If P is the incenter of triangle JKL, find PJ.

If P Is The Incenter Of Triangle JKL, Find PJ.

Answers

Answer 1

Answer:

PJ = 41.34

Step-by-step explanation:

P is incenter, three angles bisector meet

∠MJP ≅ ∠OJP

PM = PN = PO = 22   (radius: property of incenter)

∠JPM = 90 - ∠MJP = 90 - OJP = ∠JPO

ΔJPM ≅ ΔJPO   (ASA) or (SAS)

LM = JO

2x + 3 = 5x - 45

3x = 48

x = 16

JM = 35

PJ = √35²+22² = √1709 = 41.34

Answer 2

The value of PJ in triangle KJL is 41.32 units.

What is incenter?

The point formed at the intersection of the three angle bisectors of a triangle; also the centre of the incircle.

Given that, P is incenter of the triangle KJL,

Considering the triangles ΔMJP and ΔOJP

PM = PO (property of incenter)

∠ JMP ≅ ∠ JOP

JP is common segment.

ΔJPM ≅ ΔJPO  (by SAS rule)

JM = JO  (CPCTC)

2x + 3 = 5x - 45

3x = 48

x = 16

JM = 35

Using the Pythagoras theorem,

PJ² = PM²+JM²

PJ = √35²+22² = √1709 = 41.34

Hence, The value of PJ in triangle KJL is 41.32 units.

For more references on incenter, click;

https://brainly.com/question/29480777

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