Please help! Will give brainliest

Please Help! Will Give Brainliest

Answers

Answer 1

Answer:

Letter C is the answer Hope it helps!


Related Questions

How could a solid result from the mixing of two liquids?

Answers

Answer:

Combining the two clear colorless liquids is a chemical change because a different solid substance is formed. Tell students that a precipitate is an insoluble solid that forms when two solutions are combined and react chemically. Insoluble means that the solid will not dissolve.

Explanation:

do you think hunter-gatherers are still around today? what makes you think that?​

Answers

Answer:

yes

Explanation:

some cultures in Tanzania are still follow the old ways

Why is the law of conservation of mass law and not a theory?

Answers

Answer:

In physics and chemistry, the law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as the system's mass cannot change, so quantity can neither be added nor be removed.

Explanation:

That is what I think on the subject

A law is more specific, such as this particular description of matter, whereas a theory can be more general and often includes more of a why. Atomic Theory explains why the law of conservation of matter exists; in chemical reactions, atoms simply rearrange and have the same mass before and after.

What is a theory?

A theory is a well-thought-out elaboration for natural-world anecdotes that has been built using the methodological approach and incorporates many facts and hypotheses.

A scientific law, in overall, is a description of an observed phenomenon. It does not explain why or what causes the phenomenon.

A scientific theory is an explanation for a concept. It is a common misconception that with enough research, theories can become laws.

A law is more precise, such as this detailed definition of matter, whereas a theory is more general and frequently includes more of a why.

Atomic Theory explains why the law of conservation of matter exists; atoms simply rearrange and have the same mass before and after chemical reactions.

Thus, that's why, the law of conservation of mass law and not a theory.

For more details regarding law of conservation of mass, visit:

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In the reaction, 2H2(g) + O2(g)
which the reactants appear is:
2H2O(1), the phase of matter in
a) solid.
b) liquid.
c) gas.
d) plasma.

Answers

Answer:

b liquid

Explanation:

2H

2

(g)+O

2

(g)⟶2H

2

O(l) is the correction reaction as during formation of water both hydrogen and oxygen are in gaseous form and produces water in liquid form.

If it takes 75.0 mL of 1.5 M HNO3 solution to completely neutralize 125 mL of Ca(OH)2, what is the concentration of the Ca(OH)2 solution?

Answers

Answer:

0.45 M

Explanation:

The reaction that takes place is:

2HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + 2H₂O

First we calculate how many HNO₃ moles reacted, using the given concentration and volume:

75.0 mL * 1.5 M = 112.5 mmol HNO₃

Then we convert HNO₃ moles into Ca(OH)₂ moles, using the stoichiometric coefficients:

112.5 mmol HNO₃ * [tex]\frac{1mmolCa(OH)_2}{2mmolHNO_3}[/tex] = 56.25 mmol Ca(OH)₂

Finally we calculate the concentration of the Ca(OH)₂ solution:

56.25 mmol Ca(OH)₂ / 125 mL = 0.45 M

PLEASE HELP! How does one determine how much of a molecule is produced in a reaction?
A. The mass of the products is determined by adding the mass of the
reactants.
B. Oxidation states are used to calculate the number of product
molecules.
C. The coefficients and molar masses are used to calculate amounts
of molecules.
D. The molar masses of the molecules tell how many grams of
product will form.

Answers

I believe the answer is C !

If 85.6 grams of water are produced by the reaction then how many grams of calcium hydroxide did you start with?

Answers

Answer:

I think it would double it's self

50 POINTS!! PLZ HELP! SCIENCE QUESTION!

Answers

Answer:

C im pretty sure

Explanation:

Because it is facing the opposite direction with opposite colors.

100% C. Hope this helped:)

If a ball rolling down a hill is half way between the top and bottom, how much potential energy does the ball have compared to kinetic energy?

Answers

Answer:

The gravitational potential energy and kinetic energy of this ball should be equal (assuming that there is no energy loss due to friction.)

Explanation:

The ball loses gravitational potential energy as it rolls down the hill. At the same time, the speed of the ball increases, such that the ball gains kinetic energy.

If there is no friction on this ball (and that the ball did not deshape,) all the gravitational potential energy that this ball lost would be converted to kinetic energy.

If the gravitational field strength [tex]g[/tex] is constant throughout, the gravitational potential energy of an object in that gravitational field would be proportional to its height.

If [tex]m[/tex] denote the mass of this ball, the gravitational potential energy ([tex]\rm GPE[/tex]) of this ball at height [tex]h[/tex] would be [tex]{\rm GPE} = (m \cdot g) \cdot h[/tex], which is proportional to [tex]h\![/tex].

The value of [tex]g[/tex] near the surface of the earth is indeed approximately constant (typically [tex]g \approx 9.8\; \rm m \cdot s^{-2}[/tex].)

At halfway between the top and bottom of this hill, the height of this ball would be [tex](1/2)[/tex] of its initial value (the value when the ball was at the top of the hill.) Because the [tex]\rm GPE[/tex] of this ball is proportional to its height, at halfway down the hill, the [tex]\rm GPE\![/tex] of this ball would also be [tex](1/2)\![/tex] its initial value.

However, if there was no friction on this ball (and that the ball did not deshape,) that [tex](1/2)[/tex] of the initial [tex]\rm GPE\![/tex] of this ball was not lost. Rather, these [tex](1/2)\![/tex] of the initial [tex]\rm GPE[/tex] would have been converted to the kinetic energy ([tex]\rm KE[/tex]) of this ball.

Hence, when the ball is halfway down the hill:

[tex]\displaystyle \text{GPE halfway down the hill} = \frac{1}{2}\, \text{Initial GPE}[/tex].

[tex]\begin{aligned}& \text{KE halfway down the hill}\\ &= \text{Initial GPE} - \text{GPE halfway down the hill}\\ &= \text{Initial GPE} - \frac{1}{2}\, \text{initial GPE}\\ &= \frac{1}{2}\, \text{Initial GPE}\end{aligned}[/tex].

Therefore:

[tex]\begin{aligned}& \text{GPE halfway down the hill} \\ &= \frac{1}{2}\, \text{Initial GPE} \\ &= \text{KE halfway down the hill}\end{aligned}[/tex].

In other words, under these assumptions, when this ball is halfway down the hill, the gravitational potential energy and the kinetic energy of this ball would be equal.

You add 0.300 moles of an acid to enough water to get a total of 0.500 liters of solution. Your molar concentration is?

Answers

.3/.5 is .6 M. Hope that helped.

What is the molarity of a solution that contains 2.14 moles (CH3)2SO in 2.00 L solution?

Answers

Answer:

1.07 M

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Molarity = moles of solute / liters of solutionExplanation:

Step 1: Define

[Given] 2.14 moles (CH₃)₂SO

[Given] 2.00 L

[Solve] Molarity

Step 2: Solve

Substitute in variables [Molarity]:                                                                    x M = 2.14 moles (CH₃)₂SO / 2.00 L solution[Molarity] Divide:                                                                                               x = 1.07 M

Formula for diphosphorus decoxide ? And explain

Answers

Answer:

It can be represented using the chemical formula P 20 5.It has a molecular weight of 141.945 grams per mole and its density is about 2.39 G/cm 3.It can also be termed as Diphosphorus Pentoxide, Phosphorus(V) Oxide,

Phosphoric Anhydride, Tetraphosphorus Decaoxide, Tetraphosphorus Decoxide.

is Pb --> PbSO4 reduction half reaction?​

Answers

Answer:

No its is the oxidation half

Explanation:

Because Pb lost [tex]2e^{-}[/tex]

and oxidation is losing, I abbreviate it in (OIL) not oil that used in kitchen

OIL=Oxidation Is Losing electrons

How much Oxygen would be required to react with 101 g of Methane?
A.101 g
B.202 g
C.303 g
D.404 g

Answers

Answer:

404g

Explanation:

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