 7

Now, the standard error from standard deviation is;

SE = SD/√n

SE = 7/√145

SE = 0.5813

z = Number of standard errors away from the mean = SEM/SE = 0.6/0.5813 = 1.0322

Using online P-value from z-score calculator with the z-score above and an assumed significance level of 0.05, we have;

P-value ≈ 0.303

Probability = 0.303 or 30.3%

Answer:

Step-by-step explanation:

let n(U) be the total number of school employees = 800

Let n(I) be amount of instructors = 430

Let (F) be full-time faculty = 589

Let n(InF) be the instructors who were full-time faculty = 340

The number of employees who were full-time faculty but were not instructors is expressed as:

n(FnI') = n(F) - n(InF)

n(FnI') = 589 - 340

n(FnI') = 249

Hence the number of school employees who were full-time faculty but were not instructors are 249

Answer:

Question 2: A

Question 3: 3x=3x+0

Step-by-step explanation:

For the chart use (symbolab)  it is a site that can help you with finding out the solutions by typing in the equation and it will give you an answer if it is no solution, one solution or, infinite

Answer: x=13

Step-by-step explanation:

Answer:

It would be the first one (y-2=1/3(x-2))

Step-by-step explanation:

The first one is the same function as y=x(1/3)+(1+1/3) which is the same function as the photo.

Answer:

wym

Step-by-step explanation:

whats the question

Answer:

cool 100

Step-by-step explanation:

just add them all together since its saying that she got change back and it's saying what she paid.

Step-by-step explanation:

−2x+5y=−15 and 5x+2y=−6

Rewrite equations:

−2x+5y=−15;5x+2y=−6

Step: Solve−2x+5y=−15for x:

−2x+5y=−15

−2x+5y+−5y=−15+−5y(Add -5y to both sides)

−2x=−5y−15

−2x−2=−5y−15−2(Divide both sides by -2)

x=52y+152

Step: Substitute52y+152forxin5x+2y=−6:

5x+2y=−6

5(52y+152)+2y=−6

292y+752=−6(Simplify both sides of the equation)

292y+752+−752=−6+−752(Add (-75)/2 to both sides)

292y=−872

292y292=−872292(Divide both sides by 29/2)

y=−3

Step: Substitute−3foryinx=52y+152:

x=52y+152

x=52(−3)+152

x=0(Simplify both sides of the equation)

Answer:

x=0 and y=−3

Answer:

(-6,3)

Step-by-step explanation:

Answer:

Its 9

Step-b(y-step explanation:

Can you make me brainlist??

Answer:

The answer is B just took the test!

Answer:

C. f(x)=2sin(-1.5x+0.5)-2

First, note that 100 m = 0.100 km.

Recall that

v² - u² = 2 a ∆x

where u and v are initial and final velocities; a is acceleration; and ∆x is displacement. Solve for a :

(72 km/h)² - (108 km/h)² = 2 a (0.100 km)

a = ((72 km/h)² - (108 km/h)²) / (0.200 km)

a = -32,400 km/h²

If you want to convert this to m/s², we have

(-32,400 km/h²) = (-32,400 km/h²) (1000 m/km) (1/3600 h/s)²

(-32,400 km/h²) = -2.50 m/s²

Answer:

134.3%

Step-by-step explanation:

Working out a percentage increase or decrease between the two numbers is pretty simple. The resulting number (the second input) is 750 and what we need to do first is subtract the old number, 320, from it:

750 - 320 = 430

Once we've done that we need to divide the result, 430, by the original number, 320. We do this because we need to compare the difference between the new number and the original:

430/320 = 1.343

We now have our answer in decimal format. How do we get this into percentage format? Multiply 2.3 by 100? Ding ding ding! We have a winner:

1.343 x 100 =  134.3%

Answer:

2

Step-by-step explanation:

I can't exactly explain my thinking but I estimates and the closet i got was answer 2 hoped this helped

Answer:

4 5/8 inches left

Step-by-step explanation:

1+4=5

2/8+3/8=5/8  Same denominator so it stays the same, only need to add the numerators.

5+5/8=5 5/8

5 5/8-1=4 5/8

Here is the improper fraction if you need it:

37/8

Answer:

greater than

Step-by-step explanation:

1.994 is closer to 2 than 1.493 so it is greater!

Answer:

73

Step-by-step explanation:

simple math, ez mne.

Answer:

73 days were sunny

Step-by-step explanation:

20% of 365 is 73.

Answer:

The area of the entire rectangle is [tex]20x^2-10x-30[/tex]

Step-by-step explanation:

Area of a Rectangle

The area of a rectangle of height H and width W is:

A=H.W

The rectangle has a height of H=5 and a width of [tex]W=4x^2-2x-6[/tex]. Calculate the area:

[tex]A=5*(4x^2-2x-6)[/tex]

Expand the product:

[tex]A=20x^2-10x-30[/tex]

The area of the entire rectangle is [tex]20x^2-10x-30[/tex]

Answer:

a

 The 95% confidence bounds is  [tex] 145.80 <  \mu <   158.19 [/tex]

b

It was not necessary to make any assumption about the shape of the travel  time distribution

Step-by-step explanation:

From the question we are told that

 The sample size is  n =  30  

  The sample mean  is  [tex]\=x = 152[/tex]

   The standard deviation is  [tex]\sigma = 17.3 \ second[/tex]

From the question we are told the confidence level is  95% , hence the level of significance is    

      [tex]\alpha = (100 - 95 ) \%[/tex]

=>   [tex]\alpha = 0.05[/tex]

Generally from the normal distribution table the critical value  of  [tex]\frac{\alpha }{2}[/tex] is  

   [tex]Z_{\frac{\alpha }{2} } =  1.96[/tex]

Generally the margin of error is mathematically represented as  

      [tex]E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }[/tex]

=>    [tex]E =  1.96 *  \frac{17.3 }{\sqrt{30} }[/tex]

=>     [tex]E = 6.19  [/tex]  

Generally 95% confidence bounds  is mathematically represented as  

      [tex]\= x -E <  \mu <  \=x  +E[/tex]

=>  [tex]152  -6.19 <  \mu <  152  -6.19[/tex]

=> [tex] 145.80 <  \mu <   158.19 [/tex]

This 95% confidence bounds show that there is 95% confidence that the true mean lies within this bound hence there is it was not necessary to make any assumption about the shape of the travel  time distribution