Hope this helps.
Good luck ✅.
In the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaningful in a(n) _____ scale.\
In the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaningful interval scale.
What is an interval scale?It should be noted that an interval scale means a measurement where the difference between the variables is meaningful and equal.
In this case, in the context of variables and measurement scales, the magnitude of the differences between the numbers on the scale is meaningful interval scale.
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A lab technician needs to clean medical instruments that have been exposed to bacteria. which electromagnetic wave would be most useful for this task? infrared radio ultraviolet microwave
The ultraviolet electromagnetic wave would be most useful for this task.
UV radiation is a well-known method for repressing bacteria that has certain advantages over liquid disinfectants because it may be used to clean surfaces, liquids, the air, and rooms while also operating autonomously and remotely.The disinfection of surface DNA, RNA, and bacteria is accomplished with UV light. Up to 99 percent of surface contamination is removed from research tools, containers, and other items using the UV Clave chamber's highly targeted UV irradiation. Medical instruments that are exposed to bacteria should be cleaned with UV light to remove the bacteria.Microbes are killed or made inactive by UV-C radiation by destroying their deoxyribonucleic acid (DNA).infrared microwave and radio waves will not be effective in removing the contamination and bacteria.
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Answer: Ultraviolet
Explanation: got it right on edge
A single-instance deployment of splunk enterprise handles:
A single-instance deployment of splunk enterprise handles; Indexing, Parsing, Input and Searching.
What is splunk enterprise?Splunk Enterprise collects data from any source, including metrics, logs, stream network traffic, web servers, custom applications, social media and cloud services.
Functions of single-instance deployment of splunk enterpriseThe following are the main functions;
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Note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. a 0.4-m3 rigid tank contains refrigerant-134a initially at 160 kpa and 40 percent quality. heat is now transferred to the refrigerant until the pressure reaches 600 kpa. note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. determine the amount of heat transferred. (please provide an answer before moving on to the next part.)
Based on the calculations, the amount of heat transferred is equal to 2,317 kJ.
Given the following data:
Volume of tank = 0.4 m³.
Initial pressure = 160 kPa.
Final pressure = 600 kPa.
Initial quality, x = 40% = 0.4
How to calculate the amount of heat transferred?From the superheat table A-12, the specific volumes of the saturated liquid and vapor at 160 kPa are:
Vf(160 kPa) = 0.0007437 m³/kg. Vg(160 kPa) = 0.12348 m³/kg.Next, we would determine the initial specific volume by using this formula:
V₁ = (1 - x)Vf + xVg
V₁ = (1 - 0.4)0.0007437 + (0.4)0.12348
V₁ = 0.049838 m³/kg.
Also, we would find the mass of this refrigerant at the initial state by using this equation:
m = V/V₁
m = 0.4/0.049838
Mass, m = 8.03 kg.
From the superheat table A-12, the internal energy of the saturated liquid and vapor at 160 kPa are:
Uf(160 kPa) = 31.09 kJ/kg. Ug(160 kPa) = 221.35 kJ/kg.At the initial state, we would find U₁ from the quality:
U₁ = (1 - x)Uf + xUg
U₁ = (1 - 0.4)31.09 + (0.4)221.35
U₁ = 107.19 kJ/kg.
From the superheat table A-13, the final specific volume and internal energy of the saturated liquid and vapor at 600 kPa are:
Vf = 0.057006 m³/kg.Uf = 367.81 kJ/kg.At the final state, we would find U₂ by extrapolating with the last two points in the table:
[tex]U_2 = 357.96 + (\frac{367.81 \; - \; 357.96}{0.057006\;-\;0.055522}) \times (0.049838\;-\;0.055522)\\\\U_2 = 357.96 + (\frac{9.85}{0.001484}) \times (-0.005684)\\\\U_2 = 357.96 + 37.73\\\\[/tex]
U₂ = 395.69 kJ/kg.
Now, we can calculate the amount of heat transferred:
Q = m(U₂ - U₁)
Q = 8.03(395.69 - 107.19)
Q = 8.03(288.5)
Q = 2,316.66 ≈ 2,317 kJ.
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In a Laundromat, during the spin-dry cycle of a washer, the rotating tub goes from rest to its maximum angular speed of 8.70 rev/s in 6.80 s. You lift the lid of the washer the instant the angular speed reaches the maximum value, and notice that the tub decelerates and comes to a stop in 19.0 s. Assuming that the tub rotates with constant angular acceleration while it is starting and stopping, determine the total number of revolutions undergone by the tub during this entire time interval.
Since we assume the accelerations are constant, the instantaneous acceleration is the same as the average acceleration, so in the first 6.80 seconds we have
[tex]\alpha_1 = \alpha_{\rm ave} = \dfrac{\Delta \omega}{\Delta t} = \dfrac{8.70\frac{\rm rev}{\rm s}}{6.80\,\rm s} \approx 1.28 \dfrac{\rm rev}{\mathrm s^2}[/tex]
In this time, the tub undergoes an angular displacement of
[tex]\theta_1 = \dfrac12 \alpha_1 (6.80\,\mathrm s)^2 \approx 29.6\,\mathrm{rev}[/tex]
In the next 19.0 seconds the tub has acceleration
[tex]\alpha_2 = \dfrac{-8.70\frac{\rm rev}{\rm s}}{19.0\,\rm s} \approx -0.458 \dfrac{\rm rev}{\mathrm s^2}[/tex]
and in this time, the tube undergoes an additional displacement of
[tex]\theta_2 = \left(8.70\dfrac{\rm m}{\rm s}\right)(19.0\,\mathrm s) + \dfrac12 \alpha_2 (19.0\,\mathrm s)^2 \approx 82.7\,\mathrm{rev}[/tex]
So the tub completes [tex]\theta_1+\theta_2 \approx \boxed{112\,\mathrm{rev}}[/tex].
which type of radio active decays
What is the magnitude of the magnetic dipole moment of the bar magnet
The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²
Magnetic dipole moment of the bar magnet
The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;
[tex]B = \frac{2\mu_0m}{4\pi r^3} \\\\m = \frac{4\pi r^3 B}{2\mu_0}[/tex]
where;
B is magnetic fieldm is dipole momentμ is permeability of free spacem = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)
m = 1.2 Am²
The complete question is below:
What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.
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Differences between freezing point and melting point (Atleast 5 differences)
Answer:
What is freezing point?
A liquid's freezing point is determined at which it turns into a solid. Corresponding to the melting point, the freezing point often rises with increasing pressure. In the case of combinations and for some organic substances, such as lipids, the freezing point is lower than the melting point. The first solid which develops when a combination freezes often differs in composition from the liquid, and the development of the solid alters the composition of the remaining liquid, typically lowering the freezing point gradually. Utilizing successive melting and freezing to gradually separate the components, this approach is used to purify mixtures.
What is melting point?
The temperature at which a purified substance's solid and liquid phases may coexist in equilibrium is referred to as the melting point. A solid's temperature goes up when heat is added to it until the melting point is achieved. The solid will then turn into a liquid with further heating without changing temperature. Additional heat will raise the temperature of the liquid once all of the solid has melted. It is possible to recognize pure compounds and elements by their distinctive melting temperature, which is a characteristic number.
The difference between freezing point and melting point:
While a substance's melting point develops when it transforms from a solid to a liquid, a substance's freezing point happens when a liquid transforms into a solid when the heat from the substance is removed.When the temperature rises, the melting point can be seen, and when the temperature falls, the freezing point can be seen.When a solid reaches its melting point, its volume increases; meanwhile, when a liquid reaches its freezing point, its volume decreases.While a substance's freezing point is not thought of as a distinctive attribute, its melting point is.While external pressure is a significant component in freezing point, atmospheric pressure is a significant element in melting point.Heat must be supplied from an outside source in order to reach the melting point for such a state shift. When a material is at its freezing point, heat is needed to remove it from the substance in order to alter its condition.Reference: Berry, R. Stephen. "When the melting and freezing points are not the same." Scientific American 263.2 (1990): 68-75.
hello i need help with this!!
Answer:
Yes
Explanation:
If lamp A burnt out there would still be a wire above it that connects lamp B and C to the power source
A transformer has two coils. Coil A has 75 turns and coil B has 100 turns. In the first instance, coil A is used as the primary coil, which is connected to an ac current source. As a result, the peak voltage of the secondary coil, B, has a value VP. Then, coil B is used as the primary coil and coil A becomes the secondary coil. The ac current source is then adjusted to deliver the same current to coil B as it did to coil A in the first instance. For this case, how does the peak voltage of the secondary coil, A, compare with VP.
The peak voltage based on the information given will be 1.33V.
How to calculate the voltage?From the information given, Coil A has 75 turns and coil B has 100 turns.
The voltage will be:
IVa = IVb
We will then substitute the values. c
V = 100/75
V = 1.33V
Therefore, the peak voltage based on the information given will be 1.33V.
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help pleaaase!!
A train leaves the station from rest and travels along a straight track. if the train is 500 meters from the station when it reaches a velocity of 50m/s what is the acceleration of the train?
Answer:
[tex]2.5m/s^{2}[/tex]
Explanation:
Since the distance ,s = 500m
Initial velocity, u = 0m/s
Final velocity, v = 50m/s
We can one of the kinematics equations to find the acceleration.
[tex]v^{2} =u^{2} +2as\\50^{2} =0^{2} + 2a(500)\\2500 = 0 + 1000a\\1000a = 2500\\a = \frac{2500}{1000} \\= 2.5m/s^{2}[/tex]
Answer:
S=D÷T
Explanation:
50=0.5÷T
T= 100
Which of the following is an example of an electromagnetic wave?
Sound
Ocean waves
Seismic waves
Red light
Answer:
red light light is an electromagnetic wave thats whyy
hope it helped
Explanation:
A crate is pulled with a force of 165 N at an angle 30 ° northwest. What is the resultant horizontal force on the crate?
Answer:
Resultant horizontal force = 143 N
Explanation:
Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;
Resultant horizontal force = 165 * cos 30
Resultant horizontal force = 142.89
Approximating to a whole number gives;
Resultant horizontal force = 143 N
A cylindrical metal bar of diameter 14cm and length 484 cm is to be melted to make a metalic cube.if one side of the box is 220mm,how many boxes were produced?
The number of boxes were produced willl be 7.57.n stands for the no of boxes.
What is volume?The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.
The volume of the cylindrical metal bar;
V₁=πr²h
V₁=3.4 × 7² × 484 cm
V₁=80,634.4 cm³
The one side of the box is,220mm(22 cm)
V₂ = a³
V₂ = (22)³
V₂ = 10,648 cm³
The no of boxes is found as;
n = V₁/V₂
n=80,634.4 cm³/10,648 cm³
n=7.57
Hence, the number of boxes were produced willl be 7.57
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Kinetic energy of a body is increased by by 300% what is percentage increased in momentum
Answer
100% - double
200% - triple
300% - 4X
For a 300% increase the KE must be 4 time as large
KE2 / KE1 = M V2^2 / M V1^2 = (V1 / V2)^2 = 4
So V2 = 2 V1 for the requested increase
M V2 / M V1 = V2 / V1 = 2
So the momentum would double for a 100% increase
Friction is a ____________ force
a. Artificial
b. Natural
c. Pessimistic
d. Negative
Answer:
natural is the answer
Friction is a natural force which exist
How much heat is needed to raise the temperature of 100.0 g of water by 85.0°C ? A. 8,500 J 35,500 J B. C. 1.1 J
The quantity of heat required to raise the temperature of the water is approximately 35,500 J.
Heat required to raise the temperature of water
The quantity of heat required to raise the temperature of the water is calculated as follows;
H = mcΔθ
H = 100 x 4.18 x 85
H = 35,530 J
Thus, the quantity of heat required to raise the temperature of the water is approximately 35,500 J.
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forces if magnitude 2,5 and 4 units lie in the direction 45°,90° and 135° respectively. Find: A. the magnitude. B. the direction of their resultant
A. The magnitude is 9.47N
B. The direction of the resultant force is 90°
We use vectors in answering this question.
F₁ = 2N 45°
F₂ = 5N 90°
F₃ = 4N. 135°
For the magnitude, we use vector addition twice
Consider forces F₁ and F₃
Notice that F₁ and F₃ are at right angles to each otherUsing vector summation, the net forces of F₁ and F₃ say F₀ is the square root of the summation of the squares of F₁ and F₃F₀ = 4.47N
Since F₁ and F₃ are at 45° and 135° respectively, their net force F₀ is at 90°, along the line of F₂
Fnet = F₀ + F₂ = 4.47 + 5 = 9.47N
A. The magnitude is 9.47N
B. The direction of the resultant force is 90°
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Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is________________. the same. greatest to the left of the charge. greatest below the charge. greatest to the right of the charge. greatest above the charge.
Electric field strength decreases as the distance from the source increases.
How the distance from the charge affects the magnitude of the electric field?The strength of an electric field is inversely related to square of the distance from the source. This means that the electric field strength decreases when the distance from the source increases.
So we can conclude that Electric field strength decreases as the distance from the source increases.
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3. in adlerian therapy, clients learn how core beliefs that have been helpful in the past might not work well now and then to put that understanding to use in the real world. what therapeutic process is referred to jim to overcome his core beliefs and move forward? as a counselor, how do you make him understand?
Adlerian therapy is a method in which a therapist collaborates with a client to pinpoint challenges and develop successful solutions for achieving their objectives.
Key Takeaways: Adlerian Therapy
Individual therapy, often known as Adlerian therapy, places an emphasis on the patient's capacity to effect good change in his or her own life.
Adlerian therapy consists of four stages: engagement, assessment, insight, and reorientation.
In Adler’s theory, individuals work to overcome feelings of inferiority and to act in ways that benefit the social interest.
Four Stages of Adlerian Therapy :
Engagement
Assessment
Insight
Reorientation
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Water flows through a pipe. The diameter of the pipe at point b is larger than at point a. Where is the water pressure greatest?.
The water pressure is greatest at point B which has a larger diameter in this scenario.
What is Pressure?This is defined as the force per unit area of a substance with its unit being Pascal.
The larger diameter will have more force acting on the sides which translates to a greater pressure.
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when you rub neutral objects
electrons can be knocked loose from one object and picked up by the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.
b gained electrons
A plane is coming in to taxi at an airport. It lands parallel to the surface at 480m/s and takes exactly one minute to come to a complete stop. What is its acceleration?
The acceleration of the plane will be −8 m/s²
How to find the acceleration of a plane?
Acceleration is the rate of change in velocity over time (Δv/t).
Given, that the initial velocity of the plane u=480 m/s
The final velocity of the plane is zero after landing, v= 0 m/s
t= 1 minute= 60 seconds
we know, v=u + at
0= 480 + 60a
a=[tex]\frac{-480}{60}[/tex] = -8m/s²
Thus, the acceleration of the plane is -8 m/s²
(negative acceleration implies that the object is slowing down)
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Gravity is the attractive pull between two objects that have mass. The strength of the gravitational distance. As distance between the objects increases, the force of gravity decreases. If the distance
one-fourth as strong as before. Which one of the graphs best represents the relationship between
pull is doubled,
gravity and distance. depends
on mass and the force of gravity is
A. A
B. B
C. C
D. D
Sorry for the bad picture right now i dont have to take a nice picture
Graph A best represents the relationship between pull is doubled, gravity and distance. depends on the mass and the force of gravity. Option A is correct.
What is Newton's law of gravity?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
The expression for the gravitational force is given as;
[tex]\rm F = G\frac{Mm}{r^2}[/tex]
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
Decreasing the distance would increase the gravity of the planet.
Gravity is the attraction force that draws two mass-containing objects together. the gravitational distance's strength.
The force of gravity weakens as the distance between the items rises. if the separation is just one-fourth as great as previously. In the graph, the link between pull and doubled is best represented by A.
Hence option A is correct.
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Please help me! Uniform acceleration problem sheet:
In 1997, the thrust SSC, a turbofan powerd vehicle, acheive the land speed world record of 780.34 mph (1,223.65km/h) and became the first car to break the sound barrier. If it tool 1 minute for the thrust SSC to reach its top speed, what was the average acceleration during the time?
From the calculation, the value of the acceleration is 5.8 m/s^2.
What is uniform acceleration?The term uniform acceleration refers to a situation in which the velocity increases by equal amounts in equal time intervals.
Given the fact that the car started from rest and reached a velocity of 780.34 mph or 348.84 m/s in 1 minute of 60 seconds;
v = u + at
a = v/t
a = 348.84 m/s/ 60 seconds
a = 5.8 m/s^2
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A circuit consists of three resistors and a 3.50 V battery. Two of the resistors have known resistances of 5 Ω and 10 Ω respectively. The third resistor has an unknown resistance. When the battery is connected to the circuit, the current running through the battery is measured to be 10 A.
a. Calculate the resistance of the unknown resistor.
b. Draw the circuit and label each component.
The resistance of the unknown resistor is determined as 0.39 ohms.
Equivalent resistance of the circuitThe total resistance of the circuit is calculated as follows;
V = IR
R = V/I
R = (3.5)/10
R = 0.35 ohms
The resistors are in parallel arrangement
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/0.35 = 1/5 + 1/10 + 1/R₃
100/35 = 3/10 + 1/R₃
20/7 = 3/10 + 1/R₃
1/R₃ = 20/7 - 3/10
1/R₃ = (200 - 21)/70
1/R₃ = 179/70
R₃ = 70/179
R₃ = 0.39 ohms
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A car of mass 750 kg accelerates away from traffic lights. At the end of the first 100 m it has reached a speed
of 12 m/s. During this time, its engine provides an average forward force of 780 N, and the average force of
friction on the car is 240 N.
a Calculate the work done on the car by the force of its engine.
b Calculate the work done on the car by the force of friction.
c Using ke. = mv2, calculate the increase in the car's kinetic energy at the end of the first 100 m.
d Explain whether your answers are consistent with the principle of conservation of energy.
the work done on the car by the force of its engine is 78,000 J.
" The work done on the car by the force of friction is 24,000 J.
Increasing the car's kinetic energy at the end of the first 100 m is 54,000J
a. Completed work = force x distance. Engine output = 780 N, that is,
780 N x 100 m = 78,000 J.
b. Completed work = force x distance. Friction force = 240 N, that is,
240 N x 100 m = 24,000 J.
c. Kinetic energy = 1 \ 2 x m x v2
= 1 \ 2 x 750 kg x 12 squared = 375 x 144 = 54,000 J.
How powerful is the engine of a car?Mainstream car and truck engines typically produce 100-400 pounds. -Torque feet. This torque is generated by the engine piston as it moves up and down on the engine crankshaft, causing the engine to rotate (or twist) continuously.
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What is the difference between a conductor and an insulator?
Select one:
O a. An insulator transfers thermal energy while a conductor does not. Insulators do not
allow thermal energy to move through them.
Ob.
A conductor transfers thermal energy while an insulator does not.
O c.
Both conductors and insulators transfer thermal energy, but not electrical energy.
One of them does not transfer energy.
O d. Both conductors and insulators transfer electrical energy, but not thermal energy.
Answer:
b
Explanation:
An insulator does not transfer thermal or electrical energy but a conductor does
Particles q1 = +8.0 uC, q2 = +3.5 uC, and
93 = -2.5 uC are in a line. Particles q1 and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q2?
Answer:
11.1845088571 N
Explanation:
F = k(q1q2)/(d^2)
An electric motor rated 2.5kw is used to lift bales of hay to a store in a dairy farm. A single bale has a mass of 5kg. If the store is 4 meters above the ground, how many bales can the motor raise in 2 minutes.