Answer:
32401
92012
65810
100000
A student walks from her car to a tree, 29 meters away at 1 m/s, and returns at 6 m/s. What is her average speed for the entire trip in m/s?
A 1391.3 kg car is traveling at 29.8 m/s when the driver takes his foot off the gas pedal. It takes 4.9 s for the car to slow down to 20 m/s. How large is the net force slowing the car
Answer:
Fnet = 2782.6 N
Explanation:
Newton's 2nd Law states that the net force applied to an object, is equal to its mass times the acceleration.By definition, acceleration is the rate of change of velocity with respect to time, as follows:[tex]a = \frac{\Delta v}{\Delta t}[/tex]
where Δv = vf - v₀ and Δt = tfi - t₀, replacing by the givens:
[tex]\Delta v = v_{f} - v_{o} = 20 m/s - 29.8 m/s = -9.8 m/s[/tex]
Δt = 4.9 s
⇒[tex]a = \frac{-9.8m/s}{4.9s} = -2 m/s2[/tex]
We can now apply Newton's 2nd Law, solving for Fnet, as follows:[tex]F_{net} = m* a = 1391.1 kg * (-2 m/s2) = -2782.6 N[/tex]
The magnitude of the is net force (How large it is ) is just:Fnet = 2782.6 N10a. Phoebe Physics pulls a 5 kg wagon with a force of 80 N. What is the
net force if the force of friction between the wagon and the ground is 12
N? *
Answer:
68 N
Explanation:
We have a force of 80 N going to one direction and 12 N to the other direction. we subtract 12 from 80 and get 68 N which is the total net force
The net force acting on the wagon is equal to 68 N.
What is the net force?The net force acting on an object can be defined as the vector sum of all forces acting. The net force is a single force that can give same the effect as the original forces on the object's motion.
The net force will be the resultant force with a similar effect on the rotational motion as all actual forces taken together by the object.
In the question, the applied force will act in the opposite direction of the frictional force so we need to subtract these two forces to find the net force.
Given, the applied force to push the wagon = 80 N
The frictional force between wagon and ground = 12 N
The net force on the wagon = 80N + (-12N) = 68 N
Therefore, the net force equal to 68 N will act in the direction of the applied force.
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6. If an object has an acceleration of –3 m/s?, describe its motion.
Answer:
Its motion is accelerating backward or changing velocity in a backward motion.
Explanation:
We know acceleration is a vector quantity, therefore, containing both magnitude and direction. The negative sign represent direction so here, it's representing a backward motion. The magnitude here is 3, meaning that is is moving at a changing velocity of 3 m/s, meaning each second, the velocity increases 3 m/s going backward.
David tosses an egg horizontally from the top of a building, with an initial velocity of 6.5 m/s. The building is 60m high. The time takes the egg to hit the ground is
Answer: 3.5 seconds
Explanation:
two cars A and B are 600 meters apart car A travels due east at some speed per on a collision course with car b which travels due west at half speed as car A if the two cars fatally collide with each other in 5 seconds how fast was car A going?
Answer:
Car A was going at 80 m/s
Explanation:
Let's call "x" the unknown speed of car A. In such case, the speed of car B would be x/2.
We proceed to describe the distance covered by car A (dA) in the 5 seconds it took to collide: dA = speed * time = x * 5 = 5 x
Now the distance covered by car B (dB) in the same time would be:
dB = speed * time = (x/2) * 5 = 5 x / 2
Now, we know that the distance that separated both cars was 600 meters, so the addition of what car A covered plus what car B covered must equal 600 m, and in equation form:
dA + dB = 600
5 x + 5 x / 2 = 600
combining like terms:
15 x / 2 = 600
multiplying both sides by 2:
15 x = 1200
divide both sides by 15:
x = 80 m/s
This is the speed of car A.
Find v2v1v2v1, the ratio of the speed v2v2v_2 of the two-block system after the first collision to the speed v1v1v_1 of the block of mass m1m1m_1 before the collision.
Answer:
v₂/v₁ = 0.777
Note: The question is incomplete. The complete question is given below;
A block of mass m1 1.40 kg moving at 12.00 m/s undergoes a completely inelastic collision with a stationary block of mass m2 0.400 kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 2.70 kg, which is initially at rest. The three blocks then move, stuck together, with speed v3.(Figure 1) Assume that the blocks slide without friction Express your answer numerically using three significant figures
Part A Find , the ratio of the velocity 2 of the two-block system after the first collision to the velocity V1 of the block of mass m1 before the collision.
Explanation:
Velocity, v₁ (of mass m₁) = 12.0 m/s
Velocity of the two masses after inelastic collision = v₂
According to the principle of conservation of linear momentum, momentum before collision is equal to momentum after collision
m₁u₁ + m₂u₂ = (m₁ + m₂)v₂
where m₁ = mass of first block = 1.40 kg
u₁ = initial velocity of first block = 12.0 m/s
m₂ = mass of second block = 0.40 kg
u₂ = initial velocity of second block = 0 m/s
v₂ = final velocity of the two-block system = ?
Substituting the values in the conservation of momentum formula
1.4 * 12 + 0.4 * 0 = (1.4 + 0.4) * v₂
16.8 + 0 = 1.8 * v₂
v₂ = 16.8/1.8
v₂ = 9.33 m/s
v₂/v₁ = 9.33/12.0
v₂/v₁ = 0.777
The ratio of the speed should be 0.777.
Principle of conservation of linear momentum:
Since
Velocity, v₁ (of mass m₁) = 12.0 m/s
The velocity of the two masses after inelastic collision = v₂
So,
m₁u₁ + m₂u₂ = (m₁ + m₂)v₂
here
m₁ = mass of first block = 1.40 kg
u₁ = initial velocity of first block = 12.0 m/s
m₂ = mass of second block = 0.40 kg
u₂ = initial velocity of second block = 0 m/s
v₂ = final velocity of the two-block system = ?
Now
1.4 * 12 + 0.4 * 0 = (1.4 + 0.4) * v₂
16.8 + 0 = 1.8 * v₂
v₂ = 16.8/1.8
v₂ = 9.33 m/s
So,
v₂/v₁ = 9.33/12.0
v₂/v₁ = 0.777
hence, The ratio of the speed should be 0.777.
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Evenly timed disturbances in a medium create a n) O A. periodic wave O B. pulse O c. electromagnetic wave D. compression wave
Answer: periodic wave
Explanation:
i just took a test and got it right
give an example of newton’s 1st law of motion at work (write a complete sentence and use the word inertia)
Answer:
A ball rolling will eventually stop because pf the force of inertia acting on the ball.
Explanation:
Capillaries are the largest of all blood vessels.
O True
O False
Answer:
FALSE
Explanation:
does velocity, speed, and rate acceleration change if it was dropped from a higher building?
Answer:
Your answer is correct, the rates would stay the same
Explanation:
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Answer:Never smoke ciga If you are a smoker, throw them away now! Smoking is the number one cause of preventable death. It causes many cancers, heart attacks, strokes, lung diseases, and other nonfatal problems, like stained teeth, poor athletic performance, erectile dysfunction, and bad breath. There is help available to quit, including free counseling at 1-800-QUIT-NOW and medications to ease the cravings. Ask your doctor for help. Stopping is the biggest favor you can do for yourself.
Which two factors have an effect on the gravitational force between two
objects?
A. Their masses
B. The strong nuclear force
C. Their charges
D. The distance between them
E. Electromagnetic force
Answer:
A. their masses
D. the distance between them
Explanation:
100% correct
Two factors have an effect on the gravitational force between two
objects are their masses and the distance between them.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.
f = Gmm/r²
Two factors have an effect on the gravitational force between two
objects are their masses and the distance between them.
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In a grocery store, you push a 15.5 kg shopping cart with a force of 10.5 N. If the cart starts at rest, how far does it move in 3.00 s?
Answer:
The distance moved by the cart is 3.05 m
Explanation:
Given;
mass of the cart, m = 15.5 kg
applied force, f = 10.5 N
initial velocity, u = 0
time of motion, t = 3s
The final velocity of the cart is given by;
[tex]F = ma\\\\F = m(\frac{v-u}{t})\\\\ m(v-u) = Ft\\\\m(v-0) = Ft\\\\mv = Ft\\\\v = \frac{Ft}{m}\\\\ v = \frac{10.5*3}{15.5}\\\\ v = 2.032 \ m/s[/tex]
The acceleration of the cart is given by;
F = ma
a = F/m
a = 10.5 / 15.5
a = 0.677 m/s²
The horizontal distance moved by the cart is given by;
s = ut + ¹/₂at²
s = 0 + ¹/₂ (0.677)(3)²
s = 3.05 m
Therefore, the distance moved by the cart is 3.05 m
An airplane lands with a speed of 91 m/s traveling due west. It comes to rest in 952 m with a constant deceleration. What is the plane’s acceleration?
Answer:
The acceleration of the plane is -4.35 m/s²
Explanation:
Given;
initial speed of the airplane after landing, u = 91 m/s
final speed of the airplane after landing, v = 0
distance traveled, s = 952 m
Apply the following kinematic equation to determine the acceleration of the airplane;
v² = u² + 2as
0 = u² + 2as
0 = 91² + (2 x 952)a
0 = 8281 + 1904a
- 8281 = 1904a
a = - 8281 / 1904
a = -4.35 m/s²
Therefore, the acceleration of the plane is -4.35 m/s².
Find the recoil velocity of a 65kg ice hockey goalie who catches a 0.15kg hockey puck slapped at him at a velocity of 50m/s. Assume that the goalie is at rest before catching the puck, and friction between the ice and the puck-goalie system is negligible.
Answer:
0.12m/sExplanation:
Given data
mass m1=65kg
velocity v1=?
mass m2=0.15kg
v2=50m/s
We know that the expression for the conservation of momentum is given as
0=m1v1+m2v2
we want to find v1
v1=(m2v2)/m1
v1=0.15*50/65
v1=7.5/65
v1=0.115
v1=0.12m/s
Therefore the recoil velocity is 0.12m/s
Which type of energy was transformed into thermal energy when the temperature of the two books increased?
Answer:
The energy of the motion of the chemistry book was transformed into thermal energy.
Explanation:
Answer:
The person above me has the exact answer!
Explanation:
Have a nice day
A billiard ball moving at 5.30 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 4.72 m/s, at an angle of θ = 27.0° with respect to the original line of motion. Assuming an elastic collision (and ignoring friction and rotational motion), find the struck ball's velocity after the collision.
Answer:
The velocity of the struck billiard ball after collision is 2.41 m/s at an angle of 62.8⁰.
Explanation:
Given;
initial velocity of the billiard ball, u₁ = 5.3 m/s
initial velocity of the second ball, u₂ = 0
final velocity of the first ball, v₁ = 4.72 m/s at θ = 27.0°
final velocity of the second ball, v₂ = ?
Apply the principle of conservation of kinetic energy;
¹/₂m₁u₁² + ¹/₂m₂u₂² = ¹/₂m₁v₁² + ¹/₂m₂v₂²
m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²
m₁u₁² + m₂(0) = m₁v₁² + m₂v₂²
m₁u₁² = m₁v₁² + m₂v₂²
m₁ = m₂
u₁² = v₁² + v₂²
v₂² = u₁² - v₁²
v₂² = (5.3)² - (4.72)²
v₂² = 5.812
v₂ = √5.812
v₂ = 2.41 m/s
The direction of the second ball is given by;
v₂sinθ = v₁sin27
sinθ = (v₁sin27) / (v₂)
sinθ = (4.72 x 0.454) / (2.41)
sinθ = 0.8892
θ = sin⁻¹ (0.8892)
θ = 62.8⁰
Thus, the velocity of the struck billiard ball after collision is 2.41 m/s at an angle of 62.8⁰.
A ball is thrown straight up in the air with a velocity of 12 m/s. Find the maximum height the ball
reaches.
Answer:
The maximum height is 7.34 meters.
Explanation:
This problem relates to a design competition in which a 1-kg battery-powered vehicle must be propelled up a 0.9-m tall ramp within a 15-second time interval. a. For a run time of 9 seconds, how much power must the battery supply to the vehicle
Answer:
P = 0.98 W
Explanation:
Given that,
Mass, m = 1 kg
Height, h = 0.9 m
(a) We need to find power must the battery supply to the vehicle for a run time of 9 seconds. Power is given by work done divided by time. It can be given by :
[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{1\times 9.8\times 0.9}{9}\\\\P=0.98\ W[/tex]
So, the required power is 0.98 W.
On June 17th 2003, in Santa Barbara, California, the morning low tide was measured at -0.365 m. High tide was measured at 1.12 . Calculate the tidal range between these tides.
A)there was no tidal range.
b)0.755 m
c)1.485 m
This cost a lot of points pls give me an amswer before 10:50 its k if its past 10:50
Answer:
I am not sure but I think it's choice c.
c)1.485 m
Explanation:
I hope this helps.
Which of the following is a way that joints can be classified
I can't see the joints maybe ball and socket
who discovered the relationship between the fluctuating period of variable stars and their intrensic brightness
Answer:
Leavitt
Explanation:
In the course of her work, Leavitt discovered 2,400 new variable stars, half the known ones in her day. A certain group of variable stars, later called Cepheid variables, fluctuate in brightness (luminosity) in a regular pattern called their “period.” This period ranges from about one day to nearly four months.
hope this helps have a good day and can i have brainliest plz
The study of the relationship between life stressors s and the body’s ability to fight illness is called____.
A-neurology
B-psychoneuroimmunology
C-behavioral medicine
D-health psychology
Answer:
Explanation:
We love biden! We love biden! We hate trump!
Like if you agree :)
If an object that is dropped from the roof of a building takes 12 seconds to hit the ground, how
tall is the building?
Answer:
The height of the building is 705.6 m
Explanation:
Given that,
When an object is dropped from the roof of a building, it takes 12 seconds to hits the ground.
We need to find the height of the building. Let it is h. Initially, the object was at rest. Using second equation of motion to find it as follows :
[tex]h=ut+\dfrac{1}{2}at^2[/tex]
Here, a = g and u = 0
[tex]h=\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}\times 9.8\times (12)^2\\\\h=705.6\ m[/tex]
So, the building is 705.6 m tall.
why Fahrenheit thermometer is used to measure human body temperature?
Answer:
Well that is not true we use both Celsius and Fahrenheit thermometer
it just depends on where you are from, If you are from Celsius dominated country you use Celsius to measure whereas if you are from Fahrenheit dominated country you use it to measure the body heat.
If you have seen money heist (a netflix show), Helsinki uses Celsius Thermometer to check the body temperature of Arturo BECAUSE in spain they use celsius thermometer.
HOPE MY ANSWER WAS HELPFUL xD
1. Imagine that you take a 200.0 km trip. You travel the first half of the trip at 100.0 km/hr. Your speed for the second half is 50.0 km/hr. How much time does the entire trip take?
2. In the above problem, what is your average speed in km/hr and m/s
Answer:
Explanation:
Speed = Distance/Time
Given
Distance = 200km
Total speed = 100+50 = 150km/hr
Time = Distance/Speed
Time = 200/150
Time = 1.33hr
b) Average speed in km/hr is 150km/hr
Convert to m/s
150km/hr = 150 * 1000 m/1 * 3600s
150km/hr = 150,000/360
150km/hr = 416.67m/s
Why does the man fly out of the car?
A. Newtons 1st Law
B. Newtons 2nd Law
C. Newtons 3rd Law
Compute the magnetic field intensity 2 cm from a long straight wire that carries a current of 10 A. Give the result in A/m and Oersteds.
Answer:
Explanation:
Magnetic field intensity = Current (A)/length of wire (m)
Given
Current = 10A
Length of wire = 2cm = 0.02m
Required
Intensity I
Substitute into formula
Intensity = 10/0.02
Intensity = 10 × 100/2
Intensity = 1000/2
Intensity = 500A/m
Thomson effect is the combined effect of Seebeck effect
and Peltier effect. Justify your answer.plz help me
Answer:
its c
Explanation: