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2(x + 3) + (3x + 1)

Answer:

2

Step-by-step explanation:

Parallel lines have the same slope. Hope this helps!

Answer:

28.3

Step-by-step explanation:

A=3.14*3*3=28.27433 rounded to 28.3

Complete question is;

State whether true or false

The sum of a negative integer and a positive integer is always a negative integer.

Answer:

False

Step-by-step explanation:

The statement is false. This is because it's not in every case that sum of negative integer and a positive integers is equal to zero.

For example let's consider the integers -5 and 8.

The sum is; -5 + 8 = 3

The result is not negative

Whereas if we consider -8 and 5,the sum is; -8 + 5 = -3

This result is negative

So sometimes the sum can yield a positive or negative results.

Thus, the statement in the question is false.

Answer:

-11

Step-by-step explanation:

-3+(-1)+(-5)+(-2)

-3+(-1)=(-4)

-4+(-5)=(-9)

-9+(-2)=(-11)

(-11)

HOPE THIS HELPS!!

Step-by-step explanation:

10%

Answer: 18900

Step-by-step explanation:

Given the question:

In 2001, the Guinness Book of World Records recognized a breakfast which served 18,941 people as the largest ever cooked. Which number below shows 18,941 rounded to 3 significant digits?

18,941 rounded to 3 significant figures

To round to 3 significant figures, the first 3 numbers are kept intact, then the subsequent number is rounded up to 1 if up to or greater than 5 and added to the third figure. If less than 5, all subsequent numbers are rounded down to 0

Hence,

18,941 = 18900 (because 4 is less than 5, 4 and all subsequent numbers are rounded down to 0).

Answer:

Number 2

Step-by-step explanation:

Answer:

The entrance fee to the paintball park is $15

Each purchase of 15 paintballs costs $9

Step-by-step explanation:

We are given the expression [tex] 0.60n + 15 [/tex] as the total cost in dollars that a player pays when he plays paintball in the course.

Where,

n = number of paintballs a player uses

$0.60 = cost per paintball

$15 = entrance fee charged to for using the course

Completing the statement given in the question becomes now easy and clear.

We already know that the entrance fee is $15, which is the starting cost.

The cost for our each purchase of 15 paintballs is expressed as = cost per paintball × number of paintballs

= 0.60n

= 0.60 × 15 = $9

Answer:

Entrance Fee = $15

15 point balls cost = $9

Step-by-step explanation:

Answer:

15;30

Step-by-step explanation:

Answer:

4x-3y

Step-by-step explanation:

Answer:

(3x-5y) + (x+2y)

Let just go ahead and open brackets and simplify

3x - 5y + x + 2y

3x + x + 2y - 5y

4x - 3y

Brainliest??

Answer:

Step-by-step explanation:

Hope this helps! <3

Answer:

13a + 9b + 11

Step-by-step explanation:

I hope this helps!

Answer:

13a+ 9b+ 11

Step-by-step explanation:

9a+4a= 13a

4b+ 5b= 9b

4+7=11

Answer:

Percentage of bid.

Step-by-step explanation:

The auction price is the initial start of bidding. This price is set for the thing which are placed under auction and below that auction price the trade cannot take place. This is usually considered as a starting point and then bidders start to quote their bid for the auctioned. The final price is determined when the bidders quotes the highest possible price after which no one else quotes any other bid. The auction is then closed and the bidders gains the auctioned things.

Answer:

f(n) = -3n + 24

Step-by-step explanation:

Let the function representing Number of meals and amount of Pet Food remaining is,

f(n) = an + b

Where a = number of meals dispensed

n = amount of Pet food per meal

b = Initial amount of Pet food

From the table attached,

For n = 1 and f(n) = 21,

21 = a(1) + b

a + b = 21 -----------(1)

For n = 3 and f(n) = 15,

15 = a(3) + b

3a + b = 15 -----------(2)

Equation (2) - equation (1),

(3a + b) - (a + b) =  15 - 21

a = -3

From equation (1),

-3 + b = 21

b = 24

Therefore, function will be,

f(n) = -3n + 24

Answer:f(n)=-3+24

Explanation

Unit rate of the table is three therefore taking away 3 cups each time food is dispensed aka -3n. 24 represents the starting point. 21+3=24

hello

the question is incomplete, but based on directives from brainly i did an online search and i was able to get the complete question.

Researchers studying anthropometry collected body girth measurements

and skeletal diameter measurements, as well as age, weight, height and gender, for 507 physically

active individuals. The histogram below shows the sample distribution of heights in centimeters(a) What is the point estimate for the average height of active individuals? What about the  median?

(b) What is the point estimate for the standard deviation of the heights of active individuals?

What about the IQR?

(c) Is a person who is 1m 80cm (180 cm) tall considered unusually tall? And is a person who is  1m 55cm (155cm) considered unusually short? Explain your reasoning.

(d) The researchers take another random sample of physically active individuals. Would you

expect the mean and the standard deviation of this new sample to be the ones given above.

Explain your reasoning.

(e) The samples means obtained are point estimates for the mean height of all active individuals,

if the sample of individuals is equivalent to a simple random sample. What measure do we use  to quantify the variability of such an estimate? Compute this quantity using the data from  the original sample under the condition that the data are a simple random sample

Step-by-step explanation:

1. the point estimate for the average height is the mean = 171.1

the median of active individuals is 170.3

2. point estimate of sd = 9.4

to get IQR

[tex]Q3-Q1[/tex]

= 177.8 -163.8

= 14

3. mean +- SD

171.1 +-2(9.4)

171.1+18.8  = 189.9

171.1-18.8 = 152.3

[189.9, 152.3]

180CM is within the limits of 2SD. so a height of 180cm is not unusually tall

155 cm is within the 2sd limit so this height is not unusually short

4.

mean and sd are not same. a great probability exists that a different sample would have similar but different results if the same sample size is 507.

5.

[tex]9.4/sqrt507[/tex]

= 0.417

≈ 0.42

Answer:

2.088

Step-by-step explanation:

Trust me I am in high school honors algebra with almost an average of 100.

The product of 2.4 x 0.87 is 2.088.

A decimal is represented by a dot which separates the whole part and the fractional part of a number.

According to the given question we have to multiply two decimals numbers  2.4 and 0.87.

Multiplication of decimals numbers can be easily done just by removing the decimas and multiplying them in form of integers and after obtained result we'll put the decimal as many digits before from the rightmost side as the sum of the digits which those two numbers have after the decimal.

So, (24×87) = 2088 now the sum if the digits is 3 so we'll put the decimal 3 places before which is 2.088.

learn more about decimals here :

https://brainly.com/question/548650

#SPJ2

Answer:

72w+36

Step-by-step explanation:

Answer:

[tex]15 \sqrt{2 } [/tex]

that the answer

Answer:

The number of fast songs is 64 and the number of slow songs is 32

Step-by-step explanation:

∵ Y represents the number of fast songs

∵ x represents the number of slow dance songs

∵ John gets to play a total of 96 songs at his school dance

→ That means the sum of x and y is 96

∴ x + y = 96 ⇒ (1)

∵ He wants twice as many fast songs, ​y, as ​ slow dance songs, ​x

→ That means y is twice x

∴ y = 2x ⇒ (2)

→ Substitute y in equation (1) by equation (2)

∵ x + 2x = 96

∴ 3x = 96

→ Divide both sides by 3 to find x

∴ [tex]\frac{3x}{3}=\frac{96}{3}[/tex]

∴ x = 32

→ Substitute the value of x in equation (2) to find the value of y

∵ y = 2(32)

∴ y = 64

∴ The number of fast songs is 64 and the number of slow songs is 32

Answer:

d

Step-by-step explanation:

consecutive angles aren't a thing and the others there would have to be an angle on the other side.

Answer:

x= 18

y= 54

Step-by-step explanation:

(Sorry if i'm too late)

Okay lets do this!

We will start with X:

If AOD is equal to COB, then we can do 90-72 to find AON

18 +2x= 3x

18 = x (wow that was simple :))

x= 18

Lets try  Y now

If AB is a straight line, then 72 +y +3x is 180

so 72 + y + 3( 18) = 180

72 + y + 54 = 180

y = 54

We should check our work now:

2(18)+ 18 + 72 + 54 + 3 (18) + 126 = 360 !!!

Yayyyyy

So this should be correct

Please tell me if this is wrong :)))

Answer:

Step-by-step explanation:

(7p² + 4p+3)-(4p²- 3p+1)

opening the brackets

7p² + 4p + 3 - 4p²+ 3p - 1

By grouping the like terms,

7p² - 4p² + 4p + 3p + 3 - 1

3p² + 7p + 2

Hope this helps

plz mark as brainlest!!!!!!!

Answer:

25 minutes

Step-by-step explanation:

it kinda depends on how fast hes going but most likely 25 minutes

Answer: 12, 13, 14

Explanation: This was on my test last week and this is the correct answer.

Answer:

18, 19, 20

Step-by-step explanation:

We can have the lowest number be [tex]x[/tex], and the second and third numbers be [tex]x+1[/tex] and [tex]x+2[/tex]. Now we have the equation [tex]x+x+1+x+2=x+39.[/tex]

[tex]3x+3=x+39\\\\2x=36.[/tex]

x=18, so the numbers are 18, 19, and 20.

Answer:

[tex]L = (-10,10)[/tex]

Step-by-step explanation:

Given

[tex]K = (2,-6)[/tex]

[tex]T = (-4,2)[/tex]

Required

Determine the coordinates of L

Since T is the midpoint of K and L, we make use of:

[tex]T_x = \frac{K_x + L_x}{2}[/tex]

and

[tex]T_y = \frac{K_y + L_y}{2}[/tex]

Solving for [tex]L_x[/tex]

[tex]T_x = \frac{K_x + L_x}{2}[/tex]

[tex]-4 = \frac{2 + L_x}{2}[/tex]

Multiply through by 2

[tex]-8 = 2 + L_x[/tex]

[tex]L_x = -8 - 2[/tex]

[tex]L_x = -10[/tex]

Solving for [tex]L_y[/tex]

[tex]T_y = \frac{K_y + L_y}{2}[/tex]

[tex]2 = \frac{-6+L_y}{2}[/tex]

Multiply through by 2

[tex]4 = -6 + L_y[/tex]

[tex]L_y = 4 + 6[/tex]

[tex]L_y = 10[/tex]

Hence: The coordinates of L is:

[tex]L = (-10,10)[/tex]

Answer:

-0.25 or 1/4

Step-by-step explanation:

Eh just know

Answer: [tex]y=\dfrac{5}{5-6x}[/tex]

Step-by-step explanation:

The given differential equation: [tex]xy' + y = y^2[/tex]

[tex]\Rightarrow\ xy'=y^2-y[/tex]

[tex]\Rightarrow\ \frac{1}{y^2-y}y'\:=\frac{1}{x}\\\\\Rightarrow\ \dfrac{1}{y(y-1)}\dfrac{dy}{dx}=\frac{1}{x}\\\\\Rightarrow\dfrac{y-(y-1)}{y(y-1)}dy=\dfrac{1}{x}dx\\\\\Rightarrow\dfrac{1}{(y-1)}dy+\dfrac{1}{y}dy=\dfrac{1}{x}dx[/tex]

Integrate both sides , we get

[tex]\int\dfrac{1}{(y-1)}dy+\int\dfrac{1}{y}dy=\dfrac{1}{x}dx\\\\\Rightarrow\ \ln(y-1)-\ln y=\ln x+c\ \ \ \ (i)[/tex]

At x=1 , y=-5 (given)

[tex]\ln(-5-1)-\ln -5=\ln 1+c\\\\\Rightarrow\ \ln (-6)-\ln(-5)=0+c\\\\\Rightarrow\ \ln(\dfrac{-6}{-5})=c\\\\\Rightarrow\ \ln(\dfrac{6}{5})=c[/tex]

[tex][\ \ln a+\ln b=\ln ab ,\ \ \ \ \ \ln a-\ln b=\ln\dfrac{a}{b}\ ][/tex]

Put value of x in (i), we get

[tex]\ln(y-1)-\ln y=\ln x+\ln (\dfrac65)\\\\\Rigtarrow\ \ln (\dfrac{y-1}{y})=\ln(\dfrac{6}{5}x)[/tex]

[tex]\Rightarrow\ 1-\dfrac{1}{y}=\dfrac{6}{5}x\Rightarrow\ \dfrac{1}{y}=1-\dfrac{6}{5}x\\\\\Rightarrow\ \dfrac{1}{y}=\dfrac{5-6x}{5}\\\\\Rightarrow\ y=\dfrac{5}{5-6x}[/tex]

hence, the required solution: [tex]y=\dfrac{5}{5-6x}[/tex]

The solution to the differential equation

[tex]xy'+y=y^2[/tex]

given the initial condition [tex]y(1)=-5[/tex]  is [tex]y=\frac{5}{5-6x}[/tex]

Given the differential equation

[tex]xy'+y=y^2[/tex]

We can rearrange it as follows:

[tex]x\frac{dy}{dx}+y=y^2\\\\x\frac{dy}{dx}=y^2-y\\\\\frac{1}{y^2-y}\frac{dy}{dx}=\frac{1}{x}\\\\\frac{1}{y^2-y}dy=\frac{1}{x}dx[/tex]

Factoring the denominators of the LHS, and decomposing into partial fractions, we get

[tex]\frac{1}{y(y-1)}dy \implies \frac{1}{(y-1)}dy+\frac{1}{y}dy[/tex]

The final rearranged equation is

[tex]\frac{1}{(y-1)}dy+\frac{1}{y}dy=\frac{1}{x}dx[/tex]

Integrating both sides;

[tex]\int\frac{1}{y-1} dy +\int\frac{1}{y}dy=\int\frac{1}{x}dx\\\\ln(y-1)-ln(y)=ln(x)+c\\\\ln(\frac{y-1}{y})=ln(x)+c[/tex]

(We made of a law of logarithms on the last line to simplify the equation)

The initial condition [tex]y(1)=-5\implies y=-5 \text{ when }x=1[/tex]

Substituting into the general solution we got earlier

[tex]ln(\frac{y-1}{y})=ln(x)+c\\\\ln(\frac{-5-1}{-5})=ln(1)+c\\\\ln(\frac{-6}{-5})=ln(1)+c \\\\(\text{since }ln(1)=0)\\\\ln(\frac{-6}{-5})=c\\\\ln(\frac{6}{5})=c[/tex]

Substituting the value of [tex]c[/tex] back into the general solution

[tex]ln(\frac{y-1}{y})=ln(x)+c\\\\ln(\frac{y-1}{y})=ln(x)+ln(\frac{6}{5})\\\\ln(\frac{y-1}{y})=ln(\frac{6x}{5})\\\\\frac{y-1}{y}=\frac{6x}{5}[/tex]

When [tex]y[/tex] is made the subject of the formula

[tex]y=\frac{5}{5-6x}[/tex]

Therefore, the solution that satisfies the initial condition [tex]y(1)=-5[/tex] is [tex]y=\frac{5}{5-6x}[/tex]

Learn more about solving differential equations here: https://brainly.com/question/4537000