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Answer:

3Fe + 4H₂O --> Fe3O4 + 4H2

1.199 M is the concentration of KCI in the resulting solution.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

No.of moles of KCI

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{44.7 g}{74.5513 g/mol}[/tex]

= 0.599 moles

Vol.of the solution,V= 500 ml

= 0.5 liter

Molarity

[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]Molality = \frac{0.599 moles}{0.5 liter}[/tex]

= 1.199 M

Hence, 1.199 M is the concentration of KCI in the resulting solution.

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Answer:

Quadruple

Explanation:

Answer:

A

Explanation:

Answer:

1,135 grams P₄O₁₀

Explanation:

To find the mass, you need to (1) convert molecules to moles (via Avogadro's Number) and then (2) convert moles to grams (via molar mass from periodic table values). It is important to arrange the ratios/ conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 4 sig figs to reflect the given value (2.408 x 10²⁴).

Avogadro's Number:

1 mole = 6.022 x 10²³ molecules

tetraphosphorus decaoxide = P₄O₁₀

Molar Mass (P₄O₁₀): 4(30.974 g/mol) + 10(15.998 g/mol)

Molar Mass (P₄O₁₀): 283.876 g/mol

2.408 x 10²⁴ molecules P₄O₁₀                     1 mole                         283.876 g
-------------------------------------------  x  ------------------------------------  x  -----------------
                                                         6.022 x 10²³ molecules           1 mole

=  1,135 grams P₄O₁₀

The empirical formula for the compound is [tex]Fe_3PO_4[/tex] if A 8.63 g sample of a compound contains 5.51 g of iron, Fe, 1.02g of phosphorus, P, and oxygen, O.

An empirical formula tells us the relative ratios of different atoms in a compound.

We need to calculate the number of moles:

Given data:

Mass of iron - 5.51 g

Mass of phosphorus -1.02g

Mass of oxygen -2.1 g

Moles of iron - [tex]\frac{mass}{molar \;mass}[/tex]

Moles of iron - [tex]\frac{5.51 g}{56 g/mol}[/tex]

0.098 mole

Moles of phosphorus [tex]-\frac{mass}{molar \;mass}[/tex]

Moles of phosphorus -  [tex]\frac{1.02g}{31 g/mol}[/tex]

0.032 moles

Moles of oxygen -[tex]\frac{mass}{molar \;mass}[/tex]

Moles of oxygen - [tex]\frac{2.1 g}{16 g/mol}[/tex]

0.13moles

Dividing each mole using the smallest number that is divided by 0.032moles.

Fe:P:O :: 3:1:4

The empirical formula for the compound is [tex]Fe_3PO_4[/tex].

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The electrons are arranged in different orbitals, at different energy levels and sublevels.

An atomic orbital is a function describing the location and wave-like behavior of an electron in an atom.

This function can be used to calculate the probability of finding any electron of an atom in any specific region around the atom's nucleus.

Following are the sublevel with the maximum number of electrons that can be accommodated by it ;

Therefore, S-Subshell has 2 electrons, P-subshell has 3 electrons, d-subshell has 10 electrons and f-subshell has 14 electrons.

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Element X is sodium.

If there is one more shell of electrons, then this means it is one period below.

Since there is one less valence electron, it is one group to the left.

In the scientific sense the two examples of people doing work is: A and D

Work can be defined as a result of applying force to a particular object that changes its displacement in the direction of the applied force.

Work can only be done when their is a force that is being applied and a displacement that occurs.

In conclusion, In the scientific sense the two examples of people doing work is: A and D

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The weight of CoCl₂ used to make 0.5 ltr 1 Molar solution is 49.5g.

The weight of a substance can be calculated by multiplying the number of moles of the substance by its molar mass.

However,

the number of moles of CoCl₂ must be calculated using the following formula:

no of moles = 0.5L × 1M

no of moles = 0.5moles

Molar mass of CoCl₂ = 99g/mol

mass of CoCl₂  = 0.5 × 99

mass of CoCl₂  = 49.5g

Hence, the weight of CoCl₂ used to make 0.5 ltr 1 Molar solution is 49.5g.

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Gloves is the tool component which will unlikely present a hazard in this scenario.

This is referred to as potential source of harm when performing various types of activities.

Gloves will unlikely cause harm as it is used to prevent the risk of electric shock when handling electrical devices which is why it is the most appropriate choice.

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Answer:

4Al +3O₂ → 2Al₂O₃

Explanation:

To balance the chemical equation, start by identifying the number of atoms of each element on both sides of the equation.

Al +O₂ → Al₂O₃

Reactants (right-hand side of the arrow)

Al➭ 1

O➭ 2

Products (left-hand side of the arrow)

Al➭ 2

O➭ 3

Balancing the equation means that we need to ensure the number of atoms of each element is the same on both sides of the equation.

Let's balance the number of O atoms.

Al +3O₂ → 2Al₂O₃

Reactants

Al➭ 1

O➭ 3(2)= 6

Products

Al➭ 2(2)= 4

O➭ 2(3)= 6

Balancing the number of Al atoms:

4Al +3O₂ → 2Al₂O₃

Reactants

Al➭ 4

O➭ 6

Products

Al➭ 4

O➭ 6

The equation is now balanced.

Additional:

For a similar question on balancing equations, do check out the following!

Answer:

Ba, Pb, Sn, Se, Cl

Explanation:

The atomic radius increases when going right to left and top to bottom on the periodic table and decreases going the opposite way so I put it in order based on that.

Answer:

A nonmetal is a chemical element that generally lacks a predominance of metallic properties. Non-metals are mostly found in groups 5, 6 and 7. These non-metals will have 5, 6 or 7 electrons in the outer shell.

The outer shell of a non-metal is, therefore, more than half full of electrons.

Answer:

N-Cl

Explanation:

Look at the chart below. Since N-Cl bond has a electronegativity difference of (3.0-3.0) zero, they are non-polar.

2.73 atm is the pressure in the vessel. Hence, option B is correct.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= ?

V= 25.1 L

[tex]n= \frac{m}{molar \;mass \;of \;nitrogen} + \frac{m}{molar \;mass \;of \;hydrogen } +\frac{m}{molar \;mass \;of \;argon}[/tex]

[tex]n= \frac{2.80 g}{14} + \frac{0.605 g}{1} +\frac{79.9 g}{40}[/tex]

n= 2.8025

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=25°C + 273= 298 K

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]2.8025 = \frac{P\; X \;25.1 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]

P = 2.73 atm

2.73 atm is the pressure in the vessel. Hence, option B is correct.

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Gamma rays are high-energy electromagnetic waves given off during nuclear decay; option A.

Electromagnetic waves are waves which are produced as a result of the interaction of the magnetic and electric fields.

Types of electromagnetic waves include gamma rays, radio waves, ultraviolet waves.

Gamma rays are high-energy electromagnetic waves given off during nuclear decay

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Answer:

A

Explanation:

Taking into account the reaction stoichiometry, 4.515 grams of N₂ can be produced from 8.73 grams of H₂O₂ and 5.16 grams of N₂H₄.

In first place, the balanced reaction is:

N₂H₄ + 2 H₂O₂ → N₂ + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 34 grams of H₂O₂ reacts with 32 grams of N₂H₄, 8.73 grams of H₂O₂ reacts with how much mass of N₂H₄?

[tex]mass of N_{2} H_{4} =\frac{8.73 grams of H_{2} O_{2}x 32 grams of N_{2} H_{4} }{34grams of H_{2} O_{2}}[/tex]

mass of N₂H₄= 8.22 grams

But 8.22 grams of N₂H₄ are not available, 5.16 grams are available. Since you have less mass than you need to react with 8.73 grams of H₂O₂, N₂H₄ will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of N₂H₄ form 28 grams of N₂, 5.16 grams of N₂H₄ form how much mass of N₂?

[tex]mass of N_{2} =\frac{5.16 grams of N_{2} H_{4} x28 grams of N_{2}}{32 grams of N_{2} H_{4} }[/tex]

mass of N₂= 4.515 grams

Then, 4.515 grams of N₂ can be produced from 8.73 grams of H₂O₂ and 5.16 grams of N₂H₄.

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Answer:

I believe it is 68

Explanation:

to convert Celsius to kelvins you must add it to 273.15 for example 29 + 273.15 is 302.15

im so very sorry if im wrong.

The amount of ice converted into steam is 13.23 gram.

Heat of Vaporisation is the amount of heat required to convert 1 gm to liquid at its boiling point to vapour.

Let x gram of ice is there

At first x gm of ice will melt

The heat required is x * Heat of fusion = x * 79.9 = 79.9x

Then the heat required to rise the temperature of x gm of water from 0 degree to 100 degree Celsius .

= mc ΔT

= x * 1 * 100 = 100x

The heat required to convert x gm of liquid into x gm of steam

= x * 540 = 540x

The total heat supplied is 9522 cal

79.9x + 100x + 540x = 9522

719.9 x = 9522

x = 13.23 gm

The amount of ice converted into steam is 13.23 gram.

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Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.

Normality comes out to be 8.11

n-factor for [tex]Al_{2}S_{3}[/tex] is 6 and molar mass is 148g

So, on calculating equivalent mass is equal to 24.66g

FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)

                                           N=[tex]\frac{1000}{24.66*5}[/tex]

                                          N=8.11

Therefore, normality of 1 kg aluminum sulfide is 8.11

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The amount of energy absorbed by the 325g of water is 57,057J. Details about calorimetry can be found below.

The energy absorbed by a mass of substance can be calculated using the following formula;

Q = mc∆T

Where;

Q = 325g × 4.18 × (92 - 50)

Q = 57,057J

Therefore, the amount of energy absorbed by the 325g of water is 57,057J.

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Answer: A. Simple structure, molecule, single bonds, two elements

Answer:

[tex]a. \ \ \ \text{The mass of ethylene is 11.375 g}. \\ \\ b. \ \ \ \text{The volume of water produced is 7.875 ml}.[/tex]

Explanation:

a. According to the chemical equation for the combustion of ethylene, 5

   moles of oxygen are required to react with 2 moles of ethylene, hence

           [tex]m_{C_{2}H_{2}} \ = \ 35 \ \text{g} \ \times \ \displaystyle\frac{1 \ \text{mol}}{\left(2 \times 16 \right) \text{g}} \ \times \ \displaystyle\frac{2 \ \text{mol}}{5 \ \text{mol}} \ \times \ \displaystyle\frac{\left(12 \ \times \ 2 \ + \ 1 \ \times \ 2 \right) \ \text{g}}{1 \ \text{mol}} \\ \\ m_{C_{2}H_{2}} \ = \ 11.375 \ \text{g}[/tex]

b. Similarly, 5 moles of oxygen are required as a reactant to produce 2  

    moles of water, thus

             [tex]m_{H_{2}O} \ = \ 35 \ \text{g} \ \times \ \displaystyle\frac{1 \ \text{mol}}{\left(2 \times 16 \right) \text{g}} \ \times \ \displaystyle\frac{2 \ \text{mol}}{5 \ \text{mol}} \ \times \ \displaystyle\frac{\left(1 \ \times \ 2 \ + \ 16 \right) \ \text{g}}{1 \ \text{mol}} \\ \\ m_{H_{2}O} \ = \ 7.875 \ \text{g}[/tex]

      Given that the density of water is [tex]1.0 \ \text{g ml}^{-1}[/tex], therefore

                                               [tex]\rho_{H_{2}O} \ = \ \displaystyle\frac{m_{H_{2}O}}{V_{H_{2}O}} \\ \\ V_{H_{2}O} \ = \ \displaystyle\frac{m_{H_{2}O}}{\rho_{H_{2}O}} \\ \\ V_{H_{2}O} \ = \ \displaystyle\frac{7.875 \ \text{g}}{1.0 \ \text{g ml}^{-1}} \\ \\ V_{H_{2}O} \ = \ 7.875 \ \text{ml}[/tex]

11.375 g ethylene is consumed if 35.0 grams of oxygen is allowed to react and 7.875 ml of water will be produced when the 35.0 grams of oxygen is allowed to react.

A mole is defined as 6.02214076 ×[tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

According to the chemical equation for the combustion of ethylene, 5

moles of oxygen are required to react with 2 moles of ethylene, hence

[tex]m_{_C_2_H_2}[/tex]  [tex]= 35gX \frac{1 mol}{(2 \;X\; 16)g } X \frac{2 mol}{(5\;mol )} X \frac{26g}{1 mol }[/tex]

[tex]m_{_C_2_H_2} = 11.375 g[/tex]

Similarly, 5 moles of oxygen are required as a reactant to produce 2 moles of water, thus

[tex]m_{_H_2_O} = 35gX \frac{1 mol}{(2 \;X\; 16)g } X \frac{2 mol}{(5\;mol )} X \frac{18g}{1 mol }[/tex]

[tex]m_{_H_2_O} = 7.875 g[/tex]

Given that the density of water is [tex]1.0g ml^{-1}[/tex], therefore

[tex]Density = \frac{Mass \;of \;water}{Volume \;of \;water}[/tex]

[tex]Volume \;of \;water = \frac{7.875}{1.0 g ml^{-1}}[/tex]

The volume of water = 7.875 ml

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Answer:

55 grams

Explanation:

 55 grams of calcium chloride is the equivalent weigh because 55 grams of calcium chloride would supply one mole of positive or negative charges when dissolved in water.

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The moles of nitrogen produced is 0.40 moles of ammonia.

The Percent yield of ammonia is 81.2%

The moles of ammonia produced is obtained from the mole ratio of the reaction.

The mole ratio of hydrogen to nitrogen is 3 : 2

Based on the mole ratio, the limiting reactant is hydrogen.

Moles of nitrogen produced = 0.600 * 2/3 = 0.40 moles of ammonia.

mass of ammonia expected = 0.4 * 17 g = 6.8 g

Percent yield = 5.52/6.8 * 100% = 81.2%

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