Answer:
Follows are the solution to this question:
Explanation:
Its difference in power supply will be smaller whenever the pressure transducer is being performed. Its transducer sensitivity(s) is often used to calculate its number of changes occurring at voltage output of ([tex]v_o[/tex]) when the supply tension ([tex]v_s[/tex]) changes with the measured pressure ([tex]p_m[/tex]) and the rated tension of transducers ([tex]p_s[/tex]).
[tex]v_o= (s) V_s (\frac{P_m}{P_s})[/tex]
Water flows steadily through a 3.28-in-diameter pipe and discharges through a 1.64-in-diameter nozzle to atmospheric pressure. The flow rate is 26.5 gpm. (a) Calculate the minimum static pressure required in the pipe to produce this flow rate. (b) Evaluate the axial force of the nozzle assembly on the pipe flange.
Answer:
A) 61.628 Ib/ft^2
B) 3.271 Ibf
Explanation:
diameter of pipe = 3.28 inches
diameter of nozzle = 1.64 inches
flow rate = 26.5 gpm =
convert the flow rate to ft^3/s
= 26.5 gpm * 0.133681 ft^3/gallons * 1 min/ 60 seconds
= 0.059 ft^3/s
next we calculate the velocity in the pipe
Q = [tex]\frac{\pi }{4} d^{2} _{1} V1[/tex]
Q = 0.059
d1 = (3.28 / 12 )
hence V1 = ( 0.059 ) / (0.0747 * 0.7854 ) = 1 .01 ft/s
velocity in the Nozzle
Q = [tex]\frac{\pi }{4} d^{2} _{2} V2[/tex]
Q = 0.059
d2 = ( 1.64 /12 )
hence V2 = ( 0.059 ) / ( 0.7854 * 0.0187 ) = 4.02 ft/s
A) To determine the Minimum static pressure we apply the Bernoulli's equation
since the pipe and the Nozzle are at the same height the equation will be modified as
[tex]\frac{P1}{w} + \frac{V^2_{1} }{2g} = \frac{P2}{w} + \frac{v_{2} ^2}{2g}[/tex]
where w = 62.4 Ib/ft^3
V1 = 1.01
V2 = 4.02
P1 = ?
P2 = 0
g = 9.81
hence P1 ( static pressure ) = 62.4 * 0.772 = 61.628 Ib/ft^2
B) evaluate the axial force of the Nozzle assembly on the pipe flange
attached below is the detailed solution
Fx( axial force ) = -0.345 + 3.616 = 3.271 Ibf
A pequin walks 10 feet in six second how far does the pequin wals in 45 seconds
Answer:
7.5 feet
Explanation:
45 divided by 6 is 7.5
Answer:
7.5 feet
Explanation:
45 divided by 6 is 7.5
Pls help!!! will give brainly!!!
Bridge collapses have hit the news recently with more frequency. Do some research online and state two possible reasons for these collapses. How might those employed in the Health, Safety, & Environmental Management pathway help prevent these collapses and keep us safe?
Answer:
The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.
Explanation:
hope this helps
A commercial grade cubical freezer, 3 m on a side, has a composite wall consisting of an exterior sheet of 6.35-mm-thick plain carbon steel, an intermediate layer of 100-mm-thick cork insulation, and an inner sheet of 6.35-mm-thick aluminum alloy (2024). Adhesive interfaces between the insulation and the metallic strips are each characterized by a thermal contact resistance of = 2.5 x 10–4 m3 · K / W. What is the steady-state cooling load that must be maintained by the refrigerator under conditions for which the outer and inner surface temperatures are 22°C and −6°C, respectively?
Answer:
589.5 W
Explanation:
Given that
the thickness of the carbon steel and insulation is L(a) = L(c) = 0.00635 m
Width of the freezer, W = 3m
Thermal contact resistance, R(t.c) = 0.00025 m²
T(s.i) = -6°C = 267 K
T(s.o) = 22°C = 295 K
See attachment for calculation
What type of engineer construct the infrastructure necessary for roads air fields and water ports a construction engineer be environmental engineer see structural engineer D transportation engineer
Answer:
Construction engineers often focus on a specific type of construction project. Some of these specialties are: Building - commercial housing or business building. Electrical - electrical systems. Mechanical - plumbing, heating or air conditioning. Highway or Heavy - bridges, airports, highways or water waste.
Explanation:
Determine the maximum slope and maximum deflection of the simply supported beam subjected the moment M0. Assu
Answer:
hello your question is incomplete attached below is the complete question
Explanation:
attached below is the detailed solution
Taking into account that EI is constant and the Beam is made out of a single uniform material which is prismatic
The amount of FORCE that moves electrons is measured in
Which statement best explains why pneumatic cylinders need to be smaller than hydraulic cylinders?
The pneumatic system only needs enough room to have an onloff switch installed in order to operate correctly.
The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency
The control of the hydraulic system is much more precise and therefore requires a larger cylinder.
The fluid in a hydraulic system has more mass and therefore needs more storage space.
Answer:
The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency.
Explanation:
I did it on edge and got it right.
Answer:
The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency
Thanks for points!!! :D
_____________ processes are actions that create physical solutions to problems.
a
Production Processes
b
Medical Processes
c
Agricultural Processes
d
Communication Process
Answer:
yes answer d is correct
Communication Process are actions that create physical solutions to problems. The correct option is d.
What is Communication Process?Human existence and organisational survival both depend on effective communication. It is a process of generating and disseminating thoughts, facts, opinions, and sentiments from one place, individual, or group to another. The Management function of Directing depends on effective communication.
The sending party, message encoding, channel selection, message receipt by the recipient, and message decoding are all aspects of the communication process.
Feedback is when the recipient communicates something back to the original sender. These procedures are actions that result in tangible fixes for issues.
Thus, the correct option is d.
For more details regarding communication process, visit:
https://brainly.com/question/15281884
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what is the dimensions of beta
Answer:
byee byee bbbbbbbbbbbb
Seth wants to build a wall of bricks. Which equipment will help him in the process?
OA masonry pump
OB. hacksaw
OC. mortar mixer
OD. pressurized cleaning equipment
You have designed a bridge beam with an I of 1000 in4 and estimate a maximum deflection of 4 inches. In order to reduce the maximum deflection to 3.1 inches, you must increase I to ________ in4
Answer:
1290.32 In⁴
Explanation:
∆ = wL⁴/384EI
∆ is directly proportional to 1/I
∆1/∆2 = i2/i1
We have
∆1 = 4 inches
∆2 = 3.1 inches
i1 = 1000
i2 is unknown
So when we insert these values into the formula we have:
4/3.1 = i2/1000
From here we cross multiply
4x1000 = 3.1(i2)
4000 = 3.1(i2)
Divide through by 3.1
= 4000/3.1 = i2
= 1290.32 in⁴
i2 = 1290.32 in⁴
So, In order to reduce the maximum deflection to 3.1 inches, you must increase I to 1290.32 in⁴
The proportioning of a concrete mixture has resulted in the following SSD weights.
Material WSSD (Ib/yd^3) Other Info
Cement 739 Gs=3.15
Rock (coarse) 1550 Gs(SSD)= 2.7, % tot= 6%, % abs= 0.8%
Sand (fine) ? SSD =2.6, % tot=1.4%, % abs= 1.4%
Water 325
Air ___ % Air =7%
1. What is the volume of sand required?
a. 6.45 ft^3
b. 6.94 ft^3
c. 8.83 ft^3
d. 9.66 ft^3
2. What is the batch water weight?
a. 230 lbs
b. 245 lbs
c. 325 lbs
d. 405 lbs
Answer:
1) 8.84 ft ^3 ( c )
2) 325 Ibs
Explanation:
1) Determine the volume of sand required
Volume of sand = [ 1 - volume of cement - volume rock - volume air - volume water ] * Gs of sand -------- ( 1 )
Note : volume = [ mass / (density of water * Gs) ]
Volume of cement = [ 739 / ( 1685.55 * 3.15 ) ] = 0.139 yd^3
Volume of rock = [ 1550 / ( 1685.55 * 2.7 ) ] = 0.340 yd^3
volume of air = 0.07 yd^3
volume of water = 0.325
back to equation ( 1 )
[ 1 - 0.139 - 0.340 - 0.07 - 0.325 ] * 2.6 * 27 = 8.84 ft ^3
2) Determine Batch water weight
= 325 Ib/yd^3 * 1 yd^3
= 325 Ibs
A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 3 MPa in the boiler and 30 kPa in the condenser. If the quality at the exit of the turbine cannot be less than 82 percent, what is the maximum thermal efficiency this cycle can have
What do you know about love?
5. Saturated liquid R-134a enters an expansion valve at 40 C. The refrigerant leaves the expansion valve at 6 C. What is the specific volume at the exit
Answer:
The specific volume of R-134a at the exit of the expansion valve is 0.014655 cubic meters per kilogram.
Explanation:
From Thermodynamics, we know that expansion valves are devices that work at steady state, in which heat and work interactions are usually non-existent and changes in gravitational potential and translational kinetic energy. From First Law of Thermodynamics and the Principle of Mass Conservation we get that expansion valve is represented by the following model:
[tex]\dot H_{in}-\dot H_{out} = 0[/tex] (Eq. 1)
[tex]\dot m_{in}-\dot m_{out} = 0[/tex] (Eq. 2)
Where:
[tex]\dot H_{in}[/tex], [tex]\dot H_{out}[/tex] - Rates of change of inlet and output enthalpies, measured in kilowatts.
[tex]\dot m_{in}[/tex], [tex]\dot m_{out}[/tex] - Mass flow rates at inlet and outlet, measured in kilograms per second.
From definition of enthalpy and (Eq. 2), we simplify (Eq. 1) as follows:
[tex]u_{in} + P_{in}\cdot \nu_{in} = u_{out} + P_{out}\cdot \nu_{out}[/tex] (Eq. 3)
Where:
[tex]u_{1}[/tex], [tex]u_{2}[/tex] - Specific internal energies at inlet and outlet, measured in kilojoules per kilogram.
[tex]P_{1}[/tex], [tex]P_{2}[/tex] - Inlet and outlet pressures, measured in kilopascals.
[tex]\nu_{1}[/tex], [tex]\nu_{2}[/tex] - Inlet and outlet specific volumes, measured in cubic meters per kilogram.
Now we get the following information from property charts:
Inlet (Saturated Liquid)
[tex]T = 40\,^{\circ}C[/tex]
[tex]P = 1017.1\,kPa[/tex]
[tex]\nu = 0.0008720\,\frac{m^{3}}{kg}[/tex]
[tex]u = 107.39\,\frac{kJ}{kg}[/tex]
[tex]h = 108.28\,\frac{kJ}{kg}[/tex]
[tex]x = 0[/tex]
Outlet (Liquid-Vapor Mix)
[tex]T = 6\,^{\circ}C[/tex]
[tex]P = 362.23\,kPa[/tex]
[tex]\nu = 0.014655\,\frac{m^{3}}{kg}[/tex]
[tex]u = 102.968\,\frac{kJ}{kg}[/tex]
[tex]h = 108.28\,\frac{kJ}{kg}[/tex]
The specific volume of R-134a at the exit of the expansion valve is 0.014655 cubic meters per kilogram.
A triangular distributed load of max intensity w = 420 N/m acts on beam A B . The beam is supported by a pin at A and member C D , which is connected by pins at C and D respectively. Determine the reaction forces at A and C . Enter your answers in Cartesian components. Assume the masses of both beam A B and member C D are negligible.
Answer:
hello your question is incomplete attached below is the missing diagram
a = 5.20 m
b = 7.80 m
c = 4.16 m
answer :
Reaction force at A :
= Fax i + Fay j
= -14836.5 i - 9139.2 j N
Reaction force at B
= Fcx i + Fcy j
= - 14836.5 i - 11869.2 j N
Explanation:
attached below is the detailed solution
Reaction force at A :
= Fax i + Fay j
= -14836.5 i - 9139.2 j N
Reaction force at B
= Fcx i + Fcy j
= - 14836.5 i - 11869.2 j N
A strain gauge, diaphragm pressure transducer (accuracy: <0.1% reading) is subjected to a pres- sure differential of 10 kPa. If the output is meas- ured using a voltmeter having a resolution of 10 mV and accuracy of better than 0.1% of the reading, estimate the uncertainty in pressure at the design stage. How does this change at 100 and 1,000 kPa
Answer:
the design stage uncertainty for pressure is (√[ 25 + 0.10⁻⁴ P² ]) / 10 kPa
the change in sensitivity is 0.01 mV/kPa
Explanation:
Given that;
Differential pressure in the transducer ΔP = 10 kPa
Accuracy in the reading of diaphragm pressure transducer, α < 0.1%.
Resolution of the voltmeter, Rv = 10 mV
Now we write the expression for the design stage uncertainty
Us = √[(Us)₁² + (Us)₂²] ......................equ 1
nex we write the expression for design stage uncertainty for the voltmeter having resolution 10 mV .
(Us)₁² = ± 1/2Rv
we substitute the values
(Us)₁² = ± 1/2(10 mV) = ±5 mV
we write the expression for design stage uncertainty with respect to strain gauge.
(Us)₂ = aKtΔP
Kt is the strain gauge constant, Rs is the resolution for the voltmeter when accuracy in strain gauge is less than 0.1% .
Substitute the values.
(Us)₂ = (0.1%) (P mV / kPa) 10 kpa
= 0.01P mV
Here, P is a constant.
Substitute the values in equation 1
Us = √[(±5 mV)² + (0.01P mV)²]
= √[ 25 + 0.10⁻⁴ P² ]
Write the expression for the design stage uncertainty for pressure
Up = Us / ΔP
Substitute the values.
Up = (√[ 25 + 0.10⁻⁴ P² ]) / 10 kPa
therefore the design stage uncertainty for pressure is (√[ 25 + 0.10⁻⁴ P² ]) / 10 kPa
Write the value of the design stage uncertainty for pressure, ΔP is 100 kPa .
(Up)₁ = (√[ 25 + 0.10⁻⁴ P² ]) / 100 kPa
Write the value of the design stage uncertainty for pressure ΔP is 1000 kPa
(Up)₂ = (√[ 25 + 0.10⁻⁴ P² ]) / 1000 kPa
Write the expression for the sensitivity of the pressure transducer.
s = Rv / 1000 kPa
Substitute the values
s = 10 mV / 1000 kPa
= 0.01 mV/kPa
therefore the change in sensitivity is 0.01 mV/kPa
1. Make sure the inputs are set to df = 20 and p-value of 0.05 (critical value for t will adjust automatically). Now reduce degrees of freedom to 15, then to 10, and then to 5. What happens to the critical value for t?
Answer:
It moves inwards towards the center of the distribution
Explanation:
It is given :
Number of degrees of freedom , df = 19
α = 0.05
α/2 = 0.05/2 = 0.025
Therefore, [tex]$t_{\alpha/2, df} = t_{0.025,19} = \pm 2.093$[/tex]
So critical value of t = ± 2.093
Therefore, the curve moves towards the center of the distribution.
Determine the electric power consumption of the system for pumping. Would you recommend the use of a single large pump or several smaller pumps of the same total pumping power scattered along the pipeline
Answer:
Hello your question is incomplete attached below is the complete question
answer: 4493.24 Kw
I would recommend the use of several smaller pumps of the same total pumping power scattered along the pipeline
Explanation:
Calculate the Electric power consumption of the system for pumping using the formula below
[tex]W_{electric} = \frac{Qp}{n}[/tex] --------- ( 1 )
P = ΔP = 2166.67kPa ( calculated using : [tex]\frac{p_{0} flv^2}{2d}[/tex] )
where: [tex]p_{0}[/tex] = 950.6 kg/m^3 , f = 0.0083, v = 5.305 m/s, d = 0.6 m, l = 12 km
n = efficiency of motor pump = 74% = 0.74
Q = 1.5 m^3/s
input the given values into equation ( 1 )
[tex]W_{electric}[/tex] = 4493.24 Kw
I would recommend the use of several smaller pumps of the same total pumping power scattered along the pipeline
(a)A three-point transverse bending test is conducted on a cylindrical specimen of aluminum oxide having a reported flexural strength of 300MPa (43,500psi). If the specimen radius is 5.0mm (0.20in.) and the support point separation distance is 15.0mm (0.61in.), would you expect the specimen to fracture when a load of 7500N (1690lbf) is applied? Justify your answer.
Answer:
The specimen would not fracture having a flexural strength ( 300 MPa ) > ( 286.5 MPa )
Explanation:
The expression to represent the stress on a cylindrical specimen by a three-point transverse bending test
б = [tex]\frac{F_{f}L }{\pi R^3}[/tex] ---------------- ( 1 )
where : R = radius, Ff = flexural load,
L = distance between loads ( two loads )
Given data:
7500 N = flexural load
(15 * 10^-3) m = distance between loads
(5 * 10^-3) m = radius
input the given values into equation 1
б = 286.5 * 10^6 N/m^2 = 286.5 MPa
Note : the flexural strength of the cylindrical specimen is 300MPa
Therefore the specimen would not fracture having a flexural strength ( 300 MPa ) > ( 286.5 MPa )
. Convert 350 lb* ft In Joules?
Answer:
474.536 Joules
Explanation:
Use a converter machine.
1lb = 1.355818 j
350 = 1.355818 j *350
= 474.536
A total of 42 gallons of a glycol solution meeds to be added to a heating water loop to ensure the water does not freeze if there is a heating equipment failure. The glycol solution comes in 1.75 galloncans. How many cans will be needes? A total of how many cann of glycol will be required
Answer:
24 cans
Explanation:
The number of glycol solution needed to prevent water from freezing is 42 galloons. The glycol solution comes in cans of 1.75 gallons.
Therefore 1 can of glycol = 1.75 gallon.
Number of cans of glycol needed = Total gallons of glycol needed / number of gallon present in each can
Number of cans of glycol needed = 42 gallons / (1.75 gallon per can)
Number of cans of glycol needed = 24 cans
Therefore a total of 24 cans are needed.
Some wastewater has a BOD5 of 150 mg/L at 20° C. The reaction rate k at that temperature has been determined to be 0.20/day. Find BOD5 (in mg/L) at 15° C.
Answer:
The value of [tex]\mathbf{BOD_5 \ at \ 15^0 \ C \ is \simeq 130.14 \ mg/L}[/tex]
Explanation:
From the given information:
To find the BOD5 (in mg/L) at 15° C; we need to know the ultimate carbonaceous BOD and the reaction rate coefficient at 15° C.
So, to start with the calculation of the ultimate carbonaceous BOD by using the formula:
[tex]BOD_t = L_o (1-e^{-k*t})[/tex]
where;
[tex]BOD _t[/tex] = Biochemical oxygen demand at t days
[tex]L_o[/tex] = the ultimate carbonaceous
∴
[tex]150= L_o (1-e^{-0.20*5})[/tex]
[tex]L_o =\dfrac{150}{ (1-e^{-0.20*5})}[/tex]
[tex]L_o =\dfrac{150}{ (1-0.3679)}[/tex]
[tex]L_o =237.30 \ mg/L[/tex]
Thus, the ultimate carbonaceous BOD = 237.30 mg/L
For the reaction rate coefficient; we use the formula:
[tex]k_{\tau} = k_{20} \times \theta^{\tau - 20}[/tex]
where;
[tex]k_{\tau}[/tex] = rate of the reaction constant at various temperature (T) = 15
[tex]k_{20}[/tex] = rate of the reaction constant at standard laboratory = 0.20
[tex]\theta[/tex] = constant = 1.047
∴
[tex]k_{15} =0.20 \times \theta^{15 - 20}[/tex]
[tex]k_{15} =0.20 \times 1.047^{-5}[/tex]
[tex]k_{15} =0.20 \times0.7948[/tex]
[tex]k_{15} = 0.1590 / day[/tex]
Thus, at 15° C, the reaction constant (k) = 0.1590 / day
Finally, the BOD5 (in mg/L) at 15° C can be calculated by using the formula:
[tex]BOD_t = L_o (1 - e^{-k*t})[/tex]
[tex]BOD_t = 237.30 \times (1 - e^{-0.1590*5})[/tex]
[tex]BOD_t = 237.30 \times (1 -0.45158)[/tex]
[tex]BOD_t = 237.30 \times (0.54842)[/tex]
[tex]\mathbf{BOD_5 \simeq 130.14 \ mg/L}[/tex]
Write a Verilog module that describes 8-bit right shifter register with control signals A(arithmetic), L(logical), CLR(clear) and LD(load). Input signals are CLK, LD and 8-bit input D. Output signal is 8-bit output Q. CLR signal will clear Q. LD signal will load input D to Q. A signal will do arithmetic right shift of Q, while L signal will do logical right shift of Q.
4.5. In a balanced 480 V three-phase system, the line current is measured to be 15 A. Find ZY and Z .
Answer:
We are to find bar Zy and bar X in this question
We have Va = 480v
IL = 15L-25⁰
When we connect Y we have
Iph = IL = 15L-25⁰
Vph = VL/√3
= 489/√3
= 277.128V
Bar Zy = Vph/Iph = 277.128/15L-25⁰
= 18.475L25⁰
For bar Z
15L-25⁰/√3
= 8.6L-25⁰
VL = 480v
480/8.6L-25⁰
= 55.14L25⁰
Please check attachment.
what ia the value of the wod HEX begining at address 414 if the machine is Little Endian? Big endian
Answer:
hello your question is incomplete attached below is the complete question
Given you have a . 24 bit CPU The contents of memory are Address 412 413 Value0x120x34 Ox56 0x78 0x9A OxBC OxDEOxF1 0x23 414 419 418 420 415 416417 What is the value of the word in HEX beginning at address 414 if the machine is Little Endian? If it is Big Endian? Write your answer in HEX . Hex digits that are alphabetical should be written in uppercase For example A and not a Make sure that Ox appears at the beginning of your answer Do not put whitespace in your answer
Answer: Little Endian: 0x9A7856.
Big Endian: 0x56789A.
Explanation:
Given data :
24 bit CPU ( size of each word = 24 bit )
next we have to determine how many bytes are contained in each 24 bit word
= 24 / 8 = 3 bytes
with this information a word in Hex beginning at 414 will end at 416
when we use the Little Endian representation the last byte of the binary representation which is 416 will be stored first followed by 415 and then 414
hence the word beginning at 414 using little Endian = 0x9A7856.
For Big Endian the process is vice versa
Hence the word beginning at 414 using Big Endian = 0x56789A.
A steel pipe with an inside diameter of 10 in. will be used to transmit steam under a pressure of 800 psi. If the hoop stress in the pipe must be limited to 10 ksi because of a longitudinal weld in the pipe, determine the minimum satisfactory thickness for the pipe.
Answer:
The minimum satisfactory thickness for the pipe is 0.4. in
Explanation:
The computation of the minimum satisfactory thickness for the pipe is shown below:
As we know that
[tex]\sigma _h = \frac{pr}{t}[/tex]
Now for determining the thickness we have to rearrange it
[tex]t = \frac{pr}{\sigma_h}[/tex]
where,
p = pressure inside the pips
r = pipe radius
[tex]\sigma _h[/tex] = stress of the hoop
Now put the given values to the above equation
So,
[tex]t = \frac{800 \times 5}{10 \times (10)^3}[/tex]
= 0.4 in
Hence, the minimum satisfactory thickness for the pipe is 0.4. in
The same is to be considered
So i have to make a project about how an alien would live on saturn and the features it needs to adapt on it. The planet i was given was saturn. Can somebody help?
Explanation:
It would be impossible to live on Saturn, because the planet is made of gas. Unlike earth Saturn doesn’t have a surface.
Saturns atmosphere is made up of hydrogen and helium which combined together is about 99.5%, with ammonia making up the remaining 0.5%.
For an alien to survive on Saturn or live there he would definitely require oxygen as this is not present on the planet.
n a single-phase AC circuit, for a general load composed of RLC elements under sinusoidal-steady-state excitation, the average reactive power is given by
Answer:
The average reactive power is [tex]I_{rms}V_{rms} cos \phi[/tex]
Explanation:
For a single-phase AC circuit;
the peak current in the circuit is given as [tex]I_o[/tex]
the root-mean-square current is given by;
[tex]I_{rms} = \frac{I_o}{\sqrt{2}}[/tex]
the peak voltage in the circuit is given as [tex]V_o[/tex]
the root-mean-square voltage is given by;
[tex]V_{rms} = \frac{V_o}{\sqrt{2} }[/tex]
The average reactive power is given by
[tex]P_{avg} = I_{rms}V_{rms} cos \phi[/tex]
where;
[tex]cos \phi \ is \ the \ power \ factor[/tex]
Therefore, the average reactive power is [tex]I_{rms}V_{rms} cos \phi[/tex]