please help explain how to do this

Answer:

The other piece is moving at 170 m/s.

Explanation:

To find the speed of the second piece can be found by conservation of linear momentum:  

[tex] p_{i} = p_{f} [/tex]

[tex] m_{1}v_{1} = m_{2}v_{2} + m_{3}v_{3} [/tex]

Where:

m₁: is the rocket's mass = 0.5 kg      

m₂ = m₃: is the mass of the two equal pieces = 0.25 kg

v₁: is the rocket speed = 90 m/s

v₂: is the speed of the first piece = 10 m/s

v₃: is the speed of the second piece =?

[tex] 0.5*90 = 0.25(10 + v_{3}) [/tex]

[tex] v_{3} = \frac{45}{0.25} - 10 = 170 m/s [/tex]

Therefore, the other piece is moving at 170 m/s.

I hope it helps you!                                                                   

Answer:

The new angle of deflection north pole becomes smaller.

Explanation: The angle of deflection is the angle formed when an object changes course from its original course of direction or target.

The angle of deflection of a particular particle is directly proportional to its charge to mass ratio as it passed through an electric field.

As the wire is continously being lowered farther from the compass,the angle of deflection of the north pole ontinues to become smaller when compared to its initial deflection.

Am assuming the  B-field has an rms strength of 1.10×10−10T which was omitted

Answer:  E=1.686 x10⁻⁸J/hr

Explanation:

Intensity for electromagnetic wave is given as

I= cε₀(Emax)²....... equation 1

Also

B=Emax/c   ....... equation 2

puting the value of B in equation 2 in equation 1 becomes

I= cε₀(Emax)²

I= c³ε₀B²

where

c = speed of light = 3 X 10⁸m/s

ε₀=permittivity of free space = 8.85x 10-12 F m-1

B=1.10×10−10T

I= (3 X 10⁸m/s)³ X (8.85 X 10⁻12F/m) x(1.10×10−10T)²

I=2.891 X 10⁻⁶ W/m²

Energy per unit hour

E= IAt

= 2.891 X 10⁻⁶ W/m² x πr²x 3600

2.891 X 10⁻⁶ W/m² x 3.142 x ( 1.80 x 10⁻³/2) x(3600/1hr)

E=1.686 x10⁻⁸J/hr

The total energy transported per hour will be 6.62 × 10⁻⁹J

The Intensity for an electromagnetic wave is given by:

I = cε₀E₀²

where c is the speed of light, and

E₀ is the maximum value of the electric vector

Also

B = E/c  

where B is the magnetic field

Therefore:

I= cε₀E₀²

I= c³ε₀B²

Given that the magnetic field is:

B = 1.10×10⁻¹⁰ T

I= (3 X 10⁸m/s)³ X (8.85 X 10⁻12F/m) x(1.10×10−10T)²

I=2.891 X 10⁻⁶ W/m²

Energy transported per unit hour

E= IAt

where A is the area

and t is the time = 1hr = 3600s

E = 2.891 × 10⁻⁶  × πr² × 3600

E = 2.891 X 10⁻⁶ ×  3.14 × ( 1.80 x 10⁻³/4)² x (3600)

E = 6.62 × 10⁻⁹J

Learn more about electromagnetic waves:

https://brainly.com/question/13803241?referrer=searchResults

Answer:

KE=1.58J

Explanation:

In this problem we are required to solve for the total energy

"The kinetic energy is the energy possessed by a body by virtue of motion"

KE=1/2mv²

Given

Mass m=7.73g

Velocity v=409m/s

In kg= 0.00773kg

KE=1/2*0.00773*409

KE=3.16157/2

KE=1.58J

Answer:

h = 52.24 m

Explanation:

Given that,

A penny is dropped from the top of the hotel in New York. It hits a tourist in the head at 32 m/s.

Let it falls at a height of h.

We can find the value of h using the conservation of energy such that,

[tex]\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(32)^2}{2\times 9.8}\\\\h=52.24\ m[/tex]

So, it will fall at a distance of 52.24 m.

Answer:c

Explanation:

I have it

Answer:

C.

insomnia

Explanation:

plato answer

Answer:

vf = 3 m/s

Explanation:

       [tex]\Delta K = \frac{1}{2}* m* (v_{f}^{2} -v_{o} ^{2} ) = W_{Ffr} (1)[/tex]

Replacing for the givens, we get:

[tex]\Delta K = \frac{1}{2}* 20kg* (v_{f}^{2} -(5 m/s) ^{2} ) = -20 m * 8 N (2)[/tex]

[tex]v_{f} = \sqrt{-16 (m/s)2 + 25 (m/s)2} = \sqrt{9 (m/s2)} = 3 m/s[/tex]

vf = 3 m/s

Answer:

A

Explanation:

because it is used in tvs all the time

Answer:

We are given both the Force applied by the truck and the acceleration of the  truck:

Force applied (F) = 14,000 N

Acceleration (a)=  5 m/s²

Solving for the mass of the truck:

From Newton's second law of motion,

F = ma    (where F is the force applied , m is the mass of the object and a is the acceleration of the object)

replacing the variables:

14000 = (m)* 5

m = 14000/5

m = 2800

Therefore, the mass of the truck is 2800 kg

Answer:

m = 2800 N

Explanation:

14000 = (m)* 5

m = 14000/5

F= 14,000 N

a= 5 m/s^2

Answer:

A

Explanation:

if you divide the 8100 km by the 27 hours you will get 300 km per hour

Answer: there are multiple

Explanation:

light from a torch, the heat from a fire, and the sound of a police siren. You cannot hold, taste, or smell these things. They are not types of matter, but forms of energy.

Answer:

4m/s^2

Explanation:

According to newton's second law of motion:

F= ma

a= F/m

F =220N

m =55kg

a= 220/55

= 4m/s^2

Answer:

no

Explanation:

Answer:

No non-conservative forces, such as friction, act between objects within the system

Explanation:

The law of conservation of mechanical energy in a closed system states that;'The total amount of mechanical energy, in a closed system in the absence of non-conservative forces, such as friction, remains constant.' Non-conservative forces  cause energy to be lost from the system, this lost energy can't be gotten back

This implication of this is that energy can not disappear. Kinetic energy can be converted into potential energy and vice-versa in accordance with this principle.

Answer:

25776J

Explanation:

Recall that heat lost/gained is obtained from

H=mcθ

H= heat lost/gained

m= mass of water = 0.0100 kg

c= 4200 J/kg°C

θ = temperature

Heat gained by the water in rising to 100°

H=  0.0100 * 4200 * (100-22)

H= 3276 J

Latent heat of vaporization of water = mL

Latent heat of vapourization = 0.0100*(22.5*10^5)=22500J

Heat lost by iron = heat gained by water

total heat gained by water =

22500+3276=25776J

Answer:

Explanation:

efficiency of carnot engine = (Q₁ - Q₂) / Q₁ = (T₁ - T₂) / T₁

Q₁ = heat absorbed , Q₂ = heat rejected

T₁ = Temperature of source = 525 + 273 = 798 K

T₂ = Temperature of sink = 50 + 273 = 323 K

efficiency = (798 - 323) / 798

= 475 / 798 = .595

(Q₁ - Q₂) / Q₁ = .595

(250 - Q₂) / 250 = .595

250 - Q₂ = 148.75

Q₂ = 101.25 kJ

Heat rejected = 101.25 kJ .

output work = Q₁ - Q₂ = 250 - 101.25 = 148.75 kJ / s

power = 148.75 kJ /s

Answer:

4. Water stored in the tank has potential energy only.

Explanation:

when water begins to move the potential energy is converted into kinetic but until it is being used it has potential energy only.

Answer:

Explanation:

Given

speed of water balloon = 8.31m/s

Height of building = 23.0m

Required

Horizontal distance

First we need to get the time using the equation of motion

S  = ut + 1/2at²

23 = 0+1/2(9.81)t²

23 = 4.905t²

t² = 23/4.905

t² = 4.689

t = √4.689

t = 2.17secs

Next is to get the horizontal direction expressed as:

Sh = Vxt

Sh =  8.31 * 2.17

Sh = 17.99m

Sh ≈ 18m

Hence the horizontal distance of the object before striking the ground is approximately 18m

Answer:

Tension ( B )

Explanation:

When the fire hose is in use with water flowing through it and the hose is stationary, the coupling is in TENSION , this is because the force of flow in a stationary object will be in a compressive nature that will in turn cause the force on the coupling to be in a form of a Tension ( i.e. Tensile )

Answer:

Explanation:

cross sectional area = width x thickness

A = 30 x 10⁻² x 15 x 10⁻⁶ = 450 x 10⁻⁸ m

tensile strength F / A = 311 x 10⁶ N / m²

F = A x 311 x 10⁶

= 450 x 10⁻⁸ x 311 x 10⁶

= 139950 x 10⁻²

= 1399.5 N  .

Answer:

15 seconds

Explanation:

We can use this formula to solve this problem:

Velocity = Initial Velocity + Acceleration * Time

We know that initial velocity is 0, the velocity is 147, and acceleration is 9.8(because of earth's gravitational pull), so we can plug those numbers in and solve for time:

147 = 0 + 9.8*t

t = 15

Therefore, it will take 15 seconds for an object that falls from rest to reach 147 m/s.

Answer:

h = 40 m

Explanation:

       [tex]\Delta K = \frac{1}{2} * m* v_{b} ^{2}[/tex]  (2)

       where vb = speed at the bottom = 28 m/s

       [tex]\Delta U = U_{f} - U_{i} = 0- m*g*h = -m*g*h[/tex] (3)

       [tex]\frac{1}{2} * m* v^{2} = m*g*h[/tex]

       [tex]h = \frac{v_{b} ^{2} }{2*g} = \frac{(28m/s)^{2}}{2*9.8m/s2} = 40 m[/tex]

Answer:

Explanation:

Given

final speed v = 30.0m/s

initial velocity u = 0m/s

Time taken t = 1.00s

Required

constant acceleration of the police car a

Substitute the given parameters into this equation of motion

v = u + at

30 = 0 +1a

30 = a

a = 30.0m/s²

Hence the magnitude of the constant acceleration of the police car is 30.0m/s²

Answer:

Explanation:

we know that momentum is given as

P=mv

given data

P1=?

mass m1=100kg

velocity v1=7m/s

P2=?

mass m2=120kg

velocity v2=5m/s

the total momentum =P1+P2

total=m1v1+m2v2

total= 100*7+120*5

total=700+600

total= 1300kgm/s

total kinetic energy

KE total= 1/2m1v1^2+1/2m2v2^2

KE total= 1/2*100*(7)^2+1/2*120*(5)^2

KE total= 1/2*100*49+1/2*120*25

KE total= 1/2*4900+1/2*3000

KE total=2450+1500

KEtotal=3950 J

Answer:

More electrons become free due to the potential which are charge carriers. More the charge carriers, more the current.

Current causes a heating effect. Resistance of lead decreases/ n increases [I=nAve]. Current increase

Explanation:

Answer:

1975 ohm

Explanation:

The maximum current that can pass through the galvanometer is 50.0µA

p.d across the galvanometer at a full scale deflection is given by

V = IR

V = (50.0×10^-6)*25

V1 = 1/800 or 0.00125volts

Since the p.d across the multiplier and galvanometer at full scale deflection is 0.100volts,the p.d across the multiplier alone must be given by

V2 = 0.100-0.00125

= 0.09875volts

Current passing through the multiplier is (50.0×10^-6)A

Hence if R is the resistance of the multiplier, we have that

V2 = (50.0×10^-6)×R

0.09875volts = (50.0×10^-6)×R

Divide both sides by 0.09875volts

R = 0.09875/(50.0×10^-6)

R =( 0.09875) ÷ 1/20000

R = 0.09875×20000

R = 1975 ohms

Answer: the coefficient of restitution of the ball for a collision with asphalt=0.95

Explanation:

Initial height of the bounce from the ball, h  =2.47m

height of the 5th bounce of the ball , h₁= 1.51m

Making e the coefficient of the restitution, then the height covered by the ball after the 5th bounce is

h₁= e²ⁿh

Where n = 5

h₁= e²⁽⁵⁾h

e¹⁰=h₁/h

e¹⁰=1.51/2.47

e= (1.51/2.47)¹/¹⁰

e=0.95198≈ 0.95

Therefore, the coefficient of restitution of the ball for a collision with asphalt is 0.95

Answer:

The average force exerted on a person assuming that the water splashes sideways in all directions is 150 newtons.

Explanation:

From Fluid Mechanics and Newton's Laws we know that water stream is an example of a variable mass system at constant speed and the magnitude of the net force done by the water splash ([tex]F[/tex]), measured in newtons, is given by the following expression:

[tex]F = \rho\cdot \frac{dV}{dt}\cdot v[/tex] (Eq. 1)

Where:

[tex]\rho[/tex] - Density of water, measured in kilograms per cubic meter.

[tex]\frac{dV}{dt}[/tex] - Volume flow rate, measured in cubic meters per second.

[tex]v[/tex] - Flow velocity, measured in meters per second.

If we know that [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]\frac{dV}{dt} = 0.03\,\frac{m^{3}}{s}[/tex] and [tex]v = 5\,\frac{m}{s}[/tex], the average force exerted on a person is:

[tex]F = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(0.03\,\frac{m^{3}}{s} \right)\cdot \left(5\,\frac{m}{s} \right)[/tex]

[tex]F = 150\,N[/tex]

The average force exerted on a person assuming that the water splashes sideways in all directions is 150 newtons.

Answer:

(a) the angle between the wire and field is 30⁰

(b) the force is 4.8 N

Explanation:

Given;

current in the wire, I = 8 A

magnetic field, B = 1.2 T

length of the wire, L = 50.0 cm = 0.5 m

magnetic force, F = 2.4 N

The magnetic force on the wire is given by;

F = BILsinθ

where;

θ is the angle between the wire and field

sinθ = F / BIL

sinθ = 2.4 / (1.2 x 8 x 0.5)

sinθ = 0.5

θ = sin ⁻¹ (0.5)

θ = 30⁰

(b) the force on the wire if it is rotated to make an angle of 90⁰

F = BIL(sin90⁰)

F = BIL(1)

F = BIL

F = 1.2 x 8 x 0.5

F = 4.8 N