math...need help soon

Answer: 6416

Step-by-step explanation:

The perimeter of this triangle is 416 centimeters

The integration of the function f(x, y) = 2x²y³ from 0 to 3 with respect to x is 27y³.

It is the reverse of differentiation.

The function f(x, y) is given below.

f(x, y) = 2x²y³

Then the integration of the function from 0 to 3 with respect to x.

[tex]\begin{aligned} \rm \int_{0}^{3}f(x, y)dx &= \rm \int_{0}^{3}9x^2y^3 dx \\\\&= \rm 9y^3 \ \int_{0}^{3} x^2 dx\\\\&= \rm 9y^3 (\dfrac{x^3}{3}) _{0}^{3}\\\\&= \rm3y^3 (3^3 - 0 ^3)\\\\&= \rm 3y^3 \times 9\\\\&= \rm 27y^3 \end{aligned}[/tex]

More about the integration link is given below.

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So

And

Now

From mBD

Now

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Option A

After applying operations between functions, we find the following four transformations for the function [tex]f(x) = 2^{x}[/tex]:

a) 6 · f(x) - [tex]g(x) = 6 \cdot 2^{x}[/tex]

b) f(6 · x) - [tex]g(x) = 2^{6\cdot x}[/tex]/[tex]g(x) = 2^{6}\cdot f(x)[/tex]

c) f(x + 6) - [tex]g(x) = 2^{x+6}[/tex]/[tex]g(x) = 2^{6}\cdot f(x)[/tex]

d) f(x) + 6 - [tex]g(x) = 2^{x}+6[/tex]

Mathematically speaking, transformations are operations applied on a function such that its domain or range are altered. There are five operations for functions:

Let suppose that [tex]f(x) = 2^{x}[/tex], the images of this function are, respectively:

a) 6 · f(x) - Multiplication between two functions

[tex]g(x) = 6 \cdot 2^{x}[/tex]

b) f(6 · x) - Composition between two functions

[tex]g(x) = 2^{6\cdot x}[/tex]

[tex]g(x) = (2^{x})^{6}[/tex]

[tex]g(x) = (f(x))^{6}[/tex]

c) f(x + 6) - Composition between two functions

[tex]g(x) = 2^{x+6}[/tex]

[tex]g(x) = 2^{x}\cdot 2^{6}[/tex]

[tex]g(x) = 2^{6}\cdot 2^{x}[/tex]

[tex]g(x) = 2^{6}\cdot f(x)[/tex]

d) f(x) + 6 - Addition between two functions

[tex]g(x) = 2^{x}+6[/tex]

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Answer: 21 J (Joules) of work done.

Step-by-step explanation:

W = Fs, where F is force and s is displacement.

F = 7 N

s = 3 m

W = 7 N * 3 m = 21 N*m, or 21 J

21 N/m of work is done by a man to push the box.

The displacement plus a component of the applied force of the item in the direction of displacement make up the work done by a force. Work is accomplished when we push a block with some force; the body moves more quickly.

We have,

Force = 7 Newton

Distance = 3 m

We know, Work done = Force x distance

Work done = 7 x 3

Work done = 21 N/m

Thus, the amount work done is 21 N/m.

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Answer:

Step-by-step explanation:

(1 + 11)/(-2+5)= 12/3=4

y + 11 = 4(x + 5)

y + 11 = 4x + 20

y = 4x + 9

Answer:

x = 3

Explanation:

⇒ 4 - 7(x) = 1 - 6(x)

⇒ -7(x) + 6(x) = 1 - 4

⇒ -(x) = -3

⇒ x = 3

Check:

Hence, x = 3 confirmed as L.H.S = R.H.S

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \:4 - 7x = 1 - 6x[/tex]

[tex]\qquad \sf  \dashrightarrow \:4 - 1 = 7x- 6x[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 3[/tex]

so, we got the value of x as 3

Answer:

0.32

Step-by-step explanation:

3/10=0.3

2/5=0.4

0.32 is between these two numbers.

Hope this Helps

Answer:

[tex]\csc \left(x\right)=\frac{\csc \left(x\right)+\sec \left(x\right)}{1+\tan \left(x\right)}[/tex]

[tex]=\frac{1}{\sin \left(x\right)}[/tex] (expressed with sine and cosine)

[tex]\frac{1}{\sin \left(x\right)}=\csc \left(x\right)[/tex]

[tex]=\csc \left(x\right)[/tex]

Therefore, the identity has been proven true.

Answer:

x= -3

x= -5

Step-by-step explanation:

x^2 + 8x + 15 = 0

find which 2 numbers when multiplied equal 15 and when added equal 8

they are 3 and 5

(x+3)(x+5)

x+3 =0

x+5=0

x= -3

x= -5

Answer:

B is the correct answer from my understanding

Step-by-step explanation:

Answer:

45.5 m²

Step-by-step explanation:

Area (Shaded) = Area (Rectangle) - Area (Trapezoid)

Area of trapezoid:-

Area of triangle:-

Which part is shaded not said so both shaded regions area calculated

Step-by-step explanation:

cubic root(56) + cubic root(189) =

= cubic root(7×8) + cubic root(27×7) =

= 2×cubic root(7) + 3×cubic root(7) = 5×cubic root(7) =

= 9.564655914...

If the area of the triangle and the rectangle is 4 square cm and 2 square cm. Then the total surface area of the triangular prism will be 14 square cm.

A closed solid with two parallel triangular bases joined by a rectangle surface is known as a triangular prism.

The total surface area of the triangular prism will be

Total surface area = 2(area of the triangle) + 3(area of the rectangle)

The area of the rectangle will be

Rectangle area = 2 x 1

Rectangle area = 2 square cm

The area of the triangle will be

Triangle area = 0.5 x 4 x 2

Triangle area = 4 square cm

Then the total surface area will be

Total surface area = 2 x 4 + 3 x 2

Total surface area = 8 + 6

Total surface area = 14 square cm

More about the triangular prism link is given below.

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Answer:

sin²x OPTION D

Step-by-step explanation:

sorry for the bad handwriting lol

Answer:

You can easily find 6 is out of 19

Explanation:

in one step, by simply dividing 6 by 19, then multiplying the result by 100. So, 6 is out of 19 = 6 / 19 x 100 = 31.578947368421%

Answer:

its 3

Step-by-step explanation:

id ont know the formula but im certain im a very smart 6th grader!

Answer:

here

Step-by-step explanation:

find the circumference of the lid (this is like a side length of a rectangle)

2*pi*2= 12.566in

Then multiply by 3 (the other side length)

12.566*3= 37.7in squared :)

Answer:

h > 1600

Step-by-step explanation:

Since the elevation at which it is difficult for Matt to breathe (h) has to be *higher* than 1600, h is greater than 1600.

Answer: 343.5

Step-by-step explanation: multiply 15 * 17 and you get 255 then divide that by 2 and you get 127.5.

Next you multiply 8 by 27 (which is 216)

Now add 127.5 and 216 and you get 343.5

Answer:

I need more info

Step-by-step explanation:

Answer:

See below ~

Step-by-step explanation:

Table 1

⇒ Side length : Perimeter = 1 : 4

⇒ Perimeter : Side length = 4 : 1

Table 2

⇒ Radius : Diameter = 1 : 2

⇒ Diameter : Radius = 2 : 1

Table 3

⇒ Number of people : Number of tables = 5 : 1

⇒ Number of tables : Number of people = 1 : 5

Answer: 113 ( 34x3+11

Step-by-step explanation:

34x 3 on top + 7 + 24/6

34 x 3 on top + 7 = 4

34 x 3 on top + 7 + 4

34 x 3 on top + 11

34 x 3 on top + 11

Answer:

an acute triangle im guessing ik its not a right and the degrees and  the inches are small So it can't be absolute thats just what i was thinking but i might be wrong

Step-by-step explanation:

Answer:

h = - [tex]\frac{3}{10}[/tex]

Step-by-step explanation:

23h - 13h + 11 = 8 ( subtract 11 from both sides )

10h = - 3 ( divide both sides by 10 )

h = - [tex]\frac{3}{10}[/tex]

Your answer(s) will be:

0.3 (Decimal Form)

              or

3/10 (Fraction Form)

Answer:

You could ask what her average score is using mean (which is 36.25)

Step-by-step explanation:

Answer:

You could ask what her average score is using mean (which is 36.25)

Step-by-step explanation:

Answer:

30.96

Step-by-step explanation:

First you must find the diameter of the circle which is 12

Then you must use the formula A=πr²

So it should be = to A = 3.14 ×144 which is 30.96

[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]

[tex] \large\underline{ \boxed{ \sf{✰\:Notes }}}[/tex]

[tex] \rule{70mm}{2.9pt}[/tex]

[tex] \large\underline{ \boxed{ \sf{✰\: formule\: used\:✰ }}}[/tex]

[tex]{ \boxed{✟\underline{ \boxed{ \sf{\: Area \: of \: circle = \pi {r}^{2} \: }}}✟}}[/tex]

[tex]{ \boxed{✟\underline{ \boxed{ \sf{\: Area \: of \: square = side \times side \: or \: ( {s}^{2}) \: }}}✟}}[/tex]

[tex] \rule{70mm}{2.9pt}[/tex]

✛ 1st taking out the the area of circle✛

[tex] \qquad \rm{➛ \: radius(r) = \frac{12}{2} } \\ \\ \qquad \rm{➛ \: radius(r) = \frac{ \cancel{12}}{ \cancel2} } \\ \\ \qquad \rm{➛ \: radius(r) =6m}[/tex]

[tex] \\ \qquad \rm{➛Area \: of \: circle = 3.14 \times {6}^{2} \:} \\ \\ \qquad \rm{➛Area \: of \: circle = \:3.14 \times 36} \\ \\ \qquad \rm{➛Area \: of \: circle = \:113.04 {m}^{2} }[/tex]

[tex] \rule{70mm}{2.9pt}[/tex]

✛ now finding the area of square✛

[tex]\\ \qquad \rm{➛Area \: of \:square = 12×12} \\ \\ \\ \qquad \rm{➛Area \: of \:square = 144 {m}^{2} }[/tex]

[tex]\\ \rm{➛Area \: of \:shaded \: part = \: area \: of \: circle - area \: of \: squre} \\ [/tex]

★ Let's substitute value ★

[tex]\\ \rm{➛Area \: of \:shaded \: part =113.04-144} \\ \\ \qquad \rm{➛Area \: of \:shaded \: part =30.96 {m}^{2} }[/tex]

[tex] \rule{70mm}{2.9pt}[/tex]

★ Hence area of shaded part =

[tex]{ \boxed{✜\underline{ \boxed{ \sf{ \: 30.96 {m}^{2} \green✓\: }}}✜}}[/tex]

★ note here we neglect minus (-)

[tex] \rule{70mm}{2.9pt}[/tex]

Hope it helps !