please help me with this .
i’m going to give out the brainly thingy

Answer: 22 Levels

Step-by-step explanation: He would need to go one level higher just to get to level one, and another 21 to get to the level that he wants to, so the total would be 22 levels.

Answer:

The elevator moved up 21 levels

Answer:

x = 5

Step-by-step explanation:

a || b and a line intersecting them is their transversal.

[tex] \therefore m\angle 1=m\angle 5\\(corresponding \:\angle 's) \\\\

\therefore 60 - 2x = 70 - 4x\\\\

\therefore 4x - 2x = 70 - 60\\\\

\therefore 2x = 10\\\\

\therefore x =\frac{10}{2} \\\\

\huge \orange {\boxed {\therefore x = 5}}[/tex]

Answer:

[tex]y = Acos5x - Bsin5x[/tex]

Step-by-step explanation:

Given the differential equation y''-10y'+29y=0

First, we need to rewrite it as an auxiliary equation as shown:

Let y'' = m²y and y' = my

Substitute the values into the general equation

m²y-10my+29y = 0

Factor out y:

(m²-10m+29)y = 0 [The auxiliary equation]

Solve the auxiliary equation and find the roots of the equation

m²-10m+29 = 0

m = -b±√(b²-4ac)/2a

a = 1, b = -10, c = 29

m = -10±√(10²-4(1)(29))/2(1)

m = -10±√(100-116)/2

m = -10±√-16/2

m = (-10±4i)/2

m = -10/2 + 4i/2

m = -5+2i

Comparing the complex number with a+bi, a = -5 and b = 2

The general solution for complex solution is expressed as:

[tex]y = Acosax + Bsinax[/tex]

Substitute the value of a in the equation

[tex]y = Acos(-5)x + Bsin(-5)x\\y = Acos5x-Bsin5x[/tex]

Hence the general solution to the differential equation is [tex]y = Acos5x - Bsin5x[/tex]

Answer:

The 4 is in the 1,000,000´s place and 3 is in the 10,000 place

Step-by-step explanation:

Answer:

a)

s= 6t-t² -->  v = 6 -2t  --> a = -2

s=t²-6t  --> v = 2t-6       -->    a = 2

s= t²-9t+24  -->  v = 2t -9   -->  a = 2

b)

v = 6 -2t  = 0  --> t = 3

v = 2t-6  = 0   --> t = 3

v = 2t -9   = 0 --> t = 9/2

Step-by-step explanation:

si s(t) es la distancia, la velocidad es la primera derivada v(t) = s'(t)

y la acceleracion es la segunda derivada : a(t)= v'(t) = s''(t)

s= 6t-t² -->  v = 6 -2t  --> a = -2

s=t²-6t  --> v = 2t-6       -->    a = 2

s= t²-9t+24  -->  v = 2t -9   -->  a = 2

Answer:

The projectile will reach a height of 200 ft after 1.910 seconds and 13.090 seconds of being launched.

Step-by-step explanation:

This projectile is experimenting a free fall, that is, an uniform accelerated motion of the projectile due to gravity and in which effects of air friction and Earth's rotation are neglected. Given that initial and final heights, initial velocity and gravitational acceleration are known, we need to calculate time by solving the appropriate equation of motion described below:

[tex]y = y_{o} +v_{o}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}[/tex] (Eq. 1)

Where:

[tex]y_{o}[/tex] - Initial height of projectile, measured in feet.

[tex]y[/tex] - Final height of projectile, measured in feet.

[tex]v_{o}[/tex] - Initial velocity of projectile, measured in feet per second.

[tex]g[/tex] - Gravitational acceleration, measured in feet per square second.

As we must remember, quadratic functions have two roots and if we get that [tex]y_{o} = 0\,ft[/tex], [tex]y = 200\,ft[/tex], [tex]v_{o} = 120\,\frac{ft}{s}[/tex] and [tex]g = -16\,\frac{ft}{s^{2}}[/tex], then, the quadratic function is:

[tex]-8\cdot t^{2}+120\cdot t -200 = 0[/tex]

Roots are found by the Quadratic Formula:

[tex]t_{1,2} = \frac{-120\pm \sqrt{120^{2}-4\cdot (-8)\cdot (-200)}}{2\cdot (-8)}[/tex]

Whose solutions are:

[tex]t_{1} \approx 13.090\,s[/tex] and [tex]t_{2} \approx 1.910\,s[/tex].

Both roots are physically reasonable, first root represents the instant when the projectile reaches 200 feet when it is moving downwards, whereas second root represents the projectile moving upwards. Therefore, the projectile will reach a height of 200 ft after 1.910 seconds and 13.090 seconds of being launched.

Answer:

It will take 2.5 s to reach a height of 200ft.

Step-by-step explanation:

Answer:

1800000 kilometers

Step-by-step explanation:

i think im not 100% sure

Answer:

The p-value is 0.0012.

Step-by-step explanation:

The hypothesis is:

H₀: µ = 72 vs. Hₐ: µ > 72

The information provided is:

[tex]n =16\\\bar x=75.8\\\sigma=5[/tex]

Compute the test statistic value as follows:

[tex]z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}[/tex]

  [tex]=\frac{75.8-72}{5/\sqrt{16}}\\\\=3.04[/tex]

Compute the p-value as follows:

[tex]p-value=P(Z>3.04)\\\\=1-P(Z<3.04)\\\\=1-0.99882\\\\=0.00118\\\\\approx 0.0012[/tex]

*Use a z-table.

Thus, the p-value is 0.0012.

Answer:

The length of a side of the square is 6.3 units.

Step-by-step explanation:

When given vertices for a given shape, the length of the side is calculated using the formula:

√(x2 - x1)² + (y2 - y1)²

When given vertices (x1 , y1) and (x2 , y2)

Square ABCD has vertices A(-2,-3), B(4, -1), C(2,5), and D(-4,3). Find the length of a side

Side AB : A(-2,-3), B(4, -1)

√(x2 - x1)² + (y2 - y1)²

= √(4 -(-2))² + (-1 -(-3))²

= √ 6² + 2²

= √36 + 4

= √40

= 6.3245553203

≈ 6.3 units

B(4, -1), C(2,5),

√(x2 - x1)² + (y2 - y1)²

= √ (2- 4)² + (5- (-1))²

= √-2² + 6²

= √4 + 36

= √40

= 6.3245553203

≈ 6.3 units

C(2,5), D(-4,3).

√(x2 - x1)² + (y2 - y1)²

= √(-4 - 2)² + (3 - 5)²

= √-6² + -2²

= √36 + 4

= √40

= 6.3245553203

≈ 6.3 units

A(-2,-3), D(-4,3).

√(x2 - x1)² + (y2 - y1)²

= √(-4 -(-2))² + (3 - (-3))²

= √-2² + 6²

= √4 + 36

= √40

= 6.3245553203

≈ 6.3 units

Answer:

i think ur answer is -43.i hope u get it

Answer:

the answer is i guess -43

Step-by-step explanation:

|-43| = 43

so -|-43| = -43

Answer:

y = -4/3x - 4

Step-by-step explanation:

Given

(x1,y1) = (-9,8)

slope, m = -4/3

Required

Determine the line equation

The equation is of the form

y - y1 = m(x - x1)

Substitute values for y1, x1 and m

y - 8 = -4/3(x - (-9))

y - 8 = -4/3(x + 9)

y - 8 = -4/3x - 12

y = -4/3x - 12 + 8

y = -4/3x - 4

Answer:

b

Step-by-step explanation:

Answer:

G

Step-by-step explanation:

Answer:

[tex] \huge{ \boxed{ \tt{ \frac{ 7}{4} }}}[/tex]

Step-by-step explanation:

[tex] \text{Let \: the \: points \: be \: A \: and \: B}[/tex]

[tex] \sf{A \:( \: 0 \:, - 5 \: ) \longrightarrow{ \: (x1 \:, y1)}}[/tex]

[tex] \sf{B(4 \:, 2) \: \longrightarrow{ \:( x2 \:, y2)}}[/tex]

[tex] \underline{ \text{Finding \: the \: slope} }: [/tex]

[tex] \boxed{ \sf{Slope = \frac{y2 - y1}{x2 - x1}}} [/tex]

[tex] \sf{➳ \: Slope = \frac{2 - ( - 5)}{4 - 0}} [/tex]

[tex] \sf{➳ \: Slope = \frac{ 2 + 5}{4} }[/tex]

[tex] \sf{➳ \: Slope = \frac{7}{4} }[/tex]

[tex] \text{Hope \: I \: helped!}[/tex]

[tex] \text{Best \: regards!}[/tex]

~[tex] \text{TheAnimeGirl}[/tex]

Answer:

(x-2)(x+1)(x-5)

Step-by-step explanation:

Answer:

32 degrees goto the x vaule

Answer:

60 inches and he will need 4 tiles

Answer:

I really think that (3 , -3 , -3) is the answer but I could be wrong.

Step-by-step explanation:

I'm taking the quiz right now and from the graph it looks like point E is in the position (3 , -3 , -3).

Once again, sorry if I'm wrong.

Answer:

Tennessee area we don´t know there is something wrong

Colorado area is ok close to 106000 mi²

Step-by-step explanation:

Tennessee is shaped like a parallelogram base is equal to 440 miles and the height is 120 miles. Therefore

Ap = b*h  = 440 * 120   = 52800 mi²

But the area of Tennessee  is 63000 mi²

Then there is something wrong because difference in mi² is

10400 mi²

10400/ 63000 = 0,165 % faraway of the real number

In the case of Colorado

Ac = 385 * 275

Ac = 105875 mi²   pretty close to 106000 mi²

Then from double check in the areas, we conclude in a high difference in the figures for the state of Tennessee ( one or both of the figures are incorrect ). The state of Colorado area is oK

Complete Question

Problem 7.43

   A chemical plant superintendent orders a process readjustment (namely shutdown and setting change) whenever the pH of the final product falls below 6.92 or above 7.08. The sample pH is normally distributed with unknown mu and standard deviation 0.08. Determine the probability:

(a)

of readjusting (that is, the probability that the measurement is not in the acceptable region) when the process is operating as intended and [tex]\mu[/tex] = 7.0 probability

(b)

of readjusting (that is, the probability that the measurement is not in the acceptable region) when the process is slightly off target, namely the mean pH is [tex]\mu[/tex] = 7.02

Answer:

a

The value is  [tex]P(X < 6.92 or X > 7.08 ) =  0.26431 [/tex]  

b

The value  is [tex]P(X < 6.92 or X > 7.08 ) =  0.29344 [/tex]  

Step-by-step explanation:

From the question we are told that

  The mean is  [tex]\mu =  7.0[/tex]

  The standard deviation is  [tex]\sigma  =  0.08[/tex]

Considering question a

Generally the probability of readjusting when the process is operating as intended and mu  7.0 is mathematically represented as

       [tex]P(X < 6.92 or X > 7.08 ) =  P(X <  6.92  ) + P(X > 7.08)[/tex]

=>    [tex]P(X < 6.92 or X > 7.08 ) =  P(\frac{X - \mu }{\sigma} < \frac{6.9 - 7}{0.08}  ) + P(\frac{X - \mu}{\sigma} >  \frac{7.08 - 7}{0.08} )[/tex]

Generally

 [tex]\frac{X - \mu }{\sigma} = Z(The \  standardized \  value \ of \  X)[/tex]

So

=> [tex]P(X < 6.92 or X > 7.08 ) =  P(Z < \frac{6.9 - 7}{0.08}  ) + P(Z >  \frac{7.08 - 7}{0.08} )[/tex]    

=> [tex]P(X < 6.92 or X > 7.08 ) =  P(Z < -1.25) + P(Z >  1 )[/tex]  

From the z table the probability of  (Z < -1.25) and  (Z >  1 ) is  

       [tex]P(Z < -1.25) =  0.10565[/tex]

and

      [tex]P(Z >  1 ) = 0.15866[/tex]

So

=> [tex]P(X < 6.92 or X > 7.08 ) =  0.10565 + 0.15866 [/tex]      

=> [tex]P(X < 6.92 or X > 7.08 ) =  0.26431 [/tex]      

Considering question b

Generally the probability of readjusting when the process is operating as intended and mu  7.02 is mathematically represented as

       [tex]P(X < 6.92 or X > 7.08 ) =  P(X <  6.92  ) + P(X > 7.08)[/tex]

=>    [tex]P(X < 6.92 or X > 7.08 ) =  P(\frac{X - \mu }{\sigma} < \frac{6.9 - 7.02}{0.08}  ) + P(\frac{X - \mu}{\sigma} >  \frac{7.08 - 7.02}{0.08} )[/tex]

Generally

 [tex]\frac{X - \mu }{\sigma} = Z(The \  standardized \  value \ of \  X)[/tex]

So

=> [tex]P(X < 6.92 or X > 7.08 ) =  P(Z < \frac{6.9 - 7.02}{0.08}  ) + P(Z >  \frac{7.08 - 7.02}{0.08} )[/tex]    

=> [tex]P(X < 6.92 or X > 7.08 ) =  P(Z < -1.5) + P(Z >  0.75 )[/tex]  

From the z table the probability of  (Z < -1.5) and  (Z >  0.75 ) is  

       [tex]P(Z < -1.5) = 0.066807[/tex]

and

      [tex]P(Z >  0.75 ) = 0.22663[/tex]

So

=> [tex]P(X < 6.92 or X > 7.08 ) = 0.066807 + 0.22663 [/tex]      

=> [tex]P(X < 6.92 or X > 7.08 ) =  0.29344 [/tex]      

Answer:

The answer is 16

Mark me as brainliest if it was helpful

Answer:

9 1/66

Step-by-step explanation:

9 x 1 is 9 so its that but to add more proof the problem is 9 1/6, 1 1/11 multiply 6 and 11 it is 66 so the answer is 9 1/66

Answer:

6.25 hours

Step-by-step explanation:

this is rather simple really,

first, you have to work 40 hours a week

you have already worked 15 so now you can subtract that

40-15= 25hrs

if you have 4 more days of the week you divide the remaining hours by the days left

25/4= 6.25hrs

that would be the bare minimum of hours for you to work a 40 hour week.

Answer:

What Is X and Y

Step-by-step explanation:

Answer:

It is a linear equation.

Step-by-step explanation:

It has no squares in the equation, meaning the line is straight, therefore meaning the equation is linear.

Answer is 2/3

Hope this helps

Answer:

200 cans

Step-by-step explanation:

use rate method

80         40

x           100

40x=8000

x=8000/40

x=200

Answer:

(a) 0.40

(b) 0.049

(c) [tex]\bar p\sim N(0.40,0.049^{2})[/tex]

(d) Explained below

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 [tex]E(\bar p)=p[/tex]

The standard deviation of this sampling distribution of sample proportion is:

 [tex]SE(\bar p)=\sqrt{\frac{p(1-p)}{n}}[/tex]

Given:

n = 100

p = 0.40

As n = 100 > 30 the Central limit theorem is applicable.

(a)

Compute the expected value of [tex]\bar p[/tex] as follows:

[tex]E(\bar p)=p=0.40[/tex]

The expected value of [tex]\bar p[/tex] is 0.40.

(b)

Compute the standard error of [tex]\bar p[/tex] as follows:

[tex]SE(\bar p)=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.40(1-0.40)}{100}}=0.049[/tex]

The standard error of [tex]\bar p[/tex] is 0.049.

(c)

The sampling distribution of [tex]\bar p[/tex] is:

[tex]\bar p\sim N(0.40,0.049^{2})[/tex]

(d)

The sampling distribution of p show that as the sample size is increasing the distribution is approximated by the normal distribution.

Segment, ray and line are one-dimensional figures.

We need to check from the given options which are one-dimensional figures.

One-dimensional: Only a single measurement is possible for a one-dimensional figure. A line segment drawn on a surface is a one-dimensional object, as it has only length and no width.  

Here, the segment is a one-dimensional figure.

Ray is a one-dimensional figure.

Angle is a two-dimensional figure.

A line is a one-dimensional figure.

The plane is a two-dimensional figure.

A cube is a three-dimensional figure.

Therefore, segment, ray and line are one-dimensional figures.

To learn more about one-dimensional figures visit:

https://brainly.com/question/17967616.

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