ments
nts
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Mai says, "I know how to find the area of a sector or the length of an arc for central angles like 180
degrees or 90 degrees. But I don't know how to do it for central angles that make up more complicated
fractions of the circle."
1. In the diagram, the sector's central angle measures 8 degrees and the circle's radius is r units. Use
the diagram to tell Mai how to find the area of a sector and the length of an arc for any angle and
radius measure.
2. This image shows a circle with radius and central angle measurements. Find the area of the shaded
sector, and the length of the arc defined by the sector.
160%
5 in

Answer:

Your answer would be A.

Step-by-step explanation:

okay so, with a best fit line, it needs to match up with your points. unless your points go up evenly. its not going to connect to all your points.

If the angle 1 and angle 2 are vertical angles, hence they must be equal to each other, therefore m∠1 = m∠2 = 72º

Angles angle are angles that are equal to equal to each other in a line geometry.

Given the following parameters

m∠1 = 72º,

If the angle 1 and angle 2 are vertical angles, hence they must be equal to each other, therefore m∠1 = m∠2 = 72º

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Answer:

[tex]f(x) = 9x^2+9x - 18/3x + 6\\= 9(x^2 + x - 2)/3(x+2)\\= 3(x^2+x-2)/x+2\\= 3(x+2)(x-1)/x+2\\= 3x - 3[/tex]

so y = 3x - 3

since 3x + 6 is on the bottom,

[tex]3x + 6\neq 0\\3x\neq -6\\x\neq -2[/tex]

so this means it should be the graph of y = 3x - 3, but with a hole at (-2, -9)

Answer:

By comparing all the expressions with the formula (a - b)(a + b) = (a² - b²), we find that c, d and e options are correct.

Step-by-step explanation:

Concept: The condition is that, the product should result in a difference of squares. In mathematics, we have such a formula which is (a - b)(a + b) = (a² - b²). So, we need to compare all the options with this relation.

(x - y)(y - x) = -(x² - 2xy + y²)

(6 - y)(6 - y) = 36 - 12y + y²

(3 + xz)(-3 + xz) = (xz + 3)(xz - 3) = x²z² - 9 . This expression is correct

(y² - xy)(y² + xy) = [tex]y^{4} - x^{2} y^{2}[/tex]. This expression is correct

(64y² + x²)(-x² + 64y²) = (64y² + x²)(64y² - x²) = [tex]4096y^{4} -x^{4}[/tex]. This expression is correct.

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Table second represents the proportional relationship between x and y the answer is the second table.

It is defined as the relationship between two variables when the first variable increases, the second variable also increases according to the constant factor.

As we know,

The proportional relation can be expressed mathematically:

y ∝ x

y = kx

Here k is the constant of proportionality.

k = y/x

From table second:

k = 3/2 = 6/4 = 9/6

Thus, the table second represents the proportional relationship between x and y the answer is the second table.

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From the slope, it is possible to classify the lines as parallel.

A line can be represented by a linear function. The standard form for the linear equation is: ax+b , for example, y=2x+7. Where:

a= the slope

b=constant term that represents the y-intercept.

The lines are classified as parallel when they have the same slope. You will have perpendicular lines when one line is the negative reciprocal of the second line. If the lines intersect, none of the previous conditions presented are met.

The given equations are:

6x-2y=-2 (1)

y=3x+12 (2)

First, you should write the equation 1 in the standard form.

-2y=-6x-2

-y=-3x-1

y=3x+1

Therefore, the slope for equation 1 is m=3.

After that, you should indicate the slope for equation 2. Thus, m also is 3.

As, both equations present the same slope (m=3). The lines are parallel.

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Answer: The Product(?) of their slopes is 3, so the lines are parallel

Step-by-step explanation:

summary of what the other person said

Answer:

x=80.8

Step-by-step explanation:

follow BODMAS

2015-(2015÷5(x-5)÷5)=2014

2015-(2015÷5x-25÷5)=2014

2015-(405/x-5)=2014

2015-(405-5x)=2014

2015-405+5x=2014

1610+5x=2014

5x=2014-1610

(5x=404)1/5

x=80.8

Answer:

in exploratory factor analysis all the measures variables are related to every legend variable but in confirmatory factor analyse CFA research 10 specifically the number of factors required in the data in which measures variable is related with talent variable

Answer:

3x²

Step-by-step explanation:

0.482 to 1sf is 0.5

61.2x² to one sf is 60x²

√98.01 to 1sf is √100

√100 = 10

0.5 x 60x² = 30x²

30x² / 10 = 3x²

Answer:

1/3 and 1/4

multiplying 1/3 by 1/4 and 1/4 by 1/3 we get

1/3 * 1/4

1 *1 /3*4

1/12

1/4 * 1/3

1*1 / 4*3

1/12

now, both have same denominator.

Let

[tex]I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]tex

Integrate by parts:

[tex]\displaystyle \int u \, dv = uv - \int v \, du[/tex]

with

[tex]u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)[/tex]

Then

[tex]\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C[/tex]

Integrate by parts again, this time with

[tex]u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)[/tex]

so that

[tex]\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}[/tex]

Answer:

x = 5/2

Step-by-step explanation:

Given that,

[tex] \cfrac{x}{3} = \cfrac{5}{6} [/tex]

Solution:

Multiplying using criss-cross method;

Divide both sides by 6;

Done!

Hence x = 5/2.

Answer:

x = 2.5

Step-by-step explanation:

x = 3*(5/6)

The match has done below:

An expression is a set of terms combined using the operations +, – , x or , /.

= 8.32

=848.64

=8486.4

=0.832

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The equation is:

(x-5)^2+(y-(-7))^2=36

I hope it helps!

Answer:  [tex]\boldsymbol{(x - 5)^2 + (y + 7)^2 = 36}[/tex]

=========================================

Work Shown:

[tex](h,k) = (5,-7) = \text{center}\\\\r = 6 = \text{radius}\\\\(x - h)^2 + (y - k)^2 = r^2\\\\(x - 5)^2 + (y - (-7))^2 = 6^2\\\\\boldsymbol{(x - 5)^2 + (y + 7)^2 = 36}\\\\[/tex]

Answer:

9

Step-by-step explanation:

The opposite sides of a parallelogram are congruent.

Answer:

9

Step-by-step explanation:

Parallel sides are always equal. :)

The graph of x >2 is attached below

Clearly, the graph of x> 2 could be area beyond 2 on positive X axis

What is graph?

The graph is a demonstration of curves  which gives the relationship between x and y axis.

The question seems to be incomplete, because options are missing.
so the option can be of several graphs.

Thus, The correct Graph of x >2 has been attached below.

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Answer:

-3 and -7

Step-by-step explanation:

Factors of 21: 1, 3, 7, 21

3 and 7 add up to 10, but what about -10? Well, -3 * -7 is also 21, and -3 + -7 gives you -10.

Brainliest, please :)

Answer:

5.29

Step-by-step explanation:

8

[tex] \sqrt{8 { = }^{2} { - 6 {?}^{2} }^{2} } [/tex]

Answer: Missing side length (b) = 5.3 units

Step-by-step explanation:

Hii, I'd love to help you out! (:

We are provided with two sides, which are:

Luckily, there's a formula to find the third side!

The Pythagorean Theorem ([tex]\pmb{a^2+b^2=c^2}[/tex]) is the formula that we will use to find the missing side. In this formula "a" and "b" denote the "legs" of the triangle (the two shorter sides) and "c" denotes the hypotenuse (the longest side which is  opposite the right angle (the 90 degree angle)

NB: a and b are interchangeable, because a+b is the exact same thing as b+a; c is always the hypotenuse.

Now it's time for us to stick in the values.

[tex]\bigstar\underbrace{\boxed{\sf a=6;\;c=8}}[/tex]

This is what we obtain upon sticking in the values:

[tex]\tt 6^2+b^2=8^2[/tex]

Now we can solve for b.

[tex]\tt 36+b^2=64}\\b^2=64-36\\b^2=28\\b\approx5.3[/tex]

Thus, the value of "b" is 5.3. (Rounded to the nearest tenth, or one decimal place - one digit after the decimal point)

_____________

Hope I helped! Best wishes.

Reach far. Aim high. Dream big.

_____________

[tex]\underbrace[/tex]

Answer:

all real number {x | x is a real number}

Answer:

Tim is 8 years old.

Explanation:

8 is the cube number of 2, as 2 × 2 × 2 = 8. Additionally, 8 is double 4, which is the square number of 2, and half of 16, which is the square number of 4.

Tim who goes to school is 8 years old.

Good numerical ability describes your ability to think and conclude logical thoughts in your daily life also in your working role how you handle data in form of numbers, graphs, statements etc.

According to the given question Tim goes to school.

His age is a cube number let that number be x therefore age of Tim would be x³.

His age can also be defined as double of 1 square number which is 2x² and half of a different square of a numbers.

Let us equate x³ = 2x² and by hit and trial we get to know that x = 2 satisfies this condition.

So, Age of Tim could be 8 years,Now lets check our third statement half a different square number 16 is square of 4 so half of 16 is also 8.

Thus Tim is 8 years old.

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The equation fourth represents the ellipse that has vertices at (1, 0) and (11, 0), and an eccentricity of 3/5 option fourth is correct.

An ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called focus adds up to a constant. It is taken from the cone by cutting it at an angle.

We have:

The vertices of the ellipse = (1, 0) and (11, 0)

Eccentricity of ellipse = 3/5

We have equations:

[tex]\rm \dfrac{\left(x-6\right)^{2}}{100}+\dfrac{y^{2}}{64}=1[/tex]

[tex]\rm \dfrac{\left(x+6\right)^{2}}{64}+\dfrac{y^{2}}{100}=1[/tex]
[tex]\rm \dfrac{\left(x+6\right)^{2}}{16}+\dfrac{y^{2}}{25}=1[/tex]

[tex]\rm \dfrac{\left(x-6\right)^{2}}{25}+\dfrac{y^{2}}{16}=1[/tex]

From the fourth equation:

The vertices of the ellipse:

(1, 0) and (11, 0)

The eccentricity:

c²  = a² - b²

c² = 25-16

c = 3

e = c/a = 3/5

Thus, the equation fourth represents the ellipse that has vertices at (1, 0) and (11, 0), and an eccentricity of 3/5 option fourth is correct.

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The percent increase of women students is 21.13%.

Given that, an area vocational school had an enrollment of 325 men and 123 women.

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

In 2006, there were 149 women.

Percentage increase = (New value - original value)/Original value × 100

= (149-123)/123 × 100

= 26/123 × 100

= 21.13%

Therefore, the percent increase of women students is 21.13%.

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Answer: y = -x + 7

Step-by-step explanation:

The slope is [tex]\frac{5-6}{2-1}=-1[/tex], so we know the equation is of the form [tex]y=-x+b[/tex].

Substituting in the coordinates (1,6) to find b,

[tex]6=-1+b\\\\b=7[/tex]

Thus, the equation is y = -x + 7

Answer:

16 : 19

Step-by-step explanation:

Given weights of the two castings : 32 lbs and 38 lbs respectively.

Now,

Ratio of the weights of the two castings ;

= 32 : 38

= 16 : 19

32:38

16:19

Answer:

this is my answer

Answer:

12.5%

Step-by-step explanation:

To find what percent of 120 15 is, we must find what 15/120 is.

15/120 = 0.125. To convert to a percent, we move the decimal two places to the right. So, the answer is 12.5%.

Brainliest, please :)

Answer:

12.5%

Step-by-step explanation:

Answer:

A set is a well-defined collection of distinct mathematical objects.

The mean and the standard deviation are 16.15 and 12.03, respectively

The table of values is given as:

Work hours           Frequency

0 - <10                        45

10 - <20                      33

20 - <30                     20

30 - <40                       7

40 - <50                      8

Start by rewriting the table using the midpoint of each class

x      f

5     45

15    33

25    20

35    7

45    8

The mean is then calculated as:

[tex]\bar x = \frac{\sum fx}{\sum f}[/tex]

This gives

[tex]\bar x = \frac{5 * 45 + 15 * 33 + 25 * 20 35 * 7 + 45 * 8}{45 + 33 + 20 + 7 + 8}[/tex]

Evaluate the sum and the products

[tex]\bar x = \frac{1825}{113}[/tex]

Divide

[tex]\bar x = 16.15[/tex]

The standard deviation is:

[tex]\sigma =\sqrt{\frac{\sum f(x - \bar x)^2}{\sum f}}[/tex]

This gives

[tex]\sigma= \sqrt{\frac{45 * (5 - 16.15)^2 + 33 * (15 - 16.15)^2 + 20 * (25 - 16.15)^2 + 7 * (35 - 16.15)^2 + 8 * (45 - 16.15)^2 }{45 + 33 + 20 + 7 + 8}}[/tex]

Evaluate the sum and the products

[tex]\sigma= \sqrt{\frac{16350.4425}{113}}[/tex]

Divide

[tex]\sigma= \sqrt{144.694181416}[/tex]

Take the square root

[tex]\sigma= 12.03[/tex]

Hence, the mean and the standard deviation are 16.15 and 12.03, respectively

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