Marcy pulls a backpack on a wheels down the 100m hall. The 60N force is applied at an angle of 30° above the horizontal. How much work is done by Marcy?

Answers

Answer 1

Answer:

Work= Fcos∆×S

W=60N×cos 30⁰×100

W=60×0.866×100=5196.1J

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Related Questions

How do sociologists view the categories of race, class, and gender?

Multiple Choice

1. inherent and inevitable
2. socially constructed
3. unchangeable and perpetual
4. natural and biologically determined​

Answers

Answer:

2. Socially constructed

Explanation:

a box is slides down a slope

Answers

Answer:

120 N

Explanation:

From the question given above, the following data were obtained:

Angle (θ) = 35°

Mass (m) = 15 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal force (N) =?

The normal force acting on the object can be obtained as:

N = mg × Cosθ

N = 15 × 9.8 × Cos 35

N= 147 × 0.8192

N = 120 N

Therefore, the normal force acting on the object is 120 N

The National Institute of Health is testing sensors which measure the energy felt by goalkeepers when blocking soccer balls coming at them and the velocity of soccer balls. One sensor measuring velocity is inside a 16 ounce soccer ball, which is kicked by a player at an initial velocity of 31 m/s. The ball bounces off the goalkeeper at a final velocity of 2.25 m/s. How much energy in Joules should the sensor say the goalkeeper absorbed, not accounting for wind and drag

Answers

Answer:

E = 216.76 J

Explanation:

The amount of energy absorbed by the goalkeeper will be equal to the difference between the initial and the final kinetic energy of the ball.

[tex]Energy\ Absorbed = Initial\ Kinetic\ Energy - Final\ Kinetic\ Energy\\Energy\ Absorbed = E = \frac{1}{2}mv_{i}^2 - \frac{1}{2}mv_{f}^2\\E = \frac{1}{2}m(v_{i}^2 - v_{f}^2)\\[/tex]

where,

m = mass of ball = (16 ounce)(0.0283495 kg/1 ounce) = 0.4535 kg

vf = final velocity = 2.25 m/s

vi = initial velocity = 31 m/s

Therefore,

[tex]E = \frac{1}{2}(0.4535\ kg)[(31\ m/s)^2 - (2.25\ m/s)^2][/tex]

E = 216.76 J

a 1.5 kg ball is thrown vertically upward with an initial speed of 15 m/s. if the initial potential energy is taken as zero, find the ball's kinetic, potential, and mechanical energies (a) a its initial position, (b) at 5 m above the initial position, and (c) at its maximum height

Answers

Answer:

a) [tex] E_{p} = 0 [/tex]

[tex] E_{k} = 168.7 J [/tex]

[tex] E_{m} = 168.7 J [/tex]

b) [tex] E_{p} = 73.6 J [/tex]

[tex] E_{k} = 95.8 J [/tex]

[tex] E_{m} = 169.4 J [/tex]

c) [tex] E_{p} = 169.2 J [/tex]

[tex] E_{k} = 0 [/tex]

[tex] E_{m} = 169.2 J [/tex]

Explanation:

We have:

m: is the ball's mass = 1.5 kg

v₀: is the initial speed = 15 m/s

g: is the gravity acceleration = 9.81 m/s²

a) In the initial position we have:

h: is the height = 0

The potential energy is given by:

[tex] E_{p} = mgh = 0 [/tex]

The kinetic energy is:

[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J [/tex]

And the mechanical energies:

[tex] E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J [/tex]

b) At 5 m above the initial position we have:

h = 5 m

The potential energy is:

[tex] E_{p} = mgh = 1.5*9.81*5 = 73.6 J [/tex]

Now, to find the kinetic energy we need to calculate the speed at 5 m:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9 [/tex]

[tex] v_{f} = \sqrt{126.9} = 11.3 m/s [/tex]

[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J [/tex]

And the mechanical energies:

[tex] E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J [/tex]

c) At its maximum height:

[tex] v_{f}[/tex]: is the final speed = 0

[tex] h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m [/tex]

Now, the potential, kinetic and mechanical energies are:

[tex] E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J [/tex]

[tex] E_{k} = \frac{1}{2}mv^{2} = 0 [/tex]

[tex] E_{m} = 169.2 J + 0 = 169.2 J [/tex]

I hope it helps you!    

The charge on the sphere is monitored as a beam of monochromatic light shines on the sphere. Initially nothing happens. The wavelength of the light is slowly decreased. When the wavelength reaches a certain value, a positive charge is suddenly measured on the sphere. The wavelength is then held constant, and the charge continues to increase at a constant rate. The intensity of the beam is then increased without the wavelength being changed, and the rate of increase of the charge becomes greater.
In a coherent paragraph-length response, describe the cause of the charge on the sphere and the changes in the observations about the charge, in terms of physics principles.

Answers

Answer:

explanation of this effect  is  the photoelectric effect

Explanation:

Let's describe the process, when light of large wavelength falls, this implies a small energy, according to Planck's equation

           E = h f = [tex]\frac{h \ c}{ \lambda}[/tex]

the energy of the photons is not enough to carry out an electronic transition between two states of the material, when we decrease the wavelength (the energy of the photons increases), the point is reached where the energy of the beam is equal to some energy of a transition, by which the electrons are promoted and since we can see a certain charge, as the atoms are neutral, some electrons must be removed from the material, this is represented in the macroscopic case as the work function of the material, consequently a unbalanced load that is what we can measure.

When we increase the lightning intensity, what we do is that we increase the number of photons and if each photon can remove an electron, by removing the electrons the difference between it and the positive charge (fixed in the nuclei) increases.

We can analyze the interaction of the photon and the electron as a particular collision.

The explanation of this effect was made by Einstein in his explained of the photoelectric effect

As Carlos and Manual both push a 4 kg box to the right across a rough floor, the box speeds up at a rate of 2.0 m/s2.(Hint, this is the acceleration.) If you assume that Manual pushes with a force strength of 8.0 N and the friction force of the floor on the box is 5.0 N, then what is the strength of the force that Carlos pushes on the box

Answers

Answer: 5 N

Explanation:

Given

Mass of box [tex]m=4\ kg[/tex]

acceleration of box [tex]a=2\ m/s^2[/tex]

Force applied by Manual [tex]F_m=8\ N[/tex]

Friction force [tex]f=5\ N[/tex]

The net force on the block is [tex]F_{net}=m\times a=4\times 2=8 \N[/tex]

Suppose [tex]F_c[/tex] is the force applied by Carlos

[tex]\Rightarrow F_m+F_c-f=F_{net}\\\Rightarrow F_c=F_{net}-F_m+f\\\Rightarrow F_c=8-8+5=5\ N[/tex]

The strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]

What is force?

The force is defined as the external effort applied on any object to move it or to restrict it.

Here following information is given in the question:

Mass of the box m=4 kg

The acceleration of the box [tex]a=2\ \frac{m}{s^2}[/tex]

The force applied by the Manual [tex]F_m=8\ N[/tex]

The frictional force is [tex]F_f=5\ N[/tex]

The net force on the body will be calculated by

[tex]F_{net}=m\times a=4\times 2=8\ N[/tex]

The force that Carlos pushes on the box will be calculated by the equilibrium of the forces:

[tex]F_m+F_c-F_f=F_{net}[/tex]

[tex]8+F_c-5=8[/tex]

[tex]F_c=5\ N[/tex]

Thus the strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]

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A water park rider (mass = 20.0 kg) starts from rest at the top of a 48.0-m tall
water slide (A). The height at B is 16.0 m. Assuming mechanical energy
conservation, determine the potential energy (PE) and kinetic energy (KE) values
at locations A, B and C. Use g = 10.0 N/kg.

Answers

This question involves the concept of the law of conservation of energy.

The potential energy at A,B,C is "9.6 J","3.2 KJ","0 KJ", respectively.

The kinetic energy at A,B,C is "0 KJ","6.4 KJ","9.6 KJ", respectively.

What is the law of conservation of energy?

The law of conservation of energy states that total energy of the system at any instant must remain constant.

At point A

At point A, the rider is at rest at a height of 48 m on top of the slide. So the kinetic energy of the rider must be 0 KJ. And the potential energy will be given as follows:

[tex]P.E=mgh[/tex]

where,

P.E = potential energy = ?m = mass = 20 kgg = 10 m/s²h = height = 48 m

Therefore,

[tex]P.E = (20\ kg)(10\ m/s^2)(48\ m)\\[/tex]

P.E = 9600 J = 9.6 KJ

At point B

The potential energy at point B will be:

[tex]P.E=mgh[/tex]

where,

P.E = potential energy = ?m = mass = 20 kgg = 10 m/s²h = height = 16 m

Therefore,

[tex]P.E = (20\ kg)(10\ m/s^2)(16\ m)\\[/tex]

P.E = 3200 J = 3.2 KJ

According to the law of conservation of energy the rest of the total energy shall be converted to kinetic energy:

K.E = 9.6 KJ - 3.2 KJ

K.E = 6.4 KJ

At point C

At the lowest point C of the ride, the potential energy will become 0 KJ, and the whole energy shall be converted to kinetic energy, that is 9.6 KJ.

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on which principle thermometer is based?​

Answers

Answer:

Thermal Expansion

Explanation:

These liquid thermometers are based on the principal of thermal expansion. When a substance gets hotter, it expands to a greater volume. Nearly all substances exhibit this behavior of thermal expansion. It is the basis of the design and operation of thermometers.

A driver is texting without seeing the traffic ahead and crashes into a stationary vehicle. Explain what happens to the kinetic energy. Answer in 4-6 sentences.

Answers

Answer:

By Principle of Energy Conservation, the car in motion have an entire inelastic collision with the stationary vehicle, meaning that a part of the energy is dissipated due to inelastic deformation in both cars and resulting kinetic energy is lower, then the remaining kinetic energy is dissipated gradually due to friction between tires and ground by Work-Energy Theorem.

Explanation:

By Principle of Energy Conservation, the car in motion have an entire inelastic collision with the stationary vehicle, meaning that a part of the energy is dissipated due to inelastic deformation in both cars and resulting kinetic energy is lower, then the remaining kinetic energy is dissipated gradually due to friction between tires and ground by Work-Energy Theorem.

i need written answer with solution:-
a person walks 750m due north then 250 m due east of the entire walk takes 12 min find the person average velocity​

Answers

Answer:

~65.9m/min

Explanation:

Excuse the messy handwriting!

how many protons would the element with the atomic number 10 contain?

Answers

Answer:

the atomic number is the same as the proton numbers so your answer is D.10

Answer:

It contains 10 protons and 10 electrons.

How much heat does it lose to change 126 g of water from 67°C to 37°C?​

Answers

Explanation:

convert gram into kg q means amount of heat lost

A student is producing a power rating of 100 W. What will be the student's power rating if she performs 3 times the work in twice the amount of time?​

Answers

600W is the correct answerr

Which type of reaction is this formula an example of?

CH3OH + O2→CO2 + 2H2O + heat

Answers

Explanation:

This is an exothermic reaction. An exothermic reaction is one which releases heat to the surroundings. When CH3OH reacts with O2, heat is released on the product side of the reaction.

A car is stopped at a traffic signal. A second car rear-ends the first car. From the crush of the two vehicles, it is estimated that the second car was traveling at 15 mph when it impacted the first car. If the second car laid down 166 feet of skid marks before the crash took place, how fast was the second car traveling when its brakes were locked up

Answers

The question is incomplete. The complete question is :

A car is stopped at a traffic signal. A second car rear-ends the first car. From the crush of the two vehicles, it is estimated that the second car was traveling at 15 mph when it impacted the first car. If the second car laid down 166 feet of skid marks before the crash took place, how fast was the second car traveling when its brakes were locked up? The approach to the intersection where the accident took place is on a 2.5 percent downgrade. Assume the AASHTO recommended deceleration rate of [tex]$11.2 \ ft/s^2.$[/tex]

Solution :

From the equation, the skid distance is given by

[tex]$S=\frac{u_i^2-u_f^2}{2g\left(\frac{a_d}{g}+h\right)}$[/tex]

Here, [tex]$a_d$[/tex] = deceleration rate, [tex]$11.2 \ ft/s^2.$[/tex]

         h = [tex]$-\frac{2.5}{100}$[/tex] = -0.025

         [tex]$u_i$[/tex] = initial speed of the car

         [tex]$u_f$[/tex] = speed when impacted

Therefore,

[tex]$166=\frac{u_i^2-(15 \times 1.467)^2}{2\times 32.2\left(\frac{11.2}{32.2}+0.025\right)}$[/tex]

[tex]$\Rightarrow u_i^2 = 3935.36$[/tex]

[tex]$\Rightarrow u_i = 62.73 \ ft/s$[/tex]

or [tex]$ u_i = \frac{62.73}{1.467} $[/tex]

   [tex]$ u_i = 42.76 \ mph $[/tex]

What is the magnitude of the resultant vector? Round
your answer to the nearest tenth.
m
R
5 m
13 m
Intro
Done

Answers

Answer: 13.9 m

Explanation:

Answer:

13.9m

Explanation:

Answer on Edge

WILL MARK YOU BRAINLIEST
Describe the importance and reliability of systems that use digital signals to store information. (Include the advantages of storing information digitally, as opposed to physical copies.)
Describe three instances of digital transmission and storage in your everyday life. Be sure to explain how you know data transmission or storage is occurring in each instance.
Explain how radio waves and digital signals will store and transmit this assignment to your instructor.
Describe how wave behavior and interactions can affect the quality of a signal received by a mobile device.
A medical office is planning to convert to an electronic database to store patient information. What are the pros and cons to making changes in this form of storage of personal medical information instead of written physical files? Provide evidence based on your knowledge of digital storage to support your reasoning.
As seen in the lesson video, solar photovoltaic technologies help provide clean electrical energy. Using the video animation as a guide, diagram and label the absorption of photons and production of electrons (photoelectric effect) used in solar PV systems. Include a screen shot or picture of your diagram below.

Answers

Digital signals are a more reliable form of transmitting information because an error in the amplitude or frequency value would have to be very large in order to cause a jump to a different value. Signals are composed of infinite possible values. ... Sound signals can vary smoothly in volume and pitchAdvantages to using digital signals, including digital signal processing (DSP) and communication systems, include the following:

Digital signals can convey information with less noise, distortion, and interference.

Digital circuits can be reproduced easily in mass quantities at comparatively low costs.

Answer:

it is easy to change the data if you have the right computer programs

Explanation:

Water is kept in a vessel at a temperature of 100°C. What would happen if a metal ball having a temperature of 30°C is dropped in it? Mention the direction of the heat flow.

Answers

Answer:

there will be a heat flow from water to the metal ball...

Use the drop-down menus to complete the sentences.
A concave lens is
in the middle than at the edges, and causes light rays to
A convex lens is
in the middle than at the edges, and causes light rays to

Answers

Answer:

1) thinner, diverge

2) thicker, converge

Explanation:

i got it right thanks to the other user :)

A concave lens is thinner in the middle than at the edges, and causes light rays to diverge.

A convex lens is thicker in the middle than at the edges, and causes light rays to converge.

What are concave and convex lens?

The lenses used to form images of the object placed a distant apart.

The concave mirror form images by virtual meeting of the light rays and appear to meet. They are thin at the middle portion.

The convex mirror form images by real meeting of the light rays. They converge the rays coming from object. They are thick at the middle portion.

Thus, A concave lens is thinner in the middle than at the edges, and causes light rays to diverge.

A convex lens is thicker in the middle than at the edges, and causes light rays to converge.

Learn more about concave and convex lens.

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Any magnet has two ends, each one called a(n)​

Answers

pole (north pole and south pole)

Can someone answer this fast please

Answers

I believe it’s 6 like it’s most likely to be the answer but I’m sorry if it’s not
I believe the answer is 6m

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower

Answers

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

Answer:

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Explanation:

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

Answer:

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

You find an unmarked blue laser on your way to physics class. When you get to class you realize you can determine the wavelength of the laser by doing a double slit experiment. Shining the laser through a double slit with a slit separation of 0.342 mm on the wall 2.12 m away the first bright fringe is 2.80 mm from the center of the pattern. What is the wavelength

Answers

Answer:

λ = 451.7 nm

Explanation:

The expression for the constructive interference of the double diffraction experiment is

          d sin θ = m λ

let's use trigonometry

          tan θ = y / L

   

how the experiment occurs at very small angles

          tan θ = sin θ / cos θ = sin θ

          sin θ = y / L

we substitute

         d y / L = m λ  

         λ = [tex]\frac{d \ y}{m \ L}[/tex]

let's calculate

          λ = [tex]\frac{0.342 \ 10^{-3} \ 2.80 \ 10^{-3} }{1 \ 2.12 }[/tex]

          λ = 4.51699 10⁻⁷ m

          λ = 4.517 10⁻⁷ m (109 nm / 1m)

          λ = 451.7 nm

6/30
What is the total circuit resistance of the following five resistors connected in series?
R1 = 27 ohms
R2 = 33 ohms
R3 = 51 ohms
R4 = 1.2 kohms
R5 = 240 ohms
Rt =
Ohms

Answers

Answer:

Explanation:

in series, resistors just add up

27+33+51+1200+240= 1551 ohms

I’m not sure sorry hope someone helps :)

Which on the map
represents Asia?

Answers

Answer:

B because it's on Asia but that pfp tho

The answer is B that represents Asia

Two football players collide head-on in midair while chasing a pass. The first player has a 110 kg mass and an initial velocity of 4.40 m/s in the positive x direction, while the second player has a 135 kg mass and initial velocity of 3.30 m/s in the negative x direction.

Required:
What is the x component of their velocity just after impact if they cling together?

Answers

Answer:

v = 0.16 m/s in the positive x direction.

Explanation:

Assuming no external forces acting during the collision, total momentum must be conserved.Initial momentum can be expressed as follows:

       [tex]p_{o} =m_{1} * v_{o1} + m_{2} * v_{o2} (1)[/tex]

Since both players move only horizontally, (1) can be expressed in terms of the velocities in the x- directions only, taking into account that player 1 moves in the positive x-direction, and player 2 in the opposite direction, and assuming that positive velocities are in the positive x-direction also:

       [tex]p_{o} =110 kg * 4.4 m/s + 135 kg * (-3.3 m/s) (2)[/tex]

Since total momentum must be conserved, the final momentum must be equal to the initial one.We know that both players cling together after colliding, so the collision is totally inelastic.So, the final momentum can be expressed as follows:

       [tex]p_{f} =( m_{1} + m_{2} )* v_{f} (3)[/tex]

Replacing by the givens in (3), we get:

       [tex]p_{f} =( m_{1} + m_{2} )* v_{f} = (110 kg + 135 kg)* vf (4)[/tex]

Since (3) must be equal to (4) we can solve for vf, as follows:

       [tex]v_{f} = \frac {110 kg * 4.4 m/s + 135 kg * (-3.3 m/s) }{(110 kg + 135 kg)} = 0.16 m/s (5)[/tex]

Since the initial momentum has only component in the x-direction, the final one must have component in the x-direction only too.This means that vf is in the x-direction, and due to it is positive, it must aim in the positive x-direction.So, vfx = +0.16 m/s

5j-Tj=6j+3 Tj
Determine the value of T from the given vector

Answers

-1/4

Solve for j and Tj than you have
-j=4Tj
4T=-j/j
4T=-1
T=-1/4

The parallel plates in a capacitor, with a plate area of 7.90 cm2 and an air-filled separation of 2.70 mm, are charged by a 7.90 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 8.80 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates.

Answers

Answer:

A) 26V

Explanation:

(a) the potential difference between the plates

Initial capacitance can be calculated using below expresion

C1= A ε0/ d1

Where d1= distance between = 2.70 mm= 2.70× 10^-3 m

ε0= permittivity of space= 8.85× 10^-12 Fm^-1

A= area of the plate = 7.90 cm2 = 7.90 ×10^-4 m^2

If we substitute the values we

C1= A ε0/ d1

=( 7.90 ×10^-4 × 8.85× 10^-12 )/2.70× 10^-3

C1=2.589 ×10^-12 F= 2.59 pF

Initial charge can be determined using below expresion

q1= C1 × V1

V1=2.589 ×10^-12 F

V1= voltage=7.90 V

If we substitute we have

q1= 2.589 ×10^-12 × 7.90

q1= 20.45×10^-12C

20.45 pC

Final capacitance can be calculated as

C2= A ε0/ d2

d2=8.80 mm= /8.80× 10^-3

7.90 ×10^-4 × 8.85× 10^-12 )/8.80× 10^-3

C1=0.794 ×10^-12 F= 0.794 pF

Final charge= initial charge

q2=q1 (since the battery is disconnected)

q2=q1= 20.45 pC

Final potential difference

V2= q/C2

= 20.45/0.794

= 26V

What does efficient mean in your own words in science

Answers

Answer:

Efficient means something that gives 100% accuracy.

what will it be the critical angle if light is incident from glass n=1.5 in to the air n=1​

Answers

Answer:

The formula, which is fairly easy to derive, is:

The sine of the critical angle = refractive index of the “refracting medium” divided by refractive index of the “incident medium”.

In this case the “refractive medium” is air and the “incident medium” is glass.

The refractive index of air is about 1 (almost exactly).

So, in this case, the sine of the critical angle is 1 divided by 1.5 = 0.6667.

You will find the answer, from sine tables, to be approximately 41.81 degrees.

Remember that the refractive index of air is slightly more than 1. Using a better value for refractive index of air, I get the critical angle to be about

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