Answer:
B. Clamshell
Explanation:
Density is defined as mass per volume. The density of an object decides whether that object will sink or float if placed in water.
An object with higher density sinks in the water while an object with less density floats in water. In the given example, Clamshell has the highest density as it sinks in the water while other objects' wooden stick and acorn float over the water.
Clamshell has the highest density than water as well because the object has more weight per unit of volume and the buoyancy force of water decreases that allow the object to sink.
Hence, the correct answer is "B. Clamshell".
Br
A tow truck pulls a 1,500 kg car with a net force of 2,000 N. What is the
acceleration of the car? DO NOT FORGET CORRECT UNITS.
Answer:
a = F/m = 4000/1500 = 2.66m/s^2
Explanation:
A tow truck pulls a mass of 1500 kg with a force of 2000 N then the acceleration of the truck will be equal to 1.33 m/s².
What is Force?A force in physics is an input that has the power to change an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe forces.
Being such a vector quantity, a force does have magnitude and direction. The SI unit metric newton is used to measure it (N). The letter F stands for force.
According to Newton's second law's original formulation, an object's net force is equal to the speed that its momentum is changing over time.
As per the given information in the question,
Mass of car, m = 1500 kg
Force, F = 2000 N
Then, the acceleration will be,
F = m × a
a = 2000/1500
a = 1.33 m/s²
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erica wants to attend a a public four- year unviersity
Answer:
go girl
Explanation:
i'm feom public uni too
Two blocks are arranged at the ends of a massless cord over a frictionless massless pulley as
shown in the figure. Assume the system starts
from rest. When the masses have moved a distance of 0.317 m, their speed is 1.33 m/s.
The acceleration of gravity is 9.8 m/s
2
What is the coefficient of friction between
m2 and the table?
What is the magnitude of the tension in the
cord?
Answer in units of N.
Answer:
The coefficient of friction between m₂ and the table is approximately 0.2703
The magnitude of the tension in cable is 28.737 N
Explanation:
The given parameters are;
The mass of the block on the table, m₂ = 5.8 kg
The mass of the hanging block, m₁ = 4.5 kg
The distance in which the block has moved = 0.317 m
The speed after the block moves = 1.33 m/s
The acceleration due to gravity, g = 9.8 m/s²
The coefficient of friction between m₂ and the table = μ
The acceleration, a, of the blocks is given from the formula of speed, v, of a body at a given distance, s, from rest as follows;
v² = 2 × a × s
Where;
v = 1.33 m/s
s = 0.317 m
Substituting the values gives;
1.33² = 2 × a × 0.317
a = 1.33²/(2 × 0.317) ≈ 2.79
The acceleration, a ≈ 2.79 m/s²
Therefore, we have the force acting on the system given as follows;
Weight of m₁ - Frictional force of m₂ = (m₁ + m₂) × a
4.5 × 9.8 - 5.8 × 9.8 × μ = (4.5 + 5.8) × 2.79
4.5 × 9.8 - 5.8 × 9.8 × μ = 28.737 N
(4.5 × 9.8)N - 28.737 N = 5.8 × 9.8 × μ
44.1 N - 28.737 N =56.84 N × μ
15.363 N = 56.84 N × μ
μ = 15.363 N/(56.84 N) ≈ 0.2703
The coefficient of friction between m₂ and the table = μ ≈ 0.2703
The coefficient of friction between m₂ and the table ≈ 0.2703
The magnitude of the tension in cable = (m₁ + m₂) × a = 28.737 N.
The magnitude of the tension in cable = 28.737 N
is it true that mass is a measure of the force of gravity on an object
Answer:
yes it is true
Explanation:
A swimmer can travel 2.30 m/s in still water. The swimmer heads directly west across a steam whose current is 1.20 m/s n. What is his velocity relative to the ground
Answer:
velocity relative to the ground = 2.54 m/s
Explanation:
given data
still water Vx = 2.30 m/s
across a steam Vy = 1.20 m/s
solution
we get here first velocity relative to the ground is express as
velocity = [tex]\sqrt{Vx^2+Vy^2}[/tex] ...............1
put here value and we get
velocity = [tex]\sqrt{2.3^2+1.20^2}[/tex]
velocity = 2.54 m/s
A sheet of BCC iron 1.5-mm thick was exposed to a carburizing atmosphere on one side and an carburizing atmosphere on the other side at 725°C. After having reached steady state, the iron was quickly cooled to room temperature. The carbon concentrations at the two surfaces were determined to be 0.012 and 0.0069 wt%. Calculate the diffusion coefficient if the diffusion flux is 3.6 × 10-8 kg/m2-s, given that the densities of carbon and iron are 2.25 and 7.87 g/cm3, respectively.
Answer:
Diffusion coefficient D = 2.6613 × 10⁻¹¹ m²/s
Explanation:
From the given information:
Carbon concentration [tex]C_c[/tex] = 0.012
Iron concentration [tex]C_{Fe}[/tex] = 100 - 0.012 = 99.988
Density of carbon = 2.25 g/cm³
Density of iron = 7.87 g/cm³
We can convert the carbon concentrations from weight percentage to kilograms carbon per meter cubed by using the formula.
[tex]C^*_c = \dfrac{C_c}{\dfrac{C_c}{\rho_c}+\dfrac{C_{Fe}}{\rho_{Fe}}}\times 10^3[/tex]
[tex]C^*_c = \dfrac{0.012}{\dfrac{0.012}{2.25 \ g/cm^3}+\dfrac{99.988}{7.87 \ g/cm^3}}\times 10^3[/tex]
[tex]C^*_c = \dfrac{0.012}{0.00533 \ g/cm^3 + 12.71 \ g/cm^3} \times 10^3[/tex]
[tex]C^*_c = 0.9437 \ kgC/m^3[/tex]
However; for 0.0069 wt% C
[tex]C^*_c = \dfrac{C_c}{\dfrac{C_c}{\rho_c}+\dfrac{C_{Fe}}{\rho_{Fe}}}\times 10^3[/tex]
[tex]C^*_c = \dfrac{0.0069}{\dfrac{0.0069}{2.25 \ g/cm^3}+\dfrac{99.9931}{7.87 \ g/cm^3}}\times 10^3[/tex]
[tex]C^*_c =0.5429 \ kgC/m^3[/tex]
Thus; the diffusion coefficient can be computed by using the formula:
[tex]D = - J \begin {bmatrix} \dfrac{x_A-x_B}{C_A-C_B}\end {bmatrix}[/tex]
[tex]D = - (3.6 \times 10^{-8} \ kg/m^2-s) \begin {bmatrix} \dfrac{-15^{-3} \ m }{0.9437 \ kgC/m^3 - 0.5429 \ kgC/m^3}\end {bmatrix}[/tex]
D = 2.6613 × 10⁻¹¹ m²/s
Which of the following statements best describes why the mass of a bowling ball would not change if it were transported from Earth to the Moon?
Answer:
On Earth, the acceleration due to gravity is 9.8 m/s/s. ... In other words, you weigh more on Earth; you would weigh less on the moon. For instance, if you take a 10 kg bowling ball to the moon, it would still have a mass of 10 kg. However, its weight would be much less because the moon's gravity is relatively weak.
Explanation:
Se tiene una esfera gaussiana que encierra a un cubo de lado "a" que tiene una carga neta q. ¿Cuál es el flujo de campo eléctrico sobre la superficie de la esfera gaussiana?
Answer:
Φ = Q/ε₀
Explanation:
Una esfera Gaussiana, es una esfera imaginaria en cuya superficie el campo eléctrico es constante. El campo eléctrico es el producido por la carga que está encerrada por la superficie. De tal modo que si tenemos un cubo con una carga neta igual a Q y la asumimos ubicada en el centro del cubo (que es el centro de la esfera gaussiana de radio x), tendremos:
El flujo eléctrico es:
Φ = ∫ E*dS = Q/ε₀ Esta es la primera ecuación de Maxwell como E es constante por definicion
El area de una esfera es: A(s) = 4*π*x²
E * 4*π*x² = Q/ε₀
E = Q/4*π*ε₀* x²
La distancia que hay del centro del cubo a un vertice (x) es:
x² = a² + a²
x = √2a²
x = a*√2
Sustituyendo x por su valor
E = Q/4*π*ε₀*2*a²
Entonces
Φ = Q/4*π*ε₀*2*a²* ∫ dS
Φ = [Q/4*π*ε₀*2*a²] *[4*π*2*a² ]
Φ = Q/ε₀
What is the driving energy source for the heating of the Earth?
what determines the roll and pitch of a satellite.
This is for my Physical science class
If a 6kg bird is pushed by the wind with a force of 10 N. how fast does the bird
accelerate?
Answer:
a=1.667 m[tex]s^{-2}[/tex]
Explanation:
F=ma, here force is given as 10N and mass of bird is 6kg, so using the formula acceleration can be calculated as follows
∴ F=ma
1N= 1 kg m[tex]s^{-2}[/tex]
[tex]a=\frac{F}{m}[/tex]
[tex]a=\frac{10 kg ms^{-2} }{6 kg}[/tex]
∴ a= 1.667 m[tex]s^{-2}[/tex]
A rocket is shot out of a navy battleship to test a new rocket. It takes 16 seconds for the rocket
to reach its destination after leaving the barrel. If its final velocity was found to be 200 m/s,
then what was the rocket's acceleration?
In order to get the most benefits from exercise with the least amount of risk, you should
Answer:
always stretch before you exercise
Explanation:
Which does NOT illustrate Newton's First Law?
Answer:
u didnt have options? to this question
Free Fall Problems
1.)
A pencil is dropped from the top of a very tall bridge and hits the ground 3.2 s later
A) With what velocity did the pencil hit the river below?
B.)
How far did the pencil fall?||
Answer:
50.2m
Explanation:
Given parameters:
Time taken for the pencil to hit the ground = 3.2s
Unknown:
Final velocity = ?
height of fall = ?
Solution:
To solve this problem, we should apply appropriate motion equations;
A.
V = U + gt
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
t is the time taken
Insert the parameters and solve;
V = 0 + 9.8 x 3.2 = 31.36m/s
B.
h = ut + [tex]\frac{1}{2}[/tex]gt²
h is the height of fall
Insert the parameters and solve;
h = [tex]\frac{1}{2}[/tex] x 9.8 x 3.2² = 50.2m
A baby drops a ball from her hand resting on the serving tray of her high chair. at the
exact same time, she knocks another ball from the same tray at the exact same height.
Which of the following statement or statements is / are true?
1. Both balls strike the ground at the same time.
II. The dropped ball reaches the ground first.
III. The knocked ball reaches the ground first.
IV. Both balls strike the ground at the same speed
O I and IV
O ll only
I only
O Ill only
Answer:
Both balls strike the ground at the same time, and both balls strike the ground at the same speed.
Explanation:
Match the number in this mathematical expression with the number significant digits they have .
18.34cm +9.02603cm -20.2cm +150cm
1. 150cm. a.4
2. 9.02603 cm. b.6
3. 18.34cm. c. 2
4. 20.2cm. d.3
Answer:
Please check your question well. Otherwise I think there's no matching.
HELP PLEASE!!
You throw a rock with sufficient speed to put it into orbit around the asteroid 234 Ida very close to its surface. How long would it take the rock to make one orbit around the asteroid? Assume 234 Ida is spherical. Ida's mass is 4 x 1016 kg and its radius is 16 km.
A) 0.62 hr
B) 2.2 hr
C) 1.6 hr
D) 3.4 hr
Answer:
The correct option is;
B) 2.2 hr
Explanation:
The location of the rock in the orbit of the asteroid = Close to the surface of the asteroid
The required equation is given as follows;
[tex]\dfrac{G \times M \times m}{r^2} = \dfrac{m \times v^2}{r}[/tex]
[tex]\therefore v^2 = \dfrac{G \times M}{r}[/tex]
Where;
v = The orbital velocity
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
r = The radius of the planet = 16 km = 16,000 m
M = The mass of the planet = 4 × 10¹⁶ kg
∴ v² = 6.67430 × 10⁻¹¹ × 4 × 10¹⁶/16,000 = 166.8575
v = √(166.8575) = 12.92 m/s
The orbital velocity = v = 12.92 m/s
The time it takes for the rock to make one orbit round the asteroid is given as follows
The length of the orbit = The circumference of the asteroid = 2 × π × r
The length of the orbit = 2 × π × 16,000 ≈ 100530.965 m
The time it takes for the rock to make one orbit round the asteroid = The length of the orbit/(The speed of the asteroid)
The time it takes for the rock to make one orbit round the asteroid = 100530.965/(12.92) ≈ 7781.034 seconds or 2.2 hours (by approximation by one decimal place)
The time it takes for the rock to make one orbit round the asteroid ≈ 2.2 hours.
where are the new skin cells made
Answer:
epidermis
The top 18 to 23 layers of your skin are made of dead cells. New skin cells form at the bottom of the epidermis, which is the top part of your skin. Skin cells change shape. They start off kind of fat and square.
Explanation:
A child appears to be running into the street aheadIt takes 23 seconds for the driver to react and begin to brake, but this time at a rate of - 7.5 m/s ^ 2 . What is the stopping distance for the car in this situation?
Answer:
Explanation:
Given
acceleration a = - 7.5 m/s^2
time t = 23secs
Required
Stopping distance S
First let us get the initial velocity if the child using:
v = u + at
Note that v = 0
0 = u -7.5(23)
u = 7.5 * 23
u =172.5m/s
Using the equation of motion to get the stopping distance:
v² = u²+2aS
0 = u²+2aS
-u² = 2aS
-172.5² = 2(-7.5)S
29,756.25 = 15S
S =29,756.25/15
S = 1,983.75m
Hence the stopping distance is 1,983.75m
What is an application of this model?
А
It highlights the artistic abilities of scientists.
B
It illustrates the basic structure of an atom. .
С
It shows how the parts of an atom interact.
D
It demonstrates how atoms form and function.
DUE TODAY HELP ME WRITE A ESAAY NOW
I WILL MARK YOU AS BRAINLEST
it is about science
like how a scientists work
or how to be a scientist
essay is 500 words
Answer:
Explanation:
Try adding what process they have to go through to become a scientists the try adding some things that you think they work on in the labs.
A dragster's top acceleration is 60m/s2. If it accelerates for 3 seconds from the starting line, how fast will it be going
Answer:
180 m/s
Explanation:
acceleration = 60 m/s2
time = 3 secs
u(initial velocity) = 0 m/s
v(final velocity) = ?
equation used is = v = u + at
0 + 60*3
v = 180 m/s
A dragster's top acceleration is 60 meters/second². If it accelerates for 3 seconds from the starting line, then the total distance covered by it would be
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object.
As given in the problem a dragster's top acceleration is 60 meters/second². If it accelerates for 3 seconds from the starting line, then we have to find out the total distance traveled by it,
top acceleration of the dragster = 60 meters/second²
time period to accelerate = 3 seconds
By using the second equation of motion,
s = ut + 1/2at²
s = 0 + 0.5×60×3²
s = 270 meters
Thus, the total distance covered by the dragster would be 270 meters
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A red ball rolls for 6 meters across a sticky level surface and slows down to a stop. the ball was rolling at 36 meters per second when it began to roll across the sticky surface. find the acceleration, velocity final, the velocity initial, the velocity average, the distance the ball rolled, and the time of the balls roll across the sticky surface
Answer:
The initial velocity of the ball is given as 36 m/s
The final velocity of the ball is given as 0 m/s
The distance the ball rolled is given as 6 meters
The acceleration is 108 m/s²
The time the ball rolls across the sticky surface is 1/3 seconds
The average velocity is 18 m/s
Explanation:
The initial velocity of the ball, u = 36 m/s
The final velocity of the ball, v = 0 m/s
The distance the ball rolled, s = 6 meters
The acceleration, a, is given by;
v² = u² - 2×a×s, where v = 0
u² = 2 × a × s
a = u²/(2 × s) = 36²/(2 × 6) = 108 m/s²
The time the ball rolls across the sticky surface is given by the following equation;
v = u - a×t, v = 0
∴ u = a×t
t = u/a = 36/108 = 1/3 seconds
The time the ball rolls across the sticky surface = 1/3 seconds
The average velocity = Distance/time = 6/(1/3) = 18 m/s
The average velocity = 18 m/s.
convert 72km\hr into SI unit
Answer:
hello we can't convert 72 into s18 because that is another one and another one
Explanation:
0 please Marks as brainleast
A car drives off a cliff at 30 m/s. The car lands 100 meters
from the base of the cliff. How tall is the cliff?
Answer:
Height of the cliff, H = 54.66 m
Explanation:
Given that,
Speed of the car, u = 30 m/s
The car lands 100 m from the base of the cliff.
We need to find the height of the cliff.
First we will find the time time needed for the car to reach the bottom of the cliff. It can be calculated as :
[tex]t=\dfrac{h}{v}\\\\t=\dfrac{100}{30}\\\\t=3.34\ s[/tex]
Let H is the height of the cliff. Using second equation of motion as follows
[tex]H=v_yt+\dfrac{1}{2}gt^2\\\\H=\dfrac{1}{2}gt^2\\\\H=\dfrac{1}{2}\times 9.8\times (3.34)^2\\\\H=54.66\ m[/tex]
So, the cliff is 54.66 m tall.
In the data table, distance is measured in meters and time is in seconds. Calculate the boy’s average velocity using the equation
average velocity= total distance / total time
Answer:
23.59 for the average pls give brainliest sis
Answer: 23.59
HOPE THIS HELPS :D
Melanie is given an unknown substance by her teacher. Melanie’s teacher tells her that the substance has a bitter taste. Melanie also observes that the substance is slippery. These properties indicate that the substance may be which of the following?
Answer:
base
Explanation:
I hope this helps
Answer:base
Explanation:
two asteroids crashed. The crash caused both asteroids to change speed. Scientists want to use the change in speed and motion to figure out which asteroid has more mass. Based on the information in the diagram, which statement is correct? In your answer, explain what the forces were like and why the asteroids changed their motion.
Asteroid 1 has more mass than Asteroid 2.
Asteroid 1 and Asteroid 2 are the same mass.
Asteroid 1 has less mass than Asteroid 2.
Answer:
The answer is asteroid 1 has more mass
Explanation:
If the initial speed of both asteroids before the collision is equal, then the asteroid with more mass has more momentum before collision while the asteroid with lesser mass has greater momentum after the collision.
What is law of conservation of linear momentum?According to the principle of conservation of linear momentum, the sum of the momentum before the collision must equal the sum of the momentum after the collision.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where m₁ and m₂ is the mass of the objects that collided, u₁ and u₂ is their initial speed and v₁ & v₂ is their final speed.
The linear momentum is the product of the mass of the object times the velocity of that object. Conservation of momentum is a property exhibited by any object where the total amount of momentum never changes.
The principle of conservation of linear momentum states that if two objects collide with each other, then the total momentum before and after the collision will remain the same if there will be no external force acting on the colliding objects.
Therefore, the linear momentum of both asteroids will be conserved as no external force acting on them. The asteroid with more mass has more momentum before collision while the asteroid with lesser mass has greater momentum after the collision so that total momentum remains conserved.
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create an acrostic poem for the words "INERTIA"
Answer:
I- In all circumstances,
N- Never relenting to pressure.
E- Ever remaining constant and stable,
R- Resisting any form of association with other things,
T- This force will always be the same.
I- In whatever manner or pattern the force may come from.
A- Always true to the core, never changing, never relenting.
Explanation:
An acrostic poem is the formation of a poem/ poetry by using certain letters of the word to form a poem. This means that certain letters of any given word will be used as the basis for the construction and formation of a poem.
The acrostic poem for the word "INERTIA" is as follows-
I- In all circumstances,
N- Never relenting to pressure.
E- Ever remaining constant and stable,
R- Resisting any form of association with other things,
T- This force will always be the same.
I- In whatever manner or pattern the force may come from.
A- Always true to the core, never changing, never relenting.
I- In all circumstances,
N- Never relenting to pressure.
E- Ever remaining constant and stable,
R- Resisting any form of association with other things,
T- This force will always be the same.
I- In whatever manner or pattern the force may come from.
A- Always true to the core, never changing, never relenting.
What is an inertia?The inertia of any object is defined as when any object is at rest then it will be always at rest until and unless the external force is not applied on it. Also, if it is in motion, it will always in the motion until and unless an external force is not applied on it to stop it.
An acrostic poem is the formation of a poem/ poetry by using certain letters of the word to form a poem. This means that certain letters of any given word will be used as the basis for the construction and formation of a poem.
The acrostic poem for the word “INERTIA” is as follows-
I- In all circumstances,
N- Never relenting to pressure.
E- Ever remaining constant and stable,
R- Resisting any form of association with other things,
T- This force will always be the same.
I- In whatever manner or pattern the force may come from.
A- Always true to the core, never changing, never relenting.
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