Please help me with 1&2

Answer:

a)  W = - 1.92 10⁻¹⁸ J, b)    U = 1.92 10⁻¹⁸ J, c)   v = 2.05 10⁶ m / s

Explanation:

a) Work is defined by

        W = F. x

 the electric force is

         F = q E

we substitute

          W = q E x

where the displacement is parallel to the electric field

all quantities must be in the SI system

         x = 3.20 cm = 0.0320 m

         W = - 1.6 10-19 375 0.0320  

         W = - 1.92 10⁻¹⁸ J

b) potential energy

          U = [tex]k \frac{q_1q_2}{r}[/tex]

the electrical power is

          V = k q₁ / r

we can write this potential as a function of the electric field

           V = -E x

we substitute

           U = -q E x

           U = - (-1.6 10⁻¹⁹) 375 0.0320

           U = 1.92 10⁻¹⁸ J

Observe that the variation of the red potential is equal to the electrical work

c) let's use conservation of energy

starting point

          Em₀ = U = e E x

final point

          Em_f = K = ½ m v²

energy is conserved

          Em₀ = Em_f

          e E x = ½ m v²

          v² = 2 e E x / m

           v = [tex]\sqrt{ \frac{{2 \ 1.6 10^{-19} \ 375 \ 0.0320 } }{9.1 \ 10^{-31} } }[/tex]

           v = [tex]\sqrt{4.2198 \ 10^{12}}[/tex]

           v = 2.05 10⁶ m / s

Answer:

The answer is "[tex]=2.72 \ seconds \\\\[/tex]"

Explanation:

Using formula:

[tex]kr=mg \\\\k=\frac{0.156 \times 9.8}{0.418}\\\\[/tex]

  [tex]=3.65741627\ \frac{N}{M}\\\\=3.65\ \frac{N}{M}\\\\[/tex]

Calculating the time period:

[tex]T=2\pi \sqrt{\frac{m}{k}}\\\\[/tex]

   [tex]= 2 \pi \sqrt{\frac{0.156}{3.65}}\\\\= 2 \times 3.14 \sqrt{\frac{0.156}{3.65}}\\\\= 6.28 \sqrt{\frac{0.156}{3.65}}\\\\=6.28 \times 0.108210508\\\\=0.67956199\\\\=0.68\\\\[/tex]

The time to calculating the 4 oscillation:

[tex]\to 4T=4\times 0.68 =2.72 \ seconds \\\\[/tex]

The time taken by the spring to complete 4 complete oscillations will be t=2.72 sec

Oscillation is the process of repeating variation of the quantity or the recitative or periodic variations with respect to the time.

Here it is given that

mass =0.156 kg

stretch x= 4.18 cm

Now from the formula

[tex]kx=mg[/tex]

[tex]k= \dfrac{0.156\times 9.81}{0.418}[/tex]

[tex]k=3.65\ \frac{N}{m}[/tex]

Now the time period will be calculated as:

[tex]T=2\pi\sqrt{\dfrac{m}{k}[/tex]

[tex]T=2\pi\sqrt{\dfrac{0.156}{3.65}[/tex]

[tex]T=6.28\times 0.108210508[/tex]

[tex]T=0.68\ sec[/tex]

Now for the 4 oscillations the total time will be

[tex]T=4\times 0.68=2.72\ sec[/tex]

Hence the time taken by the spring to complete 4 complete oscillations will be t=2.72 sec

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1 a. Spherical Mirror

2. Both A and B

3. Concave mirror

4.Inwards

5. Pole.

These are your answer. You can mark me Brainliest. Thanks.

hope it helps you have a good day

Explanation:

spherical mirror

both A and B

inwards

pole

its wave length

its wave lenght because how its measure

Answer:

yes, should be

Explanation:

This is a hard yes or no question becuase the amplitudes are the same height but in different beating orders.

Answer:

They appear to be about the same height, so the answer is true.

Explanation:

As the fish goes deeper, the volume of air in the swim bladder increases.

Buoyant force is calculated using the following formula;

F = ρVg

where;

The volume of the fluid displaced is calculated as follows;

V = Ah

where;

Thus, we can conclude that as the fish goes deeper, the volume of air in the swim bladder increases.

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Answer:

It's A, B, and D

A. The city integrated its school

B. Atlanta became a leader in aviation

D. The population increased to one million

Explanation:

Answer:

11.3975

Explanation:

Accellus said so

Answer:

11.3975

Explanation:

its for Acellus

Explanation:

ddhjdkdjjjkjkjkkkkkkkkk

Answer:

Since v = (x(2) - x(1)) / t

point 2 obviously has the greatest displacement in a given time

Also, point 2 is the steepest line on this graph.

Answer:

her acceleration is 1 m/sec

Explanation:

The following information is given in the question

The initial velocity is 5 m/s

After 10 seconds, she would be moved at 15 m/s

We need to find the acceleration

As we know that

Acceleration = Change in speed ÷ time

Acceleration = (15 - 5) ÷ (10)

= 1 m/sec

Hence, her acceleration is 1 m/sec

The same would be considered  

Answer:

The mass of the fish is 6.493 kilograms.

Explanation:

The spring-mass system experiments a Simple Harmonic Motion, then the angular frequency ([tex]\omega[/tex]), in radians per second, is determined by the following equation:

[tex]\omega = 2\pi\cdot f[/tex] (1)

Where [tex]f[/tex] is the frequency, in hertz.

In addition, the mass of the fish ([tex]m[/tex]), in kilograms, is:

[tex]m = \frac{k}{\omega^{2}}[/tex] (2)

Where [tex]k[/tex] is the spring constant, in newtons per meter.

And the spring constant is determined by Hooke's Law:

[tex]k = \frac{F}{\Delta x}[/tex] (3)

Where:

[tex]F[/tex] - Elastic force, in newtons.

[tex]\Delta x[/tex] - Spring elongation, in meters.

If we know that [tex]F = 225\,N[/tex], [tex]\Delta x = 0.125\,m[/tex] and [tex]f = 2.65\,hz[/tex], then the mass of the fish is:

[tex]\omega = 2\pi\cdot f[/tex]

[tex]\omega \approx 16.650\,\frac{rad}{s}[/tex]

[tex]k = \frac{F}{\Delta x}[/tex]

[tex]k = 1800\,N[/tex]

[tex]m = \frac{k}{\omega^{2}}[/tex]

[tex]m = 6.493\,kg[/tex]

The mass of the fish is 6.493 kilograms.

This question involves the concepts of Hooke's Law, and the frequency of spring-mass system.

The mass of the fish is "6.5 kg".

First, we will calculate the angular speed of the system:

[tex]\omega=2\pi f[/tex]

where,

ω = angular speed = ?

f = frequency = 2.65 Hz

Therefore,

[tex]\omega = 2\pi(2.65\ Hz)\\\omega = 16.65\ rad/s\\[/tex]

Now, we will use the Hooke's Law to find out the spring constant of the spring:

[tex]K =\frac{F}{\Delta x}[/tex]

where,

K = spring constant = ?

F = force applied = maximum weight = 225 N

Δx = extension = 12.5 cm = 0.125 m

Therefore,

[tex]k=\frac{225\ N}{0.125\ m}\\\\k = 1800\ N/m\\[/tex]

Now, we will use the formula for the angular speed of a spring-mass system to find out the mass of the fish:

[tex]\omega = \sqrt{\frac{k}{m}}\\\\m = \frac{k}{\omega^2}\\\\m=\frac{1800\ N/m}{(16.65\ rad/s)^2}[/tex]

m = 6.5 kg

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The attached picture illustrates Hooke's Law.

The most common type of hydroelectric power plant is an impoundment facility. An impoundment facility, typically a large hydropower system, uses a dam to store river water in a reservoir. Water released from the reservoir flows through a turbine, spinning it, which in turn activates a generator to produce electricity.

"A turbine is a rotary mechanical device that extracts energy from a fluid flow and converts it into useful work." The work produced by a turbine can be used for generating electrical power when combined with a generator.

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Answer:

d.) form supernovas

Explanation:

Learned this in physical school last year

Hi there!

[tex]\large\boxed{5N}[/tex]

From the given diagram, 20 N is going left, and 15 N is going right.

To find the net force, we must subtract the two since the two forces go in opposite directions:

20 N - 15 N = 5N.

[tex]\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}[/tex]

A black hole is a tremendous amount of matter crammed into a very small — in fact, zero — amount of space. The result is a powerful gravitational pull, from which not even light can escape — and, therefore, we have no information or insight as to what life is like inside. A black hole is not empty, It's actually a lot of matter condensed into a single point. This point is known as a singularity.

Answer:

354

Explanation:

Answer:

a = 640 m/s²

Explanation:

From work-kinetic energy principles,

The net force acting on the second object is the gravitational force and the electric force due to the first object.

So, the gravitational force on the mass is F₁ = Gm₁m₂/r² since m₁ = m₂ = m, U = -Gm²/r²

Also, the electric force on the charge is F₂ = kq₁q₂/r² since q₁ = q₂ = q, U = kq²/r²

The net Force F = ma

So, -F₁ + F₂ = F     (F₁ is negative since it is an attractive force in the negative x -direction and F₂ is positive since it is a repulsive force in the positive x- direction)

-Gm²/r² + kq²/r² = ma

ma = -Gm²/r² + kq²/r²

a = (-Gm²/r² + kq²/r²)/m

a = (-G + kq²/m²)m/r²

Since m = 0.250 kg, q = 4.00 μC = 4.00 × 10⁻⁶ C, r = 3.00 cm = 3.00 × 10⁻² m, G = 6.67 × 10⁻¹¹ Nm²/kg², k = 9 × 10⁹ Nm²/C² and a = acceleration of second mass.

Substituting the variables into the equation, we have

a = (m/r²)(-G + k(q/m)²)]

a = (0.250 kg/{3.00 × 10⁻² m}²)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(4.00 × 10⁻⁶ C/0.250 kg)²)

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(16 × 10⁻⁶ C/kg)²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(256 × 10⁻¹² C²/kg²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 2304 × 10⁻³ Nm²/kg²  ]

a = (0.250 kg/9.00 × 10⁻⁴ m)(2.304 Nm²/kg²)

a = 0.576 Nm²/kg /9.00 × 10⁻⁴ m²

a = 0.064 × 10⁴N/kg

a = 64 × 10 N/kg)

a = 640 m/s²

Answer:

supernova explosion or death of massive star

Explanation:

"Most black holes form from the remnants of a large star that dies in a supernova explosion."

Answer:

Explained below.

Explanation:

Electromagnetism is defined as the study of the electromagnetic force that takes place between two or more electrically charged particles.

Now, in electromagnetic interaction, the charged particles tend to interact in an electromagnetic manner through the process of exchanging photons. Therefore, it was concluded from various experiments that the magnetic fields lines of forces were always closed, thereby eliminating the possibility of any magnetic monopole in such a manner that within a particular magnetic field, there will be two poles and in the solar system, the electromagnetic attraction between earth magnetic field and solar wind will be by way of a field.

Answer:

C.  10

Explanation:

The half-life of argon-44 is 12 minutes, 10 atoms of argon-44 will be left. The correct option is C.

A radioactive substance's half-life is the amount of time it takes for half of the atoms in a sample to decay.

The half-life of argon-44 in this situation is 12 minutes. Starting with 20 argon-44 atoms, half of them will have disintegrated within 12 minutes, leaving 10 atoms.

This happens because radioactive decay is an exponential process with a constant rate of decay. Every half-life cuts the number of atoms in half.

So, if we waited another 12 minutes, half of the remaining 10 atoms would decay, leaving us with 5 atoms. This process is repeated, with half of the remaining atoms dying with each half-life.

Thus, the correct option is C.

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Answer:

Explanation:

The light waves in the reflected sunlight are horizontally polarized, which illustrates that they oscillate at a [tex]90^o[/tex] angle related to a vertical line.

Depending on the condition of the height of the light, the glare can be almost entirely horizontally polarized. Furthermore, all reflections from over-water surfaces are partially polarized. The water becomes more translucent when using polarized sunglasses.

If polarized sunglasses are to be efficient against solar glare, the transmission axis should be positioned at an angle of [tex]\theta = 45^{o}[/tex]

Answer:

the image will be real and inverted

Answer:

B . Second law

Explanation:

According to second law:

Net Force acting on the body produce acceleration. The magnitude acceleration of the body is directly proportional to net force and inversly proportional to the mass.

Mathematically:

                   a = [tex]\frac{F}{m}[/tex]

and

                   F = ma

So according to the given condition Waldo should use Second law.

Explanation:

1200 is your answer for this question

Answer:

a)   λ = 4.862 10⁻⁷ m,  b)  λ = 4.341 10⁻⁷ m

Explanation:

The spectrum of hydrogen can be described by the expression

         [tex]\frac{1}{\lambda} = R_H ( \frac{1}{n_o^2} - \frac{1}{n^2} ) \ \ \ \ n>n_o[/tex]

in the case of the initial state n = 2 this series is the Balmer series

a) Find the wavelength for n = 4

let's calculate

          [tex]\frac{1}{ \lambda}[/tex] = 1,097 10⁷ ([tex]\frac{1}{2^2} - \frac{1}{4^2}[/tex])

          \frac{1}{ \lambda} = 1.097 10⁷ 0.1875 = 0.2056 10⁷

           λ = 4.862 10⁻⁷ m

b) n = 5

     \frac{1}{ \lambda} = 1,097 10⁷ ([tex]\frac{1}{2^2} - \frac{1}{5^2}[/tex])

     \frac{1}{ \lambda} = 1.097 10⁷ 0.21 = 0.23037 10⁷

      λ = 4.341 10⁻⁷ m