In each term equation below a blank line shows one term missing the terms may be an elemental symbol a coefficient or a subscript decide which term would balance the equation write the missing term in the second column the. Determine the reactants third column and products forth column of the reaction some reactions may have only one reactant or product and other reactions may have only one reactant or product and other reactions may have multiple reactants or products write your answers in the spaces in the table the first reaction involves sodium chloride not sodium carbon and iodine

In Each Term Equation Below A Blank Line Shows One Term Missing The Terms May Be An Elemental Symbol

Answers

Answer 1

Answer:

1) Cl2   2 is missing

2) H     H is missing

Explanation:


Related Questions

which is an example of a sale laboratory procedure​

Answers

Tying back long hair and securing loose clothing.

How many milliliters of 0.2560 M KCl solution will contain 20.00 g of KCl?
Answer is 1048 mL solution but how do I get to the answer?

Answers

Answer:

1048 mL

Explanation:

Step 1: Given data

Concentration of the solution: 0.2560 MMass of KCl (solute): 20.00 g

Step 2: Calculate the moles corresponding to 20.00 g of KCl

The molar mass of KCl is 74.55 g/mol.

20.00 g × 1 mol/74.55 g = 0.2683 mol

Step 3: Calculate the volume of the solution

Molarity is equal to moles of solute divided by liters of solution.

M = moles of solute / volume of solution

volume of solution = moles of solute / M

volume of solution = 0.2683 mol / (0.2560 mol/L)

volume of solution = 1.048 L = 1048 mL

Human blood contains a buffer of carbonic acid (H_2 CO_3) and bicarbonate anion (HC〖O_3〗^-) in order to maintain blood pH between 7.35 and 7.45, as a value higher than 7.8 or lower than 6.8 can lead to death. In this buffer, hydronium and bicarbonate anion are in equilibrium with carbonic acid. Furthermore, the carbonic acid in the first equilibrium can decompose into CO_2 gas and water, resulting in a second equilibrium system between carbonic acid and water. Because CO_2 is an important component of the blood buffer, its regulation in the body, as well as that of O_2 , is extremely important. The effect of this can be important when the human body is subjected to strenuous condition.
Carbonic acid buffer:
H_2 CO_3 (aq)+ H_2 O(l) ↔H_3 O^+ (aq)+HC〖O_3〗^- (aq)
1. Write the equilibrium constant expression K_c for the carbonic acid buffer in the blood.

Answers

Kc = [H3O+][HCO3-] / [H2CO3]

Remember that Kc is products over reactants. Also, you do not include liquid water in a Kc expression, since liquid water has no concentration.

The symbol for free energy is
a. DG.
b. DS.
c. DT.
d. DH.

Answers

I think the answer is A but I’m not 100% sure

How are a tundra and a desert different?

A desert has a low level of precipitation and a tundra has a high level of precipitation.
A desert is wet year-round and a tundra is dry.
A tundra has a lower levels of humidity.
A tundra has lower average temperatures year-round.
i am giving brainlyest!!!!!!!

Answers

Answer:

A tundra has a lower average temperatures year-round.

tundra has lower temperatures year round

What are types of Kinetic energy?

Answers

Answer:

Machical  Engery

Electrical Engery

Rhermal Engery  

Sound Energy  

Explanation:

Explanation:

There are five types of kinetic energy:

RadiantThermalSoundElectrical and Mechanical.

Thus, There are five types of kinetic energy

-TheUnknownScientist

How many grams of Mg(NO3), are necessary to
make 1500 mL of a 0.50 M solution?

Answers

Answer:

1.1 × 10² g

Explanation:

Step 1: Given data

Concentration of the solution (C): 0.50 M (0.50 mol/L)Volume of solution (V): 1500 mL (1.500 L)

Step 2: Calculate the moles of Mg(NO₃)₂ (solute)

Molarity is equal to the moles of solute (n) divided by the liters of solution.

C = n/V

n = C × V

n = 0.50 mol/L × 1.500 L = 0.75 mol

Step 3: Calculate the mass corresponding to 0.75 moles of Mg(NO₃)₂

The molar mass of Mg(NO₃)₂ is 148.3 g/mol.

0.75 mol × 148.3 g/mol = 1.1 × 10² g

If an ultraviolet photon has a wavelength of 77.8 nm calculate the energy of one mole ultraviolet photon.

Answers

Answer:

Explanation:

E = (hc)/(λ)

E = (6.624x10^(-27))Js x ((3×10^8)ms^(-1)) /

(77.8x10^(-9)m)

E = 2.55 x 10^(-11) J

2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent yield if 5.40 g of "hydrogen gas" are collected?

Answers

Answer:

1040%

Explanation:

To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:

Percent yield = Actual yield (5.40g) / Theoretical yield * 100

Moles Fe -Molar mass: 55.845g/mol-:

10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.

For a complete reaction of these moles there are necessaries:

0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.

As there are 14.8 moles of the acid, Fe is limiting reasctant.

The moles of H2 produced are:

0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2

The mass is:

0.277 moles H2 * (2.016g/mol) = 0.558g H2

Percent yield is:

5.40g / 0.558g * 100 = 1040%

It is possible the experiment wasn't performed correctly

pls help i will mark as brainliest​

Answers

Answer:

ano po ito?? isa po ba itong story

C. 2.86 g
D. 1.22 g
13. At what Kelvin temperature will 25.2 mol of Xe occupy a volume of 645 L at a pressure of 732 torr?
A. 361 K
B. 291 K
C. 402 K
D. 300 K

Answers

Hdhdhdhdhdhdbdhfhdhhdhfhdfhhdhdhdhdhdhdhdhdhdhdhdhhdhdhdhdhdhd

Observe the map what do the grey scar like represent?

Answers

Answer:

mid ocean ridge

Explanation:

gloves worn when working with liquid oxygen must be able to resist.​

Answers

Answer:

What is your question?

Explanation:

Can you give more context to ur question?

Consider the following exothermic process at equilibrium:

CO(g)+H2O(g)⇌CO2(g)+H2(g)

Which of the following changes would increase the amount of H2(g) present in the equilibrium mixture?

Consider the following exothermic process at equilibrium:


Which of the following changes would increase the amount of present in the equilibrium mixture?

decrease the temperature
increase [CO2]
increase [CO]
increase the volume of the container in which the reaction occurs.
more than one of the above
(Answer is not increase [CO])

Answers

For the given exothermic process at equilibrium, an increase in the concentration of CO would increase the amount of H₂.

How is equilibrium affected by changes?

When a perturbation is done on a system at equilibrium, it shifts its equilibrium position to counteract the perturbation.

Let's consider the following exothermic process at equilibrium.

CO(g) + H₂O(g) ⇌ CO₂(g) + H₂(g)

Which of the following changes would increase the amount of H₂(g) present in the equilibrium mixture?

decrease the temperature. NO. For an exothermic reaction, a decrease in the temperature will shift the equilibrium towards the reactants.increase [CO₂]. NO. This would shift the equilibrium towards the reactants.increase [CO]. YES. This would shift the equilibrium towards the products.increase the volume of the container in which the reaction occurs. NO. This wouldn't affect the equilibrium since the number of gaseous moles is the same on both sides.more than one of the above. NO.

For the given exothermic process at equilibrium, an increase in the concentration of CO would increase the amount of H₂.

Learn more about equilibrium here: https://brainly.com/question/2943338

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please help does anyone know this// science!

Answers

Answer:

its A

Explanation:

The only one that makes sense

The concentration of H3AsO3 in a solution is determined by titrating it with a 0.1741 M Ce4+ solution. The balanced net ionic equation for the reaction is: 2Ce4+(aq) + H3AsO3(aq) + 5H2O(l) 2Ce3+(aq) + H3AsO4(aq) + 2H3O+(aq) In one experiment, 18.68 mL of the 0.1741-M Ce4+ solution is required to react completely with 30.00 mL of the H3AsO3 solution.
Calculate the concentration of the H3AsO3 solution.

Answers

Answer:

0.0542 M

Explanation:

Let;

CA = concentration of Ce4+ solution = 0.1741 M

VA = volume of Ce4+ solution = 18.68 mL

CB = concentration of H3AsO3 = ?

VB  = volume of H3AsO3 = 30.00 mL

NA = Number of moles of Ce4+ solution = 2

NB = Number of moles of H3AsO3  = 1

From;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB = CAVANB/VBNA

CB = 0.1741 * 18.68 * 1/30.00 * 2

CB = 0.0542 M

How tightly particles are packed determines what state it takes.
True or False​

Answers

Answer:

True

Explanation:

tighter the molecules the slower it moves and the harder it gets

solid has very tight particles packed together

gas has its particles spread out

When magma goes down into the lower part of the mantie where it is recycled and may come right back up the ocean ridge is called..

Answers

subduction zone is the answer

The pH of an acidic solution is 5.59. What is [H+]?

Answers

Answer:

[H⁺] = 2.57x10⁻⁶ M

Explanation:

This problem can be solved using the definition of pH:

pH = -log[H⁺]

Now we isolate [H⁺] in the equation:

-pH = log[H⁺]

[tex]10^{-pH}[/tex]=[H⁺]

As we are given the pH by the problem, we can now proceed to calculate the [H⁺]:

[H⁺] = [tex]10^{-5.59}[/tex]

[H⁺] = 2.57x10⁻⁶ M

Thus, when the pH of a solution is 5,59; the molar concentration of H⁺ species is 2.57x10⁻⁶.

Plz I need helpppppp

Answers

The correct answer is b

The air bags in automobiles were once inflated by nitrogen gas generated by the rapid decomposition of
sodium azide, NaN3.

2 NaNz (s) 2 Na (s) + 3 N2 (g)

If an air bag has a volume of 53.4 L and is to be filled with nitrogen gas at a pressure of 1.07 atm and a
temperature of 23.7°C, how many moles of NaNz must decompose? You may assume the Ny behaves as
an ideal gas.

Answers

Answer:

1.57 mol NaN₃

Explanation:

2 NaN₃ (s) → 2 Na (s) + 3 N₂ (g)

First we use PV=nRT to calculate the number of N₂ moles that need to be produced:

P = 1.07 atmV = 53.4 Ln = ?R = 0.082 atm·L·mol⁻¹·K⁻¹T = 23.7 °C ⇒ 23.7 + 273.16 = 296.86 K

Inputing the data:

1.07 atm * 53.4 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.86

And solving for n:

n = 2.35 mol N₂

Finally we convert N₂ moles into NaN₃ moles, using the stoichiometric coefficients of the balanced reaction:

2.35 mol N₂ * [tex]\frac{2molNaN_3}{3molN_2}[/tex] = 1.57 mol NaN₃

1
Select the correct answer.
How long is the term of a federal judge in a constitutional court?
OA.
two years
OB

four years
Ос.
six years
OD.
lifetime

Answers

Answer:

Judges and justices serve no fixed term — they serve until their death, retirement, or conviction by the Senate. By design, this insulates them from the temporary passions of the public, and allows them to apply the law with only justice in mind, and not electoral or political concerns.

The gas phase decomposition of nitrogen dioxide at 383 °C

NO2(g)NO(g) + ½ O2(g)

is second order in NO2 with a rate constant of 0.540 M-1 s-1.
If the initial concentration of NO2 is 0.477 M, the concentration of NO2 will be
M after 12.4 seconds have passed.

Answers

Answer:

[tex][NO_2]=0.112M[/tex]

Explanation:

Hello there!

In this case, since the second-order integrated law is given by the following equation:

[tex]\frac{1}{[NO_2]} =\frac{1}{[NO_2]_0}+kt[/tex]

Thus, given the initial concentration of the nitrogen dioxide gas, the rate constant and the elapsed time, we obtain:

[tex]\frac{1}{[NO_2]}= \frac{1}{0.477M} +0.54M^{-1}s^{-1}\\\\\frac{1}{[NO_2]}=8.933M^{-1}[/tex]

[tex][NO_2]=\frac{1}{8.933M^{-1}} =0.112M[/tex]

Best regards!

provide the electronic structure diagram of propene showing all molecular orbitals​

Answers

Answer:

Explanation:The pi-molecular orbitals in propene (CH3-CH=CH2) are essentially the ... This central carbon thus provides two p-orbitals – one for each pi bond – and these two different p-orbitals have to be perpendicular, leading to a twisted structure as shown: ... It all comes down to where the location of the electron-deficient carbon  

1. Which of these is not a macromolecule? a) Alab) protein c) polysaccharide d) nucleic
acid

Answers

Answer:

a) alab

Explanation:

Two of the main macromolecules are proteins and nucleic acid, and a polysaccharide is multiple monomers (monosaccharide) that join to create another macromolecule called carbohydrates.

How many moles of C2H2 are required to produce 0.60 mol of H2O?
Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

0.60 moles

Explanation:

From the reaction:

[tex]2C_2H_2 + 5O_2 \to 4CO_2+2H_2O[/tex]

From above, Only 2 moles of CH2CH2 are required to produce 2 moles of water (H_2O).

As such, 0.6 moles of H2O will require:

x (CH2CH2) × 2 moles of (H_2O)  = 0.6 moles (CH2CH2) × 2 mole of (H_2O)

x mole of  (CH2CH2) = 0.60 moles

0.6 moles of H2O will require 0.60 moles of CH2CH2

Arrange in terms of increasing atomic radius. From smallest to largest.
S, F, Sr, Na, Ga

Answers

Answer:

F<S<Na<Ga<Sr

Explanation:

Atomic radius increased from the right of the periodic table to left, and from the top to the down

what are the advantages and disadvantages of rusting

Answers

Answer: The rusting of iron is more of a disadvantage than an advantage. Rusting forms an iron oxide which is more brittle than the iron. It less resistance to environmental degradation and permeability by water and air, therefore cannot be used for coating.

Explanation: plzz mark as brainliest

A sample of hydrogen has an initial temperature of 122.0 °F. When the temperature is lowered to -23.0 °F, the volume of hydrogen becomes 212 cm3. What was the initial volume of the hydrogen?

Answers

Answer: The initial volume of gas was [tex]282cm^3[/tex]

Explanation:

Charles's Law: This law states that volume is directly proportional to temperature of the gas at constant pressure and number of moles.

[tex]V\propto T[/tex]     (At constant pressure and number of moles)

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]  

where,

[tex]V_1[/tex] = initial volume of gas   =?

[tex]V_2[/tex] = final volume of gas = [tex]212cm^3[/tex]  

[tex]T_1[/tex] = initial temperature of gas  = [tex]122.0^0F=323.15K[/tex]    

[tex](32^0C=273.15K)[/tex]

[tex]T_2[/tex] = final temperature of gas  = [tex]-23.0^0F=242.59K[/tex]

[tex]\frac{V_1}{323.15}=\frac{212}{242.59}[/tex]  

[tex]V_2=282cm^3[/tex]

Therefore, the initial volume of gas was [tex]282cm^3[/tex]

How many moles of solute are present in 2 L of a 25M potassium nitrate (KNO3) solution?
0.5 moles
50 moles
25 moles
2 moles

Answers

mole= Molarity. Volume(L) = (25)(2)= 50 moles

50 moles

The formula used in this question is-

Mole= Molarity*Volume(in Litre)

So after putting the value

= (25)*(2)

=50 moles

What is molarity?

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution.

Learn more about Molarity here

https://brainly.com/question/14469428

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