Help please. help please. Below please

Help Please. Help Please. Below Please

Answers

Answer 1

Answer:

x = 30pitch = 7

Step-by-step explanation:

If you draw a horizontal line through the shaded triangle such that it intersects the left vertex, you see that it bisects the 60° angle at that vertex. The measure of x is the same as the measure of either half of that bisected angle, so is 30°.

The pitch associated in the table with an angle of 30° is 7.

x = 30pitch = 7

Related Questions

Find the acute angle between the diagonal of rectangle whose sides are 5cm and 7cm

Answers

Answer:

The arc tangent of angle a = (5/7)

angle a = 35.538 Degrees

Of course, we might be solving for angle b so,

angle b = 90 -35.538 Degrees = 54.462  Degrees

Step-by-step explanation:

Which is the vertex of x^2 + 10x = - 17?

Answers

Answer:

(-5, -8)

Step-by-step explanation:

Parabolas always have a lowest point (or a highest point, if the parabola is upside-down). This point, where the parabola changes direction, is called the "vertex". If the quadratic is written in the form y = a(x – h)2 + k, then the vertex is the point (h, k).

x^2 + 10x = - 17

x^2+10x+17=0

x^2+2*5x+25 - 8=0

(x+5)^2-8=0

h=-5, k= -8

vertex is (-5, -8)

Mme.​ Giselle's boutique in​ Cleveland, Ohio is planning to sell a Parisian frock. If the public view it as being the latest​ style, the frocks will be worth ​$10 comma 000. ​ However, if the frocks are viewed as​ passe, they will be worth only ​$2 comma 000. If the probability that they are stylish is 10​%, what is the expected value of the​ frocks? The expected value of the frocks​ (EV) is EVequals​$ nothing. ​(Enter your response rounded to two decimal​ places.)

Answers

Answer:

the expected value of the frocks​ (EV) is 2800

Step-by-step explanation:

the expected value of the frocks= (probability of stylish* worth)+(probability of passe* worth)

If the public view it as being the latest​ style, the frocks will be worth ​$10,000. ​

if the frocks are viewed as​ passe, they will be worth only ​$2,000.

If the probability that they are stylish is 10​%

probability of stylish = 10000

worth = 10%

probability of passe = 2000

[tex]=10 \%*10000+(1-10 \%)*2000\\\\=0.1\times 10000+(1-0.1)\times2000\\\\=1000+(0.9)\times2000\\\\=1000+1800\\\\=2800[/tex]

Therefore, the expected value of the frocks​ (EV) is 2800

When we multiply a number by 3, we

sometimes/always/never v

get the same value as if we added 6

to that number.

Stuck? Watch a video or use a hint.

Report a problem

7 of 7 ..

nyone, anywhere

Imnact

Math by grace

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Answers

Answer:

? what's the question??????????????????

Factor completely x3 + 9x2 + 27x+ 27

Answers

Answer:

(x + 3)^3

Step-by-step explanation:

I don't exactly know how to break this down into small steps. I can tell you that it is something like (x + a)^3

It turns out that a = 3 because all the signs in the given equation are +

Answer

(x + a) = (x + 3)^3

What is the sum of 7 3/5 and 2 4/5?

Answers

Step-by-step explanation:

[tex]7 \times \frac{3}{5} + 2 \times \frac{4}{5} \\ \frac{38}{5} + \frac{14}{5} \\ \frac{38 + 14}{5} \\ \frac{52}{5} \\ 10 \times \frac{2}{5} [/tex]

Answer:

Step-by-step explanation

7 [tex]\frac{3}{5}[/tex] + 2  [tex]\frac{4}{5}[/tex]

= 38/5 + 14/5

=52/5

The proportion of items in a population that possess a specific attribute is known to be 0.40. If a simple random sample of size 100 is selected and the proportion of items in the sample that contain the attribute of interest is 0.46​, what is the sampling​ error?

Answers

Answer:

The sampling error =  0.06

Step-by-step explanation:

From the given information:

Let represent [tex]\beta[/tex] to  be the population proportion = 0.4

The sample proportion be P = 0.46   &

The sample size be n = 100

The population standard duration can be expressed by the relation:

Population standard duration [tex]\sigma = \sqrt{\dfrac{\beta(1- \beta)}{n}}[/tex]

[tex]\sigma = \sqrt{\dfrac{0.4(1-0.4)}{100}}[/tex]

[tex]\sigma = \sqrt{\dfrac{0.4(0.6)}{100}}[/tex]

[tex]\sigma = 0.049[/tex]

The sample proportion = 0.46

Then the sampling error  = P - [tex]\beta[/tex]

The sampling error  = 0.46 - 0.4

The sampling error =  0.06

16. The population of a town is 41732. If there are 19569 male then find the
number of females in the towny

Answers

Answer:

The answer is, 22,163

Step-by-step explanation:

Take the total amount of people (41732) and subtract the amount of males (19569) to get your answer.

41732-19569=22,163

An insurance company charges $800 annually for car insurance. The policy specifies that the company will pay $1000 for a minor accident and $5000 for a major accident. If the probability of a motorist having a minor accident during the year is 0.2 and of having a major accident is 0.05 (and these events are mutually exclusive), what is the insurance company's expected profit on the policy

Answers

Answer: the expected profit will be $755 annually.

Explanation: Expected Profit (EP) = Charges (income for the insurance company) - probability of minor accidents X amount payable for a minor accident - probability of mayor accidents X amount payable for a major accident.

800- 1000 (0.2) -5000 (0.05)= 800-20-25= 755

what is a acute?? i dont really seem to get it

Answers

Answer:

an angle less than 90 degrees

Step-by-step explanation:

so like this angle /_

this is obtuse \_

this is right |_

Suppose that an outbreak of cholera follows severe flooding in an isolated town of 3662 people. Initially (Day 0), 36 people are infected. Every day after, 34% of those still healthy fall ill.


How many people will be infected by the end of day 9?

Answers

Answer:

3576 infected people

Step-by-step explanation:

We have to apply the following formula, which tells us the number of healthy people:

A = p * (1 - r / 100) ^ t

where,

p = initial population,

r = rate of change per period (days)

t = number of periods (days)

Now, we know that the initial population is 3,662 but there are already a total of 36 infected, therefore:

3662 - 36 = 3626

that would be our p, now, we replace:

A = 3626 * (1 - 34/100) ^ 9

A = 86.16

Therefore, those infected would be:

3662 - 86.16 = 3575.84

This means that there are a total of 3576 infected people.

Pls pls pretty pls do any of these whatever you know pls

Answers

Answer:

5) 8

6) True, a trapezium has at least 1 parallel side, and a parallelogram has 2.

7) I can't see where angle z is..., but x=42 and y= 96

Step-by-step explanation:

A rhombus has all sides of equal length, thus, if DC is 5, then all the other sides are also 5.

We see that AC is 6, and OC will be 3, or 6/2.

The pythagorean theorem shows that OD is 4, and BD is 8.

42+42=84

180-84=96

Answer:

5. BD = 8 cm

6. See explanation below.

7. x = 42; y = 96; z = 64

Step-by-step explanation:

5.

DC = 5 cm

The diagonals of a rhombus bisect each other, so since AC = 6 cm, OC = 3 cm.

The diagonals of a rhombus are perpendicular to each other, so triangle DOC is a right triangle with right angle DOC.

a^2 + b^2 = c^2

(DO)^2 + (OC)^2 = (DC)^2

(DO)^2 + (3 cm)^2 = (5 cm)^2

(DO)^2 + 9 cm^2 = 25 cm^2

(DO)^2 = 16 cm^2

DO = 4 cm

Since BD = 2DO,

BD = 2(4 cm) = 8 cm

Answer: BD = 8 cm

6.

There are different definitions of trapezium. In the U.S., trapezium is a quadrilateral, none of whose sides are parallel. According to the U.S. definition of trapezium, then, no parallelogram is a trapezium.

According to the UK definition of trapezium, a trapezium is a quadrilateral with at least 2 parallel sides. That means the other two sides may or may not be parallel. According to this definition, then a parallelogram is always a trapezium.

8.

Triangle ADB is isosceles with AD = AB. That meakes their opposite angles congruent.

x = m<ADB = 42

42 + 42 + y = 180

y = 96

In a kite, there are two pairs of congruent sides. DC = BC, so z = m<BDC

z + z + 52 = 180

2z = 128

z = 64

The number of 6th graders in RSM summer camp to that of 7th graders was 4 to 11, while the number of 5th graders to that of the 6th graders was 13 to 9. By what percent did the number of 7th graders exceed that of the number of 5th and 6th graders taken together ?

Answers

Answer:

The number of 7th graders exceed that of the number of 5th and 6th graders taken together by 5.88%.

Step-by-step explanation:

I am going to say that:

x is the proportion of 5th graders.

y is the proportion of 6th graders.

z is the proportion of 7th graders.

The number of 6th graders in RSM summer camp to that of 7th graders was 4 to 11

This means that:

[tex]\frac{y}{z} = \frac{4}{11}[/tex]

So

[tex]11y = 4z[/tex]

[tex]y = \frac{4z}{11}[/tex]

The number of 5th graders to that of the 6th graders was 13 to 9.

This means that:

[tex]\frac{x}{y} = \frac{13}{9}[/tex]

[tex]9x = 13y[/tex]

[tex]x = \frac{13y}{9}[/tex]

All of them is 100%

This means that:

[tex]x + y + z = 1[/tex]

We need to find z.

[tex]y = \frac{4z}{11}[/tex]

[tex]x = \frac{13y}{9} = \frac{13*4z}{9*11} = \frac{52z}{99}[/tex]

Then

[tex]x + y + z = 1[/tex]

[tex]\frac{52z}{99} + \frac{4z}{11} + z = 1[/tex]

The lcm(least common multiple) between 11 and 99 is 99. Then

[tex]\frac{52z + 9*4z + 99z}{99} = 1[/tex]

[tex]187z = 99[/tex]

[tex]z = \frac{99}{187}[/tex]

[tex]z = 0.5294[/tex]

By what percent did the number of 7th graders exceed that of the number of 5th and 6th graders taken together ?

z(7th graders) is 52.94%.

x + y(5th and 6th graders) is 100 - 52.94 = 47.06%

52.94 - 47.06 = 5.88

The number of 7th graders exceed that of the number of 5th and 6th graders taken together by 5.88%.

5500 milliliters equal how many liters show work

Answers

Answer:

5.5 liters

Step-by-step explanation:

1 milliliter equals to 1/1000 part of a liter, which is 0.001 liter.

1 milliliter = 1 * 0.001 liter

So if you have 5500 milliliters that means it equals to 5500 times one milliliters and 1 milliliter = 1 * 0.001 liter, so for 5500 milliliters it is 5500 times as much

5500 * 0.001

5500 * 1/1000

5500 / 1000

5.5 liters

As long as you know this number 0.001 , then it is easily to calculate between liters and milliliters.

EXTRA:

To convert from amount A which is given in a certain quantity, to another quantity, you sometimes have to multiply and in other cases you need to divide by a certain factor. The factor defines the relationship between the quantities.

Suppose you have 1000 times 1 milliliter then you can find the amount in liters by multiplying that number of milliliters times 0.001.

It is easy to see that

1000 * 1/1000

1000 / 1000

= 1 liter, but that is easy, because I choose an easy number for the amount of milliliters to convert into liters. But it works exactly the same for any amount!

The best and correct answer is 5.5 liters because in my brain I calculate it already

The distribution of grades in an introductory finance class is normally distributed, with an expected grade of 68. If the standard deviation of grades is 15, in what range would you expect 68.26 percent of the grades to fall? (Round answers to 2 decimal places, e.g. 15.25. Hint: Think in terms of what the expected highest and lowest scores would be for 68.26% of the students taking the exam.)

Answers

Answer:

The range that you would expect 68.26 percent of the grades to fall is between 53 and 83.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 68, \sigma = 15[/tex]

Middle 68.26% of the grades:

From the

50 - (68.26/2) = 15.87th percentile

To the

50 + (68.26/2) = 84.13rd percentile.

15.87th percentile:

X when Z has a pvalue of 0.1587. So X when Z = -1.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1 = \frac{X - 68}{15}[/tex]

[tex]X - 68 = -1*15[/tex]

[tex]X = 53[/tex]

84.13rd percentile:

X when Z has a pvalue of 0.8413. So X when Z = 1.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1 = \frac{X - 68}{15}[/tex]

[tex]X - 68 = 1*15[/tex]

[tex]X = 83[/tex]

The range that you would expect 68.26 percent of the grades to fall is between 53 and 83.

Which of the following is the result of the operation below?

Answers

Answer:

The result of the operation is:

[tex]\left[\begin{array}{ccc|c}1&2&3&6\\0&-1&-2&-8\\0&2&1&5\end{array}\right][/tex]

Step-by-step explanation:

The matrix provided is:

[tex]\left[\begin{array}{ccc|c}1&2&3&6\\1&1&1&-2\\0&2&1&5\end{array}\right][/tex]

The operation to be performed is:

[tex]-R_{1}+R_{2}[/tex] → [tex]R_{2}[/tex]

The operation implies that, we need to replace the values in row 2 by the result of the expression ([tex]-R_{1}+R_{2}[/tex]).

Complete the operation as follows:

[tex]\left[\begin{array}{ccc|c}1&2&3&6\\1&1&1&-2\\0&2&1&5\end{array}\right]\rightarrow \ \left[\begin{array}{ccc|c}1&2&3&6\\(-1+1)&(-2+1)&(-3+1)&(-6-2)\\0&2&1&5\end{array}\right][/tex]

                            [tex]\rightarrow\ \left[\begin{array}{ccc|c}1&2&3&6\\0&-1&-2&-8\\0&2&1&5\end{array}\right][/tex]

Thus, the result of the operation is:

[tex]\left[\begin{array}{ccc|c}1&2&3&6\\0&-1&-2&-8\\0&2&1&5\end{array}\right][/tex]

Answer:

A

Step-by-step explanation:

edge 2021

f(x) = x2 + 1
g(x) = 5-x
(f+g)(x) =
O x2 + x-4
x²+x+4
O x2-x+6
O x2 + x + 6

Answers

Answer:

[tex] \boxed{(f + g)(x) = {x}^{2} - x + 6} [/tex]

Given:

[tex]f(x) = {x}^{2} + 1 \\ \\ g(x) = 5 - x[/tex]

To Find:

[tex](f + g)(x) = f(x) + g(x)[/tex]

Step-by-step explanation:

[tex] = > f(x) + g(x) = ({x}^{2} + 1) + (5 - x) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + 1 + 5 - x\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + 6 - x\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} - x + 6[/tex]

Solve for x.
x + 3 = Sqrt 4x+17

Answers

Answer:

Step-by-step explanation

what is the area of a circle with a radius of 42 in use 3.14 for pi​

Answers

Answer:

[tex] \boxed{Area \: of \: circle = 5538.96 {in}^{2}} [/tex]

Step-by-step explanation:

Radius (r) = 42 in.

Area of circle = πr²

= 3.14 × (42)²

= 3.14 × 1764

= 5538.96 in²

Suppose your marketing colleague used a known population mean and standard deviation to compute the standard error as 52.4 for samples of a particular size. You don't know the particular sample size but your colleague told you that the sample size is greater than 70. Your boss asks what the standard error would be if you quintuple (5x) the sample size. What is the standard error for the new sample size? Please round your answer to the nearest tenth.

Answers

Answer:

The new standard error is [tex]e_{new} = 23.4[/tex]

Step-by-step explanation:

 From the question we are told that

   The standard  error is  [tex]e = 52.4[/tex]

   

Generally the standard error is mathematically represented as

       [tex]e = \frac{6}{\sqrt{n} }[/tex]

Where n is the sample size

for the original standard error we have

          [tex]52.4 = \frac{6}{\sqrt{n} }[/tex]

Now sample size is quintuple

     [tex]e_{new} = \frac{6}{\sqrt{5 * n} }[/tex]

    [tex]but \ \ 52.4 = \frac{6}{\sqrt{n} }[/tex]

  So    [tex]e_{new} = \frac{52.4}{\sqrt{5} }[/tex]

          [tex]e_{new} = 23.4[/tex]

If 20% of the people in a community use the emergency room at a hospital in one year, find

the following probability for a sample of 10 people.

a) At most three used the emergency room

b) Exactly three used the emergency room

c) At least five used the emergency room​

Answers

Answer:

a) 87.91% probability that at most three used the emergency room

b) 20.13% probability that exactly three used the emergency room.

c) 3.28% probability that at least five used the emergency room​

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they use the emergency room, or they do not. The probability of a person using the emergency room is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Sample of 10 people:

This means that [tex]n = 10[/tex]

20% of the people in a community use the emergency room at a hospital in one year

This means that [tex]p = 0.2[/tex]

a) At most three used the emergency room

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074[/tex]

[tex]P(X = 1) = C_{10,1}.(0.2)^{1}.(0.8)^{9} = 0.2684[/tex]

[tex]P(X = 2) = C_{10,2}.(0.2)^{2}.(0.8)^{8} = 0.3020[/tex]

[tex]P(X = 3) = C_{10,3}.(0.2)^{3}.(0.8)^{7} = 0.2013[/tex]

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.1074 + 0.2684 + 0.3020 + 0.2013 = 0.8791[/tex]

87.91% probability that at most three used the emergency room

b) Exactly three used the emergency room

[tex]P(X = 3) = C_{10,3}.(0.2)^{3}.(0.8)^{7} = 0.2013[/tex]

20.13% probability that exactly three used the emergency room.

c) At least five used the emergency room​

[tex]P(X \geq 5) = 1 - P(X < 5)[/tex]

In which

[tex]P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex]

From 0 to 3, we already have in a).

[tex]P(X = 4) = C_{10,4}.(0.2)^{4}.(0.8)^{6} = 0.0881[/tex]

[tex]P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.1074 + 0.2684 + 0.3020 + 0.2013 + 0.0881 = 0.9672[/tex]

[tex]P(X \geq 5) = 1 - P(X < 5) = 1 - 0.9672 = 0.0328[/tex]

3.28% probability that at least five used the emergency room​

If a rectangle has a width of 7 centimeters less than it’s length, and it’s area is 330 square centimeters. What are it’s length and width

Answers

Answer:

length 22 cmwidth 15 cm

Step-by-step explanation:

If we assume the length and width are integer numbers of centimeters, we can look at the factors of 330:

  330 = 1×330 = 2×165 = 3×110 = 5×66 = 6×55 = 10×33 = 11×30 = 15×22

The factors in this last pair differ by 7, so represent the width and length of the rectangle.

The rectangle's length and width are 22 cm and 15 cm, respectively.

On her way to work, a commuter encounters four traffic signals. Assume that the distance between each of the four is sufficiently great that her probability of getting a green light at any intersection is independent of what happened at any previous intersection. The first two lights are green for forty seconds of each minute; the last two, for thirty seconds of each minute.What is the probability that the commuter has to stop at least three times?

Answers

Answer:

7 in 36 or 0.1944

Step-by-step explanation:

The probability of having to stop at least three times is the probability of getting 3 or 4 red lights.

For the first two lights, the probability of getting them red is 20 in 60 (1/3).

For the last two lights, the probability of getting them red is 30 in 60 (1/2).

The probability of all of them being red is:

[tex]P(R=4) = \frac{1}{3}*\frac{1}{3}*\frac{1}{2}*\frac{1}{2}\\P(R=4) =\frac{1}{36}=\frac{1}{36}[/tex]

The probability of three of them being red (3 red + 1 green) is:

[tex]P(R=3) = {(1-\frac{1}{3})*\frac{1}{3}*\frac{1}{2}}*\frac{1}{2}+(1-\frac{1}{3})*\frac{1}{3}*\frac{1}{2}*\frac{1}{2}+\frac{1}{3}*\frac{1}{3}*(1-\frac{1}{2})*\frac{1}{2}+\frac{1}{3}*\frac{1}{3}*(1-\frac{1}{2})*\frac{1}{2}\\P(R=3) =2*(\frac{2}{3}*\frac{1}{3}*\frac{1}{2}*\frac{1}{2})+2*(\frac{1}{3}*\frac{1}{3}*\frac{1}{2}*\frac{1}{2})\\ P(R=3) =\frac{4}{36}+\frac{2}{36}\\ P(R=3) =\frac{6}{36}[/tex]

Therefore, the probability of at least three red lights is:

[tex]P=\frac{1}{36}+\frac{6}{36}=\frac{7}{36}\\ P=0.1944[/tex]

The probability is 7 in 36 or 0.1944.

The probability that the commuter has to stop at least three times is at least 5.55%.

Since on her way to work, a commuter encounters four traffic signals, assuming that the distance between each of the four is sufficiently great that her probability of getting a green light at any intersection is independent of what happened at any previous intersection, and the first two lights are green for forty seconds of each minute; the last two, for thirty seconds of each minute, to determine what is the probability that the commuter has to stop at least three times the following calculation must be performed:

4/6 = 2/3 = 0.66666  0.5 x 0.5 x 0.333 = 0.083333 0.5 x 0.333 x 0.333 = 0.055555

Therefore, the probability that the commuter has to stop at least three times is at least 5.55%.

Learn more in https://brainly.com/question/23273737

Consider the line 9x – 7y=-8.
What is the slope of a line perpendicular to this line?
What is the slope of a line parallel to this line?
Slope of a perpendicular line:
Х
?
Slope of a parallel line:

Answers

Answer:

Step-by-step explanation:

Before you can answer you have to solve the equation for y.

Y = 9/7 x+8/7

Parallel lines have the same slope so would also be 9/7

Perpendicular lines have opposite reciprocal slope so would be -7/9

Answer:

y=-9/7x-8/7

Step-by-step explanation:

9x – 7y=-8

-9x           -9x

-7y=-9x-8

then divide all sides by -7

y=-9/7x-8/7

During a typical Pennsylvania winter, I80 averages 1.6 potholes per 10miles. A certain county is responsible for repairing potholes in a 30-mile stretch of the interstate. LetXdenote the number of potholes thecounty will have to repair at the end of next winter.
(a) The distribution of the random variable X is (choose one)
(i) binomial
(ii) hypergeometric
(iii) negative binomial
(iv) Poisson.
(b) Give the expected value and variance of X.
(c)The cost of repairing a pothole is $5000. If Y denotes the county’s pothole repair expense for next winter, find the mean value and variance Y?

Answers

Answer:

a) (iv) Poisson.

b) E(X)=V(X)=λ=4.8

c) E(Y)=24,000

V(Y)=120,000,000

Step-by-step explanation:

We can appropiately describe this random variable with a Poisson distribution, as the probability of having a pothole can be expressed as a constant rate per mile (0.16 potholes/mile) multiplied by the stretch that correspond to the county (30 miles).

The parameter of the Poisson distribution is then:

[tex]\lambda=0.16\cdot 30=4.8[/tex]

b) The expected value and variance of X are both equal to the parameter λ=4.8.

c) If we define Y as:

[tex]Y=5000X[/tex]

the expected value and variance of Y are:

[tex]E(Y)=E(5,000\cdot X)=5,000\cdot E(X)=5,000\cdot 4.8=24,000\\\\\\ V(Y)=V(5000\cdot X)=5000^2\cdot V(X)=25,000,000\cdot 4.8=120,000,000[/tex]

The price of a truck depreciates 15% in a year.
What will be its price in a year if the initial price is
currently 25.000$? -​

Answers

Answer:

$1.66666667 (or just 1.6)

Step-by-step explanation:

$25.000 US dollars divided by 15 = $1.66666667 US dollars

Find the probability of the indicated event if ​P(E)equals0.25 and ​P(F)equals0.40. Find​ P(E or​ F) if​ P(E and ​F)equals0.05.

Answers

Answer:

[tex] P(E) =0.25, P(F) = 0.40, P(E \cap F) =0.05[/tex]

[tex] P(E \cup F)= P(E) +P(F) -P(E \cap F)[/tex]

And replacing we got:

[tex] P(E \cup F)=0.25 +0.40 -0.05 = 0.6[/tex]

Step-by-step explanation:

For this case we have the following probabilities given:

[tex] P(E) =0.25, P(F) = 0.40, P(E \cap F) =0.05[/tex]

And we want to find this probability:

[tex] P(E \cup F)[/tex]

And we can use the total probability rule given by:

[tex] P(E \cup F)= P(E) +P(F) -P(E \cap F)[/tex]

And replacing we got:

[tex] P(E \cup F)=0.25 +0.40 -0.05 = 0.6[/tex]

4-3 times 54 divided by 9 (Explain)

Answers

Answer:

6

Step-by-step explanation:

4-3x54÷9

How I'd do it is separate it:

4-3=1

Then 1x54=54

Then 54/9=6

Answer:

6

Step-by-step explanation:

[tex]4-3*54/9\\4-3 =1\\1*54 =54 \\54/9 =6[/tex]

When dots are printed from a laser printer to form letters, they must be close enough so that you do not see the individual dots of ink. To do this, the separation of the dots must be less than Raleigh's criterion of your eye at distances typical for reading Randomized Variables D 2.5 mm d-38 cm Take the pupil of the eye to be 2.5 mm in diameter and the distance from the paper to the eye as 38 cm. Find the minimum separation of two dots such that they cannot be resolved in cm. Assume a wavelength of 555 nm for visible light.

Answers

Answer:

The minimum separation is  [tex]z = 1.0292 *10^{-4} \ m[/tex]

Step-by-step explanation:

    From the question we are told that

         The  reading randomized variable are [tex]D= 2.5 \ mm[/tex] and [tex]d = 38 \ cm[/tex]

          The diameter of the pupil is  [tex]d = 2.5 \ mm = \frac{2.5}{1000} = 0.0025 \ m[/tex]

            The distance from the paper is [tex]D = 38 \ cm = 0.38 \ m[/tex]

            The wavelength is  [tex]\lambda = 555 \ nm = 555 * 10 ^{-9} m[/tex]

Generally the Raleigh's equation for resolution is  

             [tex]\theta = 1.22 [\frac{\lambda}{D} ][/tex]

substituting values

               [tex]\theta = 1.22 * \frac{555*10^{-9}}{0.0025}[/tex]  

              [tex]\theta = 2.7084*10^{-4} \ rad[/tex]

The minimum separation of two dots is mathematically represented as

            [tex]z = \theta d[/tex]

substituting values

            [tex]z = 2.7084*10^{-4} * 0.38[/tex]

             [tex]z = 1.0292 *10^{-4} \ m[/tex]

Nancy has to cut out circles of diameter 1 3/ 7 cm from an aluminium strip of dimensions 7 1/ 7 cm by 1 3/ 7 cm . How many full circles can Nancy cut?

Answers

Answer:

Nancy can cut 6 full circles

Step-by-step explanation:

Length of aluminium strip = [tex]7 \frac{1}{7} cm[/tex]

Length of aluminium strip =[tex]\frac{50}{7} cm[/tex]

Breadth of aluminium strip =[tex]1 \frac{3}{7} cm[/tex]

Breadth of aluminium strip =[tex]\frac{10}{7} cm[/tex]

Area of strip = [tex]Length \times Breadth = \frac{50}{7} \times \frac{10}{7} =\frac{500}{49}[/tex]

Diameter of circle = [tex]1 \frac{3}{7} cm[/tex]

Diameter of circle = [tex]\frac{10}{7} cm[/tex]

Radius of circle =[tex]\frac{10}{ 7 \times 2}=\frac{10}{14} cm[/tex]

Area of circle =[tex]\pi r^2 = \frac{22}{7} \times (\frac{10}{14})^2=\frac{550}{343} cm^2[/tex]

No. of circles can be cut = [tex]\frac{\frac{500}{49}}{\frac{550}{343}}=6.3636[/tex]

So,Nancy can cut 6 full circles

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