Please help me with this for 20 points !!!!

Answer:

68

Step-by-step explanation:

2.5×4×2=20

2×4×2=16

4×4×2=32

20+16+32=68

Answer:

A

Step-by-step explanation:

Answer:

1)From ΔACB

tan 36= x/7

x= 7.tan 36

x= 5.086

2) Sin63=Opp/Hyp= 12/x

=>x=12/Sin63°

x= 13.47

3) Sin=x/MP

Sin 15°=x/12x=125 in 15°

x=3.11

hope it helps...

have a great day!!

Answer:

Ivy initially put $ 650 in the account.

Step-by-step explanation:

Given that Ivy deposited some money into a savings account that earns 1% annual simple interest, and at the end of 5 years, she earned $ 32.50 in interest, to determine how much money did she put into the account initially, the following calculation must be performed:

32.50 / 5 = 6.5

1 = 6.5

100 = X

100 x 6.5 = X

650 = X

Therefore, Ivy initially put $ 650 in the account.

Answer:

C.........................

Answer:

c.The point of a pencil if u go and check all of the other stuff are right triengle the point of a pencil is  like an acute trienagle

Step-by-step explanation:

Answer:

first is 180

second is 270

third is 90

Answer:

Step-by-step explanation:

Answer:

he will need to work 8 40-hour weeks.

Explanation:

since gordon has to set aside half of his wage to pay his bills, he can only save $12.50 ÷ 2 = $6.25 for the saxophone.

we can find how much money gordon saves from a 40-hour week by multiplying this by 40: $6.25 × 40 = $250.

now, divide the total amount of money he has to save by the amount he saves each week: $2000 ÷ $250 = 8.

he will need to work 8 40-hour weeks before he can afford the saxophone.

i hope this helps! :D

Answer:

D. 28

Step-by-step explanation:

We are given the following polynomial function:

[tex]F(x) = x^2 - 2x - 7[/tex]

Find F(-5).

This is the value of F for which [tex]x = -5[/tex]. So

[tex]F(-5) = (-5)^2 - 2(-5) - 7 = 25 + 10 - 7 = 28[/tex]

28, which means that the correct answer is given by option D.

Answer:

A is not true

Step-by-step explanation:

Answer:

If Jackson misses the 5-month deadline, it will cost him $429 in finance charges.

Step-by-step explanation:

Since Jackson purchased $ 5,200 worth of electronic equipment from BetterBuy on their deferred payment plan, and the plan allows the customer to make no down payment and no payment at all for five months, while if the entire amount is paid in full before the five month deferment ends, the finance charge with an APR of 19.8% is applied each month going back to the first month, to determine how much would it cost Jackson in finance charges if he misses the 5-month deadline the following calculation should be performed:

5,200 x (1 + (0.198 / 12 x 5)) = X

5,200 x (1 + (0.0165 x 5)) = X

5,200 x (1 + 0.0825) = X

5,200 x 1.0825 = X

5.629 = X

5,629 - 5,200 = 429

Therefore, if Jackson misses the 5-month deadline, it will cost him $429 in finance charges.

Answer:

185ft squared

Step-by-step explanation:

since this is a composite solid, all we have to do is use the 2 formulas:

b x h / 2  (Triangles on the pyramid)

l x w (Rectangular faces)

to solve the surface area of the composite figure.

Answer:

The rate of interest may vary , totally depends on the market value of that agency or company or the financial agency which is providing the mortgage money at certain rate. So, option (B) the interest rate may change depending on the condition of the economy is true statement regarding adjustable rate mortgage.Step-by-step explanation: hope it helps

Answer:

[tex]{a}^{3} + {b}^{3} [/tex]

[tex] = (a + b)( {a}^{2} - ab + {b}^{2} )[/tex]

Hence, simplified

Answer:

they are adding by 3 1 and 0

Step-by-step explanation:

Answer:

Step-by-step explanation: Mean= 400/15 =26.6

Median = 27

Mode= 35 - 16 =19

No

Answer:

51

Step-by-step explanation:

Answer:

all of these

0 does not equal 1

4 does not equal 7

2 does not equal -2

-3 does not equal 3

All of the given equations have no solution.

        ax + by + c = 0

        dx + ey + f = 0

We have the given system of linear equations that has no solutions.

For no solutions, the final equation should be of the form -

α = β

where [α] and [β] are constant integers.

So all the equations result in no solution.

Therefore, all of the given equations have no solution.

To solve more questions on system of equations, visit the link below-

brainly.com/question/1126982

#SPJ2

Answer:

c

Step-by-step explanation:

4×2=2in

100÷2=50%

so it is c

Answer:

Point C

Step-by-step explanation:

Point C is half way on the line

Answer:

3 and 16

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

11miles/2hours

11 divide by 2 = 5.5 miles/1 hour

5.5 miles per hour

Answer:

5.5 miles per hour

Step-by-step explanation:

Answer:

sum

1.-28

2.5/4

3. -9.4

4. 33

5. 4.6

6. 2.4

7. -4.2

DIFFERENCE

8. -2.5

9. -7

10. 3/10

11. -31/36

12. -29/18

13. 16

14.-5/9

Step-by-step explanation: hoped this helped :))

Answer:

[tex]ab + c = d \\ ab = d - c \\ a = \frac{(d - c)}{b} [/tex]

Answer:

A=d-c/b

Step-by-step explanation:

just took the test

Answer:

y = x -6

Step-by-step explanation:

First find the slope

m= ( y2-y1)/(x2-x1)

   = (0- -6)/(6-0)

   =( 0+6)/(6-0)

   = 6/6

   = 1

The slope is 1 and the y intercept is -6

The slope intercept form is

y = mx+b where m is the slope and b is the y intercept

y = x -6

Answer:

the answer is C

Step-by-step explanation:

y = x -6

Answer:

0.9986 = 99.86% probability that you win less than 40

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

The probability of winning a slot machine is 5% and you are going to play 500 pulls.

This means that [tex]p = 0.05, n = 500[/tex]

Mean and Standard deviation:

[tex]\mu = E(X) = np = 500*0.05 = 25[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{500*0.05*0.95} = 4.8734[/tex]

What’s the probability that you win less than 40?

Using continuity correction, this is P(X < 40 - 0.5) = P(X < 39.5), which is the pvalue of Z when X = 39.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{39.5 - 25}{4.8734}[/tex]

[tex]Z = 2.98[/tex]

[tex]Z = 2.98[/tex] has a pvalue of 0.9986

0.9986 = 99.86% probability that you win less than 40

Answer:

Step-by-step explanation:

[tex]\frac{1}{4}+\frac{9}{10}y - \frac{3}{5}y+\frac{7}{8}\\\\=\frac{1}{4}+\frac{7}{8}+\frac{9}{10}y-\frac{3}{5}y\\\\[/tex]

Combine like terms. 1/4 and 7/8 are like terms and LCD of 4 and 8 is 8

9/10y and -3/5y are like terms and LCD of 10 , 5 is 10

[tex]= \frac{1*2}{4*2}+\frac{7}{8}+\frac{9}{10}y-\frac{3*2}{5*2}y\\\\=\frac{2}{8}+\frac{7}{8}+\frac{9}{10}y-\frac{6}{10}y\\\\=\frac{9}{8}+\frac{3}{10}y[/tex]

Answer:

3 • (4y + 15)

-----------------  

      40  

Step-by-step explanation:

Long explanation get ready

STEP

1

:

           7

Simplify   —

           8

Equation at the end of step

1

:

   1   9      3     7

 ((—+(——•y))-(—•y))+—

   4  10      5     8

STEP

2

:

           3

Simplify   —

           5

Equation at the end of step

2

:

   1   9      3     7

 ((—+(——•y))-(—•y))+—

   4  10      5     8

STEP

3

:

            9

Simplify   ——

           10

Equation at the end of step

3

:

   1      9          3y     7

 ((— +  (—— • y)) -  ——) +  —

   4     10          5      8

STEP

4

:

           1

Simplify   —

           4

Equation at the end of step

4

:

   1    9y     3y     7

 ((— +  ——) -  ——) +  —

   4    10     5      8

STEP

5

:

Calculating the Least Common Multiple :

5.1    Find the Least Common Multiple

     The left denominator is :       4

     The right denominator is :       10

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 1 2

5 0 1 1

Product of all

Prime Factors  4 10 20

     Least Common Multiple:

     20

Calculating Multipliers :

5.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

5.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.       5

  ——————————————————  =   ——

        L.C.M             20

  R. Mult. • R. Num.      9y • 2

  ——————————————————  =   ——————

        L.C.M               20  

Adding fractions that have a common denominator :

5.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

5 + 9y • 2     18y + 5

——————————  =  ———————

    20           20  

Equation at the end of step

5

:

  (18y + 5)    3y     7

 (————————— -  ——) +  —

     20        5      8

STEP

6

:

Calculating the Least Common Multiple :

6.1    Find the Least Common Multiple

     The left denominator is :       20

     The right denominator is :       5

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 0 2

5 1 1 1

Product of all

Prime Factors  20 5 20

     Least Common Multiple:

     20

Calculating Multipliers :

6.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 1

  Right_M = L.C.M / R_Deno = 4

Making Equivalent Fractions :

6.3      Rewrite the two fractions into equivalent fractions

  L. Mult. • L. Num.      (18y+5)

  ——————————————————  =   ———————

        L.C.M               20  

  R. Mult. • R. Num.      3y • 4

  ——————————————————  =   ——————

        L.C.M               20  

Adding fractions that have a common denominator :

6.4       Adding up the two equivalent fractions

(18y+5) - (3y • 4)     6y + 5

——————————————————  =  ——————

        20               20  

Equation at the end of step

6

:

 (6y + 5)    7

 ———————— +  —

    20       8

STEP

7

:

Calculating the Least Common Multiple :

7.1    Find the Least Common Multiple

     The left denominator is :       20

     The right denominator is :       8

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 3 3

5 1 0 1

Product of all

Prime Factors  20 8 40

     Least Common Multiple:

     40

Calculating Multipliers :

7.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 2

  Right_M = L.C.M / R_Deno = 5

Making Equivalent Fractions :

7.3      Rewrite the two fractions into equivalent fractions

  L. Mult. • L. Num.      (6y+5) • 2

  ——————————————————  =   ——————————

        L.C.M                 40    

  R. Mult. • R. Num.      7 • 5

  ——————————————————  =   —————

        L.C.M              40  

Adding fractions that have a common denominator :

7.4       Adding up the two equivalent fractions

(6y+5) • 2 + 7 • 5     12y + 45

——————————————————  =  ————————

        40                40  

STEP

8

:

Pulling out like terms :

8.1     Pull out like factors :

  12y + 45  =   3 • (4y + 15)

answer d

Step-by-step explanation:

because I learned this

Answer: 144 pi units^3

Step-by-step explanation:

Answer:

answer is b

Step-by-step explanation:

answer is b