Physics College

Our Sun has a radius of about 695,800 km and a mass of about 2.0 × 1030 kg, and rotates around its axis about once every 29 days.

Calculate the rotational velocity of the Sun.
Calculate the linear speed of particles on the outermost portion of the Sun.
Calculate the angular acceleration, tangential acceleration, and radial acceleration of the Sun.
Calculate the rotational (angular) momentum of the Sun, modeled as a uniform solid sphere. The rotational inertia of a solid sphere is (2/5)MR2.
Imagine that without any external objects interacting with it, the Sun were to collapse to the size of a neutron star, with a radius of about 15 km–about the size of Manhattan Island.

What would be its rotational inertia when it was finished collapsing?
What would be its rotational momentum when it was finished collapsing?
In what time interval would the Sun complete one rotation around its axis after it was finished collapsing

Answers

Answer 1

When a skater pulls in her arms, a kid starts up a merry-go-round from a stop, or a computer's hard disk slows to a stop when it is turned off, angular velocity is not constant.

Thus, There is an angular acceleration in each of these situations, in which changes. The angular acceleration increases with the rate of change. The rate at which angular velocity changes is referred to as angular acceleration.

The answer is that the air masses that generate tornadoes rotate, and their rate of rotation rises as their radii get smaller and angular velocity.

The skater begins her rotation by extending her limbs, then she pulls them in closer to her torso to increase the spin.

Thus, When a skater pulls in her arms, a kid starts up a merry-go-round from a stop, or a computer's hard disk slows to a stop when it is turned off, angular velocity is not constant.

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Answer 2

The rotational velocity or angular velocity of the sun is 2.5 x 10⁻⁶ rad/s.

The angular acceleration of the sun is 43.5 x 10⁻⁴ rad/s².

The angular momentum is 96.8 x 10⁴⁰kgm²/s.

Radius of the sun, R = 6.96 x 10⁸m

Mass of the sun, m = 2 x 10³⁰kg

Time period of the sun, T = 29 days = 2.51 x 10⁶s

Angular velocity is the rate of change in the angular displacement between two bodies or the pace at which an object revolves or rotates around an axis.

The rotational velocity or angular velocity of the sun is,

ω = 2π/T

ω = 2 x 3.14/2.51 x 10⁶

ω = 2.5 x 10⁻⁶ rad/s

The linear speed of particles on the outermost portion of the sun is,

v = Rω

v = 6.96 x 10⁸x 2.5 x 10⁻⁶

v = 1.74 x 10³m/s

The angular acceleration of the sun,

α = Rω²

α = 6.96 x 10⁸x (2.5 x 10⁻⁶)²

α = 43.5 x 10⁻⁴ rad/s²

The moment of inertia of the solid sphere, I = 2/5MR²

The expression for the angular momentum is given by,

L = Iω

L = 2/5 x 2 x 10³⁰ x (6.96 x 10⁸)² x 2.5 x 10⁻⁶

L = 96.8 x 10⁴⁰kgm²/s

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Related Questions

Air at 273K and 1.01x10³Nm2 pressure contains 2.70x1025 molecules per cubic meter. How many molecules per cubic meter will there be at a place where the temperature is 223K and pressure is 1.33x10 Nm-2​

Answers

The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

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