I need help ASAP?!!!!

I Need Help ASAP?!!!!

Answers

Answer 1

Answer:

B. 1 3/8

or

The second one

Step-by-step explanation:

4 1/8 ÷ 3 = 1.375 = 1 3/8

hope this helps

have a good day


Related Questions

Turn 6% into a decimal

Answers

Answer:

0.06

Step-by-step explanation:

Answer:

.06

Step-by-step explanation:

If 1 is 100%, then .06 is 6%.

Hope this helps!

It’s costs $79 to buy 5 tickets to a show.what is the cost of one ticket?

Answers

Answer:

79÷5=15.8

So the answer is (15.8)

Sketch a drawing of a square. Describe the properties of a square.

Answers

All four sides of a square are congruent and they all equal 90 degrees

A town has a population of 2000 and grows at 4% every year.
What will be the
population after 15 years, to the nearest whole number?

Answers

Answer:

3602 people in 15 years

Step-by-step explanation:

2000 ( 1 + .04)^n         .04 is 4%    n = years

2000 ( 1.04)^15 = 3602 people

Deanna uses only fruit juice and sparkling water to make
punch for a school dance. She uses 6 1/2 liters of fruit
juice. She uses 0.6 as much sparkling water as fruit
juice.

How much fruit punch does she make?
A : 3.9
B : 7.1
C: 9.4
D 10.4

I appreciate it thank you
May Allah bless you

Answers

The answer to the question is B

The shadow of a tower at a time is three times as long as its shadow when the angle of elevation of the Sun is 60°. Find the angle of elevation of the Sum at the time of the longer shadow.​

Answers

Answer:

[tex]30^{\circ}[/tex].

Step-by-step explanation:

Let [tex]\theta[/tex] denote the unknown angle of elevation. Let [tex]h[/tex] denote the height of the tower.

Refer to the diagram attached. In this diagram, [tex]{\sf A}[/tex] denotes the top of the tower while [tex]{\sf B}[/tex] denote the base of the tower; [tex]{\sf BC}[/tex] and [tex]{\sf BD}[/tex] denote the shadows of the tower when the angle of elevation of the sun is [tex]60^{\circ}[/tex] and [tex]\theta[/tex], respectively. The length of segment [tex]{\sf AB}[/tex] is [tex]h[/tex]; [tex]\angle {\sf ACB} = 60^{\circ}[/tex], [tex]\angle {\sf ADB} = \theta[/tex], and [tex]{\sf BD} = 3\, {\sf BC}[/tex]..

Note that in right triangle [tex]\triangle {\sf ABC}[/tex], segment [tex]{\sf AB}[/tex] (the tower) is opposite to [tex]\angle {\sf ACB}[/tex]. At the same time, segment [tex]{\sf BC}[/tex] (shadow of the tower when the angle of elevation of the sun is [tex]60^{\circ}[/tex]) is adjacent to [tex]\angle {\sf ACB}[/tex].

Thus, the ratio between the length of these two segments could be described with the tangent of [tex]m\angle {\sf ACB} = 60^{\circ}[/tex]:

[tex]\begin{aligned}\tan(\angle {\sf ACB}) &= \frac{\text{opposite}}{\text{adjacent}} = \frac{{\sf AB}}{{\sf BC}}\end{aligned}[/tex].

[tex]\begin{aligned}\frac{{\sf AB}}{{\sf BC}} = \tan(60^{\circ}) = \sqrt{3}\end{aligned}[/tex].

The length of segment [tex]{\sf AB}[/tex] is [tex]h[/tex]. Rearrange this equation to find the length of segment [tex]{\sf BC}[/tex]:

[tex]\begin{aligned} {\sf BC} &= \frac{{\sf AB}}{\tan(\angle ACB)} \\ &= \frac{h}{\tan(60^{\circ})}\\ &= \frac{h}{\sqrt{3}} \\ &\end{aligned}[/tex].

Therefore:

[tex]\begin{aligned}{\sf BD} &= 3\, {\sf BC} \\ &= \frac{3\, h}{\sqrt{3}} \\ &= (\sqrt{3})\, h\end{aligned}[/tex].

Similarly, in right triangle [tex]{\sf ABD}[/tex], segment [tex]{\sf AB}[/tex] (the tower) is opposite to [tex]\angle {\sf ADB}[/tex]. Segment [tex]{\sf BD}[/tex] (shadow of the tower, with [tex]\theta[/tex] as the angle of elevation of the sun) is adjacent to [tex]\angle {\sf ADB}[/tex].

[tex]\begin{aligned}\tan(\angle {\sf ADB}) &= \frac{\text{opposite}}{\text{adjacent}} = \frac{{\sf AD}}{{\sf BD}}\end{aligned}[/tex].

[tex]\begin{aligned}\frac{{\sf AB}}{{\sf BD}} = \tan(\theta) \end{aligned}[/tex].

Since [tex]{\sf AB} = h[/tex] while [tex]{\sf BD} = (\sqrt{3})\, h[/tex]:

[tex]\begin{aligned}\tan(\theta) &= \frac{{\sf AB}}{{\sf BD}} \\ &= \frac{h}{(\sqrt{3})\, h} \\ &= \frac{1}{\sqrt{3}}\end{aligned}[/tex].

Therefore:

[tex]\begin{aligned}\theta &= \arctan\left(\frac{1}{\sqrt{3}}\right) \\ &= 30^{\circ}\end{aligned}[/tex].

In other words, the angle of elevation of the sun at the time of the longer shadow would be [tex]30^{\circ}[/tex].

Lucy went on holiday for 10 days. These are the temperatures for each day. 21°C 24°C 29°C 23°C 24°C Calculate the median temperature 24°C 27°C 23°C 22°C 23°C

Answers

Answer:

Step-by-step explanation:

21   22    23   23   23   24   24   24   27   29

(23 + 24)/2= 47/2= 23.5 is the median temperature

What is the measure of the unknown angle?

Image of a full circle divided into two angles. One angle is one hundred twenty degrees and the other is unknown

Group of answer choices

210°

220°

Answers

Answer:

The answer is 240 degrees

Step-by-step explanation:

A full circle is 360 degrees.

We know one angle is 120 degrees.

360-120=240 degrees

Mrs Ferguson is mailing a package that weighs 12.5 pounds. The post office charges by the ounce to mail a package. How much does the package weigh in ounces?

F. 187 ounces

G. 200 ounces

H. 192.5 ounces

J. 100 ounces

Answers

Answer: G

Step-by-step explanation:

1 pound equals =16 ounces

12.5 * 16=200

so 200 ounces.

Follow the rules to create two number sequences that go to the fifth term each. Rule 1: Multiply by 3 starting from 10. Rule 2: Subtract 7 starting from 58. What is the first term that appears in both sequences?

A.30

B.55

C.60

D.180

Answers

Answer: A(30)
Reason 3x10=30 and as it does take a while to get there in the fourth round of 58-7 30 will be the first number first term to appear.
The answer is D is correct

The area of the parallelogram below is
square meters.
9 m
2 m

Answers

18
=L*W
So it would be 9*2= 18

Find the volume of a
cone with a base radius of 5 yd and a height of 7 yd.
Write the exact volume in terms of Tt, and be sure to include the correct unit in your answer.

Answers

Answer:

[tex]\textsf{Volume}=\sf \dfrac{175}{3} \pi \:yd^3[/tex]

Step-by-step explanation:

[tex]\textsf{Volume of a cone}=\sf \dfrac{1}{3} \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

radius (r) = 5 ydheight (h) = 7 yd

Substituting the given value into the formula:

[tex]\begin{aligned}\implies\textsf{Volume} &=\sf \dfrac{1}{3} \pi (5^2)(7)\\\\&=\sf \dfrac{1}{3} \pi (25)(7)\\ \\&=\sf \dfrac{1}{3} \pi (175)\\ \\&=\sf \dfrac{175}{3} \pi \:yd^3\\\\\end{aligned}[/tex]

Answer:

To find :-

The volume of cone

Given :-

radius (r) = 5 yd

height (h) = 7 yd

Solution :-

The volume of cone

[tex] = \frac{1}{3} \pi {r}^{2} h[/tex]

Substituting the value of 'r' and 'h' in the formula.

[tex] = \frac{1}{3} \times \frac{22}{7} \times {5}^{2} \times 7 \\ = \frac{1}{3} \times 22 \times 5 \times 5 \\ = \frac{550}{3} {yd}^{3} [/tex]

Result :-

[tex] \text {The volume of cone is} \frac{550}{3} {yd}^{3} [/tex].

[tex] \mathcal {BE \: \: BRAINLY} [/tex]

100 points!To solve the problem cos-1(cos(-pi/6)), find the angle in the interval (0,pi) whose cosine is sqrt3/2.

Answers

[tex]cos^{-1}[cos(\omega)]\implies \omega \\\\[-0.35em] ~\dotfill\\\\ cos\left( -\frac{\pi }{6} \right)\implies \stackrel{symmetry~identity}{cos\left( \frac{\pi }{6} \right)} \\\\\\ cos^{-1}\left[ cos\left( -\frac{\pi }{6} \right) \right]\implies cos^{-1}\left[ cos\left( \frac{\pi }{6} \right) \right]\implies \cfrac{\pi }{6}[/tex]

why did we use the positive version of π/6?

well, the inverse cosine function has a range of [0 , π], and -π/6 is on the IV Quadrant, out of the range for it, however it has a twin due to symmetry on the I Quadrant, that is π/6, thus the reason.

The angle in the interval (0, pi) whose cosine value is √3 / 2 is π/6 radians.

What is Cosine of an Angle?

Cosine of an angle is defined as the ratio of the adjacent side to the hypotenuse of a right angled triangle.

We have to find the angle in the interval (0, π) such that the cosine of the angle is √3 / 2.

We know that, ratio of sides of 30-60-90 triangle is 1 : √3 : 2.

Hypotenuse = 2x

Adjacent side to 30° = √3 x

Cos (30°) = Adjacent side / Hypotenuse

               = √3 x / 2x

               = √3 / 2

30 degrees is equivalent to 30 × (π/180) = π/6 in radians

Hence π/6 is the angle in the interval (0, π) whose cosine value is √3 / 2.

Learn more about Cosine Functions here :

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Quadrilateral H is a scaled copy of quadrilateral G.
40
32
40
32
Quadrilateral H
45
Quadrilateral G
What is the value of i?

Answers

Answer:

36

Step-by-step explanation:

[tex] \frac{40}{32} = \frac{45}{?} \\ \frac{32 \times 45}{40 } = 36[/tex]

If quadrilateral H is a scaled copy of quadrilateral G then the value of i is 36.

What is Quadrilateral?

A quadrilateral is a closed shape and a type of polygon that has four sides, four vertices and four angles.

Given that Quadrilateral H is a scaled copy of quadrilateral G.

Two quadrilaterals are similar if their corresponding angles are equal and also their corresponding sides must be proportional.

The sides are proportional.

40/32 = 45/i

We have to find the value of i

Apply cross multiplication

40i=45(32)

40i = 1440

Divide both sides by 40

i = 1440/40

i = 36

Hence, if quadrilateral H is a scaled copy of quadrilateral G then the value of i is 36.

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can anyone help me find the area of these two pls ?

Answers

13: 72.25
14: 52
For 14, you need to split the figure into a triangle and rectangle.

Given the functions f(x) = log2(4x) and g(x) = 4x – 3, which of the following statements is true?

Both f(x) and g(x) have a common domain on the interval (0, ∞).
Both f(x) and g(x) have the same range of (–∞, 0].
Both f(x) and g(x) have the same x-intercept of (2, 0).
Both f(x) and g(x) increase on the interval of (–4 , ∞).

Answers

The true statement about the two functions is:

"Both f(x) and g(x) increase on the interval of (–4 , ∞)."

Which statement is true regarding the given functions?

Here we have the functions:

f(x) = log₂(4x)

g(x) = 4x - 3

That can be seen in the graph at the end. In the graph the green one is the logarithmic function.

As you can see there, both of these have similar ranges that go from (-∞, ∞) and both are increasing functions.

Then the correct statement is:

Both f(x) and g(x) increase on the interval of (–4 , ∞).

Where f(x) is actually increasing on all it's domain which is  (-∞, ∞), so the statement is true.

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Answer:

Both f(x) and g(x) have a common domain on the interval (0, ∞).

Step-by-step explanation:

The person explained it perfectly in this link shown below

https://brainly.com/question/28219401?referrer=searchResults

pls give me brainist for finding the answer

Also, the answer to the question

"What type of function is f(x) = 2x^3 – 4x^2 + 5?"

A) Exponential

B) Logarithmic

C) Polynomial

D) Radical

The answer is C) Polynomial

Explanation:

The exponential equation would look like this: f(x) = 2^x

with x for the exponent

The logarithmic equation would look like this: f(x) = log2 + 4

with log in the equation

The radical equation would look like this: f(x) = x^2 + 4x -1

                                                                              3x^2 -9x +2

With divide by something

Select the correct answer from each drop-down menu. Graph shows 2 four-sided polygons in the first quadrant of a coordinate plane. First polygon is at A (3, 0), B (1, 0), C (1, 2), and D (3, 2). Second polygon is at A prime (6, 0), B prime (2, 0), C prime (2, 2), and D prime (6, 2). In the figure, polygon ABCD is transformed to create polygon A′B′C′D′. This transformation is a by a factor of .

Answers

This transformation of the polygon ABCD to A'B'C'D' is a by a factor of 2

How to determine the scale factor?

The coordinates are given as:

First polygon: A (3, 0), B (1, 0), C (1, 2), and D (3, 2). Second polygon: A' (6, 0), B'(2, 0), C'(2, 2), and D'(6, 2)

Calculate the distance AB and A'B' using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}[/tex]

This gives

[tex]AB = \sqrt{(3-1)^2 + (0-0)^2} = 2[/tex]

[tex]A'B' = \sqrt{(6-2)^2 + (0-0)^2} = 4[/tex]

Divide A'B' by AB to determine the scale factor (k)

k = 4/2

k = 2

Hence, this transformation is a by a factor of 2

Read more about transformation at:

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The size of angle BAC is:

B= 75 degrees

A= 55 degrees

C=?

Answers

Answer:

[tex]C=20degrees[/tex]

Step-by-step explanation:

[tex]75 -55=20[/tex]

or [tex]20+55=75[/tex]

So the degrees of Angle C is [tex]20[/tex]

what is 8% of 40 as a decimal

Answers

Answer:

The answer is 3.2

Step-by-step explanation:

8 x 40________100 = 3.2

Calculate the perimeter of a football field measuring 80m by 50m

Answers

Answer:

260m

Step-by-step explanation:

the length and the width of a football field is 80m and 50 meters.

perimeter- (80+50)×2= 260m

hope it helps

What is the length of the missing leg?

Answers

Answer:

2.3

Step-by-step explanation:

4²+b²=4.6²

16+b²=21.16

-16 -16

b²= 5.16

b=√5.16

b= 2.3

Answer:

2.27 in   ~2.3 in to the nearest tenth

Step-by-step explanation:

It is a right triangle ....so yo can use pythagorean theorem

4^2 + b^2 = 4.6^2

b = 2.27

Determine the measure of the missing angle
50 degrees
60 degrees
180 degrees
360 degrees

Answers

Answer:

x = 60

Step-by-step explanation:

Let x = ?

120 + 95 +85 +x =360

x +300 =360

x = 360-300

x = 60

Answer: 60

Explanation: Every polygon adds up to 360.
What you can do is 360 - 120 - 95 - 85 = 60.

OR

120 + 95 + 85 = 300
360 - 300 = 60.

simplify 3 (3a - 6) help please

Answers

Step-by-step explanation:

Simplify the expression by using the Distributive Property.

For this expression, we'll be distributing. In simpler terms, multiplying 3 into the values inside the parentheses.

Think of the expression as;

[tex]3(3a-6)=(3 \times3a)+(3 \times -6)[/tex]

Multiply;

[tex]3 \times 3a=9a[/tex] (Multiply the whole number.)

[tex]3 \times -6=-18[/tex]

Your simplified expression is [tex]9a-18.[/tex]

Pa answer po please,thank you po!!
brainliest>>>>>

Answers

Answer:

answer down below

Step-by-step explanation:

Simplify (sin? 0 + cos² O) (sin 0 + cos O)

Answers

[tex](\sin^2 \theta + \cos^2 \theta)(\sin \theta + \cos \theta)\\\\=1 \cdot(\sin \theta + \cos \theta)\\\\=\sin \theta + \cos \theta[/tex]

Answer:

D: cos^3(O)

Step-by-step explanation:

If a line falls on the points (25, 24) and (15, 17), what is its slope? Enter your answer as a fraction in lowest terms. Use a slash mark (/) as the fraction bar​

Answers

Answer:

7/10

Step-by-step explanation:

We can use the slope formula to find the slope

m = ( y2-y1)/(x2-x1)  where ( x1,y1) and (x2,y2) are two points on the line

m = ( 24-17)/(25-15)

   = 7/10

  = 7/10

Find the solutions to the equation below.
Check all that apply.
2x² +7x+3=0
A. x=2
B. x=4
C. x= 3
D. x=7
Ex=-3
F. x= -1/-2

Answers

Answer:

E and F.

Step-by-step explanation:

This can be written in quadratic formula.

x = -b +- √b² - 4ac/2a

The equation to solve is written as ax² + bx + c = 0.

a = 2, b = 7, c = 3

x = -7 +- √49 (7²) - 24 (4*2*3, or 4ac).

x = -7 +- √25

x = -7 +- 5

divide by 2a (4)

-7/4 = -1.75

5/4 = 1.25

now we do -1.75 +- 1.25

x = -1/2 (F.)

x = -3 (E.)
Sorry for the late response, I had made an error and had to fix it.


could i have some really really quick help?

Answers

Answer:

1125 m

Step-by-step explanation:

Given equation:

[tex]h=-5t^2+150t[/tex]

where:

h = height (in metres)t = time (in seconds)

Method 1

Rewrite the equation in vertex form by completing the square:

[tex]h=-5t^2+150t[/tex]

[tex]\implies h=-5t^2+150t-1125+1125[/tex]

[tex]\implies h=-5(t^2-30t+225)+1125[/tex]

[tex]\implies h=-5(t-15)^2+1125[/tex]

The vertex (15, 1125) is the turning point of the parabola (minimum or maximum point).  As the leading coefficient of the given equation is negative, the parabola opens downward, and so vertex is the maximum point.  Therefore, the maximum height is the y-value of the vertex: 1125 metres.

Method 2

Differentiate the function:

[tex]\implies \dfrac{dh}{dt}=-10t+150[/tex]

Set it to zero and solve for t:

[tex]\implies -10t+150=0[/tex]

[tex]\implies 10t=150[/tex]

[tex]\implies t=15[/tex]

Input found value of t into the original function and solve for h:

[tex]\implies -5(15)^2+150(15)=1125[/tex]

Therefore, the maximum height is 1125 metres.

h=-5t²+150t

Convert to vertex form y=a(x-h)²+k

h=-5t²+150t+1125-1125h=-5t²+150t-1125+1125h=-5(t²-30t+225)+1125h=-5(t-15)²+1125

Vertex at (15,1125)

As a is negative parabola is opening downwards hence vertex is maximum

Max height=1125m

Solve the system of equations:
3x-y= 17
5x + 3y = 5
A.(-4,5)
B.(4,-5)
C.(-4,-5)
D.(4,5)

Answers

Answer:

x=

1

3

y+

17

3

Step-by-step explanation:

This is all i can get so far, if can improve opon this let me know

An amateur soccer ball is priced at
$19.50. This is 3/4ths the price of a
professional ball. What is the price of
the professional ball?

Answers

Answer: $26

Step-by-step explanation:

   If $19.50 is 3/4, we need to find 4/4.

3/4 -> 0.75

4/4 -> 1

    We will set up a proportion and solve.

[tex]\frac{19.5}{0.75} =\frac{x}{1}[/tex]

19.5 = 0.75x

26 = x

         The professional ball is $26.

Answer:

$26

Step-by-step explanation:

19.50 = 3/4

so

to find 1/4, we do 19.50 / 3 = 6.5

6.5 = 1/4

so the price of a professional ball would be 4/4 (1 whole)

6.5 x 4 = 26

Hope this makes sense.

- profparis

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During the 1870s, more progress was made, and track work moved forward at a greater pace. 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