Nobody knows this one :(
Find x
A) 9
B)-9
C)6
D)-6

Nobody Knows This One :(Find XA) 9B)-9C)6D)-6

Answers

Answer 1

Answer:

-9

Step-by-step explanation:

164-43=121

121-139=-18

-18/2=-9

Answer 2

Answer:

-9

Step-by-step explanation:

164= x-43

164-43=x

x=121

164-43=121

121-139=18

-18/2= -9


Related Questions

1/4 of x is 6 please help solve This

Answers

Answer:

x = 24

Step-by-step explanation:

Of means multiply and is means equals

1/4 * x = 6

Multiply each side by 4

1/4*4 x = 6*4

x = 24

matatila female drink 1/2 litres of milk every day during this month of September how many litres is this all together​

Answers

Answer:

  15 litres

Step-by-step explanation:

  (1/2 litre/day)(30 days) = 15 litres

__

Multiply rate by time to get quantity.

What three numbers add up to 57, with the first number being 12

Answers

The answer is 12, 15, 30

The answer is gonna be 12 , 15 , 30

Find g(1) if g(x) = x 2 + 1

Answers

Answer:

2

Step-by-step explanation:

g(1) = 1² + 1 = 2

Step-by-step explanation:

it is 2

Urn has 5 white and 7 black balls. Urn has 3 white and 12 black balls. We flip a fair coin. If the outcome is heads, then a ball from urn is selected, whereas if the outcome is tails, then a ball from urn is selected. Suppose that a white ball is selected. What is the probability that the coin landed tails?

Answers

Answer:

Suppose that a white ball is selected, the probability that the coin landed tails = (12/37) = 0.3243

Step-by-step explanation:

Complete Question

Urn A has 5 white and 7 black balls. Urn B has 3 white and 12 black balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a white ball is selected. What is the probability that the coin landed tails?

Solution

Let the probability of that a head turns up and urn A is selcted be P(A) = (1/2)

Probability that a tail turns up and urn B is selected = P(B) = (1/2)

Probability that a white ball is picked = P(W)

The probability that a white ball is picked given that the coin toss gives a head and urn A is selected = P(W|A) = (5/12)

The probability that a white ball is picked given that the coin toss gives a tail and urn B is selected = P(W|B) = (3/15) = (1/5)

We now require the probability that the coin lands on a tail and urn B is selected given that a white ball is picked, P(B|W)

Note that the conditional probability P(X|Y) is expressed mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

And P(X n Y) = P(X|Y) × P(Y)

Hence, the required probability

P(B|W) = P(B n W) ÷ P(W)

Although, we do not have the probabilities P(B n W) and P(W), we can calculate them

P(B n W) = P(W n B) = P(W|B) × P(B) = (1/5) × (1/2) = (1/10)

P(W) = P(W n A) + P(W n B) (Since the events A and B are mutually exclusive)

P(W n A) = P(W|A) × P(A) = (5/12) × (1/2) = (5/24)

P(W n B) = (1/10)

P(W) = (5/24) + (1/10) = (37/120)

P(B|W) = P(B n W) ÷ P(W) = (1/10) ÷ (37/120) = (12/37) = 0.3243

Hope this Helps!!!

Find the sum of the first 20 terms of the sequence -7, -3, 1,…

Answers

Answer:

620

Step-by-step explanation:

The formula to find the sum of the first n terms of an arithmetic sequence is n(a1 + aN)/2, where n is the number of terms,  aN is the last term and a1 is the first term. We do not know the last term, though, so we must find it. The equation for this is an=a1+(n−1)d, where d is the common difference and a1 is the first term, and n is the number of terms. Therefore, the last term, an is, -7+(19)4 = 69.

Finally, we plug it into the first formula, the formula to find the sum, and we get 20*(-7+69)/2, which gives us 620 as our final answer.



An airplane climbs at an angle of 2.7" from an altitude of 4500 ft to an altitude of 5600 ft. How far does the airplane travel as it climbs as

measured along the horizontal?

Answers

Answer:

  23,325 ft, about 4.42 miles

Step-by-step explanation:

The geometry of the situation can be modeled by a right triangle, where the side adjacent to the 2.7° angle of climb is the horizontal distance, and the side opposite is the vertical change in altitude. That change is ...

  5600 ft -4500 ft = 1100 ft

and the angle relation is ...

  tan(2.7°) = opposite/adjacent = (1100 ft)/(horizontal distance)

Multiplying this equation by (horizontal distance)/tan(2.7°) gives ...

   horizontal distance = (1100 ft)/tan(2.7°) ≈ 23,325 ft

Dividing this by 5280 ft/mi gives ...

  horizontal distance ≈ 4.42 mi

The airplane travels about 23,325 ft, or 4.42 miles, horizontally as it climbs.

A street is 149m long is covered in snow. City workers are using a snowplow to clear the street. The snowplow has tires that are 1.7m in diameter. How many times does a tire have to turn in traveling the length of the street

Answers

Answer:

Approximately 28 times

Step-by-step explanation:

The tires are circular in shape.

We first need to find the circumference of the tire and then divide the length of the road by that circumference.

The circumference of a circle is given as:

C = πD

where D = diameter

The diameter of the tires is 1.7 m. Its circumference is therefore:

C = π * 1.7 = 5.34 m

Therefore, the number of times that the tire has to turn in traveling the length of the street is:

149 / 5.34 = 27.9 ≅ 28

Please answer this correctly

Answers

Answer:

[tex]10.71 yd[/tex]

Step-by-step explanation:

First let's find the radius of the quarter circle.

[tex]area =\frac{1}{4} \pi {r}^{2} \\ 7.065 = \frac{1}{4} *3.14 {r}^{2} \\ \frac{7.065}{3.14} = \frac{1}{4} * \frac{3.14 {r}^{2} }{3.14} \\ 9 = {r}^{2} \\ \sqrt{9} = r \\ 3 yd= r[/tex]

Now let's find the arc length of this quarter circle.

[tex] \frac{90}{360} \times 2\pi \: r \\ \frac{1}{4} \times 2 \times 3.14 \times 3 \\ = \frac{9.42}{4} \\ = 4.71yd \\ [/tex]

Now let's find the perimeter[tex]perimeter \\ = arc \: \: length + radius + radius \\ = 4.71 + 3 + 3 \\ = 10.71yd[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

10.71 yd

Step-by-step explanation:

The formula of an area of a circle:

[tex]A=\pi r^2[/tex]

r - radius

The formula of an area of a quarter circle:

[tex]A=\dfrac{1}{4}\pi r^2[/tex]

We have the area of a quarter circle:

[tex]A=7.065\ yd^2[/tex]

Substitute to the formula and solve for r :

[tex]\dfrac{1}{4}\pi r^2=7.065[/tex]     multiply both sides by 4

[tex]4\cdot\dfrac{1}{4}\pi r^2=7.065\cdot4\\\\\pi r^2=28.26[/tex]

Use 3.14 for π

[tex]3.14r^2=28.26[/tex]            divide both sides by 3.14

[tex]\dfrac{3.14r^2}{3.14}=\dfrac{28.26}{3.14}\\\\r^2=9\to r=\sqrt9\\\\\boxed{r=3\ yd}[/tex]

The circumference of this figure consists of an arc (quarter of a cirumference of a circle) and two radiuses.

The formula of a circumference of a circle:

[tex]C=2\pi r[/tex]

The formula of a quarter of a cicrumference of a circle:

[tex]L=\dfrac{1}{4}\cdot2\pi r[/tex]

Substitute

[tex]L=\dfrac{1}{4}\cdot2\pi\cdot3=1.5\pi[/tex]

Use 3.14 for π

[tex]L=1.5(3.14)=4.71\ yd[/tex]

The perimeter of a quarter circle:

[tex]P=4.71+2(3)=4.71+6=10.71\ yd[/tex]

In western Kansas, the summer density of hailstorms is estimated at about 1.5 storms per 5 square miles. In most cases, a hailstorm damages only a relatively small area in a square mile. A crop insurance company has insured a tract of 9 square miles of Kansas wheat land against hail damage. Let r be a random variable that represents the number of hailstorms this summer in the 9-square-mile tract.(a) Explain why a Poisson probability distribution is appropriate for r.Hail storms in western Kansas are a common occurrence. It is reasonable to assume the events are dependent.Hail storms in western Kansas are a rare occurrence. It is reasonable to assume the events are dependent. Hail storms in western Kansas are a common occurrence. It is reasonable to assume the events are independent.Hail storms in western Kansas are a rare occurrence. It is reasonable to assume the events are independent.What is λ for the 9-square-mile tract of land? Round λ to the nearest tenth (b) If there already have been two hailstorms this summer, what is the probability that there will be a total of four or more hailstorms in this tract of land? Compute P(r≥ 4 | r ≥ 2). (Use 4 decimal places.)(c) If there already have been three hailstorms this summer, what is the probability that there will be a total of fewer than six hailstorms? Compute P(r < 6 | r ≥ 3). (Use 4 decimal places.)

Answers

Answer:

Step-by-step explanation:

(a) Hail storms in western Kansas are a rare occurrence. It is reasonable to assume the events are independent

(b) The required [tex]\lambda[/tex] = 1.7 * 10/5 = 3.4

(c) P(r ≥ 4 | r ≥ 2)

= P(r ≥ 4)/P(r ≥ 2)

= {1 - P(r < 4)}/{1 - P(r < 2)}

For Poisson distribution, P(X = x)

[tex]= \frac{e^{- \lambda} \lambda ^x}{x !}[/tex]

Thus, P(r < 4) = P(r = 0) + P(r = 1) + P(r = 2) + P(r = 3)

= 0.5584

and P(r < 2) = P(r = 0) + P(r = 1) = 0.1468

Thus, P(r ≥ 4 | r ≥ 2) = (1 - 0.5584)/(1 - 0.1468)

= 0.5177

(d) P(r < 6 | r ≥ 3)

= P(3 ≤ r < 6)/P(r ≥ 3)

P(3 ≤ r < 6) = P(r = 3) + P(r = 4) + P(r = 5) = 0.5308

P(r ≥ 3) = 1 - {P(r = 0) + P(r = 1) + P(r = 2)}

= 0.6603

Thus, P(r < 6 | r ≥ 3) = 0.5308/0.6603 = 0.8309

An object is launched from the ground. The object’s height, in feet, can be described by the quadratic function h(t) = 80t – 16t2, where t is the time, in seconds, since the object was launched. When will the object hit the ground after it is launched? Explain how you found your answer.

Answers

Answer:

The object hits the ground 5 seconds after being launched.

Step-by-step explanation:

The height of the object in t seconds after being launched is given by the following equation:

[tex]h(t) = 80t - 16t^{2}[/tex]

When will the object hit the ground after it is launched?

This is t for which h(t) = 0.

So

[tex]80t - 16t^{2} = 0[/tex]

[tex]16t(5 - t) = 0[/tex]

Then

[tex]16t = 0[/tex]

[tex]t = 0[/tex]

This is the launch point

[tex]5 - t = 0[/tex]

[tex]t = 5[/tex]

So

The object hits the ground 5 seconds after being launched.

Answer:

The object will hit the ground after 5 seconds. You can rewrite the quadratic function as a quadratic equation set equal to zero to find the zeros of the function 0 = –16t2 + 80t + 0. You can factor or use the quadratic formula to get t = 0 and t = 5. Therefore, it is on the ground at t = 0 (time of launch) and then hits the ground at t = 5 seconds.

Step-by-step explanation:

This is the exact answer on edg 2020

State the name of the property illustrated.
V5+(-3) =(-3) + 5
Associative
O Distributive
O Both associative and commutative
>
O Commutative

Answers

Answer:

The answer is commutative and associative.

Step-by-step explanation:

Both associations and commutative is correct

A regular hexagonal prism has sides of 4 cm for the hexagonal bases and is 10 cm in height. Find its exact

volume. Then, quickly find the exact volume of a regular hexagonal pyramid inscribed in the prism. If you

don’t have a 3 in your answers, something’s gone wrong.

Answers

Answer:

Exact volume of the hexagonal prism = 240√3 cm³

Exact volume of the hexagonal pyramid = 80√3 cm³

Step by step explanation:

Volume of hexagonal prism = [(3√3)/2]×a²h

Where a = base edge

h = height

From the question,

a = 4cm, h = 10cm

V = [(3√3)/2]×(4)²×(10)

V = (3√3) × 160/2

V = 240√3 cm³

Exact volume of the hexagonal prism = 240√3 cm³

Volume of hexagonal pyramid = [(√3)/2]×a²h

a = 4cm, h = 10cm

V =  [(√3)/2]×(4)²×(10)

V = (√3) × 160/2

V = 80√3 cm³

Exact volume of the hexagonal pyramid = 80√3 cm³

A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery service 2. Express delivery service 1 has a record of 3.0% of packages being delivered late and express delivery service 2 has a record of 2.0% of packages being delivered late. A package was delivered late. What is the probability that a late package was delivered by express delivery service 2

Answers

Answer:

55.32% probability that a late package was delivered by express delivery service 2

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

[tex]P(B|A) = \frac{P(B)*P(A|B)}{P(A)}[/tex]

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Late delivery.

Event B: Service 2 was used.

A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery service 2.

100 - 35 = 65%.

So [tex]P(B) = 0.65[/tex]

Service 2 has a record of 2.0% of packages being delivered late.

This means that [tex]P(A|B) = 0.02[/tex]

Probability of a late delivery.

35% from service 1. Of those, 3% are late.

65% from service 2. Of those, 2% are late.

So

[tex]P(A) = 0.35*0.03 + 0.65*0.02 = 0.0235[/tex]

What is the probability that a late package was delivered by express delivery service 2

[tex]P(B|A) = \frac{0.65*0.02}{0.0235} = 0.5532[/tex]

55.32% probability that a late package was delivered by express delivery service 2

I am completely stumped...

Answers

Answer:

x=25[tex]\sqrt{2}[/tex]

Step-by-step explanation:

the hypotenuse is equal to a leg times the square root of 2. which means to find the leg with the hyp given. you take [tex]\frac{50}{\sqrt{2} }[/tex] which then translates to 50 root 2/2=x  therefore 25[tex]\sqrt{2}[/tex]

The Vilas County News earns a profit of $20 per year for each of its 3,000 subscribers. Management projects that the profit per subscriber would increase by 1¢ for each additional subscriber over the current 3,000. How many subscribers are needed to bring a total profit of $113,100?

Answers

Answer:

850

Step-by-step explanation:

Current profit per year = $ 20

Number of subscribers = 3000

For each additional subscriber over 3000, the profit will increase by 1 cent or by $ 0.01. For example, for 3001 (3000 + 1) subscribers, the profit will be $ 20.01 per year. Similarly, for 3002 (3000 + 2) subscribers, the profit will be $20.02 per year and so on.

So, for x additional subscribers over 3000, the profit will increase by 0.01(x). i.e. for (3000 + x) subscribers, the profit will be $(20 + 0.01x)

Since, profit per each subscriber is $(20 + 0.01x), the profit for (3000 + x) subscribers will be:

Total profit = Number of subscribers x Profit per each subscriber

Total profit = (3000 + x)(20 + 0.01x)

We want to calculate how many subscribers will be needed to bring a profit of $109,725. So, we replace Total profit by $109,725. The equation now becomes:

Using quadratic formula, we can solve this equation as:

x = -5850 is not a possible solution as this would make the total number of subscribers to be negative. So we reject this value.

Therefore, the answer to this question is 850. 850 more subscribers are needed to being a total profit of $109,725

Please answer this correctly

Answers

Answer:

17.7

Step-by-step explanation:

62.3-7=55.3

55.3-19.9=35.4

35.4/2 = 17.7

brainliest pzz

Answer:

The value of s is 17.7mm.

Step-by-step explanation:

Given that perimeter of a shape happens when all sides are add up together. So for this question :

[tex]perimeter = 7 + 19.9 + s + s[/tex]

[tex]perimeter = 26.9 + 2s[/tex]

Let perimeter = 62.3mm,

[tex]62.3 = 26.9 + 2s[/tex]

[tex]2s = 62.3 - 26.9[/tex]

[tex]2s = 35.4[/tex]

[tex]s = 35.4 \div 2[/tex]

[tex]s = 17.7mm[/tex]

grogg surveyed 135 beasts at his school about thier favorite house pet. the pie chart below summarizes his resuts. if 54 of the students preferred dogs, what is the value of x

Answers

135 total - 54dogs= 81

Determine where f(x) is discontinuous. Justify your answer.
f(x)=x^2+x-2/x-1

Answers

Answer:x=1

Step-by-step explanation:

Given

[tex]F(x)=\dfrac{x^2+x-2}{x-1}[/tex]

F(x) will be discontinuous at x=1 because value of f(x) is undefined at that point.

F(x) is defined for all values of x except at x=1

What is the value of a share of Henley Inc. to an investor who requires a 11 percent
rate of return if Henley is expected to pay a fixed dividend of $1.10 for the next 3 years and
then the dividends will grow at a constant rate of 5% indefinitely

Answers

Answer:

Value of Henley Inc.'s share is $16.76

Step-by-step explanation:

The present value of the dividends over for the three years and the terminal value of the dividends would give us a fair share price that an investor would pay

Year 1 PV of dividends=$1.10/(1+11%)^1=$0.99  

Year 2 PV of dividends=$1.10/(1+11%)^2=$0.89  

Year 3 PV of dividends=$1.10/(1+11%)^3=$0.80  

The terminal value formula=dividend*(1+g)/(r-g)

g is the dividend growth rate of 5%

r is the investor's required rate of return which is 11%

terminal value=$1.10*(1+5%)/(11%-5%)=$19.25

The terminal is discounted to present value using the discount factor of year 3

PV of terminal value =$19.25 /(1+11%)^3=$ 14.08  

Total present values=$0.99+$0.89+$0.80+$14.08 =$16.76

A man 1.75 meters tall cast a shadow 5.25 meters long. At the same time, a flagpole casts a shadow 120 meters long. How tall is the flagpole?

Answers

Answer:

40m

Step-by-step explanation:

5.25 divided by 1.75=3

120 divided by 3=40

A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes. Given this information, (a) what is the percent learning rate and (b) what is the total cumulative time to produce all 17 welded assemblies

Answers

Answer:

(a). 72.9%.

(b). 13.6 hr.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;

=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "

=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"

So, we will be making use of the Crawford learning curve model.

T(7) + 10 = T (17) = 30 min.

T(7) = T1(7)^b = 45.

T(17 ) = T1(17)^b = 30.

(T1) = 45/7^b = 30/17^b.

45/30 = 7^b/17^b = (7/17)^b.

1.5 = (0.41177)^b.

ln 1.5 = b ln 0.41177.

0.40547 = -0.8873 b.

b = - 0.45696.

=> 2^ -0.45696 = 0.7285.

= 72.9%.

(b). T1= 45/7^ - 045696 = 109.5 hr.

V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .

V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .

= 815.7 min .

= 13.595 hr.

A marketing study conducts 60 significance tests about means and proportions for several groups. Of​ them, 3 tests are statistically significant at the 0.05 level. The​ study's final report stresses only the tests with significant​ results, not mentioning the other 57 tests. What is misleading about​ this?

Answers

Answer:

hello your question lacks the required options attached is a picture of the complete question

One would expect about 5% of tests to be significant just by chance if the null hypothesis is true, and for 60 tests, this is 0.05(60) = 3 tests. This could explain why these tests are statistically significant.

Step-by-step explanation:

What is misleading about this is the study's final report because this marketing study was carried out with a level of significance of 5% (0.05) which means that if we carry the same study with varying sample data we will mostly like arrive at a conclusion against our null conclusion 5% of the time and this is not good for the the study because it is a type 1  error and has to be eliminated and it cannot be eliminated totally .

hence  One would expect about 5% of tests to be significant just by chance if the null hypothesis is true, and for 60 tests, this is 0.05(60) = 3 tests. This could explain why these tests are statistically significant.

We are told that the marketing study conducts 60 tests and that 3 tests are statistically significant at the 0.05 level, in addition to this the study's final report emphasizes only the tests with significant results without mentioning the other 57 tests.

We can interpret it as follows:

By the 0.05 level, we mean that 5% of the tests are significant by chance when the null hypothesis is true.

Here 5% of the 60.

60 * 0.05 = 3

Therefore it only mentions 3 tests and does not mention the other 57 tests, which in itself is misleading because all 60 tests should be fully mentioned in the final report.

You can afford a $850 per month mortgage payment. You've found a 30 year loan at 8% interest.

a) How big of a loan can you afford?

$
Incorrect

b) How much total money will you pay the loan company?

$
Incorrect

c) How much of that money is interest?

$
Incorrect

Answers

Answer:

  a) $115,840.97

  b) $306,000

  c) $190,159.03

Step-by-step explanation:

Loan payment calculations can be done using the amortization formula:

  A = P(r/12)/(1 -(1 +r/12)^(-12t))

where A is the monthly payment, P is the principal value of the loan, r is the annual interest rate, and t is the loan duration in years.

a) Loan amount

The principal amount of the loan can be found by filling in the given values and solving for P.

  850 = P(0.08/12)/(1 -(1 +0.08/12)^(-12·30))

  P = 850(1 -1.0066667^-360)/0.0066667 ≈ 850×136.283494

  P = 115,840.97

You could afford a loan of $115,840.97.

b) Total paid

The total amount paid is the sum of 360 payments of $850 each:

  360 × $850 = $306,000

You will pay $306,000 to the loan company.

c) Interest

The amount of interest is the difference between the amount paid and the amount borrowed:

  $306,000 -115,840.97 = $190,159.03

$190,159.03 of the amount paid is interest.

__

Additional comment

A variety of apps, calculators, and spreadsheets can do these calculations for you. The result from one of these calculators is attached. The PV is the Present Value of the series of 360 payments of $850 each. It is the loan amount.

According to the WHO MONICA Project the mean blood pressure for people in China is 128 mmHg with a standard deviation of 23 mmHg (Kuulasmaa, Hense & Tolonen, 1998). Assume that blood pressure is normally distributed. a.) State the random variable. b.) Find the probability that a person in China has blood pressure of 135 mmHg or more. c.) Find the probability that a person in China has blood pressure of 141 mmHg or less. d.)Find the probability that a person in China has blood pressure between 120 and 125 mmHg. e.) Is it unusual for a person in China to have a blood pressure of 135 mmHg? Why or why not? f.) What blood pressure do 90% of all people in China have less than?

Answers

Answer:

a) Mean blood pressure for people in China.

b) 38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c) 71.30% probability that a person in China has blood pressure of 141 mmHg or less.

d) 8.51% probability that a person in China has blood pressure between 120 and 125 mmHg.

e) Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg

f) 157.44mmHg

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If X is two standard deviations from the mean or more, it is considered unusual.

In this question:

[tex]\mu = 128, \sigma = 23[/tex]

a.) State the random variable.

Mean blood pressure for people in China.

b.) Find the probability that a person in China has blood pressure of 135 mmHg or more.

This is 1 subtracted by the pvalue of Z when X = 135.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{135 - 128}{23}[/tex]

[tex]Z = 0.3[/tex]

[tex]Z = 0.3[/tex] has a pvalue of 0.6179

1 - 0.6179 = 0.3821

38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c.) Find the probability that a person in China has blood pressure of 141 mmHg or less.

This is the pvalue of Z when X = 141.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{141 - 128}{23}[/tex]

[tex]Z = 0.565[/tex]

[tex]Z = 0.565[/tex] has a pvalue of 0.7140

71.30% probability that a person in China has blood pressure of 141 mmHg or less.

d.)Find the probability that a person in China has blood pressure between 120 and 125 mmHg.

This is the pvalue of Z when X = 125 subtracted by the pvalue of Z when X = 120. So

X = 125

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{125 - 128}{23}[/tex]

[tex]Z = -0.13[/tex]

[tex]Z = -0.13[/tex] has a pvalue of 0.4483

X = 120

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{120 - 128}{23}[/tex]

[tex]Z = -0.35[/tex]

[tex]Z = -0.35[/tex] has a pvalue of 0.3632

0.4483 - 0.3632 = 0.0851

8.51% probability that a person in China has blood pressure between 120 and 125 mmHg.

e.) Is it unusual for a person in China to have a blood pressure of 135 mmHg? Why or why not?

From b), when X = 135, Z = 0.3

Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg.

f.) What blood pressure do 90% of all people in China have less than?

This is the 90th percentile, which is X when Z has a pvalue of 0.28. So X when Z = 1.28. Then

X = 120

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.28 = \frac{X - 128}{23}[/tex]

[tex]X - 128 = 1.28*23[/tex]

[tex]X = 157.44[/tex]

So

157.44mmHg

1. What shape of the distribution is best modeled by a normal curve? *

Answers

Answer:

A symmetric bell shape

Step-by-step explanation:

A normal curve has a symmetrical bell shaped curve, this can be seen when a histogram is constructed with values that are normally distributed, the resulting shape is symmetrical and has a bell shape.

Department 1 of a two department production process shows:


Units

Beginning Work in Process 9900

Ending Work in Process 49000

Total units to be accounted for 180200


How many units were transferred out to Department 2?






131200.



180200.



170300.



49000.

Answers

Answer:

131,200 units

Step-by-step explanation:

The number of units transferred to Department 2 from Department 1 is the total units to be accounted for  which is 180,200 units minus the ending work in process of 49,000 units.

The logic here is that Department 1 is to account for 180,200 units ,part of which is the ending working process while the remainder which was transferred out is the difference between the two figures

units transferred to Department 2=180,200-49,000= 131,200.00  units

Simplify the following expression. −3√84x3

Answers

Answer:

-18root7

Step-by-step explanation:

-3root 84*3

-3root4*7*3*3

-3(2*3)root7

-18root7

College Students and Drinking Habits: A public health official is studying differences in drinking habits among students at two different universities. They collect a random sample of students independently from each of the two universities and ask each student how many alcoholic drinks they consumed in the previous week. Sample Statistics:
size(n) Mean (X) SD(s)
sample1 40 6.9 2.3
sample 2 49 5.7 1.9
The official conducts a two -sample t-test to determine whether these data provide significant evidence that students at University 1 drink more than students at University 2. The test statistics is t=2.64 with a P-value 0.005. Which of the following is an appropriate conclusion?
A) The samples provide significant evidence that students at University 1 drink more than students at university 2.
B) The samples do not provide statistically significant evidence.
C) We ca not use the t-test in this case because the variables (number of drinks) are likely skewed to the right at each university.

Answers

Answer:

Option A

Step-by-step explanation:

From the outlined data, the p value calculated was given as 0.005 which is way less than 0.05, thus we will reject the null hypothesis that there is no difference in drinking habit among students at two different universities. We can then conclude that the samples provide significant evidence that students at University 1 drink more than students at university 2.

will give brainliest ​

Answers

Answer:

About 8.2 cm

Step-by-step explanation:

Assuming that a is one of the legs of this right triangle, then using the Pythagorean Theorem:

[tex]a=\sqrt{15.3^2-12.9^2}\approx 8.2[/tex]

Hope this helps!

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