Given the following joint PDF function of two continuous random variables x and y :

[tex]f(x,y) = \left \{ {{1/4x^2 +1/4y^2 +1/6xy} \atop {0}} \right. 0\leq x\leq 1 ; 0\leq y\leq 2[/tex]\


a) find the distribution function F(x,y)

b) find marginal PDF for f(x) and f(y)

c) find P ( 0[tex]0\leq x\leq 1/2 , 0\leq y\leq 1/2[/tex]

d) if u= 2x-y and v = -x+y find the dense joint density function of u and v

Answers

Answer 1

A. The distribution function F(x,y) is ¹¹/₁₈ + ¹/₁₂ x² - ¹/₁₈ y² + ¹/₁₂ xy

B. The marginal PDF of x is ¹/₂x + ¹/₆ + ¹/₁₂x² for 0≤x≤1 and for y is /₂y + ¹/₆ + ¹/₁₂y² for 0≤y≤2

C. P(0≤x≤1/2, 0≤y≤1/2) is ¹/₃₂ + ¹/₉₆ x² for 0≤x≤1/2

D. The joint PDF of u=2x-y and v=-x+y is f(u,v) = (1/27)(2u^2+2v^2-2uv)

How did we get these values?

a) To find the distribution function F(x,y), integrate the joint PDF over the appropriate limits.

F(x,y) = ∫∫f(u,v)dudv

The limits of integration are not specified, so, determine them from the limits of the variables x and y.

So,

F(x,y) = ∫∫f(u,v)dudv

= ∫∫f(x+y,x-y)dudv (substituting u = x+y and v = x-y)

= ∫∫(¹/₄(u²+v²)+¹/₆(u²-v²))dudv (substituting x and y back in terms of u and v)

The limits of integration for u and v can be found by solving for u and v in terms of x and y as follows:

u = x+y

v = x-y

x = (u+v)/2

y = (u-v)/2

0 ≤ x ≤ 1; 0 ≤ y ≤ 2

implies

0 ≤ (u+v)/2 ≤ 1; 0 ≤ (u-v)/2 ≤ 2

Solving the above inequalities gives the following limits:

0 ≤ u ≤ 2; -u ≤ v ≤ u;

Thus,

F(x,y) = ∫∫(¹/₄(u²+v²)+¹/₆(u²-v²))dudv

= ∫²₀ ∫ᵘ_(-u) (1/4(u²+v²)+¹/₆(u²-v²))dvdu

= ¹¹/₁₈ + ¹/₁₂ x² - ¹/₁₈ y² + ¹/₁₂ xy

b) To find the marginal PDF of x, integrate the joint PDF over all possible values of y:

f(x) = ∫f(x,y)dy

So,

f(x) = ∫²₀ (¹/₄x + ¹/₄y²/x + ¹/₆y) dy

= ¹/₂x + ¹/₆ + ¹/₁₂x² for 0≤x≤1

In the same way, find the marginal PDF of y, by integrating the joint PDF over all possible values of x:

f(y) = ∫f(x,y)dx

So,

f(y) = ∫¹₀ (¹/₄x²/y + ¹/₄y + ¹/₆xy) dx

= ¹/₂y + ¹/₆ + ¹/₁₂y² for 0≤y≤2

c) To find P(0≤x≤1/2, 0≤y≤1/2), integrate the joint PDF over the appropriate limits:

P(0≤x≤1/2, 0≤y≤1/2) = ∫∫f(x,y)dxdy

So,

P(0≤x≤1/2, 0≤y≤1/2) = ∫¹₀ ∫^(1/2)_0 (¹/₄x² + ¹/₄y²/x + ¹/₆xy) dydx

= ¹/₃₂ + ¹/₉₆ x² for 0≤x≤1/2

d) To find the joint PDF of u=2x-y and v=-x+y, express x and y in terms of u and v and then apply transformation formula.

From the given equations, solve for x and y in terms of u and v as follows:

x = (u+v)/3

y = (v-u)/3

Now, find the Jacobian of the transformation:

J = ∂(x,y)/∂(u,v) =

| ∂x/∂u ∂x/∂v |

| ∂y/∂u ∂y/∂v |

=

| 1/3 1/3 |

| -1/3 1/3 |

So, |J| = 2/9

Using the transformation formula for joint PDFs:

f(u,v) = f(x(u,v), y(u,v)) |J|

Substituting x and y in terms of u and v:

f(u,v) = f((u+v)/3, (v-u)/3) (2/9)

Substituting the given joint PDF for f(x,y), we get:

f(u,v) = (¼((u+v)/3)² + ¼((v-u)/3)² + ⅙((u+v)/3)((v-u)/3))(2/9)

Simplify:

f(u,v) = (1/27)(2u²+2v²-2uv)

So, the joint PDF of u=2x-y and v=-x+y is:

f(u,v) = (1/27)(2u²+2v²-2uv)

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Related Questions

Which statement is true about the relationship between the diameter and circumference of a circle?

A. The diameter and circumference of a circle have a proportional relationship.

B. The diameter is a product of the circumference and pi.

C. The constant of proportionality between the diameter and circumference of a circle is a rational number.

D. The circumference of a circle is the quotient of the diameter and pi.

Answers

Option A The diameter and circumference of a circle have a proportional relationship is True .

What is diameter and circumference?

Diameter

The diameter is the length acrοss the circle at its widest pοint, measured frοm center tο center . The radius, a related measurement, is a line that extends frοm the circle's centre tο its edge. The diameter is equivalent tο twice the radius. (A chοrd is a line that crοsses the circle but is nοt at the widest pοint.)

Circumference

The circle's perimeter, οr the distance arοund it, is knοwn as its circumference. Imagine encircling a circle with a string. Imagine taking the string οut and extending it in a straight line. This string's length, if measured, wοuld represent yοur circle's circumference.

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PLS ANSWER QUICK
The table shows the length, in inches, of fish in a pond.


11 19 9 15
7 13 15 28


Determine if the data contains any outliers. If so, list the outliers.
There is an outlier at 28.
There is an outlier at 7.
There are outliers at 7 and 28.
There are no outliers.

Answers

Answer:

There is an outlier at 28.

Christie builds a model airplane that has a wingspan of 11. 8 inches. The model airplane has a scale of 1 inch to 2. 5 feet. What is the wingspan, in feet, of actual airplane?


A. 4. 72


B. 9. 30


C. 14. 30


D. 29. 50


PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!

Answers

The correct answer is D. 29.50.

To find the wingspan of the actual airplane, we will use the given scale factor and the wingspan of the model airplane.
Given information:
Model airplane wingspan = 11.8 inches
Scale factor = 1 inch to 2.5 feet

Step 1: Convert the model wingspan to feet using the scale factor.
1 inch on the model represents 2.5 feet on the actual airplane. To convert 11.8 inches to feet, multiply by the scale factor.
Step 2: Calculate the actual wingspan.
Actual wingspan = Model wingspan * Scale factor
Actual wingspan = 11.8 inches * 2.5 feet/inch

Step 3: Perform the multiplication.
Actual wingspan = 29.5 feet
So, the wingspan of the actual airplane is 29.5 feet.

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Pls help quick
which theorem can you use to show that the quadrilateral on the tile floor is a parallelogram

Answers

To show that the quadrilateral on the tile floor is a parallelogram, you can use the opposite sides theorem, opposite angles theorem, consecutive angles theorem, and Diagonal bisector theorem.


1. Opposite sides theorem: If both pairs of opposite sides of the quadrilateral are congruent (equal in length), then it is a parallelogram.

2. Opposite angles theorem: If both pairs of opposite angles of the quadrilateral are congruent (equal in measure), then it is a parallelogram.

3. Consecutive angles theorem: If the consecutive angles of the quadrilateral are supplementary (their sum is 180 degrees), then it is a parallelogram.

4. Diagonal bisector theorem: If the diagonals of the quadrilateral bisect each other (divide each other into two equal parts), then it is a parallelogram.

Choose the most appropriate theorem based on the given information and apply it to prove that the quadrilateral is a parallelogram.

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The outside temperature was 4°C for the next six hours the temperature changed at a mean rate of -0. 8°C per hour for the next two hours what was the final temperature

Answers

The final temperature after the next 8 hours (6 hours at -0.8°C per hour, followed by 2 hours at -0.8°C per hour) will be -2.4°C.

The final temperature can be calculated by subtracting the total temperature change from the initial temperature of 4°C.

The total temperature change during the next six hours can be calculated by multiplying the mean rate of -0.8°C per hour by the number of hours, which is 6.

-0.8°C/hour x 6 hours = -4.8°C

Therefore, the temperature after the next six hours will be:

4°C - 4.8°C = -0.8°C

For the next two hours, the temperature changed at a mean rate of -0.8°C per hour. This means the temperature decreased by:

-0.8°C/hour x 2 hours = -1.6°C

So the final temperature will be:

-0.8°C - 1.6°C = -2.4°C.

Therefore, the final temperature after the next 8 hours (6 hours at -0.8°C per hour, followed by 2 hours at -0.8°C per hour) will be -2.4°C.

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Find the domain and range of the function V(x, y) = 9√9y – 45x^2. Indicate the domain of V in equality or inequality notation. Use <= to denote ≤ and >= to denote ≥.
Domain of V = {(2,y) }

Answers

The minimum value of 9y – 45x^2 is 0, which occurs when y = 5x^2/3, so the range of V is all non-negative real numbers:

Range of V: [0, ∞)

To find the domain and range of the function V(x, y) = 9√(9y – 45x^2), we need to consider the values of x and y that make the expression under the square root non-negative, since we cannot take the square root of a negative number.

So, we have:

9y – 45x^2 >= 0

Dividing both sides by 9 and rearranging, we get:

y >= 5x^2/3

This means that the domain of V is all points (x, y) such that y is greater than or equal to 5x^2/3:

Domain of V: {(x, y) | y >= 5x^2/3}

To find the range of V, we note that the square root is always non-negative, so V(x, y) will be non-negative whenever 9y – 45x^2 is non-negative. The minimum value of 9y – 45x^2 is 0, which occurs when y = 5x^2/3, so the range of V is all non-negative real numbers:

Range of V: [0, ∞)

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Please help I need this done ASAP

Answers

Answer:

Domain is all x values

Range is all y values

Step-by-step explanation:

Your image is not clear enough for me to see the x or y coordinates so hope that helps you to figure it out on your own

if f' * (x) = 2x - 1 and g(x) - x + 3 prove that f g(x) is a linear function​

Answers

The composite function fg(x) is a linear function​ by the proof shown below

Proving that the function fg(x) is a linear function​

From the question, we have the following parameters that can be used in our computation:

f(x) = 2x - 1

g(x) = -x + 3

The above functions are linear functions

This means that the function fg(x) will also be a linear function​

To prove this, we have

f(g(x)) = 2(g(x)) - 1

substitute the known values in the above equation, so, we have the following representation

f(g(x)) = 2(-x + 3) - 1

So, we have

f(g(x)) = -2x - 7

Hence, the function is a linear function

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Solve this quick please thank you.

Answers

Answer:

[tex]y=-\dfrac{8}{x}[/tex]

Step-by-step explanation:

Inverse proportions can be represented by an equation in the form:

[tex]\boxed{y=\dfrac{k}{x}}[/tex]

where:

y and x are the two quantities in the proportion.k is the constant of proportionality.

To write an expression for the graphed function, first input the given point (-2, 4) into the inverse proportion equation and solve for k:

[tex]\implies y=\dfrac{k}{x}[/tex]

[tex]\implies 4=\dfrac{k}{-2}[/tex]

[tex]\implies 4 \cdot (-2)=\dfrac{k}{-2}\cdot (-2)[/tex]

[tex]\implies -8=k[/tex]

[tex]\implies k=-8[/tex]

Therefore, the expression for the graphed function is:

[tex]\boxed{y=-\dfrac{8}{x}}[/tex]

What is the average rate of change of the function g(x)=6x from x=-1 to x=3? show your work or explain how you obtained your response

Answers

The average rate of change of the function g(x)=6x from x=-1 to x=3 is found to be 6.

The function g(x) = 6x describes a relationship between x and the value of 6 times x. We want to find the average rate of change of this function from x = -1 to x = 3. The average rate of change tells us the average amount by which the function changes per unit of change in x over this interval.

In this case, by using the function g(x) = 6x and evaluating it for x = 3 and x = -1, a difference of 18 - (-6) = 24 is found. The difference in x's values is equal to 3 - (-1) = 4. We divide these to get an average rate of change of 6.

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What is the quotient of 223 + 3x2 + 5x – 4 divided by 22 +2+1?



Pls I need help

Answers

The quotient is -58x2 + 131x - 234 with a remainder of -5898.To solve this problem, we need to use long division. The dividend is 223 + 3x2 + 5x - 4 and the divisor is 22 + 2 + 1, which simplifies to 25.

We start by dividing 2 into 22, which gives us 11. We then write 11 above the 2 and multiply it by 25, which gives us 275. We subtract 275 from 223, which gives us -52. We bring down the 3, which gives us -523. We then repeat the process by dividing 2 into 52, which gives us 26. We write 26 above the 5 and multiply it by 25, which gives us 650. We subtract 650 from -523, which gives us -1173. We bring down the 1, which gives us -11731. We divide 2 into 117, which gives us 58.

We write 58 above the x and multiply it by 25, which gives us 1450. We subtract 1450 from -1173, which gives us -2623. We bring down the -4, which gives us -26234. We divide 2 into 262, which gives us 131. We write 131 above the 5 and multiply it by 25, which gives us 3275. We subtract 3275 from -2623, which gives us -5898. Therefore, the quotient is -58x2 + 131x - 234 with a remainder of -5898.

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A traingle has side of 7cm and 18cm if the length of the third side is a whole number how many possible traingles are there explain your answer

Answers

Therefore, there are 13 possible triangles that can be formed with sides of 7cm, 18cm and a whole number as the third side.

How to get the number of triangles

Using the triangle inequality law, Let's denote the sides of the triangle as a, b, and c. In this case, we have:

a = 7 cm

b = 18 cm

c = the third side, a whole number

Now, we apply the triangle inequality theorem to these sides:

a + b > c

=> 7 + 18 > c

=> 25 > c

a + c > b

=> 7 + c > 18

=> c > 11

b + c > a

=> 18 + c > 7

=> c > -11

Since c is a whole number, the third condition is always true, as there are no negative whole numbers. Therefore, we only need to consider the first two conditions:

11 < c < 25

Now, we list the whole numbers that fall within 11 and 25 within this range:

these are listed and counted

12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24

There are 13 whole numbers in this range. So, there are 13 possible triangles with sides of 7 cm and 18 cm, and a third side that is a whole number.

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Frank cuts a piece of cork to make trivet that has the shape and dimensions as shown.Find The Area Of The Trivet.Round Your Answer to the nearest tenth if needed

Answers

Answer:

52.5

Step-by-step explanation:

First, we can see that the base is 14m. The top is 7m, and the height is 5m. Since the formula for a trapezoid is

top + base / 2 ∙ h,

we plug in our numbers to get

7 + 14 / 2 ∙ 5.

We can solve to get

21 / 2 ∙ 5

10.5 ∙ 5

52.5

Triangle ABC is similar to triangle DBE. Select the responses that make the statements true. Large triangle A B C with side length 7. 5. Smaller triangle D B C inside A B C, which shares vertex B. Side B E has length 5 and base D E has length 13

Answers

The correct responses are: "Triangle DBC is similar to triangle ABC" and "The length of side DE is 13."

Since triangle ABC is similar to triangle DBE, we know that the corresponding angles are congruent and the corresponding sides are proportional.

From the given information, we know that side BC of triangle ABC corresponds to side BE of triangle DBE, since they share vertex B. Therefore, we can use the proportion:

BC / BE = AC / DE

Substituting the given values, we have:

BC / 5 = 7.5 / 13

Solving for BC, we get:

BC = (5 x 7.5) / 13 = 2.88 (rounded to two decimal places)

Therefore, the length of side BC is 2.88.

Now we can check which of the given statements are true:

"The length of side AB is 3.75." We do not have enough information to determine the length of side AB, so this statement cannot be determined to be true or false based on the given information.

"Triangle DBC is similar to triangle ABC." This statement is true, since they share angle B and the sides BC and BE are proportional.

"Angle C in triangle ABC is congruent to angle D in triangle DBE." This statement cannot be determined to be true or false based on the given information, since we do not know which angle in triangle DBE corresponds to angle C in triangle ABC.

"The length of side AC is 4.29." This statement cannot be determined to be true or false based on the given information, since we only have information about side BC and side BE. We do not have enough information to determine the length of side AC.

"The length of side DE is 7.8." This statement is false, since the length of side DE is given as 13, not 7.8.

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plunk and ms. q run a $100$-meter race. plunk runs at $8$ meters per second, and ms. q runs at $5$ meters per second. because ms. q runs slower, she is given a $3$-second head start. plunk wins the race. how much time, in seconds, is it between the time plunk passes ms. q and the time that plunk finishes the race?

Answers

The seconds, is it between the time plunk passes Ms. q and the time that plunk finishes the race is 7.5 seconds..

Flow Distance In the Mathematics or Quants part of any competitive test, time is one of the most well-liked and significant topics. For inquiries about a variety of subjects, including motion in a straight line, circular motion, boats and streams, races, clocks, etc.

The notion of Speed, Time, and Distance is frequently employed. Candidates should make an effort to comprehend how the variables of speed, distance, and time interact.

Ms. q being slow will get a head start for the race so,

3 second head start = 3 x 5 = 15 meters

There difference in speed is 8- 5 = 3 m/s          

Time required for the Plunk to catch up to Ms. q is:

15 / 3 = 5 seconds when P catches Q  

(this is 8 seconds after Q starts the race)

In 5 seconds Plunk runs   5 x 8 = 40 meters   this is when they are at the same point that is at time 8 seconds.

60 meters left in the race will take  Plunk :

60 m / 8 m/s = 7.5 seconds to finish the race.

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Construct a square, and a regular Pentagon with equal side equal to 0. 5 inch.

Answers

To construct a square and a regular pentagon with equal side lengths of 0.5 inch, we need to use basic geometric constructions.

How can I create a square and a regular pentagon with equal side lengths of 0.5 inch?

To construct a square and a regular pentagon with equal side length of 0.5 inch, follow these steps:

(a) Construct a Square:

Draw a horizontal line segment of length 0.5 inch.From the endpoints of the line segment, draw two perpendicular lines of length 0.5 inch each, meeting at the endpoints of the original line segment.From the endpoints of these new line segments, draw two more perpendicular lines of length 0.5 inch each, meeting at the endpoints of the second line segment.

Connect the endpoints of the four line segments to form a square.

(b) Construct a Regular Pentagon:

Draw a circle with a radius of 0.5 inch. This will be the circumcircle of the pentagon.Draw a horizontal line through the center of the circle.Mark the points where the line intersects the circle. These will be the vertices of the pentagon.Draw a line segment connecting two adjacent vertices of the circle.Using a compass, copy the length of this line segment to the next vertex, and connect the two vertices to form a line segment of the pentagon.

Repeat this process for all five vertices of the circle to form the regular pentagon.

A geometric construction is a method of drawing a figure using only a straightedge (an unmarked ruler) and a compass.

For the square, we start by drawing a horizontal line segment of length 0.5 inch. We then draw two perpendicular lines of length 0.5 inch each, meeting at the endpoints of the original line segment.

These two new line segments represent the adjacent sides of the square. We then repeat this process to create the remaining two sides of the square, and connect all four endpoints to form the complete square.

For the regular pentagon, we need to construct a circle with a radius of 0.5 inch. This will be the circumcircle of the pentagon, meaning that all five vertices of the pentagon will lie on the circle.

We draw a horizontal line through the center of the circle, and mark the points where the line intersects the circle. These five points will be the vertices of the pentagon.

We then draw line segments connecting adjacent vertices, using a compass to copy the length of each line segment from the previous one.

This process will create all five sides of the pentagon, and the figure will be a regular pentagon with equal side lengths of 0.5 inch.

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By about how much will g(x,y,z) = 3x + x COS Z-y sin z+y change if the point P(x,y,z) moves from P0(1.-3,0) a distance of ds= 0.1 unit toward the point P1(-1,-1,2)?

Answers

So the estimated value of √6.02 using differentials is approximately 2.4556.

The change in g(x,y,z) can be estimated using partial derivatives and differentials.

We can start by finding the partial derivatives of g(x,y,z) with respect to x, y, and z:∂g/∂x = 3 + cos(z)∂g/∂y = -sin(z) + 1∂g/∂z = -x sin(z) - y cos(z)Next, we can use the point P0(1,-3,0) and the distance ds = 0.1 to find the differentials dx, dy, and dz:dx = -2/√6 dsdy = 2/√6 dsdz = 1/√6 dsUsing these values, we can estimate the change in g:Δg ≈ (∂g/∂x) dx + (∂g/∂y) dy + (∂g/∂z) dzΔg ≈ (3 + cos(0)) (-2/√6 ds) + (-sin(0) + 1) (2/√6 ds) + (-1 sin(0) - (-3) cos(0)) (1/√6 ds)Δg ≈ (3 - 2/√6) dsPlugging in ds = 0.1, we get:Δg ≈ (3 - 2/√6) (0.1)Δg ≈ 0.389

Therefore, the change in g(x,y,z) is estimated to be approximately 0.389 units if the point P(x,y,z) moves from P0(1,-3,0) a distance of ds = 0.1 unit toward the point P1(-1,-1,2).

Suppose we want to estimate the value of √6.02 using differentials. We can start by choosing x = 6 and Δx = 0.02. Then, we need to find the derivative of f(x) = √x with respect to x:

f(x) = √x

f'(x) = 1/(2√x)

Using these values, we can estimate Δy:

Δy ≈ dy = f'(x) Δx

dy ≈ (1/(2√6)) (0.02)

dy ≈ 0.005

This means that a small change of 0.02 in x produces a small change of approximately 0.005 in y. To estimate the value of √6.02, we can add this change to the known value of √6:

√6.02 ≈ √(6 + 0.02) ≈ √6.04 ≈ 2.4556

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Find the length of side x.
Give answer to 1dp.

Answers

Answer:

Set your calculator to degree mode.

Use the Law of Cosines.

x^2 = 18^2 + 15^2 - 2(18)(15)(cos 105°)

x^2 = 688.7623

x = 26.2 cm

what is the simplified form of the expression below (3m^4n)^3(2m^2n^5p)/6m^4n^9p^8

Answers

For the expression (3m⁴n)³(2m²n⁵p)/6m⁴n⁹p⁸, the simplified-value is 9m¹⁰n⁻¹p⁻⁷.

To simplify the expression (3m⁴n)³(2m²n⁵p)/6m⁴n⁹p⁸, we first use the exponent-rule that states (qᵃ)ᵇ = qᵃᵇ to simplify the first part of the expression:

⇒ (3m⁴n)³ = 3³(m⁴)³n³ = 27m¹²n³;

Next, we can simplify the denominator by using the rules of exponents to combine the like terms:

⇒ 6m⁴n⁹p⁸ = 2×3m⁴n⁹p⁸;

Substituting the values,

We get;

⇒ (27m¹²n³)×(2m²n⁵p)/(2*3m⁴n⁹p⁸);

Simplifying the expression by cancelling out the common factors, we get:

⇒ 9m¹⁰n⁻¹p⁻⁷;

Therefore, the simplified-value is : 9m¹⁰n⁻¹p⁻⁷.

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The given question is incomplete, the complete question is

What is the simplified form of the expression below (3m⁴n)³(2m²n⁵p)/6m⁴n⁹p⁸;

pls hurry

Write y = 2x²-12x+16 in vertex form.​

Answers

Step-by-step explanation:

f(x)  =  2x^2 -12x + 16       to get to vertex form you will need to complete the square for 'x'....to do THAT you will need the x^2 coefficient to be '1'

Start like this:

2 (x^2 - 6x)    + 16        now complete the square

2 (x^2 - 6x +9)  - 18    + 16

f(x) =  2 (x-3)^2  - 2        Done.

what is 88 closer to 64 or 125

Answers

Answer:

64

Step-by-step explanation:

Answer:

64...i think

Step-by-step explanation:

125 - 88=37

88-64=24

PLS MARK BRAINLIEST

Find the magnitude of v. v = 7i
|lv|| = _____

Answers

The magnitude of vector v is:
|v| = 7

How magnitude of vector is calculated?

The magnitude of v is simply the length of the vector v, which can be found using the Pythagorean theorem. The vector v is given as v = 7i.

To find the magnitude of v (|v|), use the formula:
|v| = √(x² + y²)

where x and y are the components of the vector v. In this case, x = 7 (from 7i) and y = 0 (since there is no j component).

Now, plug in the values of x and y into the formula:
|v| = √(7² + 0²)
|v| = √(49 + 0)
|v| = √(49)
|v| = 7

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PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Answers

Answer:true

Step-by-step explanation:

Answer:

true

Step-by-step explanation

At a hot dog eating contest, Flora ate 3 hot dogs in one minute. At this rate, how many hot dogs will Flora eat in 12 minutes? Write a proportion and solve.

Answers

Answer:36

Step-by-step explanation:

3 a minute
18 in 6 minutes
36 in 12
3:1

Find the cosine of K.
24
Save answer
26
blo
J
10
Simplify your answer and write it as a proper fraction, improper fraction, or whole number.
cos (K) =
K
Skip to

Answers

Step-by-step explanation:

remember the original trigonometric triangle inside the norm circle (radius = 1).

sine is the up/down distance from the triangle baseline or corresponding circle diameter.

cosine is the left/right distance from the center of the circle (and the point of the angle).

for larger triangles and circles all these function results need to be multiplied by the actual radius (which we skipped for the norm circle, as a multiplication by 1 is not changing anything).

when you look at the triangle with K representing the angle, we have 10 a the cosine value, 24 as the sine value and 26 as the radius.

so,

10 = cos(K) × 26

cos(K) = 10/26 = 5/13

Hello! Help please thank you ​

Answers

Answer:

2(2(3) + 2(5) + 3(5)) = 2(6 + 10 + 15) = 2(31)

= 62

D is the correct answer.

On your own paper, make a frequency table for and find the mean to the nearest hundredth. 6. 7, 6, 6, 7, 6, 5, 8, 6, 5, 9, 8, 5, 6, 8 9, 5, 8, 8, 6, 8, 7, 5, 6,9,7,7,9,6 7. 501 501

Answers

After drawing our frequency table, we also find out that our mean is 6.73.

How to make a frequency table and find the mean?

To make a frequency table, we have to count the number of times each value appears in the data set.

Frequency table:

Value       Frequency

5              4

6              8

7              4

8              6

9              3

To find the mean, we will add all values and divide by total number of values. The mean is:

= EF / N

= (6 + 7 + 6 + 6 + 7 + 6 + 5 + 8 + 6 + 5 + 9 + 8 + 5 + 6 + 8 + 9 + 5 + 8 + 8 + 6 + 8 + 7 + 5 + 6 + 9 + 7 + 7 + 9 + 6 + 7) / 30

= 6.83333333333

= 6.83.

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Problem 7. (1 point) Suppose you are given a solid whose base is the circle x2 + y2 = 36 and the cross sections perpendicular to the x- axis are triangles whose height and base are equal. Find the area of the vertical cross section A at the level X = 3.

Answers

The shape formed by a solid intersecting with a plane, so the At level X = 3, the area of the vertical cross-section A is 108 square units.

To find the area of the vertical cross section A at the level X = 3, we need to find the equation of the circle when it is intersected by the plane X = 3.
First, let's find the value of y when X = 3 using the equation of the circle x^2 + y^2 = 36:

(3)^2 + y^2 = 36
9 + y^2 = 36
y^2 = 27
y = ±√27

Since we are dealing with a circle, there are two points on the circle at X = 3, which are (3, √27) and (3, -√27).

The distance between these two points will be the base of the triangle, which is also equal to its height (as given in the problem).

Base and height of the triangle: 2 * √27

Now we can find the area A of the vertical cross-section, which is a triangle with equal base and height:

A = 1/2 * base * height
A = 1/2 * (2 * √27) * (2 * √27)
A = 4 * 27
A = 108

So, the area of the vertical cross-section A at the level X = 3 is 108 square units.

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Five machines are cutting 1.25-foot long
metal sheets. The machines are being
calibrated to ensure that they are cutting
the accurate length. The previous batches
for each machine are shown in the table.
Select all of the statements that are valid
for the data.

Answers

Only the statement "One machine is considerably more unreliable than the rest." is valid for the data.

How to get the valid statements

Total number of correct cuts = 42 + 55 + 13 + 24 + 17 = 151

Total number of cuts = 100 + 100 + 100 + 100 + 100 = 500

Percentage of correct cuts = (151/500) * 100 = 30.2%

This statement is not valid, as only 30.2% of the cuts are the correct length.

One machine is considerably more unreliable than the rest."

By examining the number of correct cuts for each machine, we can see that Machine 3 has only 13 correct cuts, while the other machines have more than 17. This statement is valid.

3. When a machine misses the correct length, it tends to cut too long."

We need to compare the number of cuts that are too long (1.26-1.27 feet) with those that are too short (1.23-1.24 feet) across all machines:

Total number of cuts too long = 4 + 2 + 3 + 6 + 4 = 19

Total number of cuts too short = 980 + 72 + 67 = 1119

This statement is not valid, as the machines tend to cut too short rather than too long.

4. "Machine 5 will cut every batch the correct length at least 92% of the time."

To check this statement, we need to find the percentage of correct cuts for Machine 5:

Percentage of correct cuts for Machine 5 = (17/100) * 100 = 17%

This statement is not valid, as Machine 5 only cuts the correct length 17% of the time, which is less than 92%.

only the statement "One machine is considerably more unreliable than the rest." is valid for the data.

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In △abc , m∠b=20° and m∠c=40°. the angle bisector at a intersects side bc at point d. find the difference between bc and ab if ad = 1

Answers

In the △ABC, the  the difference between bc and ab if ad = 1 is found to be 0.709.

We can use the angle bisector theorem to solve this problem. Let's denote the length of segment BD as x and the length of segment CD as y. Then, we can write,

BD/DC = AB/AC

Using the angle bisector theorem, we know that AB/AC = BD/DC, so we can substitute to get,

x/y = AB/AC

We can solve for AB by multiplying both sides by AC,

AB = x/y * AC

Now, we can use the law of sines to find the length of AC. We have,

sin(20°)/AB = sin(140°)/AC

Solving for AC, we get,

AC = AB * sin(20°) / sin(140°)

Substituting the expression we found for AB, we get,

AC = x/yACsin(20°) / sin(140°)

Simplifying, we get,

y = xsin(140°) / (sin(20°) - sin(140°))

We know that AD = 1, so we can use the Pythagorean theorem to find BC:

BC² = BD² + CD²

Substituting the expressions we found for BD and CD, we get,

BC² = x² + y²

Substituting the expression we found for y, we get,

BC² = x² + (xsin(140°) / (sin(20°) - sin(140°)))²

Simplifying, we get,

BC² = x²(1+sin²(140°)/(sin²(20°)-2sin(20°)sin(140°)+sin²(140°)))

Using the identity sin(140°) = sin(180° - 40°) = sin(40°), we can simplify further.

Now, we can substitute x = AD = 1 and sing a calculator, we can evaluate this expression to get,

BC² ≈ 2.917

Taking the square root, we get,

BC ≈ 1.709

Therefore, the difference between BC and AB is 0.709.

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