need help asap! Fill in the blank by entering just a number…

Answer:

11.2 km/hr

Step-by-step explanation:

Shea's speed: 48km/1.25hr=38.4 km/hr

Chris's speed: 62km/1.25hr= 49.6 km/hr

Vav= 49.6-38.4= 11.2 km/hr

Answer:

[tex]m=4\sqrt{6}[/tex]

Step-by-step explanation:

Step-by-step explanation:

first find the relation between n,m and x

Answer:.

Step-by-step explanation:

Answer:

D(1,12)

Step-by-step explanation:

See attached graph.

Answer:

nr.3 300x0.12=36rolls
nr.4 300x0.21=63 rolls

total number on rolls on nr.3 and nr.4= 99

Step-by-step explanation:

Calculate the probability for nr.3

Always try to get 100%

1=13%

2=5%

3=?

4=21%

5=19%

6=30%

Add all the percentage

1+2+4+5+6= 88%

now calculate the percentage for nr.3

100%-88%=12%

give a estimated total number of times the dice will land on nr.3 or nr.4 after 300 rolls

nr.3 300x0.12=36rolls
nr.4 300x0.21=63 rolls

total number on rolls on nr.3 and nr.4= 99

The equation that can be used to determine the value of x is Option B.

An equation is a mathematical statement formed when two algebraic expression are equated by an equal sign.

From the diagram ,

A straight line has an angle of 180 degree.

Therefore from the figure

To determine the value of x

2x + 4x = 180

6x = 180

x =30 degree

Thus the equation that can be used to determine the value of x is Option B.

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1.  m³

2. cm³

3. s³

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

1. Volume is measure in m³

2.  volume of a rectangular pencil case in cm³

3. V = s x s x s or s³

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Answer:

[tex]\boxed {24 cm^{2}}[/tex]

Step-by-step explanation:

Finding the smaller side :

⇒ P = 2(l + w)

⇒ 20 = 2(6 + w)

⇒ 6 + w = 10

⇒ w = 4 cm

Finding area :

⇒ 6 × 4

⇒ 24 cm²

Answer:

The correct answer is if you want no roots in the denominator, the correct answer is [tex]\frac{2x}{y}[/tex]* [tex]\sqrt[3]{2y^{2} }[/tex]

Step-by-step explanation:

The mistake is that you can't take a cube root of a square at step 3 when [tex]y^{2}[/tex] is taken out.

Answer:

[0, ∞)

(all real numbers greater than or equal to 0)

Explanation:

the domain of a function is all possible x-values (and the range is all possible y-values)

We know that you cannot have a negative square root, so all negative x-values are not possible--only values 0 to infinity.

So the domain of this function is [0, ∞).

{ [brackets] in math mean the number is included, (parentheses) in math means the number is not included.}

All [real] numbers ≥ 0

is the domain of y=√x

(written as: all real numbers greater than or equal to 0)

Answer:

a

Step-by-step explanation:

given a quadratic equation in standard form

ax² + bx + c = 0 ( a ≠ 0 )

then the discriminant

Δ = b² - 4ac

• if b² - 4ac > 0 then 2 real solutions

• if b² - 4ac = 0 then 2 real and equal solutions

• if b² - 4ac < 0 then no real solutions

given

[tex]\frac{3}{4}[/tex] x² - 3x = - 4 ( add 4 to both sides )

[tex]\frac{3}{4}[/tex] x² - 3x + 4 = 0 ← in standard form

with a = [tex]\frac{3}{4}[/tex] b = - 3 , c = 4

then

b² - 4ac = (- 3)² - ( 4 × [tex]\frac{3}{4}[/tex] × 4) = 9 - 12 = - 3

since b² - 4ac < 0 then equation has no real solutions

Answer:

a.  -3; no real solutions.

Step-by-step explanation:

Discriminant

[tex]\boxed{b^2-4ac }\quad\textsf{when}\:ax^2+bx+c=0[/tex]

[tex]\textsf{When }\:b^2-4ac > 0 \implies \textsf{two real solutions}.[/tex]

[tex]\textsf{When }\:b^2-4ac=0 \implies \textsf{one real solution}.[/tex]

[tex]\textsf{When }\:b^2-4ac < 0 \implies \textsf{no real solutions}.[/tex]

Given equation:

[tex]\dfrac{3}{4}x^2-3x=-4[/tex]

Add 4 to both sides of the equation so that it is in standard form:

[tex]\implies \dfrac{3}{4}x^2-3x+4=-4+4[/tex]

[tex]\implies \dfrac{3}{4}x^2-3x+4=0[/tex]

Therefore, the variables are:

[tex]a=\dfrac{3}{4}, \quad b=-3, \quad c=4[/tex]

Substitute these values into the discriminant formula to find the value of the discriminant:

[tex]\begin{aligned}\implies b^2-4ac&=(-3)^2-4\left(\dfrac{3}{4}\right)(4)\\&=9-(3)(4)\\&=9-12\\&=-3\\\end{aligned}[/tex]

Therefore, as -3 < 0, the discriminant is less than zero.

This means there are no real solutions.

Answer:

35 Floors in 6 Hours

Step-by-step explanation:

20 / 4 = X Floors Per Hour

floors per hour = 5

6*5 = 35 Floors

Answer:

Inequality is the answer

Answer: Inequality ✅

Step-by-step explanation:

Hii, do you need to know the answer to your question? No problem!

The answer to your question is "inequality".

An inequality is a number sentence that shows how two or more expressions are not equal.

An example of that is [tex]\sf 4x+4\geqslant3x-5[/tex].

So 4x+4 is greater than or equal to 3x-5, but they're not 100% equal (such is the case in equations).

--

Hope that this helped! Best wishes.

--

Answer:

(7,7.5)

Step-by-step explanation:

midpoint formula:

(10+4)/2=7

(6+9)/2=7.5

(7,7.5)

Answer: No. The intervals defined by the margin or error overlap

Step-by-step explanation:

If we think about it, with the worst margins, 55% could be 48% and then the 45% would be 52%, showing there is no clear yes or no and it is possible that the intervals could overlap

Answer:

2 units

Step-by-step explanation:

From one crest (high point) to the next crest  point is one period....

  this covers 2 units on this graph

These thoughts show you that AAS theorem is straight extension of ASA theorem.

A triangle is a simple polygon with 3 sides and 3 interior angles. It is one of the basic shapes in geometry in which the 3 vertices are joined with each other and it is denoted by the symbol △. There are various types of triangles that are classified on the basis of the sides and angles.

ASA congruence theorem: If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.

AAS congruence theorem: If two angles and the non-included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.

Consider two triangles ΔABC and ΔA'B'C' .

If        m∠A = m∠A'

and   m∠B = m∠B'

         AB = A'B'

then two triangles ΔABC and ΔA'B'C' are congruent by AAS theorem.

Thus, these thoughts show you that AAS theorem is straight extension of ASA theorem.

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Answer:  The Sample Response is the answer Edge uses as a correct answer. Answer varies depending on your response.

Step-by-step explanation:

This answer is correct I got it right on Edge 2022. The proof is down below.

Sample Response: The interior angle measures of a triangle add up to 180 degrees. Thus, if you are given angle-angle-side, you can solve for the third angle measure and essentially have angle-side-angle because the given side will now be the included side.

As long as you explain and include these in your answer it should be correct: (If you decide to answer using your own words)

Hope this helps someone. Good luck! :)

The two values of x best represent where the two functions are equal will be (12,11)

A diagram depicting the relationship between two or more variables, each measured along with one of a pair of axes at right angles.

Given data;

Linear function passing through;

(1, 2), (3, 4), (6,7) and (8, 9)

Quadratic function passing through

(3, 4), (5, 0), (7, 4) & (8, 9)

Let x be two values of x best represent where the two functions are equal;

The value of the x is obtained from the graph where the two line meets.

The value of x willl be (12,11)

Hence, the two values of x best represent where the two functions are equal will be (12,11)

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Using the cosine ratio, the expression that can be used to determine the  side length of the given rhombus is: x = 10/cos 30.

The cosine ratio that can be used to solve a right triangle is, cos ∅ = adj/hyp.

x represents the side of the rhombus as shown in the image attached.

cos 30 = 10/x

x(cos 30) = 10

x = 10/cos 30

Thus, the equation that would be used to determine the side length is: x = 10/cos 30

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Answer:

A

Step-by-step explanation:

10/cos 30°

Two possible solutions are: (4.5, 8.5) and (8, 6.3)

Let x represents hours dog walking and y represents hours washing cars.

So, we have:

Earnings = Rate of dog walk * x + Rate of car wash * y

This gives

Earnings = 7x + 11y

He wants to earn at least $125.

This means that:

7x + 11y ≥ 125

See attachment for the graph of the inequality

From the attached graph, two possible solutions are: (4.5, 8.5) and (8, 6.3)

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Answer:

there ya go :)

1 is the values are in the range of the function graphed below. Option E is corect.

The domain denotes all potential x values, while the range denotes the domain's possible y values.

The domain is the value of x which lies between the -2 ≤ x  ≤ 1.While the range shows the value of y which is equal to  1.

Hence, option E is correct

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An augmented matrix is invertible if the linear system has a unique solution.

The augmented matrix is known as a rectangular matrix.

The properties of an augmented matrix includes:

Note that the inverse of a matrix must be unique

And If A is invertible, then its inverse is unique.

If the linear system is unique, then the augmented matrix is invertible.

Thus, an augmented matrix is invertible if the linear system has a unique solution.

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Answer:

A. True

Step-by-step explanation:

One of the ways to check this is solving each side of the equation.

(5+4)+10=5+(4+10)

Remember PEMDAS.

Parenthesis first.

(9)+10=5+(14)

Now, you can drop the parenthesis and add the numbers together.

9+10=19

5+14=19

19=19

This is a true statement.

Hope this helps!

If not, I am sorry.

factorise 3 squared+ 5x +12

To factor an expression, we can identify common factors between each terms, and take them out.

117n + 90

Both terms have the common factor of 9. Factor this out:

= 9(13n + 10)

13 and 10 do not have a common factor. Therefore, this is the final factored expression.

9(13n + 10)

Answer:

Try searching online

Step-by-step explanation:

go to your browser then search up
How to do proportional relationships in math 7th grade ?? Please explain ?!!

Answer: Transitive property of congruence

Answer:

  5.  Substitution

  6.  Substitution

Step-by-step explanation:

The properties of congruence generally match those of equality;

  A ≅ A . . . . reflexive property

  A ≅ B, B ≅ C ⇒ A ≅ C . . . . transitive property

  A ≅ B, A ≅ C ⇒ B ≅ C . . . . substitution

__

In this proof, the conclusions (statements 5 and 6) are based on substitution. In each case, the elements of the congruence have previously been shown to be congruent to the same thing. This is the setup for making use of the substitution property of congruence.

The area of a regular octagon with an apothem of 2 cm is 3cm ^2.

The area of a regular octagon with an apothem of 2 cm.

Given the apothem length,

the area of a regular polygon becomes,

[tex]A=\frac{1}{2}\times P\times A[/tex]

P=  the perimeter of the regular polygon

A is the apothem of the regular polygon

Here, we get

p=2=2cm, a=3cm.

So, plugging in the given values, we get

[tex]A=\frac{1}{2} \times 2cm\times 3cm[/tex]

A=1cm⋅3cm

A=3cm^2

Therefore the area of a regular octagon with an apothem of 2 cm is 3cm ^2.

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#1

As d is days

So days can't be negative

hence domain is W or Whole numbers set.

But according to the equation

Round to next whole as it's no of days

d=2

Domain=[2,oo)

#b

Put d=0

f(0)

It passes through (0,7)

But 0 is not in domain ,hence no y intercept in real

#C

f(11)

f(4)

Rate of change

It represents change in radius