Please help me find the area of compound shapes?!?!

Answer:

467 hours.

Step-by-step explanation:

3736 / 8

= 467.

Answer:

a) 3n+5

b) n+16

c) [tex]\frac{n-9}{2}[/tex]

d) [tex]\frac{x-u}{x+u}[/tex]

Answer: the chance that a given event will occur

Step-by-step explanation:

Answer:

4. 56 is 8 times as many as 7.

56 = 8 x 7

5. 6, 12, 18, 24, and 30

6. 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72.

Hope this helps!

Hey there!

SIMPLIFYING #4

Question reads….

“56 is _____ times as many as _____”

~ The factors of 56 is/are

• 1, 2, 4, 7, 8, 14, 28, & 56

~ The factor pairs of 56 is/are

• 1 × 56 = 56
• 2 × 28 = 56
• 4 × 14 = 56
• 7 × 8 = 56

~ So, for the FIRST portion we can day

“56 is _2_ times as many as _28_”

(or you could choose any numbers from your factoring pair !)

SIMPLIFYING #5

Question reads….

“List the first five multiples of 6”

~ Meaning of multiples

• Multiples is any number that can be divided EVENLY without any remainders.

~So, the first five multiples are….

• 6, 12, 18, 24, & 30

SIMPLIFYING #6

Question reads….

“Name all the factors of 72”

~ Meaning of factoring/factor
• Factoring is another name for factorizing/factorization. It is basically a number that when you’re multiplying with another number that produces a number or expression

~ So, the factors of 72 is/are….

• 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36 , & 72

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Using Gauss's method, the sum of the numbers in the given series [ 15 11 7 . . . . ( –129 ) ] is -2664.

An arithmetic sequence is simply a sequence of numbers in which the difference between the consecutive terms is constant.

From Gauss's method nth term is an arithmetic sequence is expressed as;

n = (( first term - last term )/d) + 1

d is the common difference between terms.

Given the series in the question;

15 11 7 . . . (–129)

d = 15 - 11 = 4

Next, we find n

n = (( first term - last term )/d) + 1

n = (( 15 - (-129))/4) + 1

n = ( 144/4 ) + 1

n = 36 + 1

n = 37

Now, using the common difference between terms the sun will be;

S = 15 + 11 + 7 . . . -125 -129

Also

S = -129 -125 . . . + 7 + 11 + 15

We add

2S = -114, 114, 114 . . . . n

Hence, the sum will be;

2S = ( -114 ) × n

2S = ( -114 ) × 37

2S = -5328

S = -5328 / 2

S = -2664

Therefore, using Gauss's method, the sum of the numbers in the series [ 15 11 7 . . . (–129) ] is -2664.

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The number of cookies baked by Tanya in 12 batches of 18 cookies per batch including 70 cookies of Monday is 286.

A mathematical model or function is the model which is used to explain any system, the effect of the components by study and estimate the functions of systems.

The total number of cookies made by Tania on the Monday is 70 and want to make more than this on Tuesday.

The capacity of the pan is to cook 18 cookies per batch. The function she used to predict the number of cookies is,

y=70+18(x)

Here, x is the number of batches.

The cookies baked by her in 12 batches,

y=70+18(x)

y=70+18(12)

y=286.

Thus, the number of cookies baked by Tanya in 12 batches of 18 cookies per batch including 70 cookies of Monday is 286.

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Answer: The answer would be A. A flower being pink and a flower being a rose are independent of each other.

Step-by-step explanation:took the test and it was correct on edmentun!!

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ P(\stackrel{x_1}{5}~,~\stackrel{y_1}{7})\qquad Q(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ PQ=\sqrt{[-1 - 5]^2 + [-1 - 7]^2}\implies PQ=\sqrt{(-6)^2 + (-8)^2} \\\\\\ PQ=\sqrt{36+64}\implies PQ=10[/tex]

Answer:

Step-by-step explanation:

45÷8 = 5.625

1. Major Arc

2. Semicircle

3. Minor Arc

An arc whose measure is less than 180 degrees is called a minor arc.

An arc whose measure is greater than 180 degrees is called a major arc.

An arc whose measure equals 180 degrees is called a semicircle, since it divides the circle in two.

1. The arc ZMF defines a major arc as the measure is more than 180.

2. Arc TFM defines semicircle as it measure 180 degrees.

2. Arc TZ defines a minor arc as the measure is less than 180.

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Answer:

(2, 11)

Step-by-step explanation:

Using the information you were give, plug it into this formula:

(x₁ + x₂)/2, (y₁ + y₂)/2

This should give you a new coordinate.

The graph is a linear inequality, and the inequality that describes the graph is y < 2x - 1

From the graph, we have the following features:

Next, we calculate the slope using:

[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]

So, we have:

[tex]m = \frac{1 + 1}{1 - 0}[/tex]

m = 2

The inequality is then calculated using:

y < mx + b

This gives

y < 2x - 1

Hence, the inequality that describes the graph is y < 2x - 1

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The tangent lines of the cubic function f(x) = x(x - 2)(x - 6) at the zeros 0, 2 and 6 are y = 12x, y = -8x + 16 and y = 24x - 144

The cubic function is given as:

f(x) = x(x - 2)(x - 6)

Expand

f(x) = x³ - 8x² + 12x

Differentiate the function

m = 3x² - 16x + 12

At the point x = 0, we have:

m = 3(0)² - 16(0) + 12

m = 12

Also, we have:

f(0) = 0

A linear equation is represented as:

y = m(x - x₁) + y₁

So, we have:

y = 12(x - 0) + 0

y = 12x

At the point x = 2, we have:

m = 3(2)² - 16(2) + 12

m = -8

Also, we have:

f(2) = 0

A linear equation is represented as:

y = m(x - x₁) + y₁

So, we have:

y = -8(x - 2) + 0

y = -8x + 16

At the point x = 6, we have:

m = 3(6)² - 16(6) + 12

m = 24

Also, we have:

f(6) = 0

A linear equation is represented as:

y = m(x - x₁) + y₁

So, we have:

y = 24(x - 6) + 0

y = 24x - 144

The above means that the tangent lines are:

y = 12x, y = -8x + 16 and y = 24x - 144

From the attached graph, we can see that the tangent lines at the zero values x = 0 and x = 2 intersect the graph of f(x) at the zero value x = 6

The equation is given as:

f(x) = (x - a)(x - b)(x - c)

To prove the statement using a computer algebra system, simply follow the next steps:

See attachment (2) for proof

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Answer:

q=-5

Step-by-step explanation:

8q+6=4q-14

Remove q from one side

8q+6=4q-14

-4q    -4q

4q+6=-14

Remove 6 from both sides

4q+6=-14

    -6   -6

4q=-20

Divide 4 to isolate q

4q/4=-20/4

q=-5

Hey ! there

Answer:

Step-by-step explanation:

The question says that two consecutive Integer have a sum of 195 . And we are asked to find the integers.

For finding integers we are assuming them . So ,

Solution : -

According to question ,

So ,

[tex] \dashrightarrow \qquad \: x + x + 1 = 195[/tex]

Step 1 : Adding like terms ( x and x ) on left side :

[tex] \dashrightarrow \qquad \: 2x + 1 = 195[/tex]

Step 2 : Subtracting 1 on both sides :

[tex] \dashrightarrow \qquad \: 2x + \cancel{1} - \cancel{1} = 195 - 1[/tex]

Simplifying it ,

[tex] \dashrightarrow \qquad \: 2x = 194[/tex]

Step 3 : Dividing with 2 on both sides :

[tex] \dashrightarrow \qquad \: \dfrac{ \cancel{2}x}{ \cancel{ 2}} = \cancel{\dfrac{194}{2} }[/tex]

On further calculations , We get :

[tex] \dashrightarrow \qquad \: \purple{\underline{\boxed{\frak{ x = 97}}}} \quad \: \bigstar[/tex]

We know that ,

✰ Therefore , first number is 97 .

✰ Therefore , second number is 98.

Verifying : -

Now , we are verifying our answer by substituting value of first and second number and equating it with 195 . So ,

Therefore , our solution is correct .

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[tex]\blue{\textsf{\textbf{\underline{\underline{Question:-}}}}[/tex]

                Two consecutive integers have a sum of 195. Find the integers

[tex]\blue{\textsf{\textbf{\underline{\underline{Answer:-}}}}[/tex]

The integers are 97 and 98.

[tex]\blue{\textsf{\textbf{\underline{\underline{How to Solve:-}}}}[/tex]

                 If integers are [tex]\textbf{consecutive,}[/tex] they stand right next to each other.

Example:- 7 and 8. 7 and 8 are consecutive integers because they stand right next to each other.

Now, let the integer be n.

The integer next to n is 1 greater than n, or n+1.

So we set up the following equation:-

[tex]\bigstar{\fbox{n+n+1=195}[/tex]

[tex]\textsf{\underline}}[/tex]Add the n's:-

[tex]\Longrightarrow[/tex] [tex]\sf{2n+1=195}[/tex]

Subtract 1 on both sides:

[tex]\sf{2n=195-1}[/tex]

[tex]\sf{2n=194}[/tex]

Divide by 2 on both sides:-

[tex]\bigstar{\fbox{n=97}[/tex]

Now that we've found the first integer, finding the second integer is easy, because we can subtract the first integer from the sum of both integers:-

195-97=98

So the second integer is 98.

Quick Check:-

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Let's learn the relationship

So Area is directly proportional to length

The Garden B has largest area

But hang on this is incorrect it's rectangle other side might be too long .

We can calculate also

For garden A

Area

LB

For garden B

Area

Surprisingly assumption at first turned right

Garden A has highest area not Garden B

Answer:

Garden A

Step-by-step explanation:

Formula

(where w is the width and l is the length)

Given:

Using the formula for the perimeter to calculate the missing side length:

Perimeter = 2(w + l)

⇒ 120 = 2(25 + l)

⇒ 120 = 50 + 2l

⇒ 2l = 70

⇒ l = 35 ft

Therefore, the dimensions of Garden A are:

Area = w × l

⇒ Area of Garden A = 25 × 35

                                  = 875 ft²

Given:

Using the formula for the perimeter to calculate the missing side length:

Perimeter = 2(w + l)

⇒ 120 = 2(w + 50)

⇒ 120 = 2w + 100

⇒ 2w = 20

⇒ w = 10 ft

Therefore, the dimensions of Garden B are:

Area = w × l

⇒ Area of Garden B = 10 × 50

                                  = 500 ft²

As 875 > 500, Garden A has the largest area.

Answer:

x=-5

Step-by-step explanation:

Answer:

Equation of the perpendicular line is x = -5

Step-by-step explanation:

The equation of the given line is y =-3

This means that the given line is parallel to the x axis. Imagine a horizontal line and for all values of x, the y value is constant -3. So the line perpendicular to this line would be one that is parallel to the Y axis. Imagine a vertical line. This line would have the same x value for all values of Y. Equation would be of the form

x = constant.

It is given that the line passes through (-5, -3), from which we get that constant value as -5.

Equation of the perpendicular line is x = -5

Answer:

the answer is b

Step-by-step explanation:

ive did it before

Answer:

y=8

Step-by-step explanation:

SR=2×SG

AND SG=GR

3y-16=2×4

3y-16=8

3y=8+16

3y=24

y=8

Answer:

27.5

Step-by-step explanation:

<DAC is an inscribed angle that subtends a half circle, so m<DAC = 90°.

Triangle DAC is a right triangle.

CD = 30

AD = 12

(AC)² + (AD)² = (CD)²

(AC)² + 144 = 900

AC = √756

AC = 27.5

Answer:

630 word

10.5 minute: 10×60+0.5×60=600+30=630 second

60 word 60second

? word 630 second

?=630

Step-by-step explanation:

630 words !?! Because 10.5×60=630

Answer:

answer is 152

Step-by-step explanation:

i mutiplied $16 and $8 and got 128 the subtracted 128 and 280 and final answer is 152

Answer:

y = 2x - 6

Step-by-step explanation:

     Equation of the line:

            [tex]\sf \boxed{ y = mx +b}[/tex]

      Here m is the slope and b is the y-intercept.

Step 1:  Find the slope

       (3 , 0) ⇒ x₁ = 3  & y₁ = 0

       (4 , 2) ⇒ x₂ = 4  &  y₂ = 2

      [tex]\sf \boxed{Slope=\dfrac{y_2-y_1}{x_2-x_1}}[/tex]

                [tex]\sf = \dfrac{2 -0}{4-3}\\\\= \dfrac{2}{1}\\\\=2[/tex]

Step2: Now, substitute the value of 'm' in the equation.

    y = 2x + b

Step3: In the above equation plug in any point. Here, (3 ,0) is chosed.

      0 = 2*3 + b

      0 = 6 + b

      -6 = b

Step4: Equation of the line:

Answer:

Well We  need to get rid of 1200 mb so your estimated guess would be to delete~2523~ photos If i get this wrong Im very sorry.

Step-by-step explanation:

The standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin and directrix is y² = 16x.

It is the locus of a point that moves so that it is always the same distance from a non-movable point and a given line. The non-movable point is called focus and the non-movable line is called the directrix.

Given that the parabola's vertex is located at the origin and that the directrix is at x = -4, the focus is at (4,0).

Then the equation can be written as

[tex]\rm \sqrt{(x-4)^2 +(y-0)^2} = \sqrt{(x+4)^2 + (y-y)^2}\\\\\sqrt{(x-4)^2 +(y-0)^2} = \sqrt{(x+4)^2}[/tex]

On squaring both sides, we have

[tex]\begin{aligned} (x-4)^2 +(y-0)^2 &= (x+4)^2 \\\\x^2 + 16 - 8x +y^2 &= x^2 + 16 + 8x\\\\y^2 &= 16x \end{aligned}[/tex]

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