In a large class in statistics, the final examination grades have a mean of 67.4 and a standard deviation of 12. Assuming that the distribution of these grades is normal, the number of passes in a class of 180 is:_________ (if you get a number with decimals points, round up to the next whole number)

Answers

Answer 1

Answer:

The number of passes in a class of 180 is 75.

Step-by-step explanation:

The problem does not state, so I will suppose the passing grade is 70.

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 67.4, \sigma = 12[/tex]

Proportion of students who passed:

This is 1 subtracted by the pvalue of Z when X = 70. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{70 - 67.4}{12}[/tex]

[tex]Z = 0.22[/tex]

[tex]Z = 0.22[/tex] has a pvalue of 0.5871.

1 - 0.5871 = 0.4129

Out of 180:

0.4129*180 = 74.32

Rounding up

The number of passes in a class of 180 is 75.


Related Questions

Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if a relation is not an equivalence relation, please list each property that is missing and the reason why it is missing.) (1) {(0,0), (1,1), (2,2), (3,3)} (2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)} (3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)} (4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

Answers

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

Reflexivity: If [tex]\forall x \in A, x \rightarrow x[/tex]Symmetry: [tex]\forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x[/tex]Transitivity: [tex]\forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z[/tex]

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 400 gram setting. It is believed that the machine is underfilling the bags. A 9 bag sample had a mean of 397 grams with a standard deviation of 25. A level of significance of 0.025 will be used. Assume the population distribution is approximately normal. Determine the decision rule for rejecting the null hypothesis. Round your answer to three decimal places.

Answers

Answer:

Reject [tex]H_o[/tex] if [tex]t < -2.306[/tex]

Step-by-step explanation:

The decision rule for rejecting the null hypothesis is shown below:-

The machine is thought to be underfilling so that the test is left tailed.

Now the Degrees of freedom is

= 9 - 1

= 8

Critical left tailed value t for meaning level [tex]8 \ df[/tex] and 0.025 = -2.306

Therefore Decision rule will be in the following way:

Reject [tex]H_o[/tex] if [tex]t < -2.306[/tex]

Determine whether the results appear to have statistical​ significance, and also determine whether the results appear to have practical significance. In a study of a gender selection method used to increase the likelihood of a baby being born a​ girl, 1961 users of the method gave birth to 961 boys and 1000 girls. There is about a 20​% chance of getting that many girls if the method had no effect. 1. Does the weight loss program have statistical​ significance?A. ​Yes, the program is statistically significant because the results are unlikely to occur by chance.B. Yes, the program is statistically significant because the results are likely to occur by chance.C. No, the program is not statistically significant because the results are likely to occur by chance.D. No, the program is not statistically significant because the results are unlikely to occur by chance.2. Does the weight loss program have practical​ significance?A. Yes, the program is practically significant because the results are too unlikely to occur by chance.B. No, the program is not practically significant because the results are likely to occur even if the weight loss program has no effect.C. No, the program is not practically significant because the amount of weight lost is trivial.D. Yes, the program is practically significant because the amount of lost weight is large enough to be considered practically significant.

Answers

Answer:

C. No, the program is not statistically significant because the results are likely to occur by chance.

Step-by-step explanation:

At a significance level that is smaller than 0.2, the effect is not significant.

We have a P-value of 20%, which means that we have 20% chances of getting this sample given that the method has no effect.

We then can conclude that there is not enough evidence to support the claim that the method is effective.

Choose a reasonable estimate for the amount of water a cup would hold.

Answers

Answer:

A cup of water can hold a cup of water (or about 250 mL)

Step-by-step explanation:

anything between 1 and 4 cups should be an acceptable answer

If this helps, please consider giving me brainliest

Answer:

I'm gonna go with 250 ML

Step-by-step explanation:

One liter is a little more than 1 quart.

250 mL = 0.25 L

1. (a) The life time of a certain brand of bulbs produced by a company is normally distributed, with mean 210 hours and standard deviation 56 hours. What is the probability that a bulb picked at random from this company’s products will have a life time of:
(i) at least 300 hours,
(ii) at most 100 hours,
(iii) between 150 and 250 hours.
(b) In a contest, two friends, Kofi and Mensah were asked to solve a problem. The
probability that Kofi will solve it correctly is ' and the probability that Mensah
(
will solve it correctly is ) . Find the probability that neither of them solved it correctly.
*

Answers

Answer:

1a) (i) 0.0537

(ii) 0.0250

(iii) 0.6188

1b) The probability that neither Kofi nor Mensah solves the problem correctly = (9/20) = 0.45

Step-by-step explanation:

The complete Question is presented in the attached image to this answer.

1a) This is a normal distribution problem with

Mean lifetime of bulbs = μ = 210 hours

Standard deviation = σ = 56 hours

(i) at least 300 hours, P(x ≥ 300)

We first standardize 300 hours

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (300 - 210)/56 = 1.61

To determine the required probability

P(x ≥ 300) = P(z ≥ 1.61)

We'll use data from the normal probability table for these probabilities

P(x ≥ 300) = P(z ≥ 1.61) = 1 - P(z < 1.61)

= 1 - 0.94630 = 0.0537

(ii) at most 100 hours, P(x ≤ 100)

We first standardize 100 hours

z = (x - μ)/σ = (100 - 210)/56 = -1.96

To determine the required probability

P(x ≤ 100) = P(z ≤ -1.96)

We'll use data from the normal probability table for these probabilities

P(x ≤ 100) = P(z ≤ -1.96) = 0.0250

(iii) between 150 and 250 hours.

P(150 < x < 250)

We first standardize 150 and 250 hours

For 150 hours

z = (x - μ)/σ = (150 - 210)/56 = -1.07

For 250 hours

z = (x - μ)/σ = (250 - 210)/56 = 0.71

To determined the required probability

P(150 < x < 250) = P(-1.07 < z < 0.71)

We'll use data from the normal probability table for these probabilities

P(150 < x < 250) = P(-1.07 < z < 0.71)

= P(z < 0.71) - P(z < -1.07)

= 0.76115 - 0.14231

= 0.61884 = 0.6188 to 4 d.p.

1b) Probability that Kofi solves the problem correctly = P(K) = (1/4)

Probability that Mensah solves the problem correctly = P(M) = (2/5)

Probability that Kofi does NOT solve the problem correctly = P(K') = 1 - P(K) = 1 - (1/4) = (3/4)

Probability that Mensah does NOT solve the problem correctly = P(M') = 1 - P(M) = 1 - (2/5) = (3/5)

To find the probability that neither of them solves the problem correctly, we first make the logical assumption that the probabilities of either of them solving the problem are independent of each other.

Hence, the probability that neither of them solves the problem correctly = P(K' n M')

P(K' n M') = P(K') × P(M') = (3/4) × (3/5) = (9/20) = 0.45

Hope this Helps!!!

There are 4, 6, and 7 points on three lines. How many quadrilaterals is it possible to create with given points as vertices?

Answers

Answer:

  1707

Step-by-step explanation:

Let's designate the three sets of collinear points, A, B, C, having 4, 6, 7 points, respectively.

Since there are 3 sets of collinear points, exactly two of the vertices must come from the same set.

For two vertices from set A, the remaining two must come from the 13 members of sets B and C. There are a total of (4C2)(13C2) = 468 such quadrilaterals.

For two vertices from set B, we have already counted the quadrilaterals that result when the remaining two are from set A. There are 4·7 = 28 ways to have one each from sets A and C, and 7C2 = 21 ways to have two from set C. Thus, the additional number of quadrilaterals having 2 vertices in set B is ...

  (6C2)(28 +21) = 735

For two vertices from set C, we have already counted the cases where two are from A or two are from B. There are 4·6 = 24 ways to have one each of the remaining vertices from sets A and B. Then the number of additional quadrilaterals having two points from set C is ...

  (7C2)(4)(6) = 504

So, the total number of unique quadrilaterals is ...

  468 +735 +504 = 1707

__

nCk means "the number of ways to choose k from n"

nCk = n!/(k!(n-k)!)

How to solve? What are the rules in BODMAS

Answers

Answer:

18/35

Step-by-step explanation:

1 1/5 ÷ 2  1/3

Change from mixed numbers to improper fractions

1 1/5 = (5*1+1)/5 = 6/5

2 1/3 = (3*2+1)/3 = 7/3

6/5÷ 7/3

Copy dot flip

6/5* 3/7

18/35

Answer:

Step-by-step explanation:

I don't say you must have to mark my ans as brainliest but if it has really helped u plz don't forget to thank me my friend...

The temperature outside when Colin went to bed was -4°F. When he woke up the next

morning, it was -11°F outside. Describe the change in temperature by completing the

statements.

Answers

Step-by-step explanation:

The temperature outside when Colin went to bed was -4°F. When he woke up the next  morning, it was -11°F outside

To find the change in the temperature , find the difference in temperature

Change in temperature = temperature in morning - temperature at night

change in temperature = [tex]-11 -(-4)= -7[/tex]

temperature changed by -7 °F

So the temperature is dropped by 7°F

Answer:

the temperature is dropped by 7°F

The temperature change when he woke up the next morning given the data was –7 °F.

Data obtained from the question  

From the question given above , the following data were obtained:

Temperature at night (T₁) = –4 °F  Temperature in the morning (T₂) = –11 °F Change in temperature (ΔT) =?

How to determine the change in the temperature

The temperature change when Colin woke up can be obtained by taking the difference in the temperature at night and morning. This is illustrated as follow:

ΔT = T₂ – T₁

ΔT = –11 – (–4)

ΔT = –11 + 4

ΔT = –7 °F

Thus, from the calculation made above, we can conclude that there was a temperature drop of –7 °F when he woke up the next morning

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1 point
4. A tin can in the shape of the cylinder shown is filled with coconut oil. If
coconut oil costs $0.01 per cubic centimeter, what is the cost of filling the
tin can with coconut oil?
8 cm
O
A. $603.10
B. $12.06
O ooo
c. $6.03
O
D. $1.92​

Answers

Answer:

$6.03

Step-by-step explanation:

Let's begin by listing out the given variables:

height (h) = 12 cm, diameter (d) = 8 cm, r = d ÷ 2  ⇒ r = 4 cm, cost of coconut oil (c) = $0.01 /cm³

The formula of cylinder is given by:

V = πr²h = π * 4² * 12 = 603.1858 cm³

cost of filling the tin can with coconut oil = cost of coconut oil * Volume of cylinder

Cost = c * V = 0.01 * 603.1858

Cost = $6.03

A customer will be charged extra if the weight of their suitcase is above 48 pounds.
​Write an inequality to represent w, the weight of the suitcase in pounds, that will have an extra charge.
​Enter your answer by clicking and using the expression evaluator.

Answers

Answer:

[tex]w>48[/tex] pounds

Step-by-step explanation:

The customer will be charged extra if the weight of their suitcase is above 48 pounds.

Let the weight of the suitcase = w (in pounds)

Therefore, w above (greater than) 48 pounds is written mathematically as:

[tex]w>48[/tex] pounds

This is the inequality that represents w, the weight of the suitcase in pounds, that will have an extra charge.

What is the area of a circle with a radius of 6 inches?
9. in.
O 125 in.
O 36in 2
81 in 2​

Answers

Answer:

A = 36pi in^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

A = pi 6^2

A = 36pi in^2

Solution,

Radius(r)=6 inches

Area of circle=?

Now,

Area of circle=pi r ^2

=pi (6)^2

36 pi inches^2

So the right answer is 36 pi inches^2

Hope it helps

Using the graph as your guide, complete the following statement.
The discriminant of the function is
O A. negative
OB zero
O C positive

Answers

Answer:it’s ZERO

Step-by-step explanation:

The discriminant of the function is zero

What is a function?

A relation is a function if it has only One y-value for each x-value.

The discriminant tells you where the graph of the parabola goes through the x-axis, if at all.

If the discriminant is negative there are no real zeros and the parabola does not cross or touch the x-axis;

if the discriminant is positive the parabola will go through the x axis in 2 places;

if the discriminant is 0 the parabola will touch the x-axis in 1 place.

Our discriminant is 0 since the parabola only touches the x-axis but does not go through.

Hence, the discriminant of the function is zero

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36 inches, 20 inches, and 24 inches. What type of triangle did Rosa draw?

Answers

Answer:

Scalene triangle

Step-by-step explanation:

2. 4 masks and 1 pack of gloves costs $18. Three packs of gloves and 4 masks costs $22. What is the cost of one pack of gloves and one mask?

Answers

Answer:

One mask=$4

One pack of glove=$2

Step-by-step explanation:

Let mask=m

Let glove=g

4m+g=18 (1)

4m+3g=22 (2)

From (1)

g=18-4m

Substitute g=18-4m into equation (2)

4m+3g=22

4m+3(18-4m)=22

4m+54-12m=22

4m-12m=22-54

-8m=-32

Divide both sides by -8

m=4

Substitute m=4 into equation (1)

4m+g=18

4(4)+g=18

16+g=18

g=18-16

g=2

One mask=$4

One pack of glove=$2

Waiting times​ (in minutes) of customers at a bank where all customers enter a single waiting line and a bank where customers wait in individual lines at three different teller windows are listed below. Find the coefficient of variation for each of the two sets of​ data, then compare the variation. Bank A​ (single line): 6.5 nbsp 6.7 nbsp 6.7 nbsp 6.8 nbsp 7.1 nbsp 7.3 nbsp 7.4 nbsp 7.7 nbsp 7.7 nbsp 7.7 Bank B​ (individual lines): 4.3 nbsp 5.4

Answers

Complete Question

1. Waiting times​ (in minutes) of customers at a bank where all customers enter a single waiting line and a bank where customers wait in individual lines at three different teller windows are listed below. Find the coefficient of variation for each of the two sets of​ data, then compare the variation.

Bank A (single lines): 6.5, 6.6, 6.7, 6.8, 7.2, 7.3, 7.4, 7.6, 7.6, 7.7

Bank B (individual lines): 4.1, 5.4, 5.8, 6.3, 6.8, 7.8, 7.8, 8.6, 9.3, 9.7

- The coefficient of variation for the waiting times at Bank A is ----- %?

- The coefficient of variation for the waiting times at the Bank B is ----- ​%?

- Is there a difference in variation between the two data​ sets?

Answer:

a

The coefficient of variation for the waiting times at Bank A is [tex]l =[/tex]6.3%

b

The coefficient of variation for the waiting times at Bank B is [tex]l_1 =[/tex]25.116%

c

The waiting time of Bank B has a considerable higher variation than that of Bank A

Step-by-step explanation:

From the question we are told that

  For Bank A  : 6.5, 6.6, 6.7, 6.8, 7.2, 7.3, 7.4, 7.6, 7.6, 7.7

 For  Bank B : 4.1, 5.4, 5.8, 6.3, 6.8, 7.8, 7.8, 8.6, 9.3, 9.7

The sample size is  n =10

The mean for Bank A is

          [tex]\mu_A = \frac{6.5+ 6.6+ 6.7+ 6.8+ 7.2+ 7.3+ 7.4+ 7.6+ 7.6+ 7.7}{10}[/tex]

          [tex]\mu_A = 7.14[/tex]

The standard deviation is mathematically represented as

      [tex]\sigma = \sqrt{\frac{\sum|x- \mu|}{n} }[/tex]

        [tex]k = \sum |x- \mu | ^2 = 6.5 -7.14|^2 + |6.6-7.14|^2+ |6.7-7.14|^2+ |6.8-7.14|^2 + |7.2-7.14|^2+ |7.3-7.14|^2, |7.4-7.14|^2+ |7.6-7.14|^2+|7.6-7.14|^2+|7.7-7.14|^2[/tex]

[tex]k = 2.42655[/tex]

    [tex]\sigma = \sqrt{\frac{2.42655}{10} }[/tex]

    [tex]\sigma = 0.493[/tex]

The coefficient of variation for the waiting times at Bank A is  mathematically represented as  

        [tex]l = \frac{\sigma}{\mu} *100[/tex]

        [tex]l = \frac{0.493}{7.14} *100[/tex]

       [tex]l =[/tex]6.3%

Considering Bank B

     The mean for Bank B is

               [tex]\mu_1 = \frac{4.1+ 5.4+ 5.8+ 6.3+6.8+ 7.8+ 7.8+ 8.6+ 9.3+ 9.7}{10}[/tex]

              [tex]\mu_1 = 7.16[/tex]

The standard deviation is mathematically represented as      

       [tex]\sigma_1 = \sqrt{\frac{\sum|x- \mu_1|}{n} }[/tex]

    [tex]\sum |x- \mu_1 | ^2 =4.1-7.16|^2 +| 5.4-7.16|^2+ |5.8-7.16|^2 + | 6.3-7.16|^2 + |6.8-7.16|^2 + | 7.8-7.16|^2 +|7.8-7.16|^2 +|8.6-7.16|^2 + |9.3-7.16|^2 +|9.7-7.16|^2[/tex]

[tex]\sum |x- \mu_1 | ^2 =32.34[/tex]

    [tex]\sigma_1 = \sqrt{\frac{32.34}{10} }[/tex]

     [tex]\sigma_1 = 1.7983[/tex]

The coefficient of variation for the waiting times at Bank B is  mathematically represented as  

        [tex]l_1 = \frac{\sigma }{\mu} *100[/tex]

        [tex]l_1 = \frac{1.7983 }{7.16} *100[/tex]

        [tex]l_1 =[/tex]25.116%

Lines a and b are parallel.

Parallel lines a and b are cut by transversals s and t. The angles formed by the intersection of lines a, s, and t, clockwise from top left are (7 x) degrees, blank; formed by lines b and s are blank, blank, blank, (11 x) degrees; formed by lines b and t are 90 degrees,

What is the value of x?
5
10
35
55

If you answer correctly, we will name the brainiest!
This is a challenge question, you have 5 minutes.

Answers

Answer:

The answer is x=5.

Step-by-step explanation:

11x + 7x + 90 = 180

18x + 90 = 180

       -90    -90

= 18x = 90

 x = 5

x is 5!

Value of x is 10°.

Correct option is B.

What is angle?

A figure which is formed by two rays or lines that shares a common endpoint is called an angle. The word “angle” is derived from the Latin word “angulus”, which means “corner”.

Given,

a || b

cut by transversal s and t

lines b and t have angle = 90°

The first top left angle between a, s, t = 7x

The last bottom angle between s and b = 11x

a || b, so a and t will also have angle = 90°

by the figure,

180° - 11x + 90° - 7x + 90° = 180°

360° - 18x = 180°

18x = 180°

x = 10°

Hence, 10° is value of x.

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Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and the event that the A2 right leg tag is lost. Suppose these two events are independent and P(A1)=P(A2)=0.4. Find the probability that exactly one tag is lost, given that at least one tag is lost (write it up to second decimal place).

Answers

Answer:

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

Step-by-step explanation:

Independent events:

If two events, A and B, are independent, then:

[tex]P(A \cap B) = P(A)*P(B)[/tex]

Conditional probability:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: At least one tag is lost

Event B: Exactly one tag is lost.

Each tag has a 40% = 0.4 probability of being lost.

Probability of at least one tag is lost:

Either no tags are lost, or at least one is. The sum of the probabilities of these events is 1. Then

[tex]p + P(A) = 1[/tex]

p is the probability none are lost. Each one has a 60% = 0.6 probability of not being lost, and they are independent. So

p = 0.6*0.6 = 0.36

Then

[tex]P(A) = 1 - p = 1 - 0.36 = 0.64[/tex]

Intersection:

The intersection between at least one lost(A) and exactly one lost(B) is exactly one lost.

Then

Probability at least one lost:

First lost(0.4 probability) and second not lost(0.6 probability)

Or

First not lost(0.6 probability) and second lost(0.4 probability)

So

[tex]P(A \cap B) = 0.4*0.6 + 0.6*0.4 = 0.48[/tex]

Find the probability that exactly one tag is lost, given that at least one tag is lost (write it up to second decimal place).

[tex]P(B|A) = \frac{0.48}{0.64} = 0.75[/tex]

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

Suppose a random variable, x, follows a Poisson distribution. Let μ = 2.5 every minute, find the P(X ≥ 125) over an hour. Round answer to 4 decimal places.

Answers

Answer:

P(X ≥ 125) = 0.9812

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the normal distribution.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\lambda[/tex] is the mean in the given interval, which is the same as the variance.

Normal distribution:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The Poisson can be approximated to the normal, with [tex]\mu = \lambda, \sigma = \sqrt{\lambda}[/tex]

Let μ = 2.5 every minute

This is the mean of the Poisson, so [tex]\lambda = 2.5n[/tex], in which n is the number of minutes.

P(X ≥ 125) over an hour

An hour has 60 minutes, so [tex]n = 60, \lambda = 2.5*60 = 150, \sigma = \sqrt{150} = 12.25[/tex]

Using continuity correction, this is [tex]P(X \geq 125 - 0.5) = P(X \geq 124.5)[/tex], which is 1 subtracted by the pvalue of Z when X = 124.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{124.5 - 150}{12.25}[/tex]

[tex]Z = -2.08[/tex]

[tex]Z = -2.08[/tex] has a pvalue of 0.0188

1 - 0.0188 = 0.9812

So

P(X ≥ 125) = 0.9812

Please answer this correctly I want genius or expert people to answer this correctly.

Answers

Answer:

18.84mm^2

Step-by-step explanation:

Surface area of a cylinder can be found with the following formula:

2πrh+2πr^2

r is radius

h is height

Plug our values in

2π1(2)+2π(1)^2

2π(2)+2π(1)

4π+2π

6(3.14)

18.84

If the ratio of similarity between two similar polygons is 4:3.2, this ratio converts to

1:8.

8:1.

4:5.

5:4.

Answers

Answer:

5   : 4

Step-by-step explanation:

4:  3.2

Multiply by 10 to get rid of the decimal

4*10 : 3.2* 10

40 : 32

Divide each side by 8 to simplify

40/8   : 32/ 8

5   : 4

Represent the relationship between the total cost and the number of items, if total cost t is proportional to the number n of items purchased at a constant price p.

Answers

Answer:

t = pn

Step-by-step explanation:

We are to find the relationship between total cost and the number of items.

First we would represent the relationship between total cost and number of items with variables

Let the total cost = t

and the number of items = n

Total cost t is proportional to the number n of items:

t ∝ n

t = kn

where k is constant

Since it is purchased at a constant price p, the constant of proportionality would be p. the k would be replaced with p

t = pn

Please help! Correct answer only, please! Consider the matrix shown below: Find the inverse of the matrix A: (i.e Find A^-1).

Answers

Answer: A

Step-by-step explanation:

Formula for inverse of a matrix is:

[tex]A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\qquad \rightarrow \qquad A^{-1}=\dfrac{1}{ad-bc}\left[\begin{array}{cc}d&-b\\-c&a\end{array}\right][/tex]

[tex]A=\left[\begin{array}{cc}2&5\\3&8\end{array}\right] \qquad \rightarrow \qquad A^{-1}=\dfrac{1}{2(8)-5(3)}\left[\begin{array}{cc}8&-5\\-3&2\end{array}\right]\\\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \quad =\dfrac{1}{1}\left[\begin{array}{cc}8&-5\\-3&2\end{array}\right]\\\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \quad =\left[\begin{array}{cc}8&-5\\-3&2\end{array}\right][/tex]

We have that  Option A is the correct option as its the correct in verse of the Matrix A

From the question we are told that:

[tex]A= \begin{vmatrix}2 & 5 \\3 & 8\end{vmatrix}[/tex]

Inverse of a Matrix

The inverse of matrix is another matrix, which on multiplication with the given matrix gives the multiplicative identity. For a matrix A, its inverse is A^{-1}, and A.A^{-1} = I.

Therefore the inverse of the Matrix A is

[tex]A= \begin{vmatrix}2 & 5 \\3 & 8\end{vmatrix}[/tex]

Giving

[tex]A^{-1}= \begin{vmatrix}8 & -5 \\-3 & -2\end{vmatrix}[/tex]

In conclusion

The correct Option is Option A as its the correct in verse of the Matrix A

For more information on this visit

https://brainly.com/question/4017205

In conclusion

Mr. Collins and Ms. LaPointe are saving money to buy a new motorcycle. The total amount of money Mr. Collins will save is given by the function p(x) = 62 + 5x. The total amount of money Ms. LaPointe will save is given by the function a(x) = x2 + 38. After how many months, x, will they have the same amount of money saved?

Answers

We have been given that Mr. Collins and Ms. LaPointe are saving money to buy a new motorcycle. The total amount of money Mr. Collins will save is given by the function [tex]p(x) = 62+5x[/tex]. The total amount of money Ms. LaPointe will save is given by the function [tex]a(x) = x^2+38[/tex]. We are asked to find number of months when they have the same amount of money saved.

To solve our given problem, we will equate both equations as:

[tex]x^2+38=62+5x[/tex]

[tex]x^2-5x+38=62+5x-5x[/tex]

[tex]x^2-5x+38=62[/tex]

[tex]x^2-5x+38-62=62-62[/tex]

[tex]x^2-5x-24=0[/tex]

[tex]x^2-8x+3x-24=0[/tex]

[tex]x(x-8)+3(x-8)=0[/tex]

[tex](x-8)(x+3)=0[/tex]

[tex](x-8)=0,(x+3)=0[/tex]

[tex]x=8,x=-3[/tex]

Since time cannot be negative, therefore, after 8 months they will have the same amount of money saved.

prove
cos A /(1- sin A) = (1 + sin A)/cos A​

Answers

Answer:

answer is in exaplation

Step-by-step explanation:

cosA

+

cosA

1+sinA

=2secA

Step-by-step explanation:

\begin{lgathered}LHS = \frac{cosA}{1+sinA}+\frac{1+sinA}{cosA}\\=\frac{cos^{2}A+(1+sinA)^{2}}{(1+sinA)cosA}\\=\frac{cos^{2}A+1^{2}+sin^{2}A+2sinA}{(1+sinA)cosA}\\=\frac{(cos^{2}A+sin^{2}A)+1+2sinA}{(1+sinA)cosA}\\=\frac{1+1+2sinA}{(1+sinA)cosA}\end{lgathered}

LHS=

1+sinA

cosA

+

cosA

1+sinA

=

(1+sinA)cosA

cos

2

A+(1+sinA)

2

=

(1+sinA)cosA

cos

2

A+1

2

+sin

2

A+2sinA

=

(1+sinA)cosA

(cos

2

A+sin

2

A)+1+2sinA

=

(1+sinA)cosA

1+1+2sinA

/* By Trigonometric identity:

cos² A+ sin² A = 1 */

\begin{lgathered}=\frac{2+2sinA}{(1+sinA)cosA}\\=\frac{2(1+sinA)}{(1+sinA)cosA}\\\end{lgathered}

=

(1+sinA)cosA

2+2sinA

=

(1+sinA)cosA

2(1+sinA)

After cancellation,we get

\begin{lgathered}= \frac{2}{cosA}\\=2secA\\=RHS\end{lgathered}

=

cosA

2

=2secA

=RHS

Therefore,

\begin{lgathered}\frac{cosA}{1+sinA}+\frac{1+sinA}{cosA}\\=2secA\end{lgathered}

1+sinA

cosA

+

cosA

1+sinA

=2secA

Keep gettin those wrong. Please help!!!

Answers

Answer: About 14.14 in^3

Step-by-step explanation:

We know that the circumference of a sphere is C=2πr. We are given that the circumference is 9.42 in. We can find the radius to get our volume.

[tex]9.42=2\pi r[/tex]

[tex]4.71=\pi r[/tex]

[tex]r=1.5\\[/tex]

Now that we know radius, we can find our volume.

[tex]V=\frac{4}{3} \pi r^3[/tex]

[tex]V=\frac{4}{3} \pi (1.5)^3[/tex]

[tex]V=14.14in^3[/tex]

PPPLLLLLEEAAASSSEEE HELP!!!!!!!!!
Consider the following​ situation, which involves two options. Determine which option is less expensive. Are there unstated factors that might affect your​ decision?
You currently drive 275 miles per week in a car that gets 16 miles per gallon of gas. You are considering buying a new​ fuel-efficient car for ​$18 comma 000 ​(after trade-in on your current​ car) that gets 44 miles per gallon. Insurance premiums for the new and old car are ​$1000 and ​$600 per​ year, respectively. You anticipate spending ​$1100 per year on repairs for the old car and having no repairs on the new car. Assume gas costs ​$3.50 per gallon. Over a​ five-year period, is it less expensive to keep your old car or buy the new​ car?
Over a​ five-year period, the cost of the old car is ​$____ and the cost of the new car is ​$_____
​Thus, over a​ five-year period, it is less expensive to keep the old car or buy the new car?

Answers

Answer:

Step-by-step explanation:

Seja a função real dada por f(x)=4x-9. Calcule f(6) - f(5). ( ) 4 ( ) 1 ( ) 2 ( ) -4 ( ) -1

Answers

Answer:

4

Step-by-step explanation:

A função em questão, f(x), é:

[tex]f(x)=4x-9[/tex]

Primeiramente calcule os valores das funções para x=5 e x=6:

[tex]f(5)=4*5-9\\f(5)=11\\f(6)=4*6-9\\f(6)=15[/tex]

Em seguida, subtraia f(5) de f(6):

[tex]f(6)-f(5) = 15-11\\f(6)-f(5) = 4[/tex]

A resposta para o problema é 4

The price of oil, in dollars per barrel, declined last week by 3.5%. If it started the week at 102.00 per barrel, at what per barrel price did it end the week?

Answers

Answer:

98.57

Step-by-step explanation:

3.5% over 100% X 102=3.43

102-3.43= 98.57

if the perimeter of a square gardern is 84feet . what is the area of the qardern​

Answers

Answer:

441

Step-by-step explanation:

84 / 4 = 21

21 x 21 = 441

Answer:

441

Step-by-step explanation:

84/2=42

Please answer this question !! Thank you !! Will give brainliest !! Really important !!

Answers

Answer:

0 = 3x -2y -6

Step-by-step explanation:

The general form of the equation of a line is 0 = Ax + By + C

y = 3/2x -3

Subtract y from each side

0 = 3/2x -y -3

Multiply each side by 2

0 = 3x -2y -6

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