julia and her friends are making kites out of paper. For each kite, they need a piece of paper that is \dfrac{65}{100} \text{ meter} 100 65 ​ meterstart fraction, 65, divided by, 100, end fraction, start text, space, m, e, t, e, r, end text wide. How many centimeters of paper will they need to make 444 kites?

Answer:

D.

Step-by-step explanation:

that is the answer to the question above

To solve this problem, we can to simply plot using a graphing tool and the region under the area would be given. We would see there's no solution for this compound inequality

The given inequalities in this question are

When we plot this, we would see that no solution exists for this compound inequality problem.

Kindly check the attach image for more details.

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Area of three rectangles

Area of two triangles

Total

Check the picture below.

so hmm if we look at the cone straight from the front and check a cross-section of it, it'd look like the cross-section of the right-hand-side of the picture.

Now, with the cylinder having radius "r" and height "h", those two triangles we see in greenish color are similar, thus we can use proportions to correlate "h" and "r", so let's do that.

[tex]\cfrac{2.5-h}{r}~~ = ~~\cfrac{h}{5.5-r}\implies 13.75-5.5h-2.5r+rh=rh \\\\\\ 13.75-2.5r=5.5h\implies \boxed{\cfrac{13.75-2.5r}{5.5}=h}[/tex]

now, let's plug that in the volume of the cylinder's equation

[tex]V(r)=\pi r^2\cdot \cfrac{13.75-2.5r}{5.5}\implies V(r)=\cfrac{\pi }{5.5}(13.75r^2-2.5r^3) \\\\\\ \cfrac{dV}{dr}=\cfrac{\pi r(27.5-7.5r)}{5.5}\hspace{5em}0~~ < ~~r ~~ < ~~ 2.5[/tex]

now, our "r" variable can't be 0 or 2.5, as the cylinder tiptoes up and down, because if that ever happens, our cylinder's volume goes poof.

[tex]0=\cfrac{\pi r(27.5-7.5r)}{5.5}\implies 0=27.5-7.5r\implies 7.5r=27.5 \\\\\\ r=\cfrac{27.5}{7.5}\implies r=\cfrac{11}{3}[/tex]

the way I do region testing for the 1st derivative, is I usually grab the critical point and subtract hmm say 0.0000001 from it and put it in a variable in my calculator, then I add 0.0000001 to it and put it in another variable, then I use that variable in the 1st derivative calculation.  Anyhow, doing so and running a 1st derivative test, we'd see that the region to the left of 11/3 is positive whilst the region to the right is negative, as you can see in the picture at the bottom, yielding a maximum extremum, r = 0 is another critical point but as we noticed the constraints is out of bounds, so not in consideration.

so V(r) is at a maximum when r = 11/3

[tex]\blacksquare~~ r=\cfrac{11}{3} ~~\blacksquare \hspace{5em} \cfrac{13.75-2.5\left( \frac{11}{3} \right)}{5.5}=h~\hfill \implies ~\hfill \blacksquare~~ \cfrac{5}{6}=h ~~\blacksquare[/tex]

Answer:

C

Step-by-step explanation:

Black line

slope = Δy / Δx = -3 / 3 = -1

Y intercept = 3

LINE equation ( y = slope times x + y intercept): y = -x +3

Blue line

slope = Δy / Δx = 2 / 2 = 1

Y intercept = -2

LINE equation ( y = slope times x + y intercept): y = x -2

Answer:

389.1 units² (nearest tenth)

Step-by-step explanation:

Regular polygon: all side lengths are equal, all interior angles are equal.

Apothem: a line drawn from the center of any polygon to the midpoint of one of the sides

Radius: a line drawn from the center of the polygon to a vertex.

Therefore, we have been given the apothem of this regular dodecagon.

[tex]\textsf{Area of a regular polygon}=\dfrac{n\:l\:a}{2}[/tex]

where:

[tex]\textsf{Length of apothem (a)}=\dfrac{l}{2 \tan\left(\frac{180^{\circ}}{n}\right)}[/tex]

where:

First, calculate the length of one side of the regular dodecagon by substituting a = 11 and n = 12 into the apothem formula:

[tex]\implies 11=\dfrac{l}{2 \tan\left(\frac{180^{\circ}}{12}\right)}[/tex]

[tex]\implies l=11 \cdot 2 \tan\left(\frac{180^{\circ}}{12}\right)[/tex]

[tex]\implies l=44-22\sqrt{3}[/tex]

Now substitute n = 12, the found value of l, and a = 11 into the area formula:

[tex]\implies \textsf{Area}=\dfrac{12(44-22\sqrt{3})(11)}{2}[/tex]

[tex]\implies \textsf{Area}=389.0622274...[/tex]

[tex]\implies \textsf{Area}=389.1\: \sf units^2 \: (nearest\:tenth)[/tex]

Answer:

389.1 square units

Step-by-step explanation:

Area of the Dodecagon (12-sided polygon)

Area Formula

Finding the length (l)

Apothem Formula

Finding Area

[tex]\displaystyle \dfrac{\dfrac{4c^2-36}{8c^2-24c}}{\dfrac{12c+36}{2c^2 -6c}}\\\\\\=\left(\dfrac{4c^2 -36}{8c^2 -24c}\right) \cdot \left(\dfrac{2c^2 -6c}{12c+36}\right)\\\\\\=\left[\dfrac{4(c^2 -9)}{8(c^2-3)}\right]\cdot\left[\dfrac{2(c^2-3)}{12(c+3)}\right]\\\\\\=\dfrac{8(c^2-3^2)}{8 \cdot 12(c+3)}\\\\\\=\dfrac{(c+3)(c-3)}{12(c+3)}\\\\\\=\dfrac{c-3}{12}[/tex]

[tex]\text{Hence the answer is d.}[/tex]

Answer:

d

Step-by-step explanation:

separate the 2 divisions and simplify each , that is

[tex]\frac{4c^2-36}{8c^2-24c}[/tex] ← factor numerator/ denominator

= [tex]\frac{4(c^2-9)}{8c(c-3)}[/tex] ← factor difference of squares on numerator

= [tex]\frac{4(c-3)(c+3)}{8c(c-3)}[/tex] ← cancel (c - 3) and 4/8 on numerator/ denominator

= [tex]\frac{c+3}{2c}[/tex]

---------------------------------------------------

[tex]\frac{12c+36}{2c^2-6c}[/tex] ← factor numerator/ denominator

= [tex]\frac{12(c+3)}{2c(c-3)}[/tex] ← cancel 12 and 2 on numerator/ denominator

= [tex]\frac{6(c+3)}{c(c-3)}[/tex]

----------------------------------------------------------

to divide the top fraction by the lower fraction

leave top fraction, change division to multiplication, turn lower fraction upside down.

[tex]\frac{c+3}{2c}[/tex] × [tex]\frac{c(c-3)}{6(c+3)}[/tex] ← cancel (c + 3) and c on numerator/ denominator

= [tex]\frac{c-3}{2(6)}[/tex]

= [tex]\frac{c-3}{12}[/tex] → d

Answer:

? what do u want me todo

Step-by-step explanation:

Answer:

a. 2^(x-2) = g^(-1)(x)

b. A, B, D

Step-by-step explanation:

the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)

1. replace g(x) with y and solve for x

y = log₂(x) + 2

subtract 2 from both sides to isolate the x and its log

y - 2 = log₂(x)

this text is replaced by the second image -- it was marked as inappropriate

thus, 2^(y-2) = x

replace x with g^(-1)(x) and y with x

2^(x-2) = g^(-1)(x)

2. plug this in to points A, B, C, D, E, and F

A: (2,1)

plug 2 in for x

2^(2-2) = 2⁰ = 1 so this works

B: (4, 4)

2^(4-2) = 2²= 4 so this works

C: (9, 3)

2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work

(5, 8)

2^(5-2) = 2³ = 8 so this works

E: (3, 5)

2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work

F: (8, 5)

2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work

[tex]\text{Equation of parabola in vertex form,}\\\\~~~~~~~~~y = a(x-h)^2 +k\\\\\implies 26 = a(1+2)^2 -1~~~~~~~~;[(x,y) = (1,26)~ \text{and}~ (h,k) = (-2,-1)]\\\\\implies 26 = 9a -1\\\\\implies 9a = 26+1\\\\\implies 9a = 27\\\\\implies a = \dfrac{27} 9 \\\\\implies a = 3\\\\\text{Now,}\\\\~~~~~~~~y = 3(x+2)^2 -1~~~~~~~~~~;[\text{Vertex form.}]\\\\\implies y=3(x^2 +4x +4) -1\\\\\implies y = 3x^2 +12x +12 -1 \\\\\implies y=3x^2 +12x+11~~~~~~~~;[\text{Standard form.}][/tex]

Answer:

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

The horizontal line on a graph is the x axis and the "C" appears to be on the horizontal line therefore the answer would be x-axis

reasons its not the other answer choices

Y axis is the vertical line

Origin is where the two axis cross

Quadrant 1 may appear where C is however the C is pointing to the X axis

Answer:

close countess

Step-by-step explanation:

remember that the sign has to be postive so just change all the signs ,  then,   you'll have a leading coefficient of  +1,  in front of the [tex]x^{2}[/tex],  the 5 is in front of the 2nd term,  they were just trying to trick you with that.   the last answer is good     :)

Answer:

3r + 5

Step-by-step explanation:

by "combining like terms", this means that if we have, for example,

1 * x + 5 * x, we can factor this out to be x*(1+5) = 6 * x and the like terms (1x and 5x) are combined

thus, we have

-5r + 8r + 5

the "like terms" here are -5r and 8r because they both have an r attached to it. thus, we can set out to only factor the r in these two numbers, resulting in

-5 * r + 8 * r + 5 = r * (-5 + 8) + 5 = r * 3 + 5 = 3r + 5

(6^2)__>__(-6^2)

-5__=__ |-5|

0.372×1,000__<__37.2×100

The density of the gold substance is 3.53 g/cm^3

The density of a substance is the degree of compactness of a substance and it can be determined by the ratio of the mass of the substance to volume.

Mathematically, the density can be computed as:

[tex]\mathbf{Density = \dfrac{mass}{volume}}[/tex]

[tex]\mathbf{Density = \dfrac{14.12 \ g}{4 \ cm^3}}[/tex]

Density = 3.53 g/cm^3

Therefore, we can conclude from the above calculation that the density of the gold with a mass of 14.12 grams and a volume of  4 cubic centimeters is 3.53 g/cm^3.

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Answer:

A 3.53 g/cm^3 if it not a it still 3.53g/cm^3

Step-by-step explanation:

Answer:

1/428

Step-by-step explanation:

There are 428 pages,

Each page likely to be turned onto as equally as every other page,

and there is one possible correct page.

Answer:

Because 1/10 is less than 10

Step-by-step explanation:

10 is 100 times greater than 1/10

[tex]\frac{10}{1/10} =100[/tex]

Hope this helps

Answer:

Step-by-step explanation:

jfift

6540 g

Convert kilograms (kg) into grams (g) by multiplying the amount of kilograms (kg) by 1000 :

[tex]\boxed{\rm{6.45\:kg\:\:\:\:\:\:\:}}[/tex]  times 1,000 --> [tex]\boxed{\rm{6540\:g\:\:\:\:}}[/tex]

[tex]\Large\text{6540\:g}[/tex]

[tex]\small\text{hope\:helpful~}[/tex]

Answer:

[tex]\overline{BC}[/tex]

Step-by-step explanation:

[tex]\overline{BC}[/tex] does NOT intersect [tex]\overline{AG}[/tex]

Hope it helps you in your learning process.

Answer:

f(x) has slope (10-0)/(10-5) = 10/5 = 2

and intercept y - mx = 0 - 5(2) = -10 so f(x) = 2x - 10

g(x) has slope (10-0)/(2+3) = 2 and intercept y - mx = 10 - 2*2 =6

so g(x) = 2x + 6

So to transform f to g, you move the graph 16 units up.

Step-by-step explanation:

The measure of the side PR in PQR is 8.07 units and the measure of angle J in JKL is 35.30 degree.

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

Applying cos law in the triangle PQR:

[tex]\rm PR = \sqrt{5^2+9^2-2(5)(9)cos63}[/tex]

PR = 8.07 units

Applying sin law in the triangle, JKL:

[tex]\rm Angle \ J = sin^{-1}[sin 52 \ (\dfrac{11}{15})][/tex]

Angle J = 35.30 degree

Thus, the measure of the side PR in PQR is 8.07 units and the measure of angle J in JKL is 35.30 degree.

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Answer: POR NADA

Step-by-step explanation: ANSWER ON EDMENTUM/PLUTO

Answer:

17s

Step-by-step explanation:

Note: an expression is NOT an equation

"Product" means the answer to a multiplication of two numbers.

You are asked to write the answer to 17 and s being multiplied together.

The product is therefore

17 x s = 17s

Answer:

A, C, & D only

Step-by-step explanation:

All of the following are listed on your credit report except option B) your checking account balance.

Answer:

When the y variable tends to increase as the x variable increases we say there is a positive correlation between the variables

Answer:

The rule is +2

This is the 194th term

Step-by-step explanation:

This is an arithmetic sequence because 2 is added every time.

2x + 1 = 389

2x = 388

x = 194

194* 2 + 1 = 389

mark brainliest please!

Answer:

398 i think

Step-by-step explanation:

Answer:

50

Step-by-step explanation:

since the Pythagorean theorem is

[tex]c=[/tex] √[tex]a^2+b^2[/tex]

b is the bottom line (48)

a is the right line (14)

c is the top line (c)

plug that in

[tex]c =[/tex] √[tex]14^2 + 48^2[/tex]

then do the exponets

[tex]14^2[/tex] = 14 * 14 = 196

[tex]48^2[/tex] = 48 * 48 = 2304

then add them together

196 + 2304 = 2500

[tex]c =[/tex] √2500

the sqrt of 2500 is 50 (50 * 50 = 2500)

c = 50

your answer is 50

hope this helps:)

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's calculate the value of c using Pythagoras theorem ~

[tex]\qquad \sf  \dashrightarrow \: c {}^{2} = a {}^{2} + {b}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c {}^{2} = {14}^{2} + {48}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c = \sqrt{196 + 2304} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c = \sqrt{2500} [/tex]

[tex]\qquad \sf  \dashrightarrow \: c = 50 \: units[/tex]

Step-by-step explanation:

the volume of a box (or prism) is always

length × width × height

so, box A

13 × 12 × 16 = 2,496 in³

box B

18 × 25 × 16 = 7,200 in³

box C

12 × 14 × 22 = 3,696 in³

box D

20 × 22 × 17 = 7,480 in³

so, she can use B or D.