In a vacancy for a position of animal breeder in an organization, then criteria of selection were work experience, entrance exam, and interview results. The relative importance of these criteria was regarded to be different. The weights of these criteria and scores obtained by 3 candidates (out of 100 in each criterion) are given in the following table. In addition, the selection of a candidate is based on the average result on these criteria, (full question attached)​

Answer:

a

Step-by-step explanation:

Answer: 2

Step-by-step explanation:

[tex]g(-2)=-2\\\\g(1)=4\\\\\frac{g(-2)-g(1)}{-2-1}=\frac{-2-4}{-3}=\boxed{2}[/tex]

The measure of the third angle in the ΔABC is 70 degrees

In ΔABC, m∠2 = 70 and m∠1 = 40, find the measure of all third angle of ΔABC.

The given parameters are:

m∠2 = 70

m∠1 = 40

The sum of angles in a triangle is:

m∠1 + m∠2 + m∠3 = 180

So, we have:

70 + 40 + m∠3 = 180

Subtract 110 from both sides

m∠3 = 70

Hence, the measure of the third angle in the ΔABC is 70 degrees

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The range of the function g(x) will be (–∞, –4] ∪ [2, ∞). Option C is correct.

The domain denotes all potential x values, while the range denotes all possible y values.

When we plot the graph of the given function we will get the maximum and the minimum value till we get the function plot. The difference in the value of those coordinates is the range of the function.

The range of the function g(x) will be (–∞, –4] ∪ [2, ∞).

Hence option C is correct.

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Answer:

29, 36, 38

Step-by-step explanation:

The pattern is add 7 then 2, then 7, then 2, then 7, then 2. You should get the hang of it. All you have to do is just do the same thing for the next three numbers.

Answer:

[tex]\boxed{\sf x=12}[/tex]

Step-by-step explanation:

By applying Similar Triangles Theorem:-

[tex]\sf \cfrac{x}{6} =\cfrac{6}{3}[/tex]

We'll multiply both sides of the equation by 6, the LCM of 6,3.

[tex]\sf x=2 \times 6[/tex]

[tex]\sf x=12[/tex]

Answer:

4x+2h+5

Step-by-step explanation:

[tex]\frac{(2(x+h)^{2}+5(x+h)) - (2x^{2} +5x) }{h} \\[/tex]

For now I'm just going to ignore the denominator for simplicity

[tex](2(x^{2}+2xh+h^{2})+5x+5h) - (2x^{2} +5x)\\(2x^{2}+4xh+2h^{2}+5x+5h) - (2x^{2} +5x)\\(4xh+2h^{2}+5h)\\\\\frac{(4xh+2h^{2}+5h)}{h}\\ 4x+2h+5[/tex]

Final step just distributes the division

Based on the definition of a circumcircle, the center of the circle as shown in the image below is located: B. inside the triangle.

A circumcircle, as shown in the diagram attached below, is a circle that is drawn so that all the vertices of a triangle touches the circumference of the circle.

Thus, as shown in the image attached below, the center of the circle is located: B. inside the triangle.

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Answer: OUTSIDE THE TRIANGLE

Step-by-step explanation: ANSWER ON EDMENTUM/PUTO

Answer:

8.888(8)

Step-by-step explanation:

(26 +2/3)/ 1/3 =8.8888888889

The number of the units were started into production in a period will be 25,375.

A industry's fully prepared kinds of goods, as well as the primary materials needed to make them, are considered to as inventory.

If there were zero units of beginning work in process inventory, 4,714 units of ending work in process inventory, and 20,661 completed and transferred out units.

Completed and transferred out = 20,661

Ending Inventory = 4,714

Units accounted for = 25,375

Beginning Inventory = 0

Units started into production = [Units accounted for – Beginning work in progress Inventory] = 25,375

Units accounted for = 25,375

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Answer:slope is 0.4

Step-by-step explanation:

y2-y1 divided by x2-x1

2-4/0-5=0.4

Answer:

Step-by-step explanation:

sin θ=1/4,tan θ>0

so θ lies in first quadrant.

cos θ=√(1-sin²θ)=√(1-(1/4)²)=√(1-1/16)=√(15/16)=√15/4

[tex]2cos^2 \frac{\theta}{2} =1+cos \theta[/tex]

[tex]2~cos^2\frac{\theta}{2} =1+\frac{\sqrt{15} }{4} =\frac{4+\sqrt{15}}{4} \\cos~\frac{\theta}{2} =\sqrt{\frac{4+\sqrt{15} }{4 \times 2} } \\cos\frac{\theta}{2} =\frac{\sqrt{8+2\sqrt{15}} }{4}[/tex]

Answer:

3/4 - 5/12

Step-by-step explanation:

first you make the demoninators the same so 3*4=12

and if you *3 you do it to the numerator

so its 9/12-5/12

the unsimplified fraction is 4/12

if wanted simplified version its 1/3

[tex]\frac{3}{4}-\frac{5}{12}\\[/tex]

First make the denominators equal so you can easily add the numerators

Common Factor of 4 and 12: 12

So multiply [tex]\frac{3}{4}[/tex] with 3 for both numerator and denominator (4*3=12, to make denominator equal)

[tex]\frac{9}{12} - \frac{5}{12} =\frac{4}{12}[/tex]

Simplify further

[tex]\frac{4}{12} =\frac{1}{3}[/tex]

[tex]\frac{1}{3}[/tex] is the answer

Hope it helps!

Thank you for asking this question. Here is your answer:

We will consider the price of the truck to be $x

And the amount of tax in the percentage would be 13%

13/100

= $ 0.13x (this is the actual amount of the tax)

Now we will calculate the total price of the truck =

$x + $ 0.13x

= $ x(1 + 0.13)

If there is any confusion please leave a comment below.

Answer:

x = 1, -5

Step-by-step explanation:

4(x^2 + 4x - 5) = 0

4(x - 1)(x + 5) = 0

x = 1, -5

Answer:

Theres no bag we cant solve it without you showing a picture or describing it

Step-by-step explanation:

Answer:

a = -9

b = -3

c = 11

d = 19

Step-by-step explanation:

a. x = -2

y= x² + 3x + 1

y= -2²+ 3(-2)+1

y= -4-6+1

y = -9

b. x= -1

y= x² + 3x+ 1

y= -1² + 3(-1) +1

y= -1 -3 + 1

y = -3

c. x =2

y = x² + 3x +1

y= 2²+ 3(2) +1

y= 4 +6 +1

y = 11

d. x= 3

y = x² +3x +1

y = 3² +3(3) +1

y= 9 +9 +1

y = 19

Answer:

Graph C

Step-by-step explanation:

Graph A (-3, -2) (0, 7)

3(7) + 9(0) = 21

21 = 21 ✓

3(-2) + 9(-3) = 21

-6 - 27 = 21

-33 = 21  ✖

Graph B (0, -7) (3,2)

We know from above that (0, 7) is a point on the line 3y + 9x = 21, therefore point (0, -7) cannot be on that line.

3(2) + 9(3) = 21

6 + 27 = 21

33 = 21  ✖

Graph C (0, 7) (3, -2)

We know from above that (0, 7) is a solution.

3(-2) + 9(3) = 21

-6 + 27 = 21

21 = 21 ✓

Since both points on graph C is a solution to the equation of the line given, it is the answer (looking at graph D is not necessary unless you want to double check your answer).

Answer:

R ,is the Resultant of two forces,

∠ACB +50°=180°

∠ACB=180° -50°

∠ACB=130°

→Cos(130°)=Cos (180°-50°)= -cos 50°= -0.6427

Magnitude of resultant force =70.70 Newtons(Approx)

The equivalent equation to find the ordered pair will be y=0.3x where x represents the number of days the book is late and y represents the total fine fee.

A linear equation is an equation where the highest degree in the equation is 1.

for example, y=mx,

where y and x is the variable and m, is the constant.

Given, that the librarian charges $0.30 per each day that the book is late to submit

for estimating the relation between the number of days the book is late and the total fine fee

Let's assume the number of days the book is late is x,

and the total fine is y

the librarian charges $0.30 per one day

so for x days, the total charge will be =0.30x

so from above, it is clear that the linear equation will be

y=0.3x

applying all the order pairs in this equation we can decide.

The equivalent equation to find the ordered pair will be y=0.3x

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Answer:

Complemetry angle = 90° - 40°

= 50°

Hii!

___________________________________________________________

Answer:

[tex]\sf 48\textdegree[/tex]

Step-by-step explanation:

The sum of complementary angles is always 90 degrees.

We can find the complement of 90 by setting up an equation; (let x be the unknown angle).

[tex]\implies[/tex] 42+x=90

Subtract 42 from both sides

x=48

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Hope that this helped! Best wishes.

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Answer:

[tex]x = \frac{25}{13} [/tex]

Step-by-step explanation:

Given:

[tex] \frac{2}{5} x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6} x[/tex]

Combine like terms:

[tex] \frac{2}{5} x - \frac{5}{6} x = \frac{1}{3} + \frac{1}{2} [/tex]

Find GCF :

[tex] \frac{12}{30} x - \frac{25}{30} = \frac{2}{6} + \frac{3}{6} [/tex]

Subtraction and Addition :

[tex] \frac{13}{30} x = \frac{5}{6} [/tex]

Divide both sides by 13/30 :

[tex] \frac{ \frac{13}{30} }{ \frac{13}{30} } x = \frac{ \frac{5}{6} }{ \frac{13}{30} } [/tex]

Simplify :

Multiplication (Reciprocal) :

[tex]x = \frac{5}{6} \times \frac{30}{13} [/tex]

[tex]x = \frac{150}{78} [/tex]

[tex]x = \frac{25}{13} [/tex]

Answer :

[tex]x = \frac{25}{13} [/tex]

Hope it helps

Answer:

See below ~

Step-by-step explanation:

1) a) 50 km / 2 h

⇒ 25 km/h

b) 540 kg / 3 days

⇒ 180 kg/day

c) 125 m / 5 min.

⇒ 25 m/min.

A unit rate means a rate for one of something. We write this as a ratio with a denominator of one. For example, if you ran 70 yards in 10 seconds, you ran on average 7 yards in 1 second. Both of the ratios, 70 yards in 10 seconds and 7 yards in 1 second, are rates, but the 7 yards in 1 second is a unit rate…

a) 50km/2h

=> 25 kilometers per hour

b) 540kg/3d

=> 180 kilogram per day

c) 125m/5min

=> 25 meter per minute

The Z-score is 2.306 to three decimal places. However, the Z-test statistic value shows that it is greater than the Z-critical value, so we reject the null hypothesis [tex]\mathbf{H_o}[/tex]

A z-score is a measurement of how often standard deviations the score obtained from a z-test is beyond or under the mean population.

From the given data information, let us find the mean and the standard deviation.

[tex]\mathbf{Mean (\bar x) = \dfrac{1154+5998+1007+...3987+4187+887}{10}}[/tex]

[tex]\mathbf{Mean (\bar x) = \dfrac{24256}{10}}[/tex]

Mean (x) = 2425.6

The hypothesis testing can be computed as:

[tex]\mathbf{H_o: \mu = 2425.6}[/tex]

[tex]\mathbf{H_1: \mu \ne 2425.6}[/tex]

The standard deviation (σ) is:

[tex]\mathbf{=\mathbf{ \sqrt{\dfrac{(1154-2425.6)^2+....+(887-2425.6)^2}{10-1}}}}[/tex]

[tex]\mathbf{= \sqrt{3199489}}[/tex]

= 1788.71

Now, the Z-test statistic is determined using the formula:

[tex]\mathbf{|Z| = |\dfrac{\bar x - \mu }{\sigma}| }[/tex]

[tex]\mathbf{|Z| = |\dfrac{2425.6 -6550 }{1788.71}| }[/tex]

[tex]\mathbf{|Z| = |-2.3058| }[/tex]

Z ≅ 2.306  

Therefore, at a 0.05 level of significance, the Z-critical value is 2.306. However, since the Z-test statistic value shows that it is greater than the Z-critical value, so we reject the null hypothesis [tex]\mathbf{H_o}[/tex]

The complete question is given as:

Using a sequencing method called "RNAseq," a researcher determines the level of FOXP2 expression in 10 different samples of lung tissue, and obtains these data:

Scientist has previously determined that FOXP2 is expressed in brain tissue at a level of 6,550. Calculate the Z-score associated with a test to see if the average expression of FOXP in her lung tissue samples is different from the levels she measured from brain tissue.

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Answer:

(u + [tex]\frac{65}{2}[/tex] )²

Step-by-step explanation:

u² + 65u

to complete the square

add ( half the coefficient of the u- term )²

= u² + 2([tex]\frac{65}{2}[/tex] )u + [tex]\frac{4225}{4}[/tex]

= (u + [tex]\frac{65}{2}[/tex] )²

The length of the AC is x^2  + 4x  - 12.

That quadrilateral in which opposite sides are parallel is called a parallelogram.

Thus, a parallelogram is always a quadrilateral but a quadrilateral can or cannot be a parallelogram.

Given :

In Parallelogram ABCD, diagonals AC and BD intersect at point E.

such that

AE = x^2 - 12,

CE = 4x

We know that the diagonal of a parallelogram bisect each other.

x^2 - 12 = 4x

x^2  - 4x  - 12= 0

(x-6)(x-2) = 0

Hence, the value of x = 6, 2.

AC = AE + CE = x^2  + 4x  - 12.

The length of the AC is x^2  + 4x  - 12.

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Answer:54

Step-by-step explanation:

There are quicker ways to solve this but a simple and easy way to do this would be by dividing your number by the percent so 288/80 and with this, you would get your number for 1 percent or 3.6. Now you can multiply that number by the percent your need to find so 15. And 15 x 3.6 is = 54.