how permeable and porous would an aquifer be?

Answer:

2.345 would be the most precious because you have more numbers to work with and exact numbers

c                                                                                                                                                  cccccccccccccccccccccccccccccccccccccccccccccccccccccc

Answer:

Encoding

Explanation:

Encoding is the initial learning of information. Encoding is the process of passing new information coming from sensory input  into our brain so that it can be easily retrievable. In a nutshell, it is the sum total of the processes by which external information such as the list of items your mother asked you to pick up at the grocery store to be converted into a manner that can be stored within the brain and recalled later from long-term memory.

Encoding has to do with transferring external stimuli into short term and subsequently long-term memory.

Answer:

hiatory

Explanation:

Answer:

A

Explanation:

Answer:

Explanation:

Remember, we are told that "Professor Wooddro teaches an Introduction to Philosophy at the college, and loves to talk about the meaning of life and death" which would require having verbal intelligence (the ability to understand and relate information using words).

Intrapersonal intelligence is also reflected by Professor Wooddro as we are told he "enjoys struggling with life's most challenging questions", which shows his knowledge of his own strengths or weaknesses.

Answer:

Radius, r = 100321.43m or 10.03 * 10^4m

Explanation:

Given the following data;

Acceleration, a = 0.028m/s²

Speed = 53m/s

Centripetal acceleration is given by the formula;

[tex] Acceleration, a = \frac {v^{2}}{r}[/tex]

Substituting into the equation, we have;

[tex] Acceleration, a = \frac {53^{2}}{0.028}[/tex]

[tex] Acceleration, a = \frac {2809}{0.028}[/tex]

Radius, r = 100321.43m or 10.03 * 10^4m

Answer:

1

 [tex] t_a  =  13.49 \  s   [/tex]

2

 The distance is   [tex] D = 55.2 \  m  [/tex]    

Explanation:

From the question we are told that

   The maximum speed of the cheetah is  [tex]v =  103 \  km/h =  28.61 \  m/s[/tex]

    The maximum of  gazelle is  [tex]u =  76.5 \  km/h =  21.25 \  m/s[/tex]

     The distance ahead is [tex]d =  99.3 \  m[/tex]

Let  [tex]t_a[/tex] denote the time which the cheetah catches the gazelle

Gnerally the equation representing the distance the cheetah needs to move in order to catch the gazelle is

           [tex] v* t_a = d +  u* t_a [/tex]

=>          [tex] 28.61 t_a = 99.3 +  21.25t_a [/tex]

=>          [tex] 7.36 t_a = 99.3  [/tex]

=>         [tex] t_a  =  13.49 \  s   [/tex]

Now at t =  7.5 s  

             [tex]7.5 v = D+  7.5u [/tex]

=>          [tex] 28.61 * 7.5  = D +  21.25* 7.5  [/tex]

=>          [tex] 7.36 *  7.5 =D  [/tex]

=>         [tex] D = 55.2 \  m  [/tex]        

Hence the for the gazelle to escape the cheetah it must be 55.2 m

Answer:

Astrophobia

Explanation:

heop it help

Answer:

Tech B is correct.

Explanation:

The voltage drop between the two terminals of a circuit is the measurement of the potential difference between the two terminals.

If [tex]v_1[/tex] and [tex]v_2[/tex] ( assuming [tex]v_1 > v_2[/tex]) are potentials at terminal 1 and terminal 2 of the given open circuit.

According to A, the measurement of the potential drop is 12 volts, i.e

The measurement of potential difference [tex]=v_1 -v_2[/tex]

= 12 volts which is correct.

But according to B, a measurement of 12 volts means there are 12 volts on each side of the switch ([tex]v_1= 12[/tex] volts and [tex]v_2=12[/tex] volts), i.e

According to the claim of B, the potential difference (or drop) across the terminals is

[tex]v_1-v_2= 12-12=0[/tex] but the measured potential drop is 12 volts, so B is wrong.

Hence, Tech B is correct.

Answer:

Explanation:

By multiplying the rotational frequency with the circumference we can determine the average speed of the object. The circular velocity formula is expressed as, vc = 2 πr / T. Where in, r denotes the radius of the circular orbit. T is time period.

Answer:

2πr

as we know that the circumference of a circle is 2 * π * r, the arc length of the whole circle is 2πr units. Then using the formula s = r * theta, the angle theta equals the arc length divided by the radius. Therefore theta = 2πr/r = 2π radians.

I hope it will helpful for you

mark as brainest answer

thank you

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\ [/tex]

We have

[tex]density = \frac{224}{53} \\ = 4.2264150943396...[/tex]

We have the final answer as

Hope this helps you

Answer:

The density is 4.2

Explanation:

D=M/V

Density is equal to mass/Volume thus D=M/V

Answer:

UR ANSWER IS WAVELENGTH

Answer:

Explanation:

In this case, gravity is pulling down on them ( both teams ), the strong - arm team is excerting thrust by trying to pull the rope, and you've got the drag of the other team pulling back.

Answer:

velocity is the speed and direction  of  a moving object

Explanation:

that is basicaly the defention

Answer:

[tex]F=-870\ N[/tex]

Explanation:

Net Force

The net force applied to an object of mass m that moves at an acceleration a is given by:

F=m.a

The acceleration can be calculated by the equations of the constant acceleration motion:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

Where vf is the final speed, vo is the initial speed, and t is the time.

Substituting the given values:

[tex]\displaystyle a=\frac{1-30}{2}=\frac{-29}{2}=-14.5\ m/s^2[/tex]

The force absorbed by his seat belt:

[tex]F=60\ kg\cdot (-14.5\ m/s^2)[/tex]

[tex]\boxed{F=-870\ N}[/tex]

Force absorbed by the seatbelt is : 870 N

Given data :

mass of body = 60 kg

Initial velocity ( V₁ ) = 30 m/s

Final velocity ( V₂ ) = 1 m/s

Time = 2 secs

Determine the force absorbed by the seat belt

Force = Mass * acceleration  --- ( 1 )

where ;

acceleration = Δ v / t  ---- ( 2 )

Δ v = ( 30 - 1 ) = 29 m/s

t = 2 secs

Back to equation ( 2 )

acceleration = 29 / 2 = 14.5 m/s²

∴ Force exerted on seatbelt

F = m * a

  = 60 kg * 14.5 m/s²  =  870 N

Hence we can conclude that the force absorbed by his seatbelt is 870 N

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Answer:

You should tell her in a nice way that that's just not your style and if she doesnt accept that then maybe you should just not talk to her for a while and let her cool down

Explanation:

Hope this helps

Answer:

140KG

Explanation:

Answer: true

Explanation:

Answer:

true

Explanation:

Using lubricants such as oil or grease can reduce the friction between the surfaces

Answer:

I think?

Explanation:

1.  20 seconds

2. 1 mile

3.  3 miles

I think i got it right not sure

Answer:

Explanation:

1m/ 10s^2

5 miles?

15 miles

Answer:

Alkaline earth metals.

Explanation:

For e.g The metals of group ll are: Be, Mg, Ca, etc

Answer:

ΔE = 1.031 eV

Explanation:

For this exercise let's calculate the energy of the photons using Planck's equation

          E = h f

wavelength and frequency are related

         c = λ f

         f = c /λ

let's substitute

         E = h c /λ

let's calculate

         E = 6.63 10⁻³⁴ 3 10⁸/1064 10⁻⁹

         E = 1.869 10⁻¹⁹ J

let's reduce to eV

         E = 1.869 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

        E = 1.168 eV

therefore the electron affinity is

         ΔE = E - 0.137

         ΔE = 1.168 - 0.137

         ΔE = 1.031 eV

The electron affinity of thulium in units of electron volts per atom is; ΔE ≈ 1.031 eV

From Planck's equation, we can find the energy of the photons when given wavelength as;

E = hc/λ

Where;

h is Planck's constant = 6.626 × 10⁻³⁴ J.s

c is speed of light = 3 × 10⁸ m/s

λ is wavelength

We are given;

wavelength; λ = 1064 nm = 1064 × 10⁻⁹ m

Thus;

E = (6.626 × 10⁻³⁴ × 3 × 10⁸)/(1064 × 10⁻⁹)

E2 = 1.868 × 10⁻¹⁹ J

Converting to eV gives;

E2 = (1.868 × 10⁻¹⁹)/(1.6 × 10⁻¹⁹)

E2 = 1.1675 eV

We are given E1 = 0.137 eV.

Now, electron affinity is simply change in energy. Thus;

ΔE = 1.1675 - 0.137

ΔE ≈ 1.031 eV

Read more at; https://brainly.com/question/14004834

Answer:

The weight of the dough bars after being cooked.

A road laid out on an air-hockey table, with a thin coat of ice on the table, and a little bit of oil or lard on top of the ice.

NOTE:  The car couldn't actually GO anywhere on this road, because a car needs friction in order to move where you want it to.  A car on THIS road would just go wherever the wind blew it.

Answer:

ummmmmwm whattt

Explanation:

wuhsnnsnsnsnms

Answer:

medicines

band-aids

aqua liquid

paracetamol

Explanation:

Extra items:

alcohol

cottons

bitadine

cotton buds

mask

One way:

The ball returned to the thrower's hand after 5 seconds.  It spent 2.5 seconds going up, and 2.5 seconds coming back down.

Use the formula Distance = (1/2) (acceleration) (time squared)

Distance = (1/2) (gravity) (2.5 sec)

Distance = (1/2) (9.8 m/s ²) (6.25 sec² )

Distance = (4.9 m/s²) (6.25 sec²)

Distance = 30.63 meters

Another way:

The thrower threw the ball straight up at 25 m/s.

It sailed upward for 2.5 seconds.

At the top of its trip, before it started falling, its speed was zero.

Its average speed was (1/2) (25+0) = 12.5 m/s

At an average speed of 12.5 m/s for 2.5s, the ball rose (12.5x2.5) = 31.25m.

(Why are the two answers different ?

Because if the ball was thrown straight up at 25 m/s, it would actually return to the thrower in 5.1 seconds, not 5.0 seconds.

So if you use the acceleration of gravity to solve the problem, you get one answer, but if you use 5.0sec to solve it, you get a slightly different one.)

Answer: 211.75m

Explanation:

Listing everything the question gives you:

Vi = 5.5

a = 2.5

t = 11

ΔX = ?

Then pick a kinematic equation to solve for the missing variable

I used this one: Δx = Vit + [tex]\frac{1}{2} at^2[/tex]

When you plug in all ur variables you get Δx = 211.75m

The object has travelled a distance of 211.75 meters.

We have an object moving with an initial velocity of 5.5 m/s.

We have to determine how far will it have traveled during the time of its acceleration.

The rate of change of velocity with respect to time is called Acceleration.

a = dv/dt

According to the question -

initial velocity = u = 5.5 m/s

acceleration = a = 2.5 m/s²

time = t = 11 seconds

Therefore -

S = ut + [tex]\frac{1}{2} at^{2}[/tex]

S = 5.5 x 11 + 0.5 x 2.5 x 11 x 11

S = 211.75 meters

Therefore, the object has travelled a distance of 211.75 meters.

To solve more questions on Kinematics visit the link below-

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Answer:

6.71dm³

Explanation:

Given parameters:

Initial Volume of hydrogen gas  = 8.98dm³

Initial Temperature  = 38.8°C; in Kelvin  = 38.8 + 273  = 311.8K

Final temperature = -39.9°C; in Kelvin  = -39.9 + 273  = 233.1K

Unknown:

Final volume = ?

Solution:

To solve this problem, we apply the Charles's law. It states at;

   "The volume of a fixed mass (mole) of a gas varies directly as its absolute temperature if the pressure is constant".

  Mathematically;

          [tex]\frac{V_{1} }{T_{1} }[/tex]   =      [tex]\frac{V_{2} }{T_{2} }[/tex]

V and T are temperature values

1 and 2 are the initial and final states

 Insert the parameters and solve for V₂

      [tex]\frac{8.98}{311.8 }[/tex]   = [tex]\frac{V_{2} }{233.1}[/tex]

         V₂ x 311.8 = 8.98 x 233.1

          V₂  = 6.71dm³