In this periodic table, which color or colors represent the elements that are
metals?
A. Blue and green
B. Orange and green
C. Orange only
D. Blue only

Answer:

They are in the same group on the periodic table indicating that they have the same number of valence electrons.

Explanation:

Answer:

d. It contains one valence electron.

Since, potassium has one valence electron so it can easily donate one electron during chemical reaction.

Answer:

Explanation:

Option 1 15. Proton 16 neutron 15 electron

Isotopes have same atomic no but different atomic mass

Answer:

Dehydrogenation of alkanes is endothermic

Explanation:

The dehydrogenation of alkanes is an endothermic reaction. The enthalpy change for the reaction is highly positive.

Recall that for an endothermic reaction, increase in temperature increases the rate of forward reaction.

As a result of that, the dehydrogenation of alkanes proceeds in the foward direction at elevated temperatures.

The number of moles of H₂ formed when 2.97 g sample of Mg reacts with excess HCl is 0.122 moles

To determine the number of moles of H₂ that can be formed if 2.97 g sample of Mg reacts with excess HCl,

First, we will write a balanced chemical equation for the reaction

Mg + 2HCl → MgCl₂ + H₂

From the reaction above,

It means that 1 mole of Mg will react with 2 moles of HCl to produce 1 mole of MgCl₂ and 1 mole of H₂

Now, we will determine the number of moles of Mg present in the given sample.

From the question,

Mass of Mg = 2.97 g

Using the formula

[tex]Number \ of \ moles = \frac{Mass}{Molar \ mass}[/tex]

Molar mass of Mg = 24.305 g/mol

∴ [tex]Number \ moles \ of \ Mg = \frac{2.97}{24.305}[/tex]

Number of moles of Mg in the sample = 0.122 moles

Since, 1 mole of Mg will react with 2 moles of HCl to produce 1 mole of MgCl₂ and 1 mole of H₂

∴ 0.122 moles of Mg will react with excess HCl to produce 0.122 moles of  H₂

Hence, the number of moles of H₂ formed when 2.97 g sample of Mg reacts with excess HCl is 0.122 moles

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Answer:

I would say all of the above

Explanation:

I say this because we use material and energy, we grow and develop, we are made up of cells, and we respond to the environment.

Answer:

Equilibrium

Explanation:

Correct on edge 2020

Answer:

A - Equilibrium

Explanation:

For edge:)

Answer:

177 grams

Explanation:

moles of CaF₂ = [tex]\frac{mass}{molar mass}[/tex] = [tex]\frac{365}{78}[/tex] = 4.67949

moles of F-atom = 2×moles of CaF₂ = 2×4.67949 = 9.35898

(mol)×(molar mass)= 9.35898×19 = 177.82062

Therefore, 177 grams of F are in the mixture.

Answer:

Jupiter

Explanation:

Answer:Approximate density of the high-leaded brass(alloy) =8.306g/cm³

Explanation:

The density of an  alloy is its mass (100g) divided by its volume

Therefore we have that the alloy (high-leaded brass) has a composition of

60.5 wt% Cu with density  8.94g/cm3

34.5 wt% Zn, wth densty  7.13g/cm3

5.0 wt% Pb with densty g/cm3

The total volume of the alloy will be the mass / density of ts composition given as :

60.5gCu/DCu + 34.5gZn/DZn + 5.0gPb/Dpb

= 60.5/8.94 + 34.5/7.13+ 5.0/11.35

= 6.76 cm³ + 4.838 cm³+0.4405 cm³ = 12.0385cm³

Approximate density of the high-leaded brass(alloy) = 100g/  12.0385cm³ =8.306g/cm³

Answer:

2,000,000

Explanation:

Answer:

yeah 2,000,000

Explanation:

Answer:

layers of epithelial tissue

Answer:

It's B

Explanation:

Answer: Entropy is increasing

Explanation:

Answer:

false

Explanation:

Answer:

Molecules from food and molecules of oxygen move from the mouth and the nose to cells of the body through a series of blood vessels, including veins, arteries, and microscopically small blood vessels (capillaries), that extend throughout the body.Explanation:

Answer:

Molecules from food and air enter your body through your nose and mouth. These particles go down your throat and your lungs, and to your stomach. The blood also distributes these molecules.

Hope this helps!

Answer:

The charges are typically used to determine the mole ratio and composition of the individual atoms of elements in the compound

Explanation:

Take for instance the following compounds:

[tex]NaOH[/tex] and [tex]H_{2} O[/tex]

I hope this helps.

The question is incomplete; the complete question is;

For the following reaction:

H2CO3 + S2- ---------> HCO3- + HS-

The equilibrium constant is greater than one. The strongest acid in this system is ___________ and the weakest base is ____________.

A) H2CO3 and HS-                  

B) S2- and HS-                        

C) HCO3- and S2-                    

D) HS- and S2-

E) H2CO3 and HCO3-

Answer:

H2CO3 and HS-  

Explanation:

According to the Brownstead- Lowry theory of acids and bases, an acid is a proton donor while a base is specie that accepts protons.

A strong acid has a greater tendency to donate protons. If we look at the reaction, H2CO3 has the greatest ability to donate protons hence it is the strongest acid.

On the other hand, HS- has the least ability to accept protons so it is the weakest base.

Answer:

m1v1=m2v2 change 35 ml to l = 0.035L

12*0.035 = M2*1.20

Solve for M2 = 0.35M

Explanation:

Answer:

0.0003125 g

Explanation:

Given data:

Half life of iodine-125 = 60 days

Mass of iodine pellet  = 0.020 g

Mass of iodine remain after one year = ?

Solution:

one year = 365 days

Number of half lives = Time elapsed/ half life

Number of half lives = 365 days/ 60 days

Number of half lives = 6

At time zero = 0.020 g

At 1st half life = 0.020 g/2 = 0.01 g

At 2nd half life = 0.01 g / 2 = 0.005 g

At 3rd half life = 0.005 g/2 = 0.0025 g

At 4th half life = 0.0025 g / 2 = 0.00125 g

At 5tht half life = 0.00125 g / 2 =  0.000625 g

At 6th half life = 0.000625 g/ 2 = 0.0003125 g

Answer:

CrCl₃.

Explanation:

From the question given above, the following data were obtained:

Mass of chromium (Cr) = 22.60 g.

Mass of metal chloride = 68.83 g.

Empirical formula =.?

Next, we shall determine the mass of chlorine (Cl) in the metal chloride. This can be obtained as follow:

Mass of chromium (Cr) = 22.60 g.

Mass of metal chloride = 68.83 g.

Mass of chlorine (Cl) =.?

Mass of chlorine (Cl) = (Mass of metal chloride) – (Mass of chromium)

Mass of chlorine (Cl) = 68.83 – 22.60

Mass of chlorine (Cl) = 46.23 g

Finally, we shall determine the empirical formula for the metal chloride as follow:

Cr = 22.60 g.

Cl = 46.23 g

Divide by their molar mass

Cr = 22.60 / 52 = 0.435

Cl = 46.23 / 35.5 = 1.302

Divide by the smallest

Cr = 0.435 /0.435 = 1

Cl = 1.302 /0.435 = 3

The empirical formula for the metal chloride is CrCl₃

Answer:

3.22 L

Explanation:

0.00 C = 273 K

k = C +273

606 K + 273 K = 879 K

879/273 = 3.219

V2 = 3.22 L

Answer:

22.4 g

Explanation:

Calculate the mass of sodium acetate that must be added to 500.0 mL of 0.300 M acetic acid to form a pH  = 5.00 buffered solution.

Step 1: Given data

Volume of solution: 500.0 mL

[acetic acid]: 0.300 M

pH = 5.00

pKa of acetic acid: 4.74

Step 2: Calculate the concentration of sodium acetate

We will use the Henderson-Hasselbach equation.

pH = pKa + log [sodium acetate]/[acetic acid]

5.00 = 4.74 + log [sodium acetate]/0.300 M

[sodium acetate] = 0.546 M

Step 3: Calculate the moles of sodium acetate

We have 500.0 mL of a 0.546 M sodium acetate solution

0.5000 L × 0.546 mol/L = 0.273 mol

Step 4: Calculate the mass of sodium acetate

The molar mass of sodium acetate is 82.03 g/mol.

0.273 mol × 82.03 g/mol = 22.4 g

Answer:

Explanation:

The volume of the gas can be found by using the formula for Boyle's law

[tex]P_1V_1 = P_2V_2[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

We have

[tex]V_2 = \frac{10 \times 1}{5} = \frac{10}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

40.92%

Explanation:

CaCo₃(s)-->CaO(s)+CO₂(g)

mass of Co2(g)= 1.33grams

mass of CaO(s)=(3.25-1.33)=1.92grams

mass % of CaCO₃ = [tex](\frac{1.33}{3.25} )[/tex]×100%

40.92%

Answer:

Reaction product A is more likely to form in the epoxide ring-opening reaction

Explanation:

The diagram for the reaction can be seen in the image attached below.

An epoxide is any class of organic compound, cyclic ethers, having a three-membered ring; they are usually prepared by selective oxidation of alkenes or by ring-closure of halohydrins(any class of organic compound having a hydroxyl functional group and a halogen on neighboring carbon atom ) which are used in making plastic.

Answer:

Explanation:

C₆H₁₂     + H₂O      =     C₆H₁₃OH

hexene                      hexanol

1 mole                             1 mole  

Mol weight of hexene = 84

Mol weight of hexanol   = 102

5.33g of hexene = .06345 moles

4.6 g of hexenol = .0451 moles

percentage yield of hexanol

= .0451 x 100 / .06345

= 71.07 %

Moles of hexene used = .0451 moles