In triangle ABC, what is the m

Answer:

the interest for 100 in 5 years us 12.5

Answer:

Common difference:  30

General term formula:   [tex]a_n=30n-9[/tex]

52nd term:  1551

Step-by-step explanation:

Given sequence:

21, 51, 81, 111

Calculate the difference in terms:

[tex]21 \underset{+30}{\longrightarrow} 51 \underset{+30}{\longrightarrow} 81 \underset{+30}{\longrightarrow} 111[/tex]

The sequence is increasing by 30 each time, so as there is a common difference, this is an arithmetic sequence with a common difference of 30.

General form of an arithmetic sequence

[tex]a_n=a+(n-1)d[/tex]

where:

Given:

Substitute the given values into the formula to find the general term formula:

[tex]\implies a_n=21+(n-1)30[/tex]

[tex]\implies a_n=21+30n-30[/tex]

[tex]\implies a_n=30n-9[/tex]

To find the 52nd term, simply substitute n = 52 into the found general term formula:

[tex]\implies a_{52}=30(52)-9[/tex]

[tex]\implies a_{52}=1560-9[/tex]

[tex]\implies a_{52}=1551[/tex]

Answer:

8/15

Step-by-step explanation:

For right triangles tan p = opposite leg / adjacent leg

tan p = 24 /45   =   8/15

Answer:

ggggjgfdvhgffgutddfgj

It has a period of 2pi

the equation to find the period of a sin/cos function is

[tex]period = \frac{2\pi}{b} [/tex]

y = -2 sin(x) has a normal period of 2pi because the b value in this equation isn't stated, making it equal to 1

the basic equation for a sin function is

[tex]y = a \: \sin(b(x - c) ) + d[/tex]

Answer: The first graph

Step-by-step explanation: A graph’s inverse will have all of their roots inverted as well. If you put the graph f(x)= 3x+3 into a graphing calculator, you’ll be able to see all the roots. From there, just invert (switch) the roots. Since on the original graph the most prominent roots are {(0,3), (-1,0),(-2,-3)}, you just need to invert those roots and find them ALL on one of the graphs, then you have your answer. So, the inverted roots will be {(3,0),(0,-1),(-3,-2)}.

Still, I find the simplest thing is to put them into a graphing calc like GeoGebra.

Answer:

A.) 132.3 mm Hg

B.) 49 years old

Step-by-step explanation:

[tex]P= 0.006y^{2} -0.01y+119[/tex]

P = blood pressure

y = age in years

A.) Solution

To find: P

Given: y = 48

[tex]P= 0.006y^{2} -0.01y+119[/tex]

P = 0.006 x 48 x 48 - 0.01 x 48 + 119

P = 0.006 x 2,304 - 0.48 + 119

P = 13.824 - 0.48 + 119

P = 132.344 ⇒ 132.3

B.) Solution

To find: y

Given: P = 132.92

[tex]P= 0.006y^{2} -0.01y+119[/tex]

[tex]132.92= 0.006y^{2} -0.01y+119[/tex]

[tex]0.006y^{2} -0.01y-13.92[/tex]

.......................................................

Answer: 49 years old

The equation of the line will be y = 4x. Then the correct option is A.

The equation of line is given as

y = mx + c

Where m is the slope and c is the y-intercept.

Writing an Equation from a Table

A 2-column table with 6 rows. Column 1 is labeled x with entries 8, 12, 16, 20, 24, 28. Column 2 is labeled y with entries 2, 3, 4, 5, 6, 7.

Then at (2, 8) and (3, 12), we have

y – 8 = [(12 – 8) / (3 – 2)] (x – 2)

y – 8 = 4x – 8

     y = 4x

Then the correct option is A.

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Answer:

y = - 3x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 1, 2) and (x₂, y₂ ) = (0, - 1)

m = [tex]\frac{-1-2}{0-(-1)}[/tex] = [tex]\frac{-3}{0+1}[/tex] = [tex]\frac{-3}{1}[/tex] = - 3

the line crosses the y- axis at (0, - 1 ) ⇒ c = - 1

y = - 3x - 1 ← equation of line

Answer:

Dimensions = 8 CM and 12 CM

length = 12 CM

width = 8 cm

perimeter = 2 ( length + width)

= 2( 12 + 8)

= 2 ( 20)

= 40 CM

ratio = 12/40

= 6/20

= 3/10

The area of the water well is [tex]4\pi r^2[/tex]

The radius is given as:

Radius, R = 2r

The area of the water well is calculated using:

[tex]A = \pi R^2[/tex]

This gives

[tex]A = \pi (2r)^2\\\\\\[/tex]

Evaluate the expression

[tex]A = 4\pi r^2[/tex]

Hence, the area of the water well is [tex]4\pi r^2[/tex]

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Answer:

  (a)  x = 12

Step-by-step explanation:

The radicals in this equation can be eliminated simply by squaring both sides. Then the resulting linear equation is solved in two steps.

__

  [tex]\left(\sqrt{2x-8}\right)^2=\left(\sqrt{x+4}\right)^2\\\\2x-8=x+4\qquad\text{simplify}\\\\x-8=4\qquad\text{subtract $x$}\\\\\boxed{x=12}\qquad\text{add 8}[/tex]

_____

Additional comment

You know the contents of each radical must not be negative. That means 2x-8 ≥ 0, or x≥4. We know x=4 doesn't work in the equation (0≠√8), so we only need to check the answers x=12 and x=7. Of those, only x=12 satisfies the equation.

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} ( {x}^{ \frac{3}{2} } )= \dfrac{3}{2} \sqrt{x} [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} \bigg( \cfrac{1}{ {x}^{3} } \bigg)= \cfrac{- 3}{ {x}^{4} } [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} \bigg( \cfrac{1}{ \sqrt{x}^{} } \bigg)= \cfrac{ - 1}{ 2\sqrt{{x}^{ { 3}{} } }} [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

properties to be used here :

[tex]\qquad \tt \rightarrow \:\cfrac{d}{dx}( {x}^{ n } ) = n \sdot{x}^{n - 1} [/tex]

[tex]\large \textsf{Question : 1} [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} ( {x}^{ \frac{3}{2} } )[/tex]

[tex]\qquad \tt \rightarrow \:y = \dfrac{3}{2} x { }^{ \frac{3}{2} - 1 } [/tex]

[tex]\qquad \tt \rightarrow \:y = \dfrac{3}{2} x { }^{ \frac{3 - 2}{2} } [/tex]

[tex]\qquad \tt \rightarrow \:y = \dfrac{3}{2} x { }^{ \frac{1}{2} } [/tex]

[tex]\qquad \tt \rightarrow \:y = \dfrac{3}{2} \sqrt{x} [/tex]

[tex]\large \textsf{Question : 2} [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} \bigg( \cfrac{1}{ {x}^{3} } \bigg)[/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} ({ {x}^{ - 3} } )[/tex]

[tex]\qquad \tt \rightarrow \:y = - 3 { {x}^{ - 3 - 1} } [/tex]

[tex]\qquad \tt \rightarrow \:y = - 3 { {x}^{ - 4} } [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{- 3}{ {x}^{4} } [/tex]

[tex]\large \textsf{Question : 3} [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} \bigg( \cfrac{1}{ \sqrt{x}^{} } \bigg)[/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} \bigg( \cfrac{1}{{x}^{ \frac{1}{2} } } \bigg)[/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{d}{dx} ({ {x}^{ - \frac{1}{2} } } )[/tex]

[tex]\qquad \tt \rightarrow \:y = -\cfrac{1}{2} { {x}^{ - \frac{1}{2} - 1} } [/tex]

[tex]\qquad \tt \rightarrow \:y = -\cfrac{1}{2} { {x}^{ \frac{ - 1 - 2}{2} } } [/tex]

[tex]\qquad \tt \rightarrow \:y = -\cfrac{1}{2} { {x}^{ \frac{ - 3}{2} } } [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{ - 1}{ 2{x}^{ \frac{ 3}{2} } } [/tex]

[tex]\qquad \tt \rightarrow \:y = \cfrac{ - 1}{ 2\sqrt{{x}^{ { 3}{} } }} [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer: 48

Step-by-step explanation:

We need to find the least common multiple of 12 and 16.

Finding the prime factorizations of 12 and 16,

[tex]12=2^{2} \times 3\\\\16=2^{4}[/tex]

Thus, the least common multiple is [tex]2^{4} \times 3=\boxed{48}[/tex]

The number of cows and ducks in the garden are 3 and 4 respectively.

Let the numbers of cows be x and the number of ducks is y.

Total number of legs=20

Total number of eyes=14

Linear equation for the total number of legs in the garden,

4x+2y=20 -(1)

Linear equation for the total number of eyes in the garden,

2x+2y=14 -(2)

Solve the system of the two linear equations to find the values of x and y.

Subtract equation (1) from equation (2), and we get,

2x=6

[tex]x=\frac{6}{2}\\[/tex]

x=3

Substitute the value of x in equation (1), and we get,

4(3)+2y=20

12+2y=20

2y=20-12

2y=8

[tex]y=\frac{8}{2}\\[/tex]

y=4

Number of cows=3

Number of ducks=4

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Answer:

8

Step-by-step explanation:

let the ratio constant be 'x'

=> 2x:3x

sum = 2x + 3x = 5x

Total number of boys

=>(2x/5x)20 = 8

The ratio of boys and girls in a classroom is 2 : 3 respectively. If the total number of children is 20. How many boys are there in the class ?

In this question we are provided with the ratio of boys isto girls that is 2 : 3 it is also given that total number of children are 20. We are asked to calculate number of boys.

[tex] \green{ \small \pmb{\tt{ First \: we \: will \: form \: an \: equation }}}[/tex]

Let us assume the number of girls as 3x and number of boys as 2x.

Total number of children = 20

3x + 2x = 20

[tex] \orange{\small \pmb{\tt{ Now \: we \: will \: solve \: this \: equation }}}[/tex]

[tex] \small\frak{ 3x + 2x = 20}[/tex]

[tex] \small\frak{ 5x = 20}[/tex]

[tex] \small\frak{ x = \dfrac{20}{5} = 4}[/tex]

[tex] \small \underline{ \boxed{\pmb{x = 4} }} \large \: \star[/tex]

Boys = 2 × 4 = 8

Girls = 3 × 4 = 12

[tex] \tiny \tt{spbankingandsscseries}[/tex]

Answer:

1,3 is the answer... if you look down here↓:

Step-by-step explanation:

it is a bracket used in maths

Answer:

They are kind of like outer brackets, so if you have some expression like this:

5 + (4 × 6 + (7 - 8)),

it's better to write it like this:

5 + [4 × 6 + (7 - 8)],

so you can read it more easily.

Answer:

x = 2, y = 1 or (2, 1)

Step-by-step explanation:

Solving by elimination method :

The solution is : x = 2, y = 1 or (2, 1)

The zeros of the quadratic function f(x) = 2x² + 16x - 9 are given as follows:

[tex]x = -4 + \sqrt{\frac{41}{2}}, x = -4 - \sqrt{\frac{41}{2}}[/tex]

A quadratic function is given according to the following rule:

[tex]y = ax^2 + bx + c[/tex]

The solutions are:

[tex]x_1 = \frac{-b + \sqrt{\Delta}}{2a}[/tex]

[tex]x_2 = \frac{-b - \sqrt{\Delta}}{2a}[/tex]

In which:

[tex]\Delta = b^2 - 4ac[/tex]

In this problem, the equation is given by:

f(x) = 2x² + 16x - 9.

The coefficients are a = 2, b = 16, c = -9, hence:

[tex]\Delta = 16^2 - 4(2)(-9) = 328[/tex]

Then:

[tex]x_1 = \frac{-16 + \sqrt{328}}{2(2)} = -4 + \sqrt{\frac{41}{2}}[/tex]

[tex]x_2 = \frac{-16 - \sqrt{328}}{2(2)} = -4 - \sqrt{\frac{41}{2}}[/tex]

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5[tex]\sqrt{3}[/tex]

Special right triangles, such as the one shown, have unique equations that can be used to find missing sides.

30-60-90 Triangles

The angle measurements show us that this is a 30-60-90 triangle. This name refers to the 3 angle measurement. There are 2 types of special right triangles, 45-45-90 and 30-60-90. For most triangles, it would take the law of sine or cosine to find a missing side with only 1 side given. But, with special right triangles, we can use shortcuts to find a.

Formulas

For all 30-60-90 triangles, there are 3 sides: the hypotenuse (c), the long leg (a), and the short leg (b). The shortcuts for 30-60-90 triangles are based on the length of the short leg.

The formulas are as follows (the variables match the variable given in the figure):

Solving for a

So, to find a, we must first find b. Since b is equal to half of c, we can divide the value of c by 2.

Thus, b = 5

Next, plug this value into the formula for b

Answer:

Last option

Step-by-step explanation:

cos30° = a/10  

a = 10cos30°

     [tex]cos30=0.8660=\frac{\sqrt{3} }{2}[/tex]

[tex]a=10(\frac{\sqrt{3} }{2} )=5\sqrt{3}[/tex]

Hope this helps

Answer:

hes a titan

Step-by-step explanation:

A comparison of the actual number of people who violate the speed limit to the total number of drivers is an example of a rate

A rate is known as the quantity measured with respect to another measured quantity. It refers to the comparison of a part to a whole.

It is also the measure of a part with respect to a whole or a proportion.

Therefore, a comparison of the actual number of people who violate the speed limit to the total number of drivers is an example of a rate

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Answer:

The answer is (-2,6)

Step-by-step explanation:

Answer: (-2, 6)

Step-by-step explanation:

An easy way to solve this is to plug in each answer into the system of inequalities to figure out with ordered pair adheres to the rules of both equation.

Let's use the first ordered pair as an example: (-3,4)

Is this true?:

4 > (-3)² +1

4 < (-3)² - (-3) + 1

No, it is not:

4 < 10

4 < 13

Let's try the second answer:

Is this true?:

6 > (-2)² + 1

6 < (-2)² -(-2) + 1

YES, it is!

6 > 5

6 < 7

(-2, 6) is your answer. To check, verify that the last two answer choices are wrong.

The time spent by the repairman there will be 3 hours so the correct answer is option D.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Given that:-

A roof repairman charges a $60 consult fee, and then $45 per hour to complete repairs. if the homeowner pays a total of $195.

The time will be calculated as:-

Total amount =  $195

Now the fixed consulting cost will be $60 and will be deducted from the

total amount.

Variable cost = 195 - 60 = 135

The $45 per hour charge so for $145 the time will be:-

Time = 135 / 45

Time =  3 Hours

Therefore the time spent by the repairman there will be 3 hours so the correct answer is option D.

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