Please help me with this

Please Help Me With This

Answers

Answer 1

Answer:

7 Newton's East

Explanation:

when the force is going in the same direction in this case east, you add the forces.


Related Questions

If the only force exerted on a star far from the center of the Galaxy (r = 7.40 ✕ 1020 m) is the gravitational force exerted by the ordinary matter (Mord = 1.90 ✕ 1041 kg), find the speed of the star. Assume a circular orbit and assume all the Galaxy's matter is concentrated at the center.

Answers

Answer:

The value is  [tex]v = 1.309*10^{5}\ m/s[/tex]

Explanation:

The radius is [tex]r = 7.40 *10^{20} \  m[/tex]

The mass of the ordinary matter is [tex]M_{rod} =  1.90 *10^{41}\  kg[/tex]

Generally the speed of the star is mathematically represented as

         [tex]v = \sqrt{\frac{G * M}{r} }[/tex]

Here G is the gravitational constant with a value

        [tex]G = 6.67384 * 10^{-11}[/tex]

So

      [tex]v = \sqrt{\frac{6.67384 * 10^{-11} * 1.90 *10^{41}}{7.40 *10^{20}} }[/tex]

=>    [tex]v = 1.309*10^{5}\ m/s[/tex]

un avión aterriza en la superficie de un portaaviones a 50 m/s y se detiene por completo en 120 metros, ¿cuál es la aceleración necesaria para detenerlo?

Answers

Answer:

La aceleración necesaria para detener el avión es - 10.42 m/s².

Explanation:

Un movimiento uniformemente acelerado (M.U.A) es aquél cuya aceleración es constante y la velocidad de un objeto cambia a medida que el movimiento evoluciona.

Siendo la aceleración "a" el cambio de velocidad al tiempo transcurrido en un punto A a B, la velocidad inicial la velocidad que tiene un cuerpo al iniciar su movimiento en un período de tiempo y la velocidad final la velocidad que tiene un cuerpo al finalizar su movimiento en un período de tiempo, entonces en  M.U.A se cumple:

Vf² - Vo² = 2*a*d

donde:

Vf: Velocidad final Vo: Velocidad inicial a: Aceleración d: Distancia recorrida

En este  caso:

Vf: 0 m/s, porque el avión se detieneVo: 50 m/sa: ?d: 120 m

Reemplazando:

(0 m/s)² - (50 m/s)² = 2*a*120 m

Resolviendo:

[tex]a=\frac{(0 m/s)^{2} -(50 m/s)^{2} }{2*120 m}[/tex]

a= - 10.42 m/s²

La aceleración necesaria para detener el avión es - 10.42 m/s².

A beam of protons is directed in a straight line along the positive zz ‑direction through a region of space in which there are crossed electric and magnetic fields. If the electric field magnitude is E=450E=450 V/m in the negative yy ‑direction and the protons move at a constant speed of v=7.9×105v=7.9×105 m/s, what must the direction and magnitude of the magnetic field be in order for the beam of protons to continue undeflected along its straight-line trajectory? Select the direction of the magnetic field BB .

Answers

Answer:

The magnitude is [tex]B = \frac{450}{7.9* 10^5}[/tex]

The direction is  the positive x axis

Explanation:

From the question we are told that

   The  electric field is  E = 450 V/m in the negative y ‑direction

   The speed of the proton is  [tex]v= 7.9* 10^5\  m/s[/tex] in the positive z direction

Generally the overall force acting on  the proton is mathematical represented as

              [tex]F_E =  q(\vec E + \vec v  * \vec B)[/tex]

Now for the beam of protons to continue un-deflected along its straight-line trajectory then  [tex]F_E =0[/tex]

So

          [tex] 0  =  q( E (-y) + v(z)  * \vec B)[/tex]

=>      [tex]E\^y = v \^ z  * \vec B[/tex]

Generally from unit vector cross product vector multiplication

         [tex]\^ z  \ *  \  \^ x  =  \^  y[/tex]

So the direction of  B (magnetic field must be in the positive x -axis )

So

       [tex]E\^y = v \^ z  *  B\^ x [/tex]

=>     [tex]E\^y = vB ( \^ z  *  \^ x) [/tex]

=>     [tex]E\^y = vB ( \^y) [/tex]        

=>      [tex]E = vB [/tex]  

=>      [tex]B = \frac{450}{7.9* 10^5}[/tex]

=>      [tex]B =  0.0005696 \ T [/tex]  

   

   

If 2000 kg cannon fires 2 kg projectile having muzzle velocity 200 m/s then the KINETIC ENERGY of the projectile will be ("E4" means "*10^4") *
1 point
4E4 J
1E4 J
1E3 J
None of the above

Answers

Answer:

[tex]K=4\times 10^4\ J[/tex]

Explanation:

Given that,

Mass of cannon is,M =  2000 kg

Mass of projectile, m = 2 kg

Velocity of the projectile, v = 200 m/s

We need to find the kinetic energy of the projectile. We know that the formula for the kinetic energy of an object is given by :

[tex]K=\dfrac{1}{2}mv^2\\\\\text{Putting all the values, we get}\\\\K=\dfrac{1}{2}\times 2\times (200)^2\\\\K=40000\ J[/tex]

or

[tex]K=4\times 10^4\ J[/tex]

So, the kinetic energy of the projectile will be [tex]4\times 10^4\ J[/tex].

If a projectile hits a stationary target, and the projectile continues to travel in the same direction, the mass of the projectile is less than the mass of the target. the mass of the projectile is equal to the mass of the target. the mass of the projectile is greater than the mass of the target. nothing can be said about the masses of the projectile and target without further information. this is an unphysical situation and will not actually happen.

Answers

The correct arrangement of the question is;

If a projectile hits a stationary target, and the projectile continues to travel in the same direction,

A) the mass of the projectile is less than the mass of the target.

B) the mass of the projectile is equal to the mass of the target.

C) the mass of the projectile is greater than the mass of the target.

D) nothing can be said about the masses of the projectile and target without further information.

E) this is an unphysical situation and will not actually happen.

Answer:

Option C: The mass of the projectile is greater than the mass of the target.

Explanation:

We want to find what will happen when a projectile continues in motion after it hits a target.

Now, for the projectile to keep moving in that direction after it hits the target, it means it had a force bigger than the force of the target to overpower it and force it to move with it.

Now, from law of inertia, Force = ma.

But in this case acceleration is 0 because the speed of the projectile is constant.

Thus, the force depends on the mass. So for a higher force, the mass of the projectile has to be more than that of the stationary object.

Thus, option C is correct

A current of 1.0 A from a 1.0 mm diameter wire enters a sphere which is 1.0 m in radius and exits through a 1.0 mm diameter wire on the opposite side of the sphere. What is the smallest value of current density in the sphere?

Answers

Answer:

The current density in the sphere is 0.32 A/m²

Explanation:

Given that,

Current = 1.0 A

Diameter = 1.0 mm

Radius of sphere = 1.0 m

We need to calculate the current density in the sphere

Using formula of current density

[tex]J=\dfrac{I}{A}[/tex]

Where, I = total current

A = area of sphere

Put the value into the formula

[tex]J=\dfrac{1.0}{\pi\times(1.0)^2}[/tex]

[tex]J=0.32\ A/m^2[/tex]

Hence, The current density in the sphere is 0.32 A/m²

Similar to Hippocrates, modern scientists who study etiology believe that
sickness is caused by spiritual events such as demons entering the body.
diseases come from natural causes such as bites from infected insects.
all diseases can be cured by the right combinations of different treatments.
the best treatment for a germ is a calming practice such as yoga or massage.

Answers

In  Medicine, "etiology" means the origin or cause of a disease.

Similar to Hippocrates, modern scientists who study etiology believe that   diseases come from natural causes such as bites from infected insects.

Answer:diseases come from natural causes such as bites from infected insects

Explanation: just took test

Consider the system consisting of two pendulums coupled by a spring. Write the equations of motion in matrix form. Use small angle approximation.

Answers

Answer:

hello your question is incomplete attached below is the complete question

and solution to the question

Explanation:

To write The equation of the motion in Matrix form

i)First we write the net torque equation for left mass

ii)Next we write the net torque equation for right mass

iii) represent the equation of motion in Matrix form

Astronomers have proposed the existence of a ninth planet in the distant solar system. Its semi-major axis is suggested to be approximately 600 AU. If this prediction is correct, what is its orbital period in years

Answers

Answer:

T = 1.4696 10⁴ years

Explanation:

For this exercise we must use Kepler's laws, specifically the third law which is the application of the universal law of gravitation to Newton's second law

               F = ma

               G m M / r² = m a_c = m v² / r

                G M / r = v²

the speed of the circular orbit is

               v = 2π r / T

           

we substitute

               G M / r = 4π² r² / T²

               T² = (4π² / G M)  r³

Kepler proved that this expression is the same if the radius is changed by the semi-major axis of an ellipse

               T² = (4π² /GM)  a³

the constant is worth

                (4π² / GM) = 2.97 10⁻¹⁹    s² / m³

let's reduce the distance to SI units

AU is the distance from the Earth to the Sun

               a = 600 AU = 600 AU (1.496 10¹¹ m / 1 AU)

               a = 8.976 10¹³ m

               T² = 2.97 10⁻¹⁹ (8.976 10¹³)³

               T² = 21.4786 10²²

               T = 4.63 10¹¹ s

Let's reduce to years

               T = 4.63 10¹¹s (1 h / 3600s) (1 day / 24 h) (1 year / 365 days)

               T = 1.4696 10⁴ years

what is a proper way and a safe way to dispose batteries

Answers

Answer:

throw them away............

You need to throw them away

PLEASE HELP 25 POINTS WHAT IS THE ANSWER

Answers

The answer is letter C vro

thanks me.later

An FM radio station, 20 miles away, broadcast at a 93.4 MHz frequency(a) What is the wavelength of the radio wave associated with this signal ?(b) How long does it take for the signal to reach your radio from the station ?

Answers

Answer:

(a) Wavelength = 3.21 m (b) Time = [tex]1.07\times 10^{-4}\ s[/tex]

Explanation:

Given that,

The frequency of FM radio station, f = 93.4 MHz

(a) We need to find the wavelength of the radio wave associated with this signal. The relation between wavelength and frequency is given by :

[tex]c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{93.4\times 10^6}\\\\\lambda=3.21\ m[/tex]

(b) It is given that, an FM radio station, 20 miles away. Let t is time taken for signal to reach your radio from the station. So,

[tex]t=\dfrac{d}{c}\\\\t=\dfrac{20\times 1609.34}{3\times 10^8}\\\\t=1.07\times 10^{-4}\ s[/tex]

Hence, this is the required solution.

The sun produces energy via nuclear fusion at the rate of 4×1026 J/s . Based on the proposed overall fusion equation, how long will the sun shine in years before it exhausts its hydrogen fuel? (Assume that there are 365 days in the average year.)

Answers

Answer:

2 x 10^10 years.

Explanation:

Given that the sun produces energy via nuclear fusion at the rate of 4×1026 J/s . Based on the proposed overall fusion equation, how long will the sun shine in years before it exhausts its hydrogen fuel? (Assume that there are 365 days in the average year.)

Let us first calculate energy from hydrogen gas.

4(1.007825) + 2(0.00549) - 4.002603 = 0.029795 amu

Since 4.0313 amu H+ > 0.029795 amu =  ratio of 1 to 0.00739

dE = ((2*10^30 kg) x 0.8 x 0.25)(3.00x10^8 m/s)^2 = 3.6x10^46 kg x m^2/s^2  

3.6x10^46 kg x m^2/s^2 x 0.00739 = 2.6604 x 60^44 kg x m^2/s^2

4x10^26 J/s x s = 2.6604x10^44 kg x m^2/s^2  solve for s.

s = 6.651x10^17 seconds

6.651x10^17 seconds x 1 min/60 s x 1 hr/ 60 min x 1 day/ 24 hr x 1 yr / 365 days = 2.1x10^10 years

 Based on the proposed overall fusion equation, it will therefore take the sun shine 2 x 10^10 years before it exhausts its hydrogen fuel.

A tennis ball is dropped from the top of a tall building. a second tennis ball is thrown down from the same building make a statement about the acceleration of each tennis ball.

A) The first ball falls with a greater acceleration

B) The second ball falls with a greater acceleration.

C) they both are with the same acceleration because they started from the same height.

D) they both are the same acceleration because they are in free fall.

E) more information is required

Answers

The two balls have the same acceleration because they are in free fall.

The two balls projected downwards from the top of the build are influenced by gravity. Both ball experience free fall due to gravity.

The equation of motion of the two ball is given as;

v² = u² + 2gh

where;

v is the final velocity of each ballu is the initial velocity of each ballh is the distance traveled by each ballg is acceleration due to gravity = 9.8 m/s²

Thus, we can conclude that the two balls have the same acceleration because they are in free fall.

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A force of 40 N is applied tangentially to the rim of a solid disk of radius 0.10 m. The disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 145 rad/s2. Determine the mass of the disk.

Answers

Answer:

 m = 2,759 kg

Explanation:

For this exercise we use the torque relationship

           τ = I α

         

the moment is

          τ= F r sin θ

since the force is tangential to the ring, the angle is 90º sin 90 = 1

          τ = F r

the moment of inertia of a ring is given by

         I = m r²

let's substitute

           F r = m r²α

            m = F / r α

let's calculate

          m = 40 / (0.10 145)

          m = 2,759 kg

A 1200-kg car pushes a 2100-kg truck that has a dead battery to the right. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4500 N. Which, if any, of the following gives a correct acceleration constraint for this problem? The variable ac is the acceleration of the car, and the variable t is the acceleration of the truck.

a. ac=at
b. ac=−at
c. ac=21001200at
d. ac=12002100at
e. There are no acceleration constraints for this problem.

Answers

Answer:

Option A: a_c = a_t

Explanation:

Let's denote the force acting on the car due to the truck as F_ct

Similarly, the force acting on the truck due to the car is denoted as F_tc.

Now, F_ct = m_c × a_c

Where;

m_c is mass of car

a_c is acceleration of car

Also, F_tc = m_t × a_t

Where;

m_c is mass of truck

a_c is acceleration of truck

Now, since the car is the one pushing the truck, from Newton's laws, we can say that they stick together and move in the same direction at the same acceleration.

Thus, the truck will move with an acceleration equal to that of the car pushing it.

Thus; a_c = a_t

A negative charge -Q is placed inside the cavity of a hollow metal solid. The outside of the solid is grounded by connecting a conducting wire between it and the earth. Is any excess charge induced on the inner surface of the metal? Is there any excess charge on the outside surface of the metal? Why or why not? Would someone outside the solid measure an electric field due to the charge -Q? Is it reasonable to say that the grounded conductor has shielded the region outside the conductor from the effects of the charge -Q? In principle, could the same thing be done for gravity? Why or why not?

Answers

Answer:

a)  + Q charge is inducce that compensates for the internal charge

b) There is no excess charge on the external face q_net = 0

c) E=0

Explanation:

Let's analyze the situation when a negative charge is placed inside the cavity, it repels the other negative charges, leaving the necessary positive charges to compensate for the -Q charge. The electrons that migrated to the outer part of the sphere, as it is connected to the ground, can pass to the earth and remain on the planet; therefore on the outside of the sphere the net charge remains zero.

With this analysis we can answer the specific questions

a)  + Q charge is inducce that compensates for the internal charge

b) There is no excess charge on the external face q_net = 0

c) If we create a Gaussian surface on the outside of the sphere the net charge on the inside of this sphere is zero, therefore there is no electric field, on the outside

d) If it is very reasonable and this system configuration is called a Faraday Cage

e) We cannot apply this principle to gravity since there are no particles that repel, in all cases the attractive forces.

1pt During a phase change, as energy is added, the temperature of a substance
O A. increases
O B. is constant
O C. decreases
O D. first increases and then decreases to its original value

Answers

Answer:

D

Explanation:

Because first phase thr it will follow the law of thermodynamics as it will reach the equilibrium point then decrrases afterwards

Which formula describes Boyle's law?
ОА.
OB.
D = m/v
V1T2 = V2T
P1V1 = P2V2
P1T2 = P2T1
Ос.
OD

Answers

Answer: P1V1 = P2V2

Explanation:

A cannon ball is shot horizontally off a 37.0 m cliff and lands a distance of 18.5 m
from the base of the cliff. Whall was the initial horizontal velocity of the cannon ball?

Answers

Answer:

vₓ = 6.73 m/s

Explanation:

Assuming no other external influences than gravity, in the horizontal direction (which we make to coincide with the x- axis) , speed is constant, so, applying the definition of average velocity, we can write the following equation:

       [tex]v_{x} = \frac{\Delta x}{\Delta t} (1)[/tex]

Now, in the vertical direction (coincident with the y- axis) , as both movements are independent each other, initial velocity is zero, so we can write the following equation for the vertical displacement:

       [tex]\Delta h = \frac{1}{2} * g * t^{2} (2)[/tex]

where Δh = -37.0 m , g = -9.8 m/s2Solving (2) for t, we get:

       [tex]t = \sqrt{\frac{2*\Delta h}{g} } =\sqrt{\frac{2*37.0m}{9.8m/s2}} = 2.75 s (3)[/tex]    

Taking t₀ = 0, ⇒ Δt = tReplacing (3) in (1), we get:

       [tex]v_{x} = \frac{\Delta x}{\Delta t} = \frac{x}{t} = \frac{18.5m}{2.75s} = 6.73 m/s[/tex]

As the horizontal velocity is constant, the initial horizontal velocity is just the average one, i.e., 6.73 m/s.

Complete each statement by dragging the forms of energy into their appropriate boxes.
wind turbine
roller coaster going downhill
toaster
car
A
converts electrical energy into thermal energy.
A
converts rotational energy into electrical energy.
A
converts gravitational energy into mechanical energy.
A
converts rotational energy into mechanical energy.

Answers

Statements 1,2,3 and 4 match statements B, C, A, and D respectively.A wind turbine converts rotational energy into electrical energy.

What is the law of conservation of energy?

According to the Law of conservation of energy. Energy can not be created nor be destroyed, it can transfer from one to another form.

1.A wind turbine converts rotational energy into electrical energy.

2.A roller coaster going downhill converts gravitational energy into mechanical energy

3. Toaster converts electrical energy into thermal energy

4.A car converts rotational energy into mechanical energy.

Hence,statements 1,2,3 and 4 match statements B, C, A, and D respectively.

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1.
Which of these is a relative adverb?

where

lovely

who

Answers

Who is the right answer

Answer:

Where

Explanation:

1 identify two ways (factors) you can change in order to the charge the objects experience

Answers

Answer:

Follows are the solution to this question:

Explanation:

Please find the correct question in the attached file:

In point (a), The one factor is the charge on each of the objects. In point (b), at this point, the second factor is used as the distance between the charges.

The two ways to charge an object are Friction and Induction.

Charging an object:

To charge and object generally we can think of three ways, Friction, Conduction, and Induction. Here I am going to explain charging by friction and induction.

(i) Charging by Friction:

In this case, two objects are rubbed against each other. The friction between the two objects creates enough energy for the transfer of charges  ( electrons) from one object's surface to the other. So the imbalance in the electrons produces a charge on the objects.

(ii) Charging by induction:

In this case, an already charged object is brought near a neutral object but there is no contact between the objects. The charged object attracts or repels the electrons of the neutral object, depending upon the type of charge it has. Thus creating a charge imbalance in the neutral object.

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based on how this sample looks, which term describes the matter that makes up granite?
OA. pure substance
OB. element
OC. mixture
OD. compound​

Answers

Answer:

C. mixture

Explanation:

A mixture is an impure substance. It has the following properties;

It's composition is indefinite Their constituents retain their identities i.e. physical properties are retained Constituents react differently to changed conditionsThey can easily be separated into constituents by physical methods.

Granite is a rock. A rock is usually formed by a combination of different minerals.

Granite is made up of many compounds and so it is a mixture.


Objects want to keep doing the same thing is a way of stating ....

Answers

Answer:

Objects want to keep doing the same thing is a way of stating Newtons First Law.

The correct option is (a) inertia. "Objects want to keep doing the same thing" it implies a connection to the principle of inertia in physics. Inertia is the property of matter that resists changes in its state of motion or rest.

According to Newton's first law of motion, an object will remain at rest or continue moving in a straight line at a constant velocity unless acted upon by an external force. This property is commonly known as "the law of inertia." In other words, objects tend to maintain their current state of motion (whether at rest or in motion) unless influenced by an external force.

When we say "Objects want to keep doing the same thing," we're drawing an analogy between this scientific principle and human behavior. It suggests that objects, like humans, have a natural inclination to resist change and continue their current course of action. This analogy helps convey the idea that objects exhibit a tendency to persist in their existing state.

"Objects want to keep doing the same thing" to inertia emphasizes the notion that objects, like humans, tend to maintain their current state of motion or rest unless influenced by an external force.

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The correct question is:

Objects want to keep doing the same thing is a way of stating ......

a) inertia

b) force

c) power

d) moment

Consider the four scenarios involving visible light. In scenario A, visible light has a wavelength of 715.3 nm. Determine its frequency, energy per photon, and color.

Answers

Answer:

1. frequency (f) = 4.194 × 10^14Hz

2. Energy of photon (E) = 2.779 × 10^-19 J

3. Color is RED

Explanation:

1. Based on the information in this question, a visible light has a wavelength of 715.3 nm.

λ = v/f

Where; λ = wavelength (nm)

v = speed of light (3 × 10^8m/s)

f = frequency (Hz)

f = v/λ

f = 3 × 10^8/715.3 × 10^-9

f = 0.004194 × 10^(8+9)

f = 0.004194 × 10^17

f = 4.194 × 10^14Hz

2. Energy per photon is calculated thus;

E = hf

Where; E = energy of photon (J)

h = Planck's constant (6.626 × 10^-34 J/s)

f = frequency (Hz)

E = 6.626 × 10^-34 × 4.194 × 10^14

E = 27.789 × 10^(-34+14)

E = 27.789 × 10^-20

E = 2.779 × 10^-19 J

3. Based on the wavelength range of the visible spectrum, wavelength of 715.3nm falls between 625-740nm, which is RED color of light. Hence, the color of the visible light is RED.

The frequency is "[tex]419.5\times 10^{12} \ s^{-1}[/tex]", energy per photon is "[tex]2.780\times 10^{-19} \ J[/tex]" and the color is "red".

Given:

Wavelength,

[tex]\lambda = 715.1 \ nm[/tex]

or,

           [tex]= 715.1 \ nm\times (10^-9 \ m/nm)[/tex]

As we know the formula,

→ [tex]Frequency = \frac{Speed \ of \ light}{wavelength}[/tex]

By substituting the values, we get

                    [tex]= \frac{(3\times 10^8) }{715.1\times 10^{-9} }[/tex]

                    [tex]= 419.5\times 10^{12} \ s^{-1}[/tex]  

Now,

The energy per photon will be:

→ [tex]E = Planck's \ constant\times Frequency[/tex]

      [tex]= 6.626\times 10^{-34}\times 419.5\times 10^{12}[/tex]

      [tex]= 2.780\times 10^{-19} \ J[/tex]

Thus the above answer is correct.

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A cart with an unknown mass is at rest on one side of a track. A student must find the mass of the cart by using Newton’s second law. The student attaches a force probe to the cart and pulls it while keeping the force constant. A motion detector rests on the opposite end of the track to record the acceleration of the cart as it is pulled. The student uses the measured force and acceleration values and determines that the cart’s mass is 0.4kg . When placed on a balance, the cart’s mass is found to be 0.5kg . Which of the following could explain the difference in mass?

Answer choices:

A) The track was not level and was tilted slightly downward.

B) The student did not pull the cart with a force parallel to the track.

C) The wheels contain bearings that were rough and caused a significant amount of friction.

D) The motion sensor setting was incorrect. The student set it up so that motion away from the sensor would be the negative direction.

Answers

Answer: The correct answer is A) The track was not level and was tilted slightly downward.

Explanation: This is because of the two values: 0.4 kg and 0.5 kg. I won't go into much detail but due to this difference of mass, we know that the track was not level.

"The track was not level and was tilted slightly downward" could explain the difference in the mass.

Mostly because the university student or learners calculates a mass of just over the spring quantity, the vehicle speed seems to have been higher than there would have had to be.Option B, as well as Option C, are wrong because the acceleration would've been smaller in each of these 2 circumstances, so that computed mass would've been larger.

Thus Option A is appropriate.

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What is the final velocity (in m/s) of a hoop that rolls without slipping down a 3.50-m-high hill, starting from rest

Answers

Answer:

8.29m/s

Explanation:

Given

Height of hill H = 3.50m

Initial velocity u = 0m/s

Required

Final velocity v

Using the equation of motion

v² = u²+2gH

v² = 0²+2(9.81)(3.5)

v² = 0+7(9.81)

v² = 68.67

v = √68.67

v = 8.29m/s

Hence the final velocity of the hoop is 8.29m/s

An electromotive force E(t) = 200, 0 ≤ t ≤ 50 0, t > 50 is applied to an LR-series circuit in which the inductance is 50 henries and the resistance is 5 ohms. Find the current i(t) if i(0) = 0.

Answers

Answer:

The answer is below

Explanation:

An LR series circuit has a differential equation in the form of:

[tex]L\frac{di}{dt}+iR=E(t)\\ \\Given\ that\ 50H,R=5\ ohms,E(t)=200,for\ 0 \leq t \leq\ 50. Hence:\\\\50\frac{di}{dt}+5i =200\\\\\frac{di}{dt}+0.1i =4\\\\Solving\ the\ differential\ equation:\\\\The\ integrating\ factor(I)=e^{\int\limits {0.1} \, dt }=e^{0.1t}. The\ DE\ becomes:\\\\e^{0.1t}\frac{di}{dt}+e^{0.1t}(0.1i) =4e^{0.1t}\\\\e^{0.1t}i=\int\limits {4e^{0.1t}} \, dt \\\\e^{0.1t}i=40e^{0.1t}+A\\\\i(t)=40+Ae^{-0.1t}\\\\but\ i(0)=0\\\\0=40+Ae^{-0.1(0)}\\\\A=-40\\\\i(t)=40-40e^{-0.1t}\\\\[/tex]

At 50 seconds:

[tex]i(50)=40-40e^{-0.1*50}\\\\i(50)=40-40e^{-5}[/tex]

[tex]L\frac{di}{dt}+iR=E(t)\\ \\Given\ that\ 50H,R=5\ ohms,E(t)=0,for\ t> 50. Hence:\\\\50\frac{di}{dt}+5i =0\\\\\frac{di}{dt}+0.1i =0\\\\\frac{di}{dt}=-0.1i\\\\\frac{di}{i}=-0.1dt\\\\\int\limits {\frac{di}{i}} =\int\limits {-0.1} \, dt\\ \\ln(i)=-0.1t+A\\\\taking\ exponential:\\\\i=e^{-0.1t+A}\\\\i=e^{-0.1t}e^A\\\\i(t)=Ce^{-0.1t}\\\\i(50)=40-40e^{-5}=Ce^{-5}\\\\C=40(e^5-1)\\\\i(t)=40(e^5-1)e^{-0.1t}\\\\[/tex]

[tex]i(t)=\left \{ {{40-40e^{-0.1t}\ \ \ \ 0 \leq t \leq 50 } \atop {40(e^5-1)e^{-0.1t}\ \ \ \ t>50}} \right.[/tex]

Basalt is a rock that cooled quickly after lava erupted through a volcano.

What is the best description of its texture?

Answers

when the lava erupted from the volcano basalt was the rock that cooled quickly or basalt was the only one rock that cooled quickly after the lava erupted from the volcano

Explanation:

plz don't forget to mark me brainliest

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