Please please help I'm stuck!!!
Answer: iDc im in 3grade
Explanation:sorry
Which scale do geologists use to estimate the total energy released by an earthquake?
Answer:
Richter scale Magnitude
Richter scale. Magnitude is a measure of the amount of energy released during an earthquake, and you've probably heard news reports about earthquake magnitudes measured using the Richter scale. Something like, "A magnitude 7.3 earthquake struck Japan today.
Explanation:
Hope I helped!
Forces act on a box that is initially at rest as shown. Coefficient of friction between the object and the surface is μ=0.1.
If the box' mass is 6kg box and if it is moving with acceleration of 0.4m/s2, what distance will the box travel if it was pushed for 4s?
Answer:
3.2 m
Explanation:
From the question given above, the following data were obtained:
Coefficient of friction (μ) = 0.1
Initial velocity (u) = 0 m/s
Mass (m) = 6 Kg
Acceleration (a) = 0.4 m/s²
Time (t) = 4 s
Distance (s) =.?
The distance travelled can be obtained as illustrated below:
s = ut + ½at²
s = (0×4) + (½ × 0.4 × 4²)
s = 0 + (0.2 × 16)
s = 0 + 3.2
s = 3.2 m
Thus, the box will travel 3.2 m in 4 s.
27. The traffic officer issued violation tickets to traffic
violators. If 68 of them composed 80% of the total
violators, how many violators are there in all?
A. 83
B. 84
C. 85
D. 86
28. There are 18 roses in a bunch of 24 flowers.
What percent of the flowers are roses?
A. 18%
B. 24% C. 60% D. 75%
Please help me ❤️❤️ thank u
Hope god
Answer:
27: 85
28:75%
Explanation:
27:68=80
?=100 hence (68×100)÷80
=85
28:18/24× 100
=75%
Two bicycle tires are set rolling with the same initial speed of 4.0 m/s along a long, straight road, and the distance each travels before its speed is reduced by half is measured. One tire is inflated to a pressure of 40 psi and goes a distance of 18.2 m; the other is at 105 psi and goes a distance of 92.6 m. Assume that the net horizontal force is due to rolling friction only and take the free-fall acceleration to be g = 9.80 m/s2. What is the coefficient of rolling friction μr for the tire under low pressure?
Answer:
The coefficient of rolling friction will be "0.011".
Explanation:
The given values are:
Initial speed,
[tex]v_i = 4.0 \ m/s[/tex]
then,
[tex]v_f=\frac{4.0}{2}[/tex]
[tex]=2.0 \ m/s[/tex]
Distance,
s = 18.2 m
The acceleration of a bicycle will be:
⇒ [tex]a=\frac{v_f^2-v_i^2}{2s}[/tex]
On substituting the given values, we get
⇒ [tex]=\frac{(2.0)^2-(4.0)^2}{2\times 18.2}[/tex]
⇒ [tex]=\frac{4-8}{37}[/tex]
⇒ [tex]=\frac{-4}{37}[/tex]
⇒ [tex]=0.108 \ m/s^2[/tex]
As we know,
⇒ [tex]f=ma[/tex]
and,
⇒ [tex]\mu_rmg=ma[/tex]
⇒ [tex]\mu_r=\frac{a}{g}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{0.108}{9.8}[/tex]
⇒ [tex]=0.011[/tex]
A uniform 140 g rod with length 57 cm rotates in a horizontal plane about a fixed, vertical, frictionless pin through its center. Two small 30 g beads are mounted on the rod such that they are able to slide without friction along its length. Initially the beads are held by catches at positions 11 cm on each sides of the center, at which time the system rotates at an angular speed of 23 rad/s. Suddenly, the catches are released and the small beads slide outward along the rod. Find the angular speed of the system at the instant the beads reach the ends of the rod. Answer in units of rad/s.
Answer:
The correct answer is "12 rad/s"
Explanation:
The given values are,
Mass of rod,
M = 140 g
i.e.,
= 0.14 kg
Length,
L = 57 cm
i.e.,
= 0.57 m
Mass of beads,
M = 30 g
i.e.,
= 0.03 kg
Angular speed,
r = 11 cm
i.e.,
= 0.11 m
Now,
The inertia of rods will be:
= [tex]\frac{1}{12}ML ^2[/tex]
On substituting the values, we get
= [tex]\frac{1}{12}\times 0.14\times (0.57)^2[/tex]
= [tex]0.0037905 \ kg-m^2[/tex]
The inertia of beads will be:
= [tex]mr^2[/tex]
On substituting the values, we get
= [tex]0.03\times (0.11)^2[/tex]
= [tex]0.000726 \ kg-m^2[/tex]
The total inertia will be:
= [tex]Inertia \ of \ rods+Inertia \ of \ beads[/tex]
= [tex]0.0037905 + 0.000726[/tex]
= [tex]0.0045165 \ kg-m^2[/tex]
now,
The angular speed of the system will be:
⇒ [tex]L_1w_1=L_2w_2[/tex]
On substituting the values in the above equation, we get
⇒ [tex]0.0045165\times 23 = (0.0037905 + (0.03\times 0.285^2)\times 2 )\times w_2[/tex]
⇒ [tex]0.1038795 = 0.0037905 + (0.00243675\times 2 )\times w_2[/tex]
⇒ [tex]w_2 = 12 \ rad/s[/tex]
The desperate contestants on a TV survival show are very hungry. The only food they can see is some fruit hanging on a branch high in a tree. Fortunately, they have a spring they can use to launch a rock. The spring constant is 900 N/m, and they can compress the spring a maximum of 45 cm. All the rocks on the island seem to have a mass of 500 g.
a) With what speed does the rock leave the spring?
b) To what height can the rock be launched?
Answer:
a) v = 18.86 m / s, b) h = 8.85 m
Explanation:
a) For this exercise we can use the conservation of energy relations.
Starting point. Like the compressed spring
Em₀ = K_e + U = ½ k x² + m g x
the zero of the datum is placed at the point of the uncompressed spring
Final point. With the spring if compress
Em_f = K = ½ m v²
how energy is conserved
Em₀ = Em_f
½ k x² + m g x = ½ m v²
v² = [tex]\frac{k}{m}[/tex] x² + 2gx
let's reduce the magnitudes to the SI system
m = 500 g = 0.500 kg
x = -45 cm = -0.45 m
the negative sign is because the distance in below zero of the reference frame
let's calculate
v² = [tex]\frac{900}{0.500}[/tex] 0.45² + 2 9.8 (- 0.45)
v = √355.68
v = 18.86 m / s
b) For this part we use the conservation of energy with the same initial point and as an end point at the point where the rock stops
Em_f = U = m g h
Em₀ = Em_f
½ k x²2 + m g x = m g h
h = ½ [tex]\frac{k}{g}[/tex] x² + x
let's calculate
h = [tex]\frac{1}{2} \ \frac{900}{9.8 } \ 0.45^2[/tex] - 0.45
h = 8.85 m
measured from the point where the spring is uncompressed
A kicker punts a football from the very center of the field to the sideline 41 yards downfield. (A football field is 53 yards wide.)What is the angle between the direction of the net displacement of the ball and the 50-yard line of the field
Answer:
Ur answer is 12 sir!
Explanation:
HAve a good day sir
what is the magnitude of electric field at apoint 2 meter from a point charge q= 4nc
compare and contrast series and parallel circuits?
In a series circuit, a common current flows through all the components of the circuit. While in a parallel circuit, a different amount of current flows through each parallel branch of the circuit. Whereas in the parallel circuit, the same voltage exists across the multiple components in the circuit.
Hope It Helps!
What is the name of the supercontinent that developed during the Paleozoic?
Laurasia
Tethys
Pangaea
Rodinia
Chromosomes _____.
carry thousands of genes
can be analyzed in a karyotype
always occur in pairs
are tight coils of DNA
are carried on genes
Answer:
The correct answer for this would be D.
Explanation:
Are tight coils of DNA
Please help
A meteoroid with a mass of 1,000 kg enters Earth's atmosphere with a velocity of 4,400 m/s. What is the magnitude of the meteorold's momentum at
that instant?
You have two cylindrical bar magnets with the same mass, length, and dipole moment, but different moments of inertia, I1 and I2. You place each bar magnet so that it is initially oriented perpendicular to a uniform magnetic field. When you let each bar magnet go from rest, you find that magnet 1 takes less time than magnet 2 to rotate so that it is parallel to the magnetic field. Is I1 greater than, less than, or equal to I2
Answer:
[tex]l1 < l2[/tex]; [tex]l1[/tex] is less than [tex]l2[/tex]
Explanation:
Firstly, we take a look at the concept of moment of inertia, This concept comes from the fact that it resists change in motion. A body that has a higher value of moment of inertia requires more force ( torque) to change its position as compared to a body with lesser value of moment of inertia.
Now taking a look at the situation in the question, both the magnets are placed in similar magnetic field, so having the same amount of force, hence torque acts on both magnets.
Since magnet 1 takes less time to rotate compared to magnate 2, hence magnet 1's moment of inertia should be less than that of magnet 2.
Therefore, [tex]l1 < l2[/tex]; [tex]l1[/tex] is less than [tex]l2[/tex]
A 1,250 kg car is moving due to 6,500 N engine force. If the kinetic friction coefficient between the car and the road is 0.32, what is the car's acceleration?
A) 32m/s²
B) 200m/s²
C) 50m/s²
D) 2m/s²
Answer and I will give you brainiliest
Answer:
b i hope this is correct answee
Help please thank you
A cart moves with negligible friction or air resistance along a roller coaster track. The cart starts from rest at the top of a hill of unknown height. It then goes down that first hill and up another circularly shaped hill of height 10 meters and radius 15 meters. The ride is designed so that the cart just barely loses contact with the track at the top of the second hill (10 meters above ground level). What is the height of the starting hill relative to ground
Answer:
hinit = 17.5 m
Explanation:
Assuming no friction present, the mechanical energy must be conserved, which means that at any point of the trajectory, the sum of the gravitational potential energy and the kinetic energy must keep the same.At the top of the hill, since it starts from rest, all the energy must be potential, and we can express it as follows:[tex]E_{o} = U_{o} = m*g*h_{init} (1)[/tex]
When the car arrives to the top of the second hill, as we know that it is lower than the first one, the energy of the car, must be part gravitational potential energy, and part kinetic energy.We can express this final energy as follows:[tex]E_{f} = U_{f} + K_{f} = m*g* h_{2} + \frac{1}{2} *m*v_{f} ^{2} (2)[/tex]
In order to find hinit, we need to make (1) equal to (2), and solve for it.In (2) we have the value of h₂ (10 m), but we still need the value of the speed at the top of the second hill, vf.Now, when the car is at the top of the hill, there are two forces acting on it, in opposite directions: the normal force (upward) and the weight (downward).We know also that there is a force that keeps the car along the circular track, which is the centripetal force.This force is just the net downward force acting on the car (it's vertical at the top), and is just the difference between the weight and the normal force.If the cart just barely loses contact with the track at the top of the second hill, this means that at that point the normal force becomes zero.So, the centripetal force must be equal to the weight.The centripetal force can be expressed as follows:[tex]F_{c} = m*\frac{v_{f} ^{2}}{R} (3)[/tex]
We have just said that (3) must be equal to the weight:[tex]F_{c} = m*\frac{v_{f} ^{2}}{R} = m*g (4)[/tex]
Simplifying, and rearranging, we can solve for vf², as follows:[tex]v_{f}^{2} = R*g (5)[/tex]
Replacing (5) in (2), simplifying and rearranging in (1) and (2) we finally have:[tex]h_{init} = h_{2} + \frac{1}{2} R = 10m + 7.5 m = 17.5 m (6)[/tex]
Using Bernoulli's equation Calculate the percentage increase in the speed of the air on the upper surface of the wings relative to the lower surface,if aircraft mass is 3.3×10^5kg,Total wing area is 500m^2 ,Flight level speed of 9600km/h and density of air is 1.2kgm^-3??
Explanation:
3d7eei4rueiuxx7ex5x775xe
Three 5 Ohm resistors are connected in parallel to a 9 Volt power supply. What is the current through each resistor?
Answer:
I₁ = I₂ = I₃ = 12 A
Explanation:
Since the resistors are connected in parallel across a battery. Hence, the voltage across each of them will be the same, which will be equal to the voltage of the power supply. Since each resistor has the same resistance of 5 Ω. Therefore. the current across each resistor will also be the same. We can easily calculate these current values by the use of Ohm's Law, as follows:
[tex]V = IR\\I_{1}=I_{2}=I_{3}=\frac{V}{R} \\\\I_{1}=I_{2}=I_{3}=\frac{9\ Volt}{5 \Omega}\\\\[/tex]
I₁ = I₂ = I₃ = 12 A
If you lean against a wall, the wall pushes back on you with a weaker force
true
false
false - (.do not ) if you lean against a wall the wall pushes back on you with a( n) weaker force
NEED HELP What color is the container for R-134a refrigerant? A. Light blue B. Yellow C. Dark green D.White and yellow
Answer:
It is A. Light blue
_____________
Hope this helps!
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An 80 N force causes a spring to compress 0.15 m. What is the spring constant? What is the potential energy of the spring?
The spring constant of the given spring is= -533.33
The potential energy of the spring= 6 Joule
What is force?
A push or pull that causes object to change its state of rest or motion.
It can also change the direction of a moving body.Force is a product of mass and acceleration.For spring;
K is the spring constant.
⇒Force = -kx
⇒80N=0.15m ×-k
⇒K=-80/0.15
⇒K= -533.333
So the spring constant is 533.333
Potential Energy=1/2kx²
⇒0.5×533.33 ×0.15×0.15
⇒5.95.99 N
Learn more about force here: http://brainly.com/question/25239010
#SPJ2
The bus lay 40 km at a speed of 72 km / h, and then another 60 km at a speed of 30 m / s. Determine the average speed of the bus along the way.
Answer:
25 m/s
Explanation:
From the question,
Average speed = Total distance /total time.
S' = D/T........................... Equation 1
D = 40+60 = 100 Km = 100000 m.
T = t₁+t₂
t₁ = (40×3600/72) s = 2000 s
t₂ = 60000/30 = 2000 s
T = 2000+2000 = 4000 s.
SUbstitute the values of T and D into equation 1
S' = 100000/4000
S' = 25 m/s
Which of the following is a conductor?
copper
water
aluminum
all of the above
Answer:
D all of the above
Explanation:
electricity moves easily through all of them and none of them prevent the flow of electricity
Alternate current
Hello!
I need solve 2 questions, I tried but im so bad at physics :(
1. If the frequency in the network is 50Hz, what is the period of this voltage?
2. The effective voltage value in the network is 230V. What is its maximum value?
I would like an explanation with a calculation for my understanding!!
Thanks in advance you all!
sorry bro but i don't know his i am also bad
Explanation:
but maybe you can you the formula of volatage as well as
When an object threw to the free space to make an angle of 25 degree at an initial speed of 15 m/sec, the ball takes time to reach another position 1.12 sec. Find the travelling path of the object.
Answer:
The horizontal distance traveled by the projectile is 15.23 m.
Explanation:
Given;
angle of projection, θ = 25⁰
initial velocity of the projectile, u = 15 m/s
time of flight, t = 1.12 s
The the travelling path of the object is calculated as the range of the projectile
[tex]R = u_x t\\\\R = (15\ Cos \ 25^0) \times 1.12\\\\R = 13.595 \times 1.12\\\\R = 15.23 \ m[/tex]
Therefore, the horizontal distance traveled by the projectile is 15.23 m.
The provided text reads: "a typical lightning bolt may transfer 10^20 electrons in a fraction of a second, developing a peak current of up to 10 kiloamperes." Using the value of the elementary charge of 1.6x10^-19 C We can estimate the total charge of the lightning bolt to be about *
1.6E1 C
1.6E4 C
1.6E10 C
1.6E20 C
Answer:
1.6e20
Explanation:
PLEASEEEE HELP ASAP
What are the two main divisions
of the peripheral nervous system?
A. Muscular Nervous System, Digestive Nervous
System
B. Circulatory Nervous System, Endocrine
Nervous System
C. Somatic Nervous System, Autonomic Nervous
System
What is optics???????
see my percentage of answering and thanks , it's crazy
Answer:
hi..bro
make pinky sis answer as brinlist ok
have a good day
A uniform 2.00-kg circular disk of radius 20.0 cm is rotating clockwise about an axis through its center with an angular speed 30.0 revolutions per second. A second uniform 1.50-kg circular disk of radius 15.0 cm that is not rotating is dropped onto the first disk so that the axis of rotation of the first disk passes through the center of the second disk. What is the final angular speed of the two disks when they are rotating together
Answer:
w = 132.57 rad / s
Explanation:
To solve this exercise we must define a system formed by the two discs, therefore the angular momentum is conserved
initial
L₀ = I₀ w₀
final
L_f = I w
how the moment is preserved
L₀ = L_f
I₀ w₀ = I w
the moment of inertia of disk 1 is
I₀ = ½ m₁ r₁²
The moment of inertia of the set is
I = I₀ + I₂
I = ½ m₁ r₁² + ½ m₂ r₂²
we substitute
½ m₁ r₁² w₀ = (½ m₁ r₁² + ½ m₂ r₂²) w
w = [tex]\frac{ m_1r_1^2 }{ m_1 r_1^2+ m_2r_2^2} \omega_o[/tex]
let's reduce the magnitudes to the SI system
w₀ = 30.0 rev / s (2π rad / 1 rev) = 188.5 rad / s
let's calculate
w = ( [tex]\frac{ 2 \ 0.20^2}{ 2 \ 0.20^2 + 1.5 \ 0.15^2 }[/tex]) 188.5
w = ( [tex]\frac{0.08}{ 0.11375}[/tex] ) 188.5
w = 132.57 rad / s