Give an example of appliances at home that is connected using a series connection draw the circuit in a series connection

Answer:

40.92%

Explanation:

CaCo₃(s)-->CaO(s)+CO₂(g)

mass of Co2(g)= 1.33grams

mass of CaO(s)=(3.25-1.33)=1.92grams

mass % of CaCO₃ = [tex](\frac{1.33}{3.25} )[/tex]×100%

40.92%

Answer:

The moon orbits quite fast: it moves about 0.5 degrees per hour in the sky. In 24hrs it moves 13 degrees. the moons observed motion eastward results from its physical motion of the moon along its orbit around the earth

Plz mark brainliest

Answer: Entropy is increasing

Explanation:

Answer:

177 grams

Explanation:

moles of CaF₂ = [tex]\frac{mass}{molar mass}[/tex] = [tex]\frac{365}{78}[/tex] = 4.67949

moles of F-atom = 2×moles of CaF₂ = 2×4.67949 = 9.35898

(mol)×(molar mass)= 9.35898×19 = 177.82062

Therefore, 177 grams of F are in the mixture.

Answer:

d. It contains one valence electron.

Since, potassium has one valence electron so it can easily donate one electron during chemical reaction.

Answer:

CrCl₃.

Explanation:

From the question given above, the following data were obtained:

Mass of chromium (Cr) = 22.60 g.

Mass of metal chloride = 68.83 g.

Empirical formula =.?

Next, we shall determine the mass of chlorine (Cl) in the metal chloride. This can be obtained as follow:

Mass of chromium (Cr) = 22.60 g.

Mass of metal chloride = 68.83 g.

Mass of chlorine (Cl) =.?

Mass of chlorine (Cl) = (Mass of metal chloride) – (Mass of chromium)

Mass of chlorine (Cl) = 68.83 – 22.60

Mass of chlorine (Cl) = 46.23 g

Finally, we shall determine the empirical formula for the metal chloride as follow:

Cr = 22.60 g.

Cl = 46.23 g

Divide by their molar mass

Cr = 22.60 / 52 = 0.435

Cl = 46.23 / 35.5 = 1.302

Divide by the smallest

Cr = 0.435 /0.435 = 1

Cl = 1.302 /0.435 = 3

The empirical formula for the metal chloride is CrCl₃

Answer:

for the Lewis diagram of water, hydrogens should go on the outside with oxygen in the center

Explanation:

hydrogens always go on the outside

Answer:

layers of epithelial tissue

Answer:

It's B

Explanation:

Answer:

3.22 L

Explanation:

0.00 C = 273 K

k = C +273

606 K + 273 K = 879 K

879/273 = 3.219

V2 = 3.22 L

Answer:

They are in the same group on the periodic table indicating that they have the same number of valence electrons.

Explanation:

Answer:

2.91M is the concentration of the household ammonia solution

Explanation:

18.2mL of a 0.800M HCl solution to neutralize 5.00mL

The reaction of HCl with NH3 is:

HCl + NH3 → NH4Cl

Thus, the moles of HCl needed to neutralize the household are equal to moles of NH3. That is:

18.2mL = 0.0182L * (0.800mol / L) = 0.01456 moles HCl = Moles NH3.

In 5.00mL = 0.005L:

0.01456 moles NH3 / 0.005L =

Answer:

false

Explanation:

Answer:

Explanation:

Option 1 15. Proton 16 neutron 15 electron

Isotopes have same atomic no but different atomic mass

Answer:

20.3%

Explanation:

Given mass of impure ore = 896g and mass of pure iron to be 182g after purification,

[tex]\frac{(896-182)g}{896}[/tex] × 100

= 79.7%

in subtracting the weight of impure mass from that of the pure sample, we are left with the mass of the impurities alone.

This means the mass percent of pure iron in this iron ore sample is 20.3%.

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Answer:

0.0003125 g

Explanation:

Given data:

Half life of iodine-125 = 60 days

Mass of iodine pellet  = 0.020 g

Mass of iodine remain after one year = ?

Solution:

one year = 365 days

Number of half lives = Time elapsed/ half life

Number of half lives = 365 days/ 60 days

Number of half lives = 6

At time zero = 0.020 g

At 1st half life = 0.020 g/2 = 0.01 g

At 2nd half life = 0.01 g / 2 = 0.005 g

At 3rd half life = 0.005 g/2 = 0.0025 g

At 4th half life = 0.0025 g / 2 = 0.00125 g

At 5tht half life = 0.00125 g / 2 =  0.000625 g

At 6th half life = 0.000625 g/ 2 = 0.0003125 g

Answer:

Explanation:

C₆H₁₂     + H₂O      =     C₆H₁₃OH

hexene                      hexanol

1 mole                             1 mole  

Mol weight of hexene = 84

Mol weight of hexanol   = 102

5.33g of hexene = .06345 moles

4.6 g of hexenol = .0451 moles

percentage yield of hexanol

= .0451 x 100 / .06345

= 71.07 %

Moles of hexene used = .0451 moles

Explanation:

The substances that "go in" to a chemical reaction are called the reactants (by convention these are usually listed on the left side of a chemical equation), and the substances found that "come out" of the reaction are known as the products (by convention these are usually found on the right side of a chemical equation

Answer: The reactants that go into the chemical reaction are on the left of the equation. The substances that come out of the chemical reaction are usually on the right side of the equation.

Hope it helps!

yes they decrease when the temperature drops so it's true

Answer:A cell is the smallest unit of a living thing. A living thing, whether made of one cell (like bacteria) or many cells (like a human), is called an organism. Thus, cells are the basic building blocks of all organisms. ... Several systems that function together form an organism (like a human being).

Hope this helped! If it did leave a brainliest.

Have an amazing night/day!

Answer:

1. Weigh 3.27 ×10⁻⁴ ng of NaOH  in a special balance for weighing in nanograms

2. Measure a volume of 650 mL in a test tube

3. Make the solution by mixture

Explanation:

NaOH is a strong base. As every strong base, can be completely dissociated:

NaOH →  Na⁺  +  OH⁻

If pH is 13.90, we can calculate the [OH⁻], so we would know the molarity of NaOH.

1 mol of NaOH can generate 1 mol of OH⁻

[OH⁻] = 10⁻¹³'⁹ = 1.26×10⁻¹⁴ M

In conclussion, molarity of NaOH is 1.26×10⁻¹⁴ M

M = moles of NaOH / volume of solution

We convert the volume from mL to L

650 mL . 1 L /1000mL = 0.650 L

Moles of NaOH = 0.650 L . 1.26×10⁻¹⁴ M = 8.18×10⁻¹⁵ moles

We convert the moles to mass, to determine the grams:

8.18×10⁻¹⁵ moles .  40 g/mol = 3.27 ×10⁻¹³ g

We can convert the grams to ng = 3.27 ×10⁻⁴ ng

Answer:

The charges are typically used to determine the mole ratio and composition of the individual atoms of elements in the compound

Explanation:

Take for instance the following compounds:

[tex]NaOH[/tex] and [tex]H_{2} O[/tex]

I hope this helps.

Answer:

Equilibrium

Explanation:

Correct on edge 2020

Answer:

A - Equilibrium

Explanation:

For edge:)

Answer:

Explanation:

The volume of the gas can be found by using the formula for Boyle's law

[tex]P_1V_1 = P_2V_2[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]

We have

[tex]V_2 = \frac{10 \times 1}{5} = \frac{10}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

Reaction product A is more likely to form in the epoxide ring-opening reaction

Explanation:

The diagram for the reaction can be seen in the image attached below.

An epoxide is any class of organic compound, cyclic ethers, having a three-membered ring; they are usually prepared by selective oxidation of alkenes or by ring-closure of halohydrins(any class of organic compound having a hydroxyl functional group and a halogen on neighboring carbon atom ) which are used in making plastic.

Answer:

22.4 g

Explanation:

Calculate the mass of sodium acetate that must be added to 500.0 mL of 0.300 M acetic acid to form a pH  = 5.00 buffered solution.

Step 1: Given data

Volume of solution: 500.0 mL

[acetic acid]: 0.300 M

pH = 5.00

pKa of acetic acid: 4.74

Step 2: Calculate the concentration of sodium acetate

We will use the Henderson-Hasselbach equation.

pH = pKa + log [sodium acetate]/[acetic acid]

5.00 = 4.74 + log [sodium acetate]/0.300 M

[sodium acetate] = 0.546 M

Step 3: Calculate the moles of sodium acetate

We have 500.0 mL of a 0.546 M sodium acetate solution

0.5000 L × 0.546 mol/L = 0.273 mol

Step 4: Calculate the mass of sodium acetate

The molar mass of sodium acetate is 82.03 g/mol.

0.273 mol × 82.03 g/mol = 22.4 g