Answer:
The gravitational potential energy and kinetic energy of this ball should be equal (assuming that there is no energy loss due to friction.)
Explanation:
The ball loses gravitational potential energy as it rolls down the hill. At the same time, the speed of the ball increases, such that the ball gains kinetic energy.
If there is no friction on this ball (and that the ball did not deshape,) all the gravitational potential energy that this ball lost would be converted to kinetic energy.
If the gravitational field strength [tex]g[/tex] is constant throughout, the gravitational potential energy of an object in that gravitational field would be proportional to its height.
If [tex]m[/tex] denote the mass of this ball, the gravitational potential energy ([tex]\rm GPE[/tex]) of this ball at height [tex]h[/tex] would be [tex]{\rm GPE} = (m \cdot g) \cdot h[/tex], which is proportional to [tex]h\![/tex].
The value of [tex]g[/tex] near the surface of the earth is indeed approximately constant (typically [tex]g \approx 9.8\; \rm m \cdot s^{-2}[/tex].)
At halfway between the top and bottom of this hill, the height of this ball would be [tex](1/2)[/tex] of its initial value (the value when the ball was at the top of the hill.) Because the [tex]\rm GPE[/tex] of this ball is proportional to its height, at halfway down the hill, the [tex]\rm GPE\![/tex] of this ball would also be [tex](1/2)\![/tex] its initial value.
However, if there was no friction on this ball (and that the ball did not deshape,) that [tex](1/2)[/tex] of the initial [tex]\rm GPE\![/tex] of this ball was not lost. Rather, these [tex](1/2)\![/tex] of the initial [tex]\rm GPE[/tex] would have been converted to the kinetic energy ([tex]\rm KE[/tex]) of this ball.
Hence, when the ball is halfway down the hill:
[tex]\displaystyle \text{GPE halfway down the hill} = \frac{1}{2}\, \text{Initial GPE}[/tex].
[tex]\begin{aligned}& \text{KE halfway down the hill}\\ &= \text{Initial GPE} - \text{GPE halfway down the hill}\\ &= \text{Initial GPE} - \frac{1}{2}\, \text{initial GPE}\\ &= \frac{1}{2}\, \text{Initial GPE}\end{aligned}[/tex].
Therefore:
[tex]\begin{aligned}& \text{GPE halfway down the hill} \\ &= \frac{1}{2}\, \text{Initial GPE} \\ &= \text{KE halfway down the hill}\end{aligned}[/tex].
In other words, under these assumptions, when this ball is halfway down the hill, the gravitational potential energy and the kinetic energy of this ball would be equal.
A double replacement reaction is a chemical reaction between two ionic compounds in which ions are interchanged to form two new compounds
a. True
b. False
Answer: True
Explanation:
The statement that "A double replacement reaction is a chemical reaction between two ionic compounds in which ions are interchanged to form two new compounds" is true.
We should also note that a double replacement reaction can also be referred to as a metathesis reaction. In such cases, the ions of the compounds involved will be exchanged in order for a new compound to be formed. An example of a metathesis reaction is:
FeSO4 + CuCl2 = FeCl2 + CuSO4
why fermentation carried temperature in range of 30 to 40°C
Answer:
i dont kno
Explanation:
Explanation:
As temperature increases, fermentation rate accelerates. With increased fermentation rate, more aromatic compounds are produced because the metabolic intermediates are excreted from the yeast cells just like people getting sweaty and stinky during vigorous exercise.
what mass of sodium hydroxide is needed to neutralise 24.5kg of sulfuric acid
H2SO4 + N2 = 2NH3
Answer:
23.92 g
Explanation:
Molar mass of H2SO4 = (2×1)+32+(16×4)= 2+32+48= 82g/mol
H2SO4 + 2NaOH ---> Na2SO4 + 2H2O
I mole of H2SO4 = 2 moles of NaOH
24.5/82 = 24.5/82 × 2
= 0.598 moles of NaOH will neutralize
Mass= mole× molar mass
Molar mass of NaOH= 23+16+1 = 40g/mol
Mass= 0.598 × 40 = 23.92g of NaOH
Answer:
20g
Explanation:
First of all, you have got your formula wrong. It should be [tex]H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O[/tex].
Start by finding the Relative Formula Mass for sulfuric acid. [tex]H_{2}SO_{4}[/tex] is equal to (2x1)+32+(16x4)=98. You then calculate Mols by doing [tex]Mols=\frac{Mass}{Relative Formula Mass}[/tex]. So, [tex]\frac{24.5}{98} = 0.25[/tex], so the Mols of Sulfuric Acid is 0.25.
The Mol ratio of Sulfuric Acid to Sodium Hydroxide is 1:2, so 0.25:0.5.
Now, you have to find the Relative Formula Mass of Sodium Hydroxide, or [tex]NaOH[/tex]. 23+16+1=40. Finally, multiply 0.5 by 40, and you'll find that the maximum mass is 20g.
Which of the following components does a disc brake system use?
brake shoe
adjuster screw
wheel cylinder
caliper
The caliper is a component which is used by a disc brake system for performing its function.
What are the components of disc brake system?The disc braking system consist of components such as disc/rotor, a brake calliper and brake pads. When the brake pedal is pushed, brake fluid creates pressure that produces friction.
So we can conclude that the caliper is a component which is used by a disc brake system for performing its function.
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A 33.0g sample of glass, which has a specific heat capacity of 0.670·J·g−1°C−1, is dropped into an insulated container containing 200.0g of water at 70.0°C and a constant pressure of 1atm. The initial temperature of the glass is 7.6°C. Assuming no heat is absorbed from or by the container, or the surroundings, calculate the equilibrium temperature of the water. Be sure your answer has 3 significant digits.
Answer:
68.4°C is the final temperature of the water
Explanation:
In this problem, the heat lost by the water is equal to the heat lost by the sample of glass, that is:
W(Gl)*S(Gl)*ΔT(Gl) = W(H₂O)*S(H₂O)*ΔT(H₂O)
Where W is mass (Gl = 33.0g; H₂O = 200.0g)
S is specific heat (Gl = 0.670J/g°C; H₂O = 4.184J/g°C)
And ΔT is change in temperature ( Gl = T-7.6°C; H₂O = 70.0°C-T)
Replacing:
33.0g*0.670J/g°C*(T-7.6°C) = 200.0g*4.184J/g°C*(70.0°C-T)
22.11*(T-7.6) = 836.8*(70.0-T)
22.11T - 168.04 = 58576 - 836.8T
858.91T = 58744.04
T = 68.4°C is the final temperature of the water
0.01 M HCl solution has a pH of 2. Suppose that during the experiment, both the universal pH indicator and the cabbage indicator turn orange-red for 0.01 M HCl. What can you conclude about the the cabbage indicator key?
A) It matches the universal pH indicator and is indicating the proper pH.
B) It should completely match the universal indicator key for all pH values greater than 7 (base).
C) It should completely match the universal indicator key for all pH values.
D) There was some sort of experimental error, because the indicators should never match.
Answer:
(A) It matches the universal pH indicator and is indicating the proper pH.
Explanation:
Correct on edge 2021
Given the data from the question, the correct statement is:
The cabbage indicator matches the universal pH indicator and is indicating the proper pH (Option A) What is pH ?This is simply a measure of the acidity / alkalinity of a solution.
The pH measures the hydrogen ion concentration while the pOH measures the hydroxide ion concentration
pH scaleThe pH scale is a scale that gives an understanding of the variation of the acidity / alkalinity of a solution.
The scale ranges from 0 to 14 indicating:
0 to 6 indicates acid 7 indicates neutral 8 to 14 indicate basicpH indicatorsThese are devices / equipment used to indicate if a solution is acidic, neutral or basic.
From the question given above, we were told that the universal and the cabbage pH indicator gives the same result.
Therefore, we can conclude that the cabbage indicator is indicating the proper pH (Option A)
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4. If you had.35 grams of chloric acid, how many molecules would you have?
Answer:
.4 moles
Explanation:
this is if it's 35 grams
Why doesn't all soil look and feel the same? List 3 reasons
Answer:
all soil are also different due to how they were form
Which carbohydrate strengthens plant cells?
A. glucose
B. glycogen
C. cellulose
D. lactose
Answer: Its C
Explanation:
A tank of water was contaminated with a colored dye (D). To determine the concentration of D, an analyst took 5.0-mL solution from the contaminated water as a sample, and measured the absorbance, yielding a value of 0.10. Afterwards, the analyst added 5.0-mL of 0.02 M standard D solution into the sample solution, and measured the absorbance, yielding a value of 0.20. What is the concentration of D in the original sample solution
Answer:
0.005 M
Explanation:
Given data:
volume of sample solution ( volume of D ) = 5.0 mL
volume of added stock solution ( V1 ) = 5.0 mL
concentration of added stock solution ( N1 ) = 0.02 M
Total volume of concentration ( V2 )= 10 mL = ( 5.0 mL + 5.0mL)
concentration of Total volume of sample ( C2 ) = 0.01
N2 = ( N1V1 ) / V2
= ( 0.02 * 5 ) / 10 = 0.01 m
absorbance of sample solution ( A1 ) = 0.10
absorbance of additional sample solution ( A2 ) = 0.20
attached below is the remaining part of the detailed solution
Which of the following is not a property of water?
A. It dissolves most ionic substances.
B. It has a lower density than most liquids do.
C. It has a higher density in the liquid state than in the solid state.
D. It has a high specific heat.
Answer:
b.it has a lower density than most liquid do
the eye is connected to the brain by nerves.
A. True
B. False
the answer is A..which is true
Which type of front is most likely moving through this area?
A. cold front
B. warm front
C. occluded front
D. stationary front
Answer:
Cold front
Explanation:
The amount of exposed surface area of the liquid affects how quickly
evaporation occurs.
O True
O False
Which carbohydrate strengthens plant cells?
A. glucose
B. glycogen
C. cellulose
D. lactose
Answer:
a
Explanation:
Answer:
c
Explanation:
edge
3) How many grams of calcium hydroxide are necessary to create 49.5 mL of a 1.55 M solution?
Answer:
5.68g
Explanation:
Water’s unique properties, high heat capacity, high density, solid phase less dense than liquid phase can be attributed to
A. The shape of the molecule
B. The polarity of the molecules and hydrogen bonding between molecules.
C. The covalent oxygen hydrogen bonds in the molecule.
D. It’s formula h2o.
Answer:
B- The polarity of the molecules and hydrogen bonding between molecules.
Explanation:
Hope this helps:)
NH3(g) + O2(g) + CH4(g) → HCN(aq) + H20(l)
Answer:
2 NH3(g) + 3 O2(g) + 2 CH4(g) = 2 HCN(aq) + 6 H2O(l)
Explanation:
Reaction stoichiometry Limiting reagent
Compound Coefficient Molar Mass Moles Weight
NH3(g) 2 17.03052
O2(g) 3 31.9988
CH4(g) 2 16.04246
HCN(aq) 2 27.02534
H2O(l) 6 18.01528
Instructions on balancing chemical equations:
Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below
Always use the upper case for the first character in the element name and the lower case for the second character. Examples: Fe, Au, Co, Br, C, O, N, F. Compare: Co - cobalt and CO - carbon monoxide
To enter an electron into a chemical equation use {-} or e
To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}.
Example: Fe{3+} + I{-} = Fe{2+} + I2
Substitute immutable groups in chemical compounds to avoid ambiguity.
For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced,
but PhC2H5 + O2 = PhOH + CO2 + H2O will
Compound states [like (s) (aq) or (g)] are not required.
If you do not know what products are enter reagents only and click 'Balance'. In many cases a complete equation will be suggested.
Reaction stoichiometry could be computed for a balanced equation. Enter either the number of moles or weight for one of the compounds to compute the rest.
Limiting reagent can be computed for a balanced equation by entering the number of moles or weight for all reagents.
The given chemical equation is already balanced and does not require any further balancing.
The chemical equation NH₃(g) + O₂(g) + CH₄(g) → HCN(aq) + H₂O(l) is already balanced because the number of atoms of each element is the same on both sides of the equation.
On the left side of the equation, there is 1 nitrogen (N) atom in NH₃ and 1 nitrogen (N) atom in HCN.
On the right side of the equation, there are 3 hydrogen (H) atoms in NH₃, 2 hydrogen (H) atoms in HCN, and 2 hydrogen (H) atoms in H₂O.
There are 3 oxygen (O) atoms in O₂ on the left side of the equation and 1 oxygen (O) atom in H₂O on the right side of the equation.
Finally, there is 1 carbon (C) atom in CH₄ on the left side of the equation.
Since the number of atoms of each element is balanced on both sides of the equation, we can conclude that the given equation is already balanced and does not require any further adjustments or coefficients.
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The complete question is:
How can I balance NH₃(g) + O₂ (g) + CH₄ (g) -> HCN (aq) + H₂O (l)?
Need help ASAP PLS SCIENCE
Answer:
3
m/s2
0.2
m/s2
Explanation:
if F=ma, then a = F/m. The unit to measure acceleration is typically m/s2.
what is the formula for tetrahydrogen monocarbide
Answer:
CH4
Explanation:
Tetra is the prefix for four. Hence the H4
Mono is the prefix for one, Hence the C
Methane (aka Tetrahydrogen monocarbide) written as CH4
Which is a pollutant associated with high-tech gadgets in landfills?
O A. Nitrogen
O B. Carbon Dioxide
O C. Iron
D. Mercury
Answer:
D
Explanation:
Most likely, the pollutant that is most associated with high-tech gadgets in landfills would be heavy metals like lead, cadmium and mercury since they are being used in most of the electronic devices. Usually these metals can be found in the batteries of these gadgets.
High-tech gadgets in landfills would be heavy metals like lead, cadmium and mercury since they are being used in most of the electronic devices. Usually these metals can be found in the batteries of these gadgets. Hence, option D is correct.
What are landfills?Modern landfills are well-engineered and managed facilities for the disposal of solid waste.
Landfills are located, designed, operated and monitored to ensure compliance with federal regulations.
For instance, television and computer monitors normally contain hazardous materials such as lead, mercury, and cadmium, while nickel, beryllium, and zinc can often be found in circuit boards.
Due to the presence of these substances, recycling and disposal of e-waste becomes an important issue.
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Change in H for
CO2 -->C+02?
Answer:
−26.4 kcal
Explanation:
According to Hess's law, the total heat changes occuring during a chemical reaction are independent of path.
2CO(g)+O
2
(g)⟶2CO
2
(g)N ,
ΔH=−135.2 kcal
The above reaction is reversed and halved, we get-
CO
2
(g)⟶CO+
2
1
O
2
(g)
ΔH=
2
135.2
kcal ....(i)
C+O
2
(g)⟶CO
2
(g)
ΔH= -94 kcal ...(ii)
Required equation
C(s)+
2
1
O
2
(g)⟶CO(g);
Adding Eqs. (i) and (ii), we get
C(s)+
2
1
O
2
(g)⟶CO(g),
ΔH =
2
135.2
−94=−26.4 kcal
Please tell 4 strong alkalis and 4 weak alkalis
Red: weak
Orange: Strong
How many moles are contained in 325 gram sample of ammonium dichromate (NH4)2Cr2O7
Answer:
Hyba odpowiedzi c. Hyba
Mole can be defined as the number of molar mass units of the compound in the sample. The moles of ammonium dichromate in 325 grams sample is 1.29 mol.
What is molar mass?The molar mass can be given as the mass of each atom in the formula unit. The molar mass of ammonium chromate is given as:
[tex]\rm (NH_4)_2Cr_2O_7=2(N)+4\;\times\;2(H)+2(Cr)+7(O)[/tex]
Substituting the mass of each atom to identify the molar mass of ammonium chromate:
[tex]\rm (NH_4)_2Cr_2O_7=2(14)+4\;\times\;2(1)+2(52)+7(16)\\ (NH_4)_2Cr_2O_7=28+8+104+112\\ (NH_4)_2Cr_2O_7=252 \;g/mol[/tex]
The molar mass of ammonium dichromate s 252 g/mol. The moles of the compound in 325 g is given as:
[tex]\rm Moles=\dfrac{mass}{molar\;mass} \\\\Moles=\dfrac{325\;g}{252\;g/mol}\\\\ Moles=1.29\;mol[/tex]
The moles of ammonium dichromate in the sample are 1.29 mol. Thus, option c is correct.
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What is an organelle
(A)Organelles are only common to prokaryotic cells
(B)An organelle is made up of different tissues working together
(C)An organelle is structure in a cell that performs a specific task...
Answer:
CExplanation:
An organelle is structure in a cel that performs a specific task or job.
Answer:
I believe the answer is C: an organelle is structure in a cell that performs a specific task
Plzz help
How many moles of H2O can be made from the complete reaction of 5.5 moles of C3H8? (Only enter the number, NO UNITS, and round to the tenth place, 1 decimal) Given: C3H8 + 5 O2 → 3 CO2. + 4 H2O
Answer:
22
Explanation:
5.5 mol C3H8 • (4 mol H2O / 1 mol C3H8 ) = 22 mol H2O
2). H2S and SO2 as follows,(8pt)
H2S + SO2 ------>S + H2O
In a particular experiment, 7.95 g of sulfur is produced by the reaction of 7.5 g of H2S with 12.75 g of SO2.
What is the % yield of sulfur?
Answer: 75.7 % yield
Explanation:
The balanced chemical equation is:
[tex]2H_2S+SO_2\rightarrow 3S+2H_2O[/tex]
According to stoichiometry :
68.2 g of [tex]H_2S[/tex] will require = 64 g of [tex]SO_2[/tex]
Thus 7.5 g of [tex]H_2S[/tex] will require = [tex]\frac{64}{68.2}\times 7.5=7.0g[/tex] of [tex]SO_2[/tex]
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 68.2 g of give = 96 g of
Thus 7.5 g of [tex]H_2S[/tex] give =[tex]\frac{96}{68.2}\times 7.5=10.5g[/tex] of [tex]S[/tex]
% yield=[tex]\frac{\text{Actual yield}}{\text {Theoretical yield}}\times 100=\frac{7.95g}{10.5g}\times 100=75.7\%[/tex]
Thus 75.7 % yield is there.
what is the molarity of a solution with 130g of CoCl2 in 1/2 liter? (can you show the steps please)
Answer:
2M
Explanation:
M=mol/L
1. Find moles of CoCl2
mass of substance/molar mass = 130/129.833 = 1.001 mol
3. Substitute in molarity equation
M=(1.001/0.5)
M= around 2M
The molarity of a solution with 130g of CoCl2 in 1/2 liter is 2M
HOW TO CALCULATE MOLARITY:
The molarity of a solution can be calculated by dividing the number of moles of that substance by its volume:Molarity = no. of moles ÷ volumeFirst, we convert 130g of CoCl2 to moles as follows:Molar mass of CoCl2 = 129.84 g/molmoles = 130g ÷ 129.84g/molmoles of CoCl2 = 1molMolarity of CoCl2 solution = 1mol ÷ 0.5LMolarity of CoCl2 = 2MTherefore, the molarity of a solution with 130g of CoCl2 in 1/2 liter is 2M.
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what is the mass of 1mol of chlorine ions?
Answer:
71g
Explanation:
i think thats right?
One mole of chlorine would be 71 g unless they said "1 mole of chlorine ATOMS".
How many kilograms of phosphorous are in a sample containing 1.00E31 phosphorous atoms?
Answer: [tex]5.15\times 10^5kg[/tex]
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.
To calculate the number of moles, we use the equation:
Putting in the values we get:
[tex]\text{Number of moles}=\frac{1.00\times 10^{31}}{6.023\times 10^{23}}=0.166\times 10^{8}moles[/tex]
1 mole of phosphorous [tex]P[/tex] weighs = 31 g
Thus [tex]0.166\times 10^8[/tex] moles of phosphorous [tex]P[/tex] weigh=[tex]\frac{31}{1}\times 0.166\times 10^8=5.15\times 10^8g=5.15\times 10^5kg[/tex]