please help! help! help!.. Two metal spheres of the material and of equal radius R are touching each other .show the force of attraction between them is proportional to
[tex]r {4}[/tex]


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Answer:

Microwaves are basically extremely high frequency radio waves, and are made by various types of transmitter. In a mobile phone, they're made by a transmitter chip and an antenna, in a microwave oven they're made by a "magnetron". Their wavelength is usually a couple of centimetres. Stars also give off microwaves.

The simplest definition of a black hole is an object that is so dense that not even light can escape its surface. If we squished the Earth's mass into a sphere with a radius of 9 mm, the escape velocity would be the speed of light. Just a wee-bit smaller, and the escape velocity is greater than the speed of light.

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Answer:

q = 1.84×10^-8coulombs

Explanation:

Surface area = 4πr²

r is the distance

1.2 = 4(3.14)r²

1.2 = 12.56r²

r² = 1.2/12.56

r² = 0.0956

r = √0.0956

r = 0.309m

Get the charge C

V = kq/r

536 = 9.0×10^9q/0.309

536×0.309 = 9×10^9q

165.73 = 9×10^9q.

q = 165.73/9×10^9

q = 1.84×10^-8coulombs

Answer:

Displacement = 70 m towards east

Explanation:

Displacement is the shortest distance between the two points.

Let us say that he starts at the point O and travels in a path ABC.

If we join the initial and final point of the path travelled by him, it will give the displacement of the man.

Distance from O to A = 40 m

Distance from A to B = 70 m

Distance from B to C = 40 m

Distance from O to A = Distance from B to C

We want the displacement which is distance between the points O and C

In rectangle opposite sides are equal. Hence Distance from O to C = Distance from A to B

Displacement = Distance from A to B

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Answer:

Displacement = 70 m towards east

Explanation:

Please provide options.

Answer:

It requires a high initial investment

Explanation:

Answer:

20000sin(40) V

Explanation:

Consider component to the east of electric field:

[tex]E_{x} =4000 sin(40)[/tex]

The charge move along this component for 5 meter

Potential difference:

[tex]5E_{x} =20000sin(40)[/tex] = 12900 V (corr, to 3 sig,fig.)

The potential difference through which the charge moved is approximately 20.0 V.

To calculate the potential difference (ΔV) through which the charge moved, we can use the formula:

ΔV = q * E * d * cos(θ)

where:

q = charge = 30.0 uC = 30.0 x 10⁻⁶ C (converted to coulombs)

E = electric field = 4000 V/m

d = displacement = 5.00 m

θ = angle between the electric field and the displacement = 40.0°

Now, substitute the values into the formula:

ΔV = (30.0 x 10⁻⁶ C) * (4000 V/m) * (5.00 m) * cos(40.0°)

First, convert the angle to radians:

θ_radians = 40.0° * (π/180) ≈ 0.6981 radians

Now, calculate ΔV:

ΔV = (30.0 x 10⁻⁶ C) * (4000 V/m) * (5.00 m) * cos(0.6981) ≈ 0.02 V

So, the potential difference through which the charge moved is approximately 20.0 V.

To learn more about potential difference, here

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Answer:

Numerous studies have shown that the economic costs of divorce fall more heavily on women. After separation, women experience a sharper decline in household income and a greater poverty risk (Smock 1994; Smock and Manning

Answer:

sadness and stress...................

Answer:

0.25 or 1/4

Explanation:

................

Answer:

EMF = 1.1929 V

Explanation:

In this case we need to use the following expression:

EMF = B *ΔA / t   (1)

Where:

B: Magnetic field

ΔA: Difference of area of the balloon

t: time

To get the area, we have the innitial diameter of the balloon, and the expanded diameter when the balloon is blown up, so, assuming the circunference of the balloon, the area can be determined with:

A = π r²   (2)

So, let's calculate the Area of the balloon before and after the blown. Remember to use the units in meter (I just divided the diameter by 2 to get the ratio, and then divide by 100 to convert the units of cm to m)

A₁ = π * (0.105)² = 0.0346 m²

A₂ = π * (0.155)² = 0.0755 m²

Now that we have both areas, let's calculate ΔA:

ΔA = A₂ - A₁

ΔA = 0.0755 - 0.0346 = 0.0409 m²

Finally, we can determine the value of the EMF, using (1):

EMF = 1.4 * 0.0409 / 0.048

Hope this helps

Answer:

Explanation:

At both interface light is travelling from a medium of lower refractive index to medium of higher refractive index. So the phase difference of 180⁰ occurring  at both interface will cancel out .

Net path difference = 2 μ t where μ is refractive index of thin layer and t is its thickness

For destructive interference

2 μ t  = (2n + 1 )λ / 2 where λ is wavelength of light , n is any number

λ = 4  μ t / ( 2 n + 1 )

For largest wavelength , n = 0

λ = 4  μ t

= 4 x 1.22 x 138 nm

= 673.44 nm .

This question is incomplete, the complete question is;

An automobile tire is filled to a gauge pressure of 200 kPa when its temperature is 20°C (Gauge pressure is the difference between the actual pressure and atmospheric pressure.)

After the car has been driven at high speeds, the tire temperature increases to 55°C

(a) Assuming that the volume of the tire does not change and that air behaves as an ideal gas, find the gauge pressure of the air in the tire. (kPa)

(b) Calculate the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent. (kPa)

Answer:

a) the gauge pressure of the air in the tire is 236 kPa

b) the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent is 205.33 kPa

Explanation:

Given the data in the question;

Gauge pressure at 20°C = 200 kPa

Absolute pressure at 20°C is; p = 200 + 101.3 = 301.3 kPa

Initial temperature T = 20°C = 20 + 273 = 293 k

Final temperature T" = 55°C = 55 + 273 = 328 K

Now, at constant volume, P"/P = T"/T  

P"T = PT"

P" = PT" / T

P" = PT" / T

we substitute

P" = ( 301.3 × 328 ) / 293

P" = 98826.4 / 293

P" = 337.29

so Gauge pressure at 55°C is;

⇒ P" - 101.3

⇒ 337.29 - 101.3 = 235.99 ≈ 236 kPa

Therefore, the gauge pressure of the air in the tire is 236 kPa

b)

Final Volume V'' = V + 10% of V  

V" = V + 0.1V

V" = 1.1V

we know that;

P"V"/T" = PV/T

P" = P (T"/T)(V/V")

we substitute

P" = 301.3 (328 /293 )(V/1.1×V)

P" =  × 1/1.1 × V/V

P" = 337.29 × 1/1.1  

P" = 306.628 kPa

so, absolute pressure at 55°C = 306.628 - 101.3 = 205.33 kPa

Therefore, the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent is 205.33 kPa

Answer:

B) 8480 J

Explanation:

From the question,

The work required to turn the Crank in on turn is

W = 2πT................ Equation 1

Where W = work, T = torque.

Given: T = 4.50 Nm, π = 3.14

Substitute into equation 1

W = 4.5(2)(3.14)

W = 28.26 J per turn.

For 300 full tern,

W = 28.26×300

W = 8476 J

Hence,

W≈ 8480 J.

The right answer is B) 8480 J

Answer:

Fnet = 14515.2 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

[tex] Fnet = Fapp + Fg[/tex]

Where;

Given the following data;

Mass = 1,152 kg

Initial velocity, u = 3m/s

Final velocity, v = 17m/s

Time, t = 5 seconds

To find the magnitude of the net force;

First of all, we would determine the acceleration of the car.

Acceleration = (v-u)/t

Acceleration = (17 - 3)/5

Acceleration = 14/5

Acceleration = 2.8m/s

To find the applied force;

Fapp = mass * acceleration

Fapp = 1,152 * 2.8

Fapp = 3225.6 N

Next, we would find the force exerted on the car due to gravity.

Fg = mass * acceleration due to gravity

We know that acceleration due to gravity is equal to 9.8m/s²

Fg = 1152 * 9.8

Fg = 11289.6N

Substituting the values into the equation, we have;

Fnet = 3225.6 + 11289.6

Fnet = 14515.2 Newton

Answer:

D

Explanation:

the answer is d because process of genetic recombination in bacteria in which genes from a host cell (a bacterium) are incorporated into the genome of a bacterial virus (bacteriophage) and then carried to another host cell when the bacteriophage initiates another cycle of infection

Answer:

a, The dimension of volume is L³

b. The dimension of speed = L/T

Explanation:

The three fundamental quantities are Mass, Length and time. Other physical quantities are obtained from or derived from these three. These other quantities are known as derived quantities. The units of the fundamental quantities are Kilogram (kg) for Mass, meters for length, and second for time.

In the given question:

a. Volume = length * breadth * height

since breadth and height all measure length, the dimension of volume becomes:

volume = length * length * length = L³

Thus, the dimension of volume is L³

b. Speed, v = distance/time

Distance measures length, therefore, the dimension of speed will be:

Speed = length / time = L/T

Therefore, the dimension of speed = L/T

Answer:

A dribble ends when the player touches the ball with both hands simultaneously or permits the ball to come to rest in one or both hands. The ball being touched with both hands simultaneously (dribble with both hands) is a double dribble

Nothing in the rulebook that says a player cannot start a dribble with two hands. A dribble can end when touching both hands simultaneously, but a single dribble is OK as long as you catch the ball

Explanation:

Answer:

No, so it's false you're correct.

Hope this helped

Answer:

5.51 m/s^2

Explanation:

Initial scale reading = 50 kg  

assume the greatest scale reading = 78.09 kg

Determine the maximum acceleration for these elevators

At rest the weight is = 50 kg

Weight ( F ) = mg = 50 * 9.81 = 490.5 N

At the 10th floor weight = 78.09 kg

Weight at 10th floor ( F ) = 78.09 * 9.81 = 766.11 N

F = change in weight

Change in weight( F ) = ma = 766.11 - 490.5 (we will take the mass as the starting mass as that mass is calculated when the body is at rest)

50 * a = 275.61

Hence the maximum acceleration ( a ) = 275.61 / 50 = 5.51 m/s^2

Answer:

The mole (symbol: mol) is the unit of measurement for amount of substance in the International System of Units (SI). It is defined as exactly 6.022 140 76 × 1023 particles, which may be atoms, molecules, ions, or electrons.

Explanation:

Answer:

a lever and a wheel and axle (i guess)

Explanation:

don't have any

Answer:

c) both have the same angular displacement

Explanation:

In this scenario, girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. Therefore, both have the same angular displacement.

Answer:

E = 4156.02 Vm⁻¹

Explanation:

The magnitude of the uniform electric field between the plates can be given by the following formula:

[tex]E = \frac{\Delta V}{d}\\[/tex]

where,

E = Electric field strength = ?

ΔV = Potetial Difference = 293 V

d = distance between plates = 7.05 cm = 0.0705 m

Therefore,

[tex]E = \frac{293\ V}{0.0705\ m}\\\\[/tex]

E = 4156.02 Vm⁻¹

Answer:

Follows are the solution to this question:

Explanation:

The magnetic force is parallel to a  [tex]\bar{V} \times \bar{B}[/tex] axis, through right law. The direction would be in a reverse way for a positive particle. The gravitational flux is upward.

1) Its magnet strength will be directed westward.

2) The [tex]\bar{V} \times \bar{B}[/tex] path is parallel to the east. The permanent magnet is oriented against the south so because the object is considered impolite.

3) Its gravitational field of the velocity v of the object is zero. Thus no force was its solution.

4) The magnetic field and velocity are all on the same track. The magnetic strength is also zero. Consequently, the answer is no power.

5) Its gravitational field is to the south.

6) Its magnetic field, as well as the speed, are different. Which magnet strength is also zero. Consequently, no power is the answer.

7) Accessible in French only. The  [tex]\bar{V} \times \bar{B}[/tex] direction parallel to the east. Its magnetic energy is guided west because the particle is charged negatively.

8) Unless the particle velocity is 0, the magnetic strength is 0. Consequentl, no power is the response.

9) Its magnet power is from the north.

10) Another one of these: The  [tex]\bar{V} \times \bar{B}[/tex]  is parallel to the west. Its gravitational field is oriented to the east as the object is negatively charged.

11) The Pope said the following: The [tex]\bar{V} \times \bar{B}[/tex]  direction is parallel to the south. The gravitational fluid is transmitted towards the North because a particle is considered impolite.

12) The gravitational field is from the east.

Answer:

Tangential speed or Rotational speed

Answer:

work  done=Fs

Explanation:

F : force

s : displacement

by definition

Explanation:

The potential energy of two particles system will be given by the negative of work by gravitational force due to particle (1)as the second particle is brought from infinity : Gravitational potential energy Second particle is brought in the gravitation of first particle.

Answer:

The goal of physics is to understand how things work from first principles. ... Courses in physics reveal the mathematical beauty of the universe at scales ranging from subatomic to cosmological. Studying physics strengthens quantitative reasoning and problem solving skills that are valuable in areas beyond physics

Answer:

you get to understand why things happen this way

Explanation:

for example, are you not curious about why when standing in the bus and when the bus stops, you will might feel like you are going to fall ,

why does this happen because....

newton's laws explains it,

inertia causes you to be reluctant to change your initial state of motion due to your mass so you fall because you are still moving at the 'speed of the bus ' , something in like that

hope this helps,

please mark also

Answer:

[tex]d=1.98\times 10^{11}\ m[/tex]

Explanation:

Messages from the Perseverance Rover on Mars reach Earth in 11 min i.e. time is 660 s

The speed of light is [tex]3\times 10^8\ m/s[/tex]

We need to find the distance between Mars and Earth. Let the distance be d.

We know that,

Distance = speed × time

So,

[tex]d=660\times 3\times 10^8\\\\d=1.98\times 10^{11}\ m[/tex]

So, Mars is [tex]1.98\times 10^{11}\ m[/tex] from the Earth.