Many scientists think human cloning is possible, so why haven't we made human clones yet?

Question 5 options:

There is not enough medical supplies to clone a human


Human cloning is extremely controversial and many people believe it is unethical


Scientists have determined that stem cells would not be beneficial to human cloning


The human genome is too complex to clone

Answer:

467.000g AICI3 to mol AICI3

Explanation

Answer:

7.49959 mol i hope this is right

Answer:

1.25×10²⁵ molecules of ethane contains 124.56 moles of Hydrogen atoms.

Answer:

3.089 L

Explanation:

From the given information, provided that the no of moles and the temperature remains constant;

[tex]P_1[/tex] = 15.6 psi

[tex]V_1[/tex] = ???

[tex]P_2[/tex] = 25.43 psi

[tex]V_2[/tex] = 1.895 L

Using Boyle's law:

[tex]P_1V_1 =P_2V_2 \\ \\ V_1 = \dfrac{P_2V_2}{P_1} \\ \\ V_1 = \dfrac{25.43 \times 1.895}{15.6} \\ \\ \mathbf{ V_1 = 3.089 \ L}[/tex]

Answer:

A. The reaction proceeds in the forward and reverse directions at the same rate.

B. Both the forward and the reverse reactions are achievable.

D. There is no net change in concentrations of reactants and products.

Explanation:

Chemical equilibrium can be defined as the state of a reversible reaction in which the concentration (rate) of the forward reaction is equal to the concentration (rate) of the backward or reverse reaction. Thus, both the reactants and products of the chemical equation don't have the tendency to change with respect to time.

Hence, the options that are true of chemical equilibria include the following;

I. The reaction moves in both forward and reverse directions simultaneously i.e at the same rate.

II. The chemical equation can attain both forward and reverse reactions.

III. The concentrations of both reactants and products are the same i.e there's no net change.

Answer:

A B D knewton

Explanation:

Answer: its c

Explanation:

Answer:D

Explanation:

Answer:

1. The balanced chemical reaction is:

[tex]HNO_3(aq)+NaOH(aq)\rightarrow NaNO_3(aq)+H_2O(l)[/tex]

2. The balanced chemical reaction is:

[tex]2HI(aq)+Sr(OH)_2(aq)\rightarrow SrI_2(aq)+2H_2O(l)[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reactions, it is necessary to keep in mind the cations and anions are switched around as a result of the bonds rearrangement in these neutralization reactions; therefore, we can proceed as follows:

1. The balanced chemical reaction is:

[tex]HNO_3(aq)+NaOH(aq)\rightarrow NaNO_3(aq)+H_2O(l)[/tex]

Because all atoms are in the same amount at each side of the equation and the resulting salt is soluble.

2. The balanced chemical reaction is:

[tex]2HI(aq)+Sr(OH)_2(aq)\rightarrow SrI_2(aq)+2H_2O(l)[/tex]

Because all atoms are in the same amount at each side of the equation and the resulting salt is soluble.

Best regards!

The mass of the kool aid needed to prepare the solution is 81.2 g.

The term concentration has to do with the amount of substance present in solution. We are told to make calculations regarding the preparation of a 237.5 ml kool-aid solution with a concentration of 1M.

Litres of water needed = 237.5/1000 = 0.2375 L

Molarity of kool-aid needed = 1 M

number of moles = 1 M *  0.2375 L = 0.2375 moles

0.2375 moles = mass of kool aid/molar mass

0.2375 moles = mass/ 342 g/mol

mass = 0.2375 moles * 342 g/mol

mass = 81.2 g

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C

Tarnishing of silver is caused by hydrogen sulfide and other sulfur containing compounds in the air reacting to the silver and resulting in a fine layer of silver sulfide. The other answers don't make sense

Answer:

The ratio of the mass of a substance to its volume is called...density.

Answer

PubChem CID/molecular formula

Explanation:

Cesium bromide

PubChem CID 24592

Molecular Formula CsBr or BrCs

Synonyms CESIUM BROMIDE 7787-69-1 Caesium bromide Cesiumbromide Cesium bromide (CsBr) More...

Molecular Weight 212.81 g/mol

Component Compounds CID 260 (Hydrogen bromide) CID 5354618 (Cesium)

have a good day /night

may i please have a branllist

Answer:

0.559 L

Explanation:

Step 1: Given data

Moles of sodium iodide (n): 0.405 mol

Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)

Step 2: Calculate the volume of solution (V)

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V  

V = n/M  

V = 0.405 mol/(0.724 mol/L) = 0.559 L

(hope this helps can i plz have brainlist :D hehe)

Answer:

water pollution is a process in which water gets polluted due to discharge of city sewage and industrial waste. I was suffering through the water born disease when I drank the contaminated water. The sources of water becomes dirty. It makes environment unbalanced. People suffer from different water born disease when they drink polluted water.

Answer:

D

Explanation:

Answer:C and D

Explanation:Just did it

Increasing the pressure and Decreasing the temperature are the two changes would make this reaction product-favored.

It is a state when a reaction is reversible and both forward and reverse reaction occur simultaneously at the same rate .

In the process of manufacture of Ammonia , both forward and reverse reaction are taking place

N₂(g) + 3H₂ (g) →  2NH₃ (g)

2NH₃(g)  →  N₂ (g) + 3H₂ (g)

when these reaction occur at same rate , the state is called equilibrium and is represented by

N₂ (g) + 3H₂(g) ⇔ 2NH₃(g) +Heat

As we can see from the equation , heat is produced in the forward reaction so if we increase the temperature the reverse reaction will be favored ,

On decreasing temperature the reaction will become product favored .

While on increasing the Pressure the manufacture of Ammonia increases.

Therefore Option C and Option D are the two changes would make this reaction product-favored.

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Answer:

2.75 × 10⁻⁶ M/s

1.69 × 10⁻⁶ M/s

9.23 × 10⁻⁻⁷ M/s

4.43 × 10⁻⁻⁷ M/s

2.1 × 10⁻⁻⁷ M/s

Explanation:

We have the following information for the isomerization of methyl isonitrile

Time (s)      [CH₃NC] (M)

  0              0.0165

2000          0.0110

5000          0.00591

8000          0.00314

12000         0.00137

15000         0.00074

To calculate the average rate of reaction (r) for each interval, we need to use the following expression:

r = -Δ[CH₃NC]/Δt

Interval 0-2000 s

r = - (0.0110 M-0.0165 M)/2000 s - 0 s = 2.75 × 10⁻⁶ M/s

Interval 2000-5000 s

r = - (0.00591 M-0.0110 M)/5000 s - 2000 s = 1.69 × 10⁻⁶ M/s

Interval 5000-8000 s

r = - (0.00314 M-0.00591 M)/8000 s - 5000 s = 9.23 × 10⁻⁻⁷ M/s

Interval 8000-12000 s

r = - (0.00137 M - 0.00314 M)/12000 s - 8000 s = 4.43 × 10⁻⁻⁷ M/s

Interval 12000-15000 s

r = - (0.00074 M - 0.00137 M)/15000 s - 12000 s = 2.1 × 10⁻⁻⁷ M/s

The average rates of reactions for the time interval between each measurement are

2.75×10⁻⁶ M/s

1.70×10⁻⁶ M/s

9.23×10⁻⁷ M/s

4.43×10⁻⁷ M/s

2.10×10⁻⁷ M/s

From the question,

We are to calculate the average rate of reaction for each of the measurement.

First, we will create a proper table for the data

Time (s)       [CH3NC] (M)

0                    0.0165    

2,000            0.0110

5,000            0.00591      

8,000            0.00314      

12,000          0.00137

15,000          0.00074

The average rate of reaction is given by the formula

[tex]Average\ rate\ of\ reaction = \frac{Final\ concentration - Initial\ concentration}{Final\ time - Initial\ time}[/tex]

1.

[tex]Average\ rate\ of\ reaction = \frac{0.0110-0.0165}{2000 -0 }[/tex]

Average rate of reaction = 2.75×10⁻⁶ M/s

2.

[tex]Average\ rate\ of\ reaction = \frac{0.00591-0.0110}{5000 -2000 }[/tex]

Average rate of reaction = 1.70×10⁻⁶ M/s

3.

[tex]Average\ rate\ of\ reaction = \frac{0.00314-0.00591}{8000 -5000 }[/tex]

Average rate of reaction = 9.23×10⁻⁷ M/s

4.

[tex]Average\ rate\ of\ reaction = \frac{0.00137-0.00314}{12000 -8000 }[/tex]

Average rate of reaction = 4.43×10⁻⁷ M/s

5.

[tex]Average\ rate\ of\ reaction = \frac{0.00074-0.00137}{15000 -12000 }[/tex]

Average rate of reaction = 2.10×10⁻⁷ M/s

Hence, the average rates of reactions for the time interval between each measurement are

2.75×10⁻⁶ M/s

1.70×10⁻⁶ M/s

9.23×10⁻⁷ M/s

4.43×10⁻⁷ M/s

2.10×10⁻⁷ M/s

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There is an increase in entropy because the energetically equivalent ways to arrange the components of the  system increased. Option A and C.

The term entropy refers to the degree of disorder in a system. Thus we know that any change that leads to an increase in the number of particles will lead to an increase in entropy.

Hence, we can see from the diagram that the energetically equivalent ways to arrange the components of the  system increased hence there is a positive increase in entropy. The correct options are therefore A and C.

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Answer:

No, alloys are independent of the amount of it's constituents.

Alloys depend on the number of it's constituents.

Only strength of alloys depends on the specific amount of ingredients/constituents/elements.

Answer:

acceleration

pls dont report me

I think the answer is C. (Increasing the number of variables in the experiment)

Answer:

ITS B

Explanation:

THE OTHER GUY WAS WRONG

Explanation:

The two main categories of energy are potential energy (stored

energy) and kinetic energy (energy presently doing

work or causing change)...I hope this helps.

Answer:

1.00 moles of CO2 is the final yield.

Explanation:

Based on the reaction:

2C2H2(g)+ 5O2(g) → 4CO2(g) + 2H2O(g)

When 2 moles of acetylene (C2H2) completely reacts with oxygen, 4 moles of CO2 are produced.

To solve this question we must use the chemical equation knowing: 2 moles C2H2 = 4 mol CO2

When 0.500 moles of acetylene react:

0.500 moles C2H2 * (4mol CO2 / 2mol C2H2) =

Complete question is;

When the concentrations of reactant molecules are increased, the rate of reaction increases. The best explanation for this phenomenon is that as the reactant concentration increases,

A)the average kinetic energy of molecules increases.

B)the frequency of molecular collisions increases.

C)the rate constant increases.

D)the activation energy increases.

E)the order of reaction increases.

Answer:

B) The frequency of molecular collisions increases.

Explanation:

When we increase number of reactant molecules, the effective collision between the reactant molecules will form a product which also increases. As a result, the overall rate of the reaction will also increase which means the frequency of the molecular collision will also increase as well.

Thus, the correct answer is Option B

Answer:

see calculations below

Explanation:

Given:     HOAc     ⇄    [H⁺]     +    [OAc⁻]            

C(i)          0.12M             0M           0.15M

mix  => 5.55ml(0.092M NaOH) / (50ml + 5.55ml)

            = 0.00555(0.092)mole NaOH / 0.0555 L Soln

            = 0.0092M in NaOH is added into the initial buffer solution

            = 0.0092M in OH⁻ (NaOH is a strong base => 100% ionized)

Rxn => Addition of 0.0092M OH⁻ will react with 0.0092M H⁺ shifting buffer            .           equilibrium to the right decreasing [HOAc] and increasing [OAc⁻] by    .           0.0092M each.

Therfore ...

Given:           HOAc      ⇄    [H⁺]     +       [OAc⁻]            

C(i)                0.12M             0M               0.15M

ΔC           - 0.0092M           +x            +0.0092M

C(f)             0.1108M             x                0.1592M  =>  New Concentrations            .                                                                                     after adding 0.0092M             .                                                                                     NaOH

Substituting new acid and ion concentrations into Ka expression ...

Ka = [H⁺][OAc⁻]/[HOAc] = (x)(0.1592M)/(0.1108M) = 1.75 x 10⁻⁵M

=> x = [H⁺](new) = (1.75 x 10⁻⁵M*)(0.1108M)/(0.1592M) = 1.22 x 10⁻⁵M in H⁺ ions

*units of Ka are Molar

FYI => Adding a strong base to a buffer solution will shift pH to more basic.

          Adding a strong acid   to a buffer solution will shift pH to more acidic.

=> (such is a good way to check that your buffer calculations are correct.)

NOTE => Question asks for moles of HOAc, Na⁺OAc⁻ & NaOH after adding base. Giving answers in terms of Molarity (moles/Liter) is same as moles. Therefore ...

[HOAc] = 0.1108M

[NaOAc] = 0.1592M

[NaOH] = ∅M (from rxn of H⁺ + OH⁻ => H₂O, all NaOH was consumed in acid/base reaction.  Remaining are only Na⁺ as a spectator ion and OH⁻ as a function of the new concentration of H⁺ => [OH⁻] = Kw/[H⁺] = 1 x 10⁻¹⁴/1.22 x 10⁻⁵ = 8.2 x 10⁻¹⁰M.

Hope this helps. :-)

Answer: a

Explanation:

this is common sense

Answer:

C'est fini sous la lettre A. Ice crystals from forming inside it's body