I really need help on this question! Thank you so much!

I Really Need Help On This Question! Thank You So Much!

Answers

Answer 1

Answer:

A. Empirical formula => C₂H₄O

B. Molecular formula => C₄H₈O₂

Explanation:

From the question given above, the following data were obtained:

Mass of C = 0.273 g

Mass of H = 0.046 g

Mass of O = 0.182 g

Molar mass of compound = 88 g/mol

A. Determination of the empirical formula of the compound.

C = 0.273 g

H = 0.046 g

O = 0.182 g

Divide by their molar mass

C = 0.273 /12 = 0.023

H = 0.046 /1 = 0.046

O = 0.182 /16 = 0.011

Divide by the smallest

C = 0.023 / 0.011 = 2

H = 0.046 / 0.011 = 4

O = 0.011 / 0.011 = 1

Thus, the empirical formula of the compound is C₂H₄O

B. Determination of the molecular formula of the compound.

Empirical formula = C₂H₄O

Molar mass of compound = 88 g/mol

Molecular formula =?

Molecular formula = [C₂H₄O]ₙ

[C₂H₄O]ₙ = 88

[(12×2) + (4×1) + 16]n = 88

[24 + 4 + 16]n = 88

44n = 88

Divide both side by 44

n = 88 / 44

n = 2

Molecular formula = [C₂H₄O]ₙ

Molecular formula = [C₂H₄O]₂

Molecular formula = C₄H₈O₂


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Answers

Answer:

Yes.

Explanation:

A combination reaction can be a redox reaction.

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Answers

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2Mg + O2 → 2Mgo

What is the greatest amount of MgO (in moles) that can be made with 7.8 moles of Mg and 4.7
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Answers

Answer:

it would be 4.5 mole left over

Explanation:

The greatest amount of MgO will be 7.8 mole and Mg will be limiting reagent.

What is limiting reagent?

The substance that would be entirely absorbed in the end of the chemical process is called as the limiting reagent.

What is mole?

A mole would be defined as the quantity of a material that includes precisely 6.02214076 X [tex]10^{23}[/tex] of the particular chemical elementary entities.

Calculation of amount of  MgO

The balanced chemical equation is 2 Mg + [tex]O_{2}[/tex] → 2MgO

It can be seen that 2 mole of Mg reacts with 1 mole of oxygen.

So, 7.8 mole of Mg = 7.8 / 2 = 3.9 mole of [tex]O_{2}[/tex].

Since, [tex]O_{2}[/tex] will be added in given reaction vessel will be 4.7 moles.

So, (4.7 - 3.9) = 0.8 moles of [tex]O_{2}[/tex] left but in this case Mg will be finished. Therefore, Mg will be limiting reagent.

It can be understood that 2 moles of Mg will give 2 mole of MgO.

That's why , 7.8 moles of Mg = 2 × 7.8 / 2 = 7.8 moles of MgO.

Therefore, 7.8 mole of magnesium oxide (MgO) could be generated and Mg will be limiting reagent.

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Answers

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R = Mixture

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Answers

On the Earth's surface gravity makes a
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A 130 kg object weighs approximately, 1274 Newtons on Earth.

The weight of an object on Earth can be calculated using the formula:
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Weight is calculated by multiplying the mass of an object by the acceleration due to gravity. On Earth, the acceleration due to gravity is approximately 9.8 meters per second squared (9.8 m/s²).

In this case, we have a 130 kg object. To find its weight on Earth, we can use the formula:

Weight = mass × acceleration due to gravity

Weight = 130 kg × 9.8 m/s²

Weight = 1274 Newtons (N)

So, the weight of a 130 kg object on Earth is approximately 1274 Newtons.

Therefore, a 130 kg object weighs approximately, 1274 Newtons on Earth.

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Answer:

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