In a carnival drawing, a green ticket wins $1, a yellow ticket wins $5, and a blue ticket wins $10. There are 20 green tickets, 10 yellow tickets and 5 blue tickets. In simplest form, what are the odds against winning less than $10?
A. 1:4
B. 1:5
C. 1:6
D. 6:1

Answer:

{0, 2, 4, 6, 8 }

Step-by-step explanation:

the range is the y- coordinates of the ordered pairs , then

range { 0, 2, 4, 6, 8 }

Answer:

28

Step-by-step explanation:

similar triangles are proportional

and add all the sides of the bigger triangle

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Answer:  [tex]\textsf{y = 4x - 12}[/tex]

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Given: [tex]\textsf{Slope = 4, Point = (2, -4)}[/tex]

Find:  [tex]\textsf{The equation in slope-intercept form}[/tex]

Solution: We need to plug in the values into point-slope form and after simplifying, distributing, and solving for y we will have our equation in slope-intercept form.

Plug in the values

Distribute and simplify

Subtract 4 from both sides

Using the information that was provided in the problem statement we were able to determine that the equation in slope-intercept form was y = 4x - 12.

Answer:

y = 4x - 12

Step-by-step explanation:

Given:

slope of 4, and point (2, -4)

Here, we're being asked to write the equation in Slope-Intercept Form. As we have been given the slope and a point on the line, we can use the Point-Slope Form to be able to find that equation.

First, know the two forms:

⇒ Point-Slope Form: y - y₁ = m(x - x₁)

where: m is the slope, and (x₁, y₁) is the given point

⇒ Slope-Intercept Form: y = mx + b

where: m is the slope, and b is the y-intercept

Now, substitute the given values into the Point-Slope Form:

⇒ y - y₁ = m(x - x₁)

⇒ y - (-4) = 4(x - 2) [simplify]

⇒ y + 4 = 4x - 8

Change to the Slope-Intercept Form:

⇒ y + 4 = 4x - 8 [subtract 4 from both sides]

⇒ y + 4 - 4 = 4x - 8 - 4

⇒ y = 4x - 12

Therefore, the equation of the line in slope-intercept form is: y = 4x - 12

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Amount of Tax = (Original Cost)(Tax %) , Option C is the right answer.

The complete question is

Most everyday purchases at the store are labeled with the price of the item before sales tax. Which expression could be used to find the amount of tax? Amount of Tax = Original Price + Total Cost Amount of Tax = (Total Cost)(Original Price) Amount of Tax = (Original Cost)(Tax %) Amount of Tax = (Total Cost)(Tax %)

Tax is the % of the amount taken by the government on the sales or income of a person , There are many kinds of taxes imposed on various sectors.

The amount of tax is taken on the cost of the product ans thus can be represented by

Amount of Tax = (Original Cost)(Tax %) , Option C is the right answer.

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Answer: 9 cm

Step-by-step explanation:

The formula for the perimeter of a rectangle is [tex]2l+2w=P[/tex]

Where

l is the length

w is the width

and P is the perimeter (34)

Because the length is 1 cm longer than the width instead of representing the length is l we can use w+1

Sub in the known values and solve

Step 1: Simplify both sides of the equation with the Distributive Property

[tex]2(w+1)+2w=34\\(2)(w)+(2)(1)+2w=34\\2w+2+2w=34\\(2w+2w)+(2)=34\\4w+2=34\\[/tex]

Step 2: Subtract 2 from both sides.

[tex]4w+2-2=34-2\\4w=32[/tex]

Step 3: Divide both sides by 4.

[tex]\frac{4w}{4}=\frac{32}{4} \\w=8[/tex]

Step 4: Add 1 to w to find the length of the longer side

[tex]w+1\\8+1\\9[/tex]

By solving y = 25 · x² - 100 through the square root method, we conclude that the two roots of the quadratic formula are y₁ = + 2 and y₂ = - 2.

Herein we have a polynomials of the form y = a · x² - b. By algebra we find that two roots exists, which are described below according to the square root method:

[tex]y_{1} = +\sqrt{\frac{b}{a} }[/tex], [tex]y_{2} = -\sqrt{\frac{b}{a} }[/tex]

If we know that a = 25 and b = 100, then the two roots of the equation are:

y₁ = + 2, y₂ = - 2

By solving y = 25 · x² - 100 through the square root method, we conclude that the two roots of the quadratic formula are y₁ = + 2 and y₂ = - 2.

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T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

[tex]\left[\begin{array}{ccc}7&6\\4&5\end{array}\right][/tex]

The inverse of the matrix is

[tex]\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right][/tex]

So, the Inverse Transformation is given by

[tex]T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})[/tex]

So, no option is correct. And the answer is

[tex]T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})[/tex]

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Answer:

Step-by-step explanation:

Answer:

1.4y

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

Answer:

2: no

3: no

4: no

5: yes

6: no

8: no

9: no

10: no

11: yes

Step-by-step explanation:

there are some simple divisibility rules that we can utilize here:

a number is divisible by __ if...

2: ends in [last digit] 0, 2, 4, 6, 8

so 275 is not divisible by 2

3: sum of digits is 3

2 + 7 + 5 = 14 [14 is not divisible by 3]

so 275 is not divisible by 3

4: last two digits are divisible by 4

75 is not divisible by 4

so 275 is not divisible by 4

5: last digit is 0 or 5

so 275 is divisible by 5

6: number is divisible by both 2 and 3

we know that 175 is not divisible by 2 or 3, so 275 is not divisble by 6

8: last three digits are divisible by 8

>> we also know that any number that 8 goes into, 4 also goes into [not always the other way around], meaning that because 175 is not divisible by 4, it must not be divisible by 8

so, 275 is not divisible by 8

9: sum of digits is divisible by 9

>> we also know that 9 only can go into numbers that 3 can go into, so because 175 is not divisible by 3, it must not be divisible by 9

so, 275 is not divisible by 9

10: last digit is 0

so, 275 is not divisible by 10

11 is a bit complicated:

sum of digit in odd places and sum of digit in even places has a difference is divisible by 11 [or is 0]

2 7 5

odd places: 2, 5 (2 + 5 = 7)

even places: 7 (7 = 7)

difference between 7 and 7 is 0 (7-7 = 0),

so, 275 is divisible by 11

hope this helps!! :)

Answer: Option (1)

Step-by-step explanation:

The domain is the set of input values, also known as the set of x-values.

Answer:

10

Step-by-step explanation:

First, divide 192 by 12, you get a unit rate of Rs. 16 per egg, then divide Rs. 160 by 16 and you get 10

The number of eggs that can be purchased at Rs. 160 is 10.

The division operator ( / ) has the quotient of its operands where the left operand exists the dividend and the right operand exists the divisor.

The cost of 12 eggs = Rs. 192

The cost of 1 egg = 192/12 = Rs. 16.

The number of eggs that can be purchased is Rs. 160 = 160/16 = 10.

Therefore, the number of eggs that can be purchased at Rs. 160 is 10.

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The value of t is 6.65

An exponential function is a mathematical function of the following form: f ( x ) = a^x. where x is a variable, and a is a constant called the base of the function.

Given:

A= 210 million

P= A e^(kt)

225 = 210 * e ^ (0.0069t)

225/210=  e ^ (0.0069t)

1.07 =  e ^ (0.0069t)

Taking log on both side

log  1.047 = 0.0069 t log e

[tex]\frac{0.0069t\ln \left(e\right)}{0.0069\ln \left(e\right)}=\frac{\ln \left(1.047\right)}{0.0069\ln \left(e\right)}[/tex]

t= log ( 1.047) / 0.0069

t= 6.65

Hence, value of t is 6.65.

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Answer:

Step-by-step explanation:

Answer: [tex]35^{\circ}[/tex]

Step-by-step explanation:

Angles ACB and DCA add to form angle ACB, which is a right angle, so:

So, [tex]m\angle ACB=6(7)-7=\boxed{35^{\circ}}[/tex]

Answer:

1/2

Step-by-step explanation:

(Is this the question? In the pic above)

Sin of an angle os the side opposite over it divided by the hypotenuse.

Sin = opposite/hypotenuse

Sin = 5/10

Sin = 1/2

Answer:

from the image above

Triangle ABE = Triangle ADE

AE = AE ( common).

angle AEB = angle AEO ( each 90°)

AB = AD ( given).

by side angle side criteria

so area of ABE = area of ADE

similarly,

BC = DC ( given)

BEC = DEC ( 90°)

EC = EC ( 9m each)

so area of BEC = Area of DEC

Answer:

y = 97°

Explanation:

Opposite angles in a quadrilateral inscribed in a circle sum ups to 180°

So following the rule:

A + C = 180°

y + 83° = 180°

y = 180° - 83°

y = 97°

This chart represents a proportional relationship. The rate of change will be 4.

Firstly, there is a proportional relationship.

Two values x  and y are said to be in a proportional relationship if x=ky, where x and y are variables and k is a constant.

The constant k is called the constant of proportionality.

Given;

x y

1 4

2 8

3 12

4 16

Here, x = ky

put the first value

k = 1/4

This chart represents a proportional relationship.

So the rate of change will be

[tex]Rate = \dfrac{y_2 - y_1}{x_2 - x_1}\\\\Rate = \dfrac{8 - 4}{2 - 1}\\\\Rate = 4[/tex]

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Answer:

[tex]x = 45 \sqrt{5} [/tex]

Step-by-step explanation:

[tex] {3}^{2 log_{3}(x) + log_{3}(5) } = {3}^{ 4log_{3}(15) } [/tex]

[tex] {3}^{ log_{3}( {x}^{2} ) } {3}^{ log_{3}(5) } = {3}^{ log_{3}( {15}^{4} ) } [/tex]

[tex]5 {x}^{2} = {15}^{4} [/tex]

[tex] {x}^{2} = \frac{ {15}^{4} }{5} [/tex]

[tex]x = \frac{ {15}^{2} }{ \sqrt{5} } ( \frac{ \sqrt{5} }{ \sqrt{5} } )[/tex]

[tex]x = \frac{ {15}^{2} \sqrt{5} }{5} = 45 \sqrt{5} [/tex]

Each given factor written as a polynomial in descending order is;  (7x + 6y)(49x² - 42xy + 36y²)

We are given the polynomial;

343x³ + 216y³

343x³ + 216y³ is a sum of cubes and factors in general as;

a³ + b³ = (a + b)(a² - ab + b²)

Thus;

343x³ + 216y³ = (7x)³ + (6y)³

= (7x + 6y)((7x)² - 7x(6y) + (6y)² )

= (7x + 6y)(49x² - 42xy + 36y²)

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Answer:

1/3×22/7×r^2h

Step-by-step explanation:

the volume =1/3 ×22/7×r^2×13.5

Answer:

15 sqrt a ^4

Step-by-step explanation:

The given expression can be simplified as [tex]96x^{9}+3x^{36} +3[/tex].

The given expression is [tex]6x^{9} (7-3).4+3x^{36} +3[/tex].

We need to simplify the given expression.

In mathematics, an algebraic expression is an expression built up from integer constants, variables, and algebraic operations.

First, multiply the numbers 6×4=24.

That is, [tex]24x^{9} (7-3)+3x^{36} +3[/tex].

Next, subtract the numbers 7-3=4.

[tex]24x^{9}.4+3x^{36} +3[/tex]

Finally, multiply the numbers 24×4=96.

[tex]96x^{9}+3x^{36} +3[/tex].

Hence, the given expression can be simplified as [tex]96x^{9}+3x^{36} +3[/tex].

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Answer:

4:5

girls:boys

16:20

divide both by 4

4:5

The correct answer is option D which is the function is even because of its symmetry about the y-axis.

The function which remains unchanged when the negative value of the variable is filled in the function is called an even function and this function is symmetric about the y-axis.

Given function:-

f(x) = 3x⁴+2x²

Now put the value x = -x in the function

f(-x) = 3( -x⁴)+2(-x²)

f(-x) = 3x⁴ + 2x²

f(-x) = f(x)

here we can see that when we put the value of negative x the function remains unchanged.

Therefore the correct answer is option D which is the function is even because of its symmetry about the y-axis.

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Option third "He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x², –x, –6x, and 6' is correct.

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have a quadratic expression to model the area of the rectangle:

= x² – 7x + 6

[tex]\rm =\left(x^2-x\right)+\left(-6x+6\right)[/tex]

[tex]=\rm x\left(x-1\right)-6\left(x-1\right)[/tex]

= (x - 1)(x - 6)

Thus, option third "He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x², –x, –6x, and 6' is correct.

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Answer:

B

Step-by-step explanation:

using the addition identity for sine

sin(A + B) = sinAcosB + cosAsinB

using the sine and cosine ratios in the right triangle

sinABC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{4}{5}[/tex]

cosABC = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{3}{5}[/tex]

using the exact values

sin60° = [tex]\frac{\sqrt{3} }{2}[/tex] , cos60° = [tex]\frac{1}{2}[/tex]

Then

sin(ABC + 60)

= sinABC cos60 + cosABC sin60

= ( [tex]\frac{4}{5}[/tex] × [tex]\frac{1}{2}[/tex] ) + ([tex]\frac{3}{5}[/tex] × [tex]\frac{\sqrt{3} }{2}[/tex] )

= [tex]\frac{4}{10}[/tex] + [tex]\frac{3}{10}[/tex] [tex]\sqrt{3}[/tex]

= [tex]\frac{2}{5}[/tex] + [tex]\frac{3}{10}[/tex] [tex]\sqrt{3}[/tex]

sin<ABc

cos<ABC

Now

By the binomial theorem,

[tex]\displaystyle \left(x^2 + \frac px\right)^6 = \sum_{n=0}^6 \binom 6n \left(x^2\right)^n \left(\frac px\right)^{6-n} = \sum_{n=0}^6 p^{6-n} \binom 6n x^{3n-6}[/tex]

where

[tex]\dbinom kn = \dfrac{k!}{n!(k-n)!}[/tex]

is the so-called binomial coefficient.

The term that's independent of x is the constant term, which occurs when [tex]3n-6=0[/tex], or [tex]n=2[/tex]. Given that this constant 240, we have

[tex]p^{6-2} \dbinom62 = 240 \implies p^4 = 16 \implies p = \pm2[/tex]

but [tex]p[/tex] must be positive, so [tex]\boxed{p=2}[/tex]