Objects 1 and 2 attract each other with a electrostatic force

of 36.0 units. If the distance separating Objects 1 and 2 is

changed to one-half the original value (i.e., halved), then the

new electrostatic force will be units.

Answers

Answer 1

Answer:

F = 144 units

Explanation:

For this exercise we use coulomb's law, for the initial conditions

           F₀ = [tex]k \frac{q_1q_2}{r_o^2}[/tex]

indicate that the force F₀ = 36.0 units and the distance is reduced to r = r₀/2 which is the new force

          F = [tex]k \frac{ q_1q_2 }{(r_o/2)^2}[/tex]

           

we substitute

          F = 4 [tex]k \frac{q_1q_2}{r_o^2}[/tex]

          F = 4 F₀

we calculate

          F = 4 36

          F = 144 units


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Answers

A for the first one, B for the second

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At the top of the hill, the ball is at the maximum height. Because the equation for gravitational potential energy is ([tex]U_{g}[/tex] = mgH), we can safely conclude that the GPE at A, the top of the hill, is the greatest in all 4 options.

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Answers

Answer:

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Explanation:

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Answers

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Answers

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Answer:

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A ball has a 17 J of kinetic energy and its mechanical energy ls 25 Joule.



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Answers

Question:

A ball has a 17 J of kinetic energy and lB mechanical energy is 25 Joule

a. Find the gravitational potential energy of the ball.  

b. if the ball has a mass of 3.2 kg, what is its height above the ground?  

c. What is the speed of the ball?

Answer:

a.  = 85

b. h = 0.25 m

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Explanation:

Part A

PEgrav = m ו g • h

In the above equation, m represents the mass of the object, h represents the height of the object and g represents the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity. So, to find:

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Part B

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The vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

The equation may be written as:

    GPE = mgh

    8 = 3.2 × 10 × h

    h = 0.25 m

Part C

The ball speed is calculated by dividing the distance by the time. If the time was 3 seconds, the average speed will be 60/3 = 20 feet per second (6.1 m/sec). KE = 1/2 MV²

            17 = 1/2 × 3.2 x V²

            V = 17 ÷ 1.6

Note, this is only the average ball speed, the speed of the ball at the time of release would be greater.


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Answers

Explanation:

VELOCITY RATIO :- The ratio of a distance through which any part of a machine moves to that which the driving part moves during the same time.
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