Let f(x)= -2x+4 and g(x)= 3x^2. Find (f+g)(x) and (f-g)(x)
State the domain of each.
Evaluate the following: (f+g)(-3) and (f-g)(-3)

The given expression is a trinomial because it consists of three terms: 4x²-y+oz⁴

A trinomial is a polynomial with three terms. It is a type of algebraic expression that consists of three monomials connected by addition or subtraction. The general form of a trinomial is:

ax^2 + bx + c

A monomial is an algebraic expression that consists of a single term. It is a polynomial with only one term. A term is a combination of a coefficient and one or more variables raised to non-negative integer exponents.  The general form of a monomial is:c * xᵃ,  yᵇ, zⁿ....

where 'c' represents the coefficient (a constant), and 'x', 'y', 'z', etc., represent variables, each raised to a non-negative exponent (a, b, n, etc.).

example of monomials:  5x² - This monomial has a coefficient of 5 and a single variable 'x' raised to the power of 2.

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The sample space in this problem is the total number of couples surveyed, which is 1000.

The sample space in probability refers to the set of all possible outcomes of an experiment. In this case, the experiment is the survey conducted by Bruskin and Goldring Research, and the possible outcomes are the different categories of time taken by couples before getting engaged.

The given information provides the number of couples in each category, which can be added to find the total number of couples surveyed:

Sample space = Number of couples never engaged + Number of couples engaged for less than 1 year + Number of couples engaged for 1 to 2 years + Number of couples engaged for more than 2 years

Sample space = 200 + 240 + 210 + 350

Sample space = 1000

Therefore, the sample space in this problem is 1000, which represents the total number of couples surveyed by the research firm.

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The type of statistical study in which the population is influenced by researchers is known as an experimental study.

In an experimental study, researchers manipulate one or more variables to observe the effect on another variable. The population in an experimental study is usually a sample that is randomly selected to represent the larger population.

The researchers intentionally intervene in the study, which can impact the behavior or responses of the participants. This can be seen as a form of bias since the researchers are influencing the population. However, in some cases, this is necessary to determine causality or to test a hypothesis.

To minimize bias, experimental studies often use control groups. The control group is used to provide a baseline for comparison with the group that is exposed to the manipulated variable. This helps to determine if any observed effects are due to the intervention or if they are due to other factors.

In summary, an experimental study is the type of statistical study in which the population is influenced by researchers. While this can introduce bias, the use of control groups and other measures can help to minimize the impact of this bias on the results.

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Answer:

1.6×10^-12..............

The probability that Jade gets the specific outcome you're interested in when rolling two dice is 1/6.

To find the probability that Jade gets a specific outcome when rolling two dice, we will use the sample space for rolling two dice, which consists of 36 possible outcomes (since there are 6 sides on each die, and we have 2 dice: 6 x 6 = 36).

Step 1: Determine the specific outcome you are interested in (for example, the sum of the numbers on the dice being 7).

Step 2: Count the number of ways this outcome can occur. For example, if we want a sum of 7, there are 6 possible outcomes: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).

Step 3: Calculate the probability by dividing the number of successful outcomes by the total number of possible outcomes in the sample space.

In our example, there are 6 successful outcomes, and there are 36 possible outcomes in the sample space:

Probability = (Number of successful outcomes) / (Total number of possible outcomes) = 6/36

Step 4: Express the probability in its simplest form by reducing the fraction. In our example, 6/36 can be reduced to 1/6.

So, the probability that Jade gets the specific outcome you're interested in when rolling two dice is 1/6.

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Answer:

the diameter is 14 and the perimeter is 43.97

Angela made $350 per week 25 years ago and Walker made $200 per week 25 years ago.

Let's assign variables to represent Angela and Walker's salaries 25 years ago. Let A be Angela's salary 25 years ago and W be Walker's salary 25 years ago.

Using the information given in the problem, we can set up two equations:

A + W = 550 (their total salary 25 years ago)
4A + 3W = 2000 (their total current salary)

To solve for A and W, we can use substitution or elimination. Let's use substitution.

From the first equation, we can rearrange to solve for A:

A = 550 - W

Substitute this into the second equation:

4(550 - W) + 3W = 2000

Distribute the 4:

2200 - 4W + 3W = 2000

Simplify:

W = 800

Now that we know Walker's salary 25 years ago was $800, we can plug that into the first equation to solve for Angela's salary:

A + 800 = 550

A = -250

Uh oh, a negative salary doesn't make sense in this context. We made a mistake somewhere.

Let's go back to our original equations and try elimination instead:

A + W = 550
4A + 3W = 2000

Multiplying the first equation by 4, we get:

4A + 4W = 2200

Subtracting the second equation from this, we get:

W = 200

Now we can plug this into either equation to solve for A:

A + 200 = 550

A = 350

So Angela made $350 per week 25 years ago and Walker made $200 per week 25 years ago.

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The angle measurement would remain as 40 degrees

No, when a geometric figure, such as a line or an angle, is translated (moved) to a new position without being rotated, reflected, or scaled, its shape and size do not change, and therefore its angle measure remains the same.

This property is a fundamental concept in geometry and is known as the "invariance of angle measure under translation". It means that if two angles are congruent (have the same measure) in their original position, they will remain congruent after being translated to a new position.

Hence The angle measurement would remain as 40 degrees

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The correct symbol to compare the expressions is < (less than).

7 × (2/10) is equivalent to 1.4, which is less than 7. Therefore, 7 is greater than 1.4, and we can write 7 × (2/10) < 7 as the comparison between the expressions.

To compare the two expressions, we can analyze their values without actually multiplying them. The expressions are:

1. 7 × (2/10)
2. 7

Now let's simplify the first expression without multiplying:

7 × (2/10) = 7 × (1/5) (since 2 and 10 have a common factor of 2)

Now let's compare:

7 × (1/5) ? 7

Since we're multiplying 7 by a fraction that is less than 1 (1/5), the result will be smaller than 7. Therefore, the correct comparison symbol is "<":

7 × (1/5) < 7

The correct expression so formed is 7 × (2/10) < 7.

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The given equation is 4h(x) = x - 4.

To find the domain of h(x), we need to determine the set of all possible input values for x that will result in a valid output value for h(x).

Since there are no restrictions on the input values for x in the given equation, the domain of h(x) is all real numbers.

Your answer: The domain of h(x) is all real numbers.

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The domain of the function 4h(x) = x - 4 is all real numbers, because there's no value of x that can make the equation undefined. It's represented as (-∞, ∞).

In the function 4h(x) = x - 4, the variable x is an independent variable and it can take any real number as value. Therefore, the domain of this function refers to the set of all possible x-values. In other words, the domain of this function is all real numbers.

A function's domain is essentially the set of all values that can be plugged into the function without causing problems such as division by zero or taking the square root of a negative number. In the given equation, there's nothing that would limit the possible values of x.

Therefore, the domain of h(x) in this case is all real numbers, symbolically represented as (-∞, ∞).

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Answer:3 gigabytes of storage.

Step-by-step explanation: Because you start at $41.50 and add 5 is $46.60 and then add 5 again and you get $51.50 then add 5 more you get $56.50.

From the function f(x,y)=y⁵ ln(−2x⁴+3y⁵).  The value of  fx = -10x³y⁵ / (-2x⁴ + 3y⁵) and

fy = y⁴ * ln(-2x⁴ + 3y⁵) * d/dy [(-2x⁴ + 3y⁵)]

To find fx, we differentiate f(x,y) with respect to x, treating y as a constant:

fx = d/dx [y⁵ ln(-2x⁴ + 3y⁵)]

Using the chain rule and the derivative of ln u = 1/u, we have:

fx = y⁵ * 1/(-2x⁴ + 3y⁵) * d/dx [-2x⁴ + 3y⁵]

Simplifying and applying the power rule of differentiation, we get:

fx = -10x³y⁵ / (-2x⁴ + 3y⁵)

Similarly, to find fy, we differentiate f(x,y) with respect to y, treating x as a constant:

fy = d/dy [y⁵ ln(-2x⁴ + 3y⁵)]

Using the chain rule and the derivative of ln u = 1/u, we have:

fy = y⁴ * ln(-2x⁴ + 3y⁵) * d/dy [(-2x⁴ + 3y⁵)]

Applying the power rule of differentiation and simplifying, we get:

fy = 15y⁴ ln(-2x⁴ + 3y⁵)

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You bought 8 stamps that cost 45 cents each and 2 stamps that cost 30 cents each.

Let's assume you bought x stamps that cost 45 cents each and y stamps that cost 30 cents each.

From the given information, we can create two equations:

The total number of stamps is 10: x + y = 10.

The total cost is $4.20: 45x + 30y = 420 (since the cost is given in cents).

Now we can solve this system of equations to find the values of x and y.

We can multiply the first equation by 30 to eliminate y:

30x + 30y = 300.

Now we have a system of equations:

30x + 30y = 300,

45x + 30y = 420.

Subtracting the first equation from the second equation, we get:

45x + 30y - (30x + 30y) = 420 - 300,

15x = 120,

x = 120/15,

x = 8.

Substituting the value of x back into the first equation:

8 + y = 10,

y = 10 - 8,

y = 2.

Therefore, you bought 8 stamps that cost 45 cents each and 2 stamps that cost 30 cents each.

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Answer:

Step-by-step explanation:

We can start by converting the distance and time to the appropriate units.

1200000 meters = 1200 kilometers (since 1 kilometer = 1000 meters)

120 minutes = 2 hours (since 1 hour = 60 minutes)

Now we can use the formula:

speed = distance / time

speed = 1200 km / 2 hours

speed = 600 km/h

Therefore, the speed of the new plane is 600 km/h.

Answer: 600km/

First step:

1200000m=1200Km * 1m=0,001km

Second step:

120min=2h *1h=60min

Last step:

1200km÷2h= 600km/

SOLUTION

600km/

Step-by-step explanation:

The equation that represents the total number of miles, m, Victoria should expect to be able to drive if she uses g gallons of gasoline is m = (19g).

We can determine the proportionality constant by dividing the total number of miles driven (76) by the number of gallons of gasoline burned (4), which gives us 19 miles per gallon (76/4 = 19).

We can then use this proportionality constant to create the equation m = (19g), where m represents the total number of miles Victoria should expect to be able to drive if she uses g gallons of gasoline. This equation tells us that for every additional gallon of gasoline burned, Victoria should expect to be able to drive an additional 19 miles.

For example, if Victoria were to burn 6 gallons of gasoline, she should expect to be able to drive 114 miles (6 x 19 = 114). This equation assumes that Victoria's car has a constant fuel efficiency of 19 miles per gallon.

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Answer:

Step-by-step explanation:

To solve the triangle, we can use the law of sines and the fact that the sum of the angles in a triangle is 180 degrees.

First, we can find angle A by using the fact that the sum of the angles in a triangle is 180 degrees:

A = 180 - B - C

A = 180 - 92 - 16

A = 72 degrees

Next, we can use the law of sines to find side a:

a/sin(A) = c/sin(C)

a/sin(72) = 32/sin(16)

a = (32*sin(72))/sin(16)

a ≈ 89.4

Finally, we can use the fact that the sum of the angles in a triangle is 180 degrees to find angle B:

B = 180 - A - C

B = 180 - 72 - 16

B = 92 degrees

Therefore, the triangle has angle B = 92 degrees, angle A = 72 degrees, and side a ≈ 89.4.

Answer:The probability of both is 1/4*13/51.

Step-by-step explanation:

There are 52 cards in the deck, 13 hearts and 13 spades. The probability of getting a heart is 13/52 or 1/4. Given an initial heart there are 51 cards remaining; the probability of a spade is now 13/51

Jane's closet space decreased by approximately 38.97%.

To find the percentage decrease of Jane's closet space, we need to first calculate the amount of decrease and then express it as a percentage of the original value.

The amount of decrease is the difference between the original closet space and the new closet space:

Decrease = Original closet space - New closet space

Decrease = 78 - 47.58

Decrease = 30.42

So Jane's closet space decreased by 30.42 square feet.

To express this decrease as a percentage of the original value, we use the following formula:

Percentage decrease = (Decrease / Original value) x 100%

Substituting the values, we get:

Percentage decrease = (30.42 / 78) x 100%

Percentage decrease ≈ 38.97%

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Answer:

3 m/s²

Step-by-step explanation:

We can use Newton's Second Law of Motion.  The Second Law of Motion states that acceleration is calculated by dividing the force by the mass.

[tex]A=\frac{F}{m}[/tex] with f being the force and m being the mass

We know that the force is 1,500 N and the mass is 500 kg.

So, let's substitute:

[tex]A=\frac{1500}{500}\\A=3[/tex]

So the acceleration of the cart is 3 m/s²

Hope this helps :)

Answer:

Of course, I can assist you with your question. The volume of a sphere with a radius of 2.5 can be calculated using the formula (4/3)*pi*(2.5^3). This results in an answer of approximately 65.45 cubic units in terms of pi.

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EDIT: The volume of a sphere with a radius of 2.5 can be calculated using the formula V = (4/3)πr^3. Plugging in the value of r as 2.5, we get V = (4/3)π(2.5)^3. Simplifying this expression, we get V = 65.45π/3. Thus, the answer in terms of π is 65.45/3π or approximately 21.82π. None of the given options matches the calculated answer.

The set R is not a subset of I. the only subset of I from the given options is A

The set I represents all isosceles triangles.

The set E represents all equilateral triangles, and an equilateral triangle is a special case of an isosceles triangle where all sides are equal. Therefore, the set E is a subset of I.

The set S represents all scalene triangles, and a scalene triangle is not isosceles since it does not have any equal sides. Therefore, the set S is not a subset of I.

The set A represents all acute triangles, and an acute isosceles triangle is a triangle where all angles are less than 90 degrees and two sides are equal in length. Therefore, the set A is a subset of I.

The set O represents all obtuse triangles, and an obtuse isosceles triangle is a triangle where one angle is greater than 90 degrees and two sides are equal in length. Therefore, the set O is not a subset of I.

The set R represents all right triangles, and a right isosceles triangle is a triangle where one angle is equal to 90 degrees and two sides are equal in length. the only subset of I from the given options is A.

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For the first problem, we can interpret the confidence interval as follows:

We are 95% confident that the true mean commuting time for workers who drive to work is between 27.74 and 30.06 minutes.

This means that if we were to repeat the sampling process many times and construct a 95% confidence interval each time, about 95% of those intervals would contain the true mean commuting time.

For the second problem, we can use the following formula to find a 95% confidence interval for the true mean length of long distance telephone calls:

[tex]CI = X ± t*(s/sqrt(n))[/tex]

Where X is the sample mean, s is the sample standard deviation, n is the sample size, and t is the t-value from the t-distribution with n-1 degrees of freedom for a 95% confidence interval.

Plugging in the values given, we get:

[tex]CI = 1.68 ± t*(5.2/sqrt(45))[/tex]

To find the value of t, we can look it up in a t-distribution table or use a calculator. For a 95% confidence interval with 44 degrees of freedom, we get t = 2.015.

Plugging this value in, we get:

[tex]CI = 1.68 ± 2.015*(5.2/sqrt(45)) = (0.86, 2.50)[/tex]

So we can interpret the interval as follows:

We are 95% confident that the true mean length of long distance telephone calls made by customers of this company is between 0.86 and 2.50 minutes longer or shorter than the sample mean of 1.68 minutes.

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The inverse for each relation:

1. {(1,‐2), (2, 3),(3, ‐3),(4, 2)} - {(-2, 1), (3, 2), (-3, 3), (2, 4)}

2. {(4,2),(5,1),(6,0),(7,‐1)} - {(2, 4), (1, 5), (0, 6), (-1, 7)}

3. Inverse equation: y=(-1/8)x+3/8

4. Inverse equation: y=3/2x+15/2

5. Inverse equation: y=2x-20

6. Inverse equation: y=[tex]x^{(1/2)}+3[/tex]

7. Since fog(x) = gof(x) = x, f and g are inverse functions.

8. Since fog(x) = gof(x) = x, f and g are inverse functions.

1. To find the inverse of the relation, we need to swap the positions of x and y for each point and then solve for y.

{(1, -2), (2, 3), (3, -3), (4, 2)}

Inverse: {(-2, 1), (3, 2), (-3, 3), (2, 4)}

2. Again, we swap x and y and solve for y.

{(4, 2), (5, 1), (6, 0), (7, -1)}

Inverse: {(2, 4), (1, 5), (0, 6), (-1, 7)}

3. To find the inverse equation for y=-8x+3, we swap x and y and solve for y.

x=-8y+3

x-3=-8y

y=(x-3)/-8

Inverse equation: y=(-1/8)x+3/8

4. To find the inverse equation for y=2/3x-5, we swap x and y and solve for y.

x=2/3y-5

x+5=2/3y

y=3/2(x+5)

Inverse equation: y=3/2x+15/2

5. To find the inverse equation for y=1/2x+10, we swap x and y and solve for y.

x=1/2y+10

x-10=1/2y

y=2(x-10)

Inverse equation: y=2x-20

6. To find the inverse equation for y=(x-3)², we swap x and y and solve for y.

x=(y-3)²

[tex]x^{(1/2)}=y-3[/tex]

[tex]y=x^{(1/2)}+3[/tex]

Inverse equation: [tex]y=x^{(1/2)}+3[/tex]

7. To verify that f(x)=5x+2 and g(x)=(x-2)/5 are inverse functions, we need to show that fog(x)=gof(x)=x for all x in the domain of f and g.

fog(x) = f(g(x)) = f((x-2)/5) = 5((x-2)/5) + 2 = x

gof(x) = g(f(x)) = g(5x+2) = ((5x+2)-2)/5 = x/5

Since fog(x) = gof(x) = x, f and g are inverse functions.

8. To verify that f(x)=1/2x-7 and g(x)=2x+14 are inverse functions, we need to show that fog(x)=gof(x)=x for all x in the domain of f and g.

fog(x) = f(g(x)) = f(2x+14) = 1/2(2x+14) - 7 = x

gof(x) = g(f(x)) = g(1/2x-7) = 2(1/2x-7) + 14 = x

Since fog(x) = gof(x) = x, f and g are inverse functions.

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The formula for the area of a circle is A = πr^2, where A is the area and r is the radius.

We are given that the radius is increasing at a rate of 5 mm per second. This means that the rate of change of the radius with respect to time is dr/dt = 5 mm/s.

To find the rate at which the area is changing, we need to find dA/dt, the derivative of the area with respect to time. We can use the chain rule to find this derivative:

dA/dt = dA/dr * dr/dt

We can find dA/dr by taking the derivative of the area formula with respect to r:

dA/dr = 2πr

Now we can substitute the values we know into the chain rule formula:

dA/dt = dA/dr * dr/dt = 2πr * 5

When the radius is 28 mm, the rate of change of the area is:

dA/dt = 2π(28) * 5 = 280π ≈ 879.64 mm^2/s

Therefore, the area is changing at a rate of approximately 879.64 mm^2/s when the radius is 28 mm.

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a. To find the probability that there are no cars in the system, we need to use the formula for the steady-state probability distribution of the M/M/1 queue:
P(0) = (1 - λ/μ)
where λ is the arrival rate (2 per hour) and μ is the service rate (3 per hour).
P(0) = (1 - 2/3) = 1/3 or 0.3333
Therefore, the probability that there are no cars in the system is 0.3333.

b. To find the average number of cars in the system, we can use Little's Law:
L = λW
where L is the average number of cars in the system, λ is the arrival rate (2 per hour), and W is the average time spent in the system.
We can solve for W by using the formula:
W = 1/(μ - λ)
W = 1/(3 - 2) = 1 hour
Therefore, the average number of cars in the system is:
L = λW = 2 x 1 = 2 cars

c. To find the average time spent in the system, we already calculated W in part b:
W = 1 hour

d. To find the probability that there are exactly two cars in the system, we need to use the formula for the steady-state probability distribution:
P(n) = P(0) * (λ/μ)^n / n!
where n is the number of cars in the system.
P(2) = P(0) * (λ/μ)^2 / 2!
P(2) = 0.3333 * (2/3)^2 / 2
P(2) = 0.1111 or 11.11%
Therefore, the probability that there are exactly two cars in the system is 11.11%.

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Answer:

B, A, C

Step-by-step explanation:

The rate is the another name for the slope.

A:

Change in y over the change in x.  You find the change by subtracting

[tex]\frac{7-3}{5-3}[/tex] = [tex]\frac{4}{2}[/tex] = 2

The rate is 2.

B:

Change in y over the change in x. You find the change by subtracting.

[tex]\frac{0-3}{-5-0}[/tex] = [tex]\frac{-3}{-5}[/tex] = [tex]\frac{3}{5}[/tex]

The rate is [tex]\frac{3}{5}[/tex].

C:

The rate is the number before the x in the equation.

The rate is 3.

Helping in the name of Jesus.

The class will use 20 yards of the 50-yard spool, leaving 30 yards of string leftover.

This leftover string could be used for future projects or saved for another occasion.

Lacey's class will use a total of 720 inches (30 inches per student x 24 students) of string for the candy necklaces.

To convert this to yards, we divide by 36 (since there are 36 inches in a yard). 720 inches ÷ 36 = 20 yards

It's important to note that when working with different units of measurement, it's necessary to convert them to the same unit before performing calculations.

In this case, we converted inches to yards in order to determine the amount of string used by the class. By doing so, we were able to determine how much string was leftover in yards, which is a more appropriate unit of measurement for a spool of string.

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Answer:

-----------------------

Given:

(i) We know 60 out of 110 can speak both languages, so as 60 out of 85. The number 60 is counted twice if we add them together.

Find the number of those speak either language:

(ii) Find the number of thise who can talk neither of these languages: