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Examine how sounds of music are related to trigonometric functions.

What does change of amplitude do? How about frequency?

Using graphs and equations, represent multiple transformations explaining their relevancy to the sound wave

An equation is formed of two equal expressions. The value of x that maximizes the area of the printed region of the billboard is 9.655 ft.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given x is the left-right width of the billboard and y is the height of the billboard. Therefore,

The total area of the billboard, A= x·y

The total printed area of the billboard, [tex]A_p=(x-2)(y-8)[/tex]

Given in problem that the area of the billboard is 3600 ft².

x·y = 3600

y = (3600)/x

Substituting the value of y in the equation of the total printed area of the billboard,

[tex]A_p = (x-2)(\dfrac{3600}{x}-8)\\\\A_p = 3600 -8x -\dfrac{7200}{x} + 16\\\\A_p =3616-8x - \dfrac{7200}{x}[/tex]

Now, the value of x is needed to be minimum, therefore, differentiating the given function,

[tex]\dfrac{d}{dx}A_p =\dfrac{d}{dx}3616-8x - \dfrac{7200}{x}\\\\\dfrac{d}{dx}A_p =-8 - \dfrac{7200}{x^2}[/tex]

Equate the differentiated function with 0,

[tex]0=-8x - \dfrac{7200}{x^2}\\\\8x = - \dfrac{7200}{x^2}\\\\x^3 = 900\\\\x = 9.655 ft.[/tex]

Hence, the value of x that maximizes the area of the printed region of the billboard is 9.655 ft.

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The inequality equation will be -5x + 20 < -10.

Inequality is defined as an equation that does not contain an equal sign.

The weather report says the temperature is 20°c and will drop 5°c per hour for the next 6 hours.

Daryl plans to be gone at least 6 hours, and he has a plant outside.

If he wants the plant to remain in temperatures above -10° should Daryl move the plant to a warmer location before leaving will be

The inequality equation will be

-5x + 20 < -10

where x is the number of hours.

Then we have

-10 < -5x + 20

5x > 30

   x > 6 hours

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Answer: Read attachment.

Step-by-step explanation: Attached below is my work. Hope it helps!

The point (3, 82) on the graph represents after Terry's hours his bank balance will be $82.

Given that, Terry brings home $14 per hour he works. When he started this job, he had $40 in the bank.

We need to write and graph the equation that would represent how much money Terry has in the bank (y) after x hours of work.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Now, y=40+14x

Graph the line using the slope and y-intercept, or two points.

Slope: 14

y-intercept: (0, 40)

The coordinates to plot the graph are (0, 40), (1, 54), (2, 68) and (3, 82).

The graph for the given equation is given below.

Therefore, the point (3, 82) on the graph represents after Terry's hours his bank balance will be $82.

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The second derivative of the first function is s"(x) = = -[8e^(x/5) - 2]e^(x/5)/25(e^(x/5) + 2)³.

The second derivative of the second function is; k''(t) = (36t² - 6)e^(-3t²)

1)  We are given the function;

s(x) = 4/(1 + 2e^(-0.2x)

First derivative is;

ds/dx = [8e^(x/5)]/5(e^(x/5) + 2)²

Second Derivative is;

d²s/dx² = -[8e^(x/5) - 2]e^(x/5)/25(e^(x/5) + 2)³

At x = 0;

d²s/dx² = -[8e^(0/5) - 2]e^(0/5)/25(e^(0/5) + 2)³

d²s/dx² = 8/675

B) We are given the function;

k(t) = e^(-3t²)

The first derivative is;

dk/dt = -6te^(-3t²)

The second derivative is;

k''(t) = (36t² - 6)e^(-3t²)

At t = 1, we have;

k''(t) = (36(1)² - 6)e^(-3(1²))

k"(t) = 1.494

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The speed of the rabbit in miles per hour is 50.33 mi/h.

We know that the speed of the jackrabbit is:

1.35 km/min.

Now we need to use the relations:

1 hour = 60 minutes.

So, in one hour, the rabit runs 60 times the distance that it runs in one minute, then:

1.35 km/min = 60*(1.35 km/h) = 81km/h

Now we need to change kilometers for miles.

1km = 0.6214 mi

Then we can rewrite:

81km/h = 81*0.6214mi/h = 50.33 mi/h

The speed of the rabbit in miles per hour is 50.33 mi/h.

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Answer:

Step-by-step explanation:

Answer:  31.792.5 cu. ft.   (choice B)

=================================================

Work Shown:

[tex]V = \pi*r^2*h\\\\V \approx 3.14*15^2*45\\\\V \approx 31,792.5 \text{ cubic feet}\\\\[/tex]

The result is approximate since [tex]\pi \approx 3.14[/tex] is approximate.

[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}[/tex]

Step-by-step explanation:

Radius (r) = 15 feet

Height (h) = 45 feet

Volume = ?

Taking π ≈ 3.14..

V = 3.14 × 15² × 45

V = 31,792.5 cu. feet

So, the cylindrical tank can hold upto 31,792.5 cu. feet of water..

The company needs 41 labels on average, each minute.

The perimeter of a circle (circumference): 2 π radius

Replacing with the values given:

C = 2 (3.14) 2 = 12.56 cm

So, the area of one label is:

Area of a rectangle: length x width = 12.56 x 7 = 87.92 cm sq.

Now, the number of label be n

87.92 x n = 3612.64 cm2

n = 3612.64 / 87.92

n = 41.09

Hence, The company needs 41 labels on average, each minute.

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Answer:

z^0= 1

(2v+2)^0 = 1

3^0 = 1

0^0= 0

Step-by-step explanation:

When you raise (almost) anything to the power zero, you get 1 and when you raise 0 to any number except 0 is 0

It will be 6 - 4.875 = 1.125 feet above the ground or 1.1 feet (rounded to the nearest tenth of a foot).

All you need to do is to replace t in the given equation with 1.5:

[tex]h=-16(1.5)^2+25(1.5)+6[/tex]

h=-4.875

The value is negative so we can assume that after 1.5 seconds the ball will be 4.875 feet lower than it was shot from.

The measurement of someone or something from head to foot or from base to top.

But we also know that it was shot from a height of 6 feet,

So it will be 6 - 4.875 = 1.125 feet above the ground or 1.1 feet (rounded to the nearest tenth of a foot).

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Answer:

Formula of Trapezoid:

A = (a + b) × h / 2

The formula can be derived in different ways. for now, we have discussed two ways:

1. By using the formula of a triangle

2. By dividing into different sections

Step-by-step explanation:

1. By using the formula of a triangle

One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.

Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.

The image is attached below.

Connect vertices P and R with a diagonal.

Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).

Its area is

S1=[tex]\frac{1}{2} *PQ*RM[/tex]

Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).

Its area is

S2=[tex]\frac{1}{2} *SR*PN[/tex]

Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.

They both are equal to the altitude of the trapezoid h.

Therefore, we can represent areas of our two triangles as

S1=[tex]\frac{1}{2}*PQ*h[/tex]

S2=[tex]\frac{1}{2}*SR*h[/tex]

Adding them together, we get the area of the whole trapezoid:

S=S1+S2=[tex]\frac{1}{2} (PQ+SR)h,[/tex]

which is usually represented in words as "half-sum of the bases times the altitude".

2. By dividing into different sections

Trapezoid PQRS is shown below, with PQ parallel to RS.

Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)

We are going to derive the area of a trapezoid by dividing it into different sections.

If we drop another line from Q, then we will have two altitudes namely PT and QU.

Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)

From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that

=> [tex]A_{PQRS} = (\frac{ah}{2}) + b_{1}h + \frac{ch}{2}[/tex]

Simplifying, we have

=>[tex]A= \frac{ah+2b_{1+C} }{2}[/tex]

Factoring we have,

=> [tex]A_{PQRS} = (a+ 2b_{1} + c)\frac{h}{2} \\= > {(a+ b_{1} + c) + b_{1} }\frac{h}{2}[/tex]

 But, [tex]a+ b_{1} + c[/tex]  is equal to [tex]b_{2}[/tex], the longer base of our trapezoid.

Hence, [tex]A_{PQRS}= (b_{1} + b_{2} )\frac{h}{2}[/tex]

We have discussed two ways by which we can derive area of a trapezoid.

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By applying algebraic handling on the two equations, we find the following three solution pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

In this question we have a system formed by a linear equation and a non-linear equation, both with no trascendent elements and whose solution can be found easily by algebraic handling:

x - y = 5      (1)

x² · y = 5 · x + 6       (2)

By (1):

y = x + 5

By substituting on (2):

x² · (x + 5) = 5 · x + 6

x³ + 5 · x² - 5 · x - 6 = 0

(x + 5.693) · (x - 1.430) · (x + 0.737) = 0

There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737

And the y-values are found by evaluating on (1):

y = x + 5

x₁ ≈ 5.693

y₁ ≈ 10.693

x₂ ≈ 1.430

y₂ ≈ 6.430

x₃ ≈ - 0.737

y₃ ≈ 4.263

By applying algebraic handling on the two equations, we find the following three solution pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

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Answer:

161 calories

Step-by-step explanation:

1) Divide 230 by 48

4.791666666666667

2) multiply 4.791666666666667 by 33.6

161

Done! Your answer is 161 calories in a 33.6 gram bag. Or just 161.

Hope this helps!

Both Amy and Laura increased their gas mileage in the first two weeks.

Option B is the correct answer.

The missing graph is attached with the answer.

A graph is a statistical way of showing data , it is used to show relation between the points.

A graph is useful in understanding the nature of a function.

From the data given in the question

The statements that can be concluded is , Option B

Both Amy and Laura increased their gas mileage in the first two weeks.

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The corresponding part of PQ is WX

The congruent statement is given as:

polygon WXYZ ≅ polygon PQRS.

This means that the corresponding points are:

W and P, X and Q, Y and R, Z and S

When two points Q and P are joined together, we have:

polygon WX ≅ polygon PQ

Hence, the corresponding part of PQ is WX

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‐10+35=25 and 25 × 20=300

Answer:

( 2, -1)

Step-by-step explanation:

(X1 + X2)/2 , (Y1 + Y2)/2

(6-2)/2 , (3-5)/2

4/2 , -2/2

2 , -1

Answer:

(2, -1)

Step-by-step explanation:

(x1, y1)=(6, 3)

(x2, y2)=(-2, -5)

[(6+(-2))/2, (3+(-5))/2]

=(4/2, -2/2)

=(2, -1)

The domain of the function is whole numbers from 0 to 10.

Given the graph of function represents the tickets sold vs cost. A movie theater sells up to 10 tickets at a time online. we have to find the domain of the graph.

As shown in the graph the number of tickets sold is 0 to 10 and also the number of tickets are always positive and a whole number. It can never be negative or in fraction form.

Hence, the value of x is a positive whole number. The domain of the function is the complete set of possible values of x. The domain of the function is whole numbers from 0 to 10.

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Answer:

The decrease in price is $61.92

The sale price is $196.08

Step-by-step explanation:

24% × 258 = 61.92

258 decrease 24% =

258 × (1 - 24%) = 258 × (1 - 0.24) = 196.08

Step-by-step explanation:

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It is correct to state that a bit can be in one of 2 states, either 1 or 0.

A bit is is a single binary digit. A bit can either be "1" or "0".

We stated that It is correct to indicate that a bit can be in one of 2 states, either 1 or 0. This indicates that 2ⁿ strings must be created in total. The string must then be processed twice.

Hence, Our time is now O(2ⁿ⁺¹) = O(2ⁿ)

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Option D statement "A 12-gallon tank would cost $47.40 to fill completely" is true.

The whole of the independent variable's possible values makes up the domain of a function.

For the given data we need to find which of the given statements are true.

From option A:

The domain is {4, 8, 11, 15}.

The domain is all possible x values so this would be 0 to infinity as you can pay for more gallons not just to that certain set of numbers.

Therefore, option A is False.

From option B:

An 11-gallon tank would cost $44.00 to fill completely.

From the given table we can see that 11-gallon tank costs $43.45.

Therefore, option B is False.

From option C:

A 9.1-gallon fill-up would cost $35.49.

To find 9.1 gallons we need to find the cost of 1-gallon.

That is, 15.80/4 = $3.95 (Given in the table)

Now the cost of 9.1 gallon tank is $3.95 x 9.1 = $35.95 not $35.49

Therefore, option C is False.

From option D:

A 12-gallon tank would cost $47.40 to fill completely.

We found that 1 gallon is $3.95.

$3.95 x 12 = $47.40

Therefore, option D is True.

Hence, from the given statements option D is True.

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Answer:

B. x = 3

Step-by-step explanation:

Simplifying

4 + 3x = 2(3x + -7) + 9

Reorder the terms:

4 + 3x = 2(-7 + 3x) + 9

4 + 3x = (-7 * 2 + 3x * 2) + 9

4 + 3x = (-14 + 6x) + 9

Reorder the terms:

4 + 3x = -14 + 9 + 6x

Combine like terms: -14 + 9 = -5

4 + 3x = -5 + 6x

Solving

4 + 3x = -5 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.

4 + 3x + -6x = -5 + 6x + -6x

Combine like terms: 3x + -6x = -3x

4 + -3x = -5 + 6x + -6x

Combine like terms: 6x + -6x = 0

4 + -3x = -5 + 0

4 + -3x = -5

Add '-4' to each side of the equation.

4 + -4 + -3x = -5 + -4

Combine like terms: 4 + -4 = 0

0 + -3x = -5 + -4

-3x = -5 + -4

Combine like terms: -5 + -4 = -9

-3x = -9

Divide each side by '-3'.

x = 3

Simplifying

x = 3

Substitute [tex]y = \sqrt x[/tex], so that [tex]y^2 = x[/tex] and [tex]2y\,dy = dx[/tex]. Then the integral becomes

[tex]\displaystyle \int \frac{dx}{\sqrt{1 + \sqrt x}} = 2 \int \frac y{\sqrt{1+y}} \, dy[/tex]

Now substitute [tex]z=1+y[/tex], so [tex]dz=dy[/tex]. The integral transforms to

[tex]\displaystyle 2 \int \frac y{\sqrt{1+y}} \, dy = 2 \int \frac{z-1}{\sqrt z} \, dz = 2 \int \left(\sqrt z - \frac1{\sqrt z}\right) \, dz[/tex]

The rest is trivial. By the power rule,

[tex]\displaystyle \int \left(\sqrt z - \frac1{\sqrt z}\right) \, dz = \frac23 z^{3/2} - 2z^{1/2} + C = \frac23 \sqrt z (z - 3) + C[/tex]

Put everything back in terms of [tex]y[/tex], then [tex]x[/tex] :

[tex]\displaystyle 2 \int \frac y{\sqrt{1+y}} \, dy = \frac43 \sqrt{1+y} (y - 2) + C[/tex]

[tex]\displaystyle \int \frac{dx}{\sqrt{1+\sqrt x}} = \boxed{\frac43 \sqrt{1+\sqrt x} (\sqrt x - 2) + C}[/tex]

Answer:

( 1, - 1 )

Step-by-step explanation:

The measure of angle OED is the measure of angle OBD. Then the correct option is C.

It is the center of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.

Circle O is shown.

Line segment JE is a diameter and line segment OB is a radius.

A line is drawn from point J to point B to form a chord.

Tangents BD and ED intersect at point D outside the circle.

The radius and tangent are orthogonal to each other.

∠OED = ∠OBD = 90°

Then the correct option is C.

The complete question is given below.

Circle O is shown. Line segment J E is a diameter and line segment O B is a radius. A line is drawn from point J to point B to form a chord. Tangents B D and E D intersect at point D outside of the circle.

Use the diagram to complete the statements.

The measure of angle EJB is the measure of angle BOE.

The measure of angle BDE is the measure of angle BOE.

The measure of angle OED is the measure of angle OBD.

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Answer:

one-half, 180 minus, equal to

Step-by-step explanation:

The solution to the equation 12x + 5x - 4 = 172x + 6 is D. No solution.

The information given is 12x + 5x - 4 = 172x + 6 and we are told to find the value of x.

12x + 5x - 4 = 172x + 6

Collect like terms

12x + 5x - 4 = 172x + 6

12x + 5x - 172x = 6 + 4

-155x = 10

x = 10/-155

x = -0.0645

Therefore, the correct option is no solution as the correct answer isn't given.

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Answer:

(-3, -13)

(-1, -7)

(1, -1)

(3, 5)

(5, 11)

Step-by-step explanation:

Plug x into the equation y = 3x - 4 for each value of x to obtain the y value.

For example:

y = 3(3) - 4

y = 9 - 4

y = 5

The x axis is labeled as Number of days.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

let x be the  number of days and y be money.

So, the equation is

y = -7x + 150.

Hence, the x axis is labeled as Number of days.

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